Physics2 mindmap final exam

PV = nRT = NkT
nR = Nk
With N = n.Na(Avodgadro)
Ideal gas

Where :
k = 1.38 x 10^-23
NA = 6.02 x 10^23
R = 0.082 when P (atm) ; V(dm^3 = liter)
R = 8.314 (Usually used) when P(Pa) ; V (m^3)
T : C + 273.15 (K)

The mean free path for a gas molecule

Distance between two molecules or atoms
With d : diameter (m)

Root- mean – square speed

Average speed
Kinetic theory of gases
Most probable speed

The mean free time

Average translational kinetic energy
Monatomic gas --> f = 3
Diatomic gas --> f = 5
Polyatomic gas --> f = 7
Isochoric ( V constant)
Isobaric ( P constant)

Molar specific heats of an ideal gas
For a particular process

V. P=nR T
p. V=nR T
(pV)=nR T
Pf.Vf – Pi.Vi = nR T

Cv = f/2*R
Cp = (f+2)/2 * R

Chapter 4

Isochoric ( V constant)

Isobaric ( P constant)
State converting of an ideal gas

Isothermal ( T constant)

Physics2 Final Exam

Adiabatic ( Q = 0 )

Eint=Q-W=nCv T (J)
Heat and first law of thermodynamics

Change in entropy

Heat : Q = nC T (J)

Cv or Cp

S=mc(lnT2-T1)

Second law of thermodynamics

S≥0

Isochoric ( V constant)

Entropy in ideal gas
Isobaric ( P constant)

Chapter 5

Isothermal ( T constant)
Adiabatic(Q=0)

S=0

Cooling or heating

Phase change
Entropy in liquid and solid

Unchanging T-process
Q = mc T
When phase change : Q = Lm