đáp án đề thi lí thuyết tốt nghiệp khóa 3 - lập trình máy tính - mã đề thi ltmt - lt (13)


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 ! 
"#!$%"&$ '()**+,)*-).
"/01!23 45
6/0784984:6"
;<=>?/@0,0-'
AB CBD CEF

  
,!"#$%&'()*+,-+./012"345 5&
)*+,6!)*+1,02)*+,78)*+1,9:)*+,6
)*+1,  !)*",;&<7=
,!#$%&'()*+,-+./012345 5&
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345 5&)*+,6!)*+1,02)*+,78)*+1,9
:)*+,6)*+1, !)*,;&<
7=
,01!@2A
"4BC
"BC
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"4BC
D'EF 6!EGH
IJKL4M4"4"4LL4MC4BC4NN4NO
#PC
"4QC
"4BC
#BPC

I;
!
I*", I*, I*B, I*M, I*R, I*C, I*S, I*Q, I*N,


L M " " LL MC BC NN N
! * L M " LL )G MC -H NN
!B ' L " -H LL )G MC NN
!M L " N )G LL MC NN
!R " N BC 'G LL NN
!C N BC MC HH LL
!S BC MC NN LL
!Q MC NN LL
!N NN LL
&IJ
KBL
* ' + -* -H )G 'G HH ++
B 0TRU=V'F.
,WX#02Y⊇$$ZY
,#02$ZY6YZ[$Z[
,\]#02$ZY[$ZY6$Z[
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"4BC
"4BC
"4BC
"4BC
D'EF#.:5E^_`a
3 _b-c3
B3 b`-cR3
M3 _`-UBdM3

R3 __-'WX3
C3 _-'\]3
S3 _b-@2'dC3
Q3 b-cM3
N3 _-SdQ3
L3 _`-@2'MdN3
"3`a-cC3
3_a-Ld"3
B3_`a-@2'Md3
4"
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'
#include <conio.h>
#include <iostream.h>
#include <math.h>
class DT
{
private:
double a[20];// Mang chua cac he so da thuc a0,
a1,
int n ;// Bac da thuc
public:
void nhap();
void hienthi();
DT operator+(const DT &d2);
double operator^(double x);// Tinh gia tri da
thuc
};
"4BC
void DT::hienthi()

{
cout<<a[0]<<"X^0";
for (int i=1 ;i<= n ;++i)
cout<<"+"<< a[i] <<"X^"<<i ;
}
"4BC
#MPC
void DT::nhap()
{
cout << "Bac da thuc:";
cin >> n;
cout << "Nhap cac he so da thuc:" ;
for (int i=0 ;i<=n ;++i)
{
cout << "\n He so bac"<<i<<":" ;
cin >> a[i] ;
}
}
"4BC
DT DT::operator+(const DT &d2)
{
DT d;
int k,i;
k = (n > d2.n)?n:d2.n ;
for (i=0;i<=k ;++i)
if (i<=n && i<=d2.n)
d.a[i] = a[i] + d2.a[i];
else
if (i<=n)
d.a[i] =a[i];

else
d.a[i] = d2.a[i];
i = k;
while (i>0 && d.a[i]==0.0) i;
d.n=i;
return d ;
}
"4QC
double DT::operator^(double x)
{
double s=0.0 , t=1.0;
for (int i=0 ;i<= n ;++i)
{
s+= a[i]*t;
t *= x;
}
return s;
}
"4BC
#RPC
void main()
{
DT p,q,f;
double x,g;
clrscr();
cout <<"\n Nhap da thuc P :" ;p.nhap();
cout <<"\n Nhap da thuc Q :" ;q.nhap();
cout << "\n Nhap so thuc x :" ;cin >> x;
f = (p+q);
g = f^x;

cout << "\n Da thuc f ";
f.hienthi();
cout<<"\n x =" << x;
cout << "\n f(x) = "<<g;
getch();
}
"4BC
M!NJO

PPPMMQDRSPPPPJTDPPPMMUFPPPPMM
#CPC