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NATIONAL UNIVERSITY OF CIVIL ENGINEERING
CONSTRUCTION ENGINEERING AND MANAGEMENT
----------------

MINI PROJECT
CONSTRUCTION ORGANIZATION
Content: Design of Construction schedule and Site logistics

SUPERVISOR NAME

: PHAM NGUYEN VAN PHUONG

STUDENT NAME

: HOANG XUAN THIEN LONG

STUDENT ID

: 1527963

CLASS

: 63XE4

DATE OF ASSIGNMENT

: 05/10/2022

HANOI , 2022

C0NSTRUCTION ORGANIZATION PROJECT

TABLE OF CONTENTS

LIST OF FIGURES

LIST OF TABLES

STUDENT: HOANG XUAN THIEN LONG

2


C0NSTRUCTION ORGANIZATION PROJECT

PROJECT DESCRIPTION

1. Introduction in the building
- Structure of the building is monolithic reinforced concrete structure. The building has
11 storeys and 20 spans. All the geometric data of the building is illustrated in the
below table.
- Construction and site conditions of the building:
• Geological properties: soil grade II with high strength of soil. There’s no need to
reinforce foundation pit.
• The level of water table is by far greater than the level of foundation pit.

2. Project data
Table 1. Project information
Number of stories
Number of bays

[�]���� (�� /�� 2)
�����(��� /�3)
Season
b(m)

Foundation

A
B
C

A(m)
t(cm)
B(m)

Body

1
2

L(m)
H1(m)
Ht(m)
Hm(m)
C1(d/h1)

Column

C2(d/h2)

F1,F2
F3, F4
F5, F6
F7, F8
F9, F10, F11
F1,F2
F3, F4
F5, F6
F7, F8
F9, F10 , F11

s(cm)
D1b
D1g

D1
Beam D (cm)
STUDENT: HOANG XUAN THIEN LONG

D2
D3

11
20
100
600
Winter
1,2
1,7
1,7

1,5
45
3,3
5,8
4,0
4,5
3,4
3,4
25/45
25/40
25/35
25/30
25/25
25/50
25/45
25/40
25/35
25/30
12
25x60
25x40
20x30
20x30
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C0NSTRUCTION ORGANIZATION PROJECT

Roof

Dm
D roof(cm)
�%

Reinf.ratio

25x60
10
2,0%

Figure 1. Structural plan of building

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

A

B

C

D

E

Figure 2. Structural elevation B-B

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

Figure 3. Structural Elevation A-A

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

Figure 4. Isolated footing plan
3. Foundation structure
a. Depth of foundation:

Hm = 3t = 120 + m ×10 = 120 + 1×10 = 130(cm) à Choose t = 45 (cm)
b. Dimension of foundation are chosen following to the formula below:
STUDENT: HOANG XUAN THIEN LONG

6

16

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C0NSTRUCTION ORGANIZATION PROJECT

- Outer footing (axis A & E):
1
1
a1 = × (0,5L1 ) + 10 × T = × (0,5 × 580) + 10 ×11 = 139(cm)
10
10
7
7
b1 = a1 = ×139 = 97.3(cm)
10
10
 Choose: a1 = 140cm; b1 = 100cm

2

A

Figure 5. Foundation axis A
- Middle footing (axis B & D):
1
1
a2 = L2 + 10 × T = × 580 + 10 ×11 = 168(cm)
10
10
7
7
b2 = a2 = ×168 = 117(cm)

10
10
 Choose: a2 = 170cm; b2 = 120cm
STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

2

B

Figure 6. Foundation axis B
- Middle footing (axis C)
1
1
a3 = L2 + 10 × T = × 400 + 10 ×11 = 150(cm)
10
10
7
7
b3 = a3 = ×150 = 105(cm)
10
10
 Choose: a3 = 150cm; b3 = 105cm

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

2

C

Figure 7. Foundation axis C
4. Ground
h0 = 2 × 45 = 90(cm)

Thickness of lining concrete:

t1 = 10 + m = 10 + 1 = 11(cm) à Choose: t = 15 (cm)
1
Thickness of reinforced concrete:

t2 = 10 + 2m = 10 + 2 ×1 = 12(cm) à Choose: t = 15 (cm)
2
Thickness of foundation sand:

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

t3 = h0 − t1 − t2 = 95 − 15 − 15 = 65(cm)

Figure 8. Ground
5. Roof
- Waterproofing:

4,5 +

n
6
= 4,5 +
= 4,8
20
20
à Choose: 5 cm

n
6
12 + = 12 + = 14
3
3
- Heat proofing:
à Choose: 15 cm
- 2 layers of traditional terra-cotta floortile (ceramic tile)

Figure 9. Roof
6. Wall
- According to axis: External wall 200 (mm), internal wall 110 (mm).
- Plaster 40% of external wall area ; 50% of internal wall area.
- Paint 40% of external wall area ; 50% of internal wall area.

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

- Doors ( and windows) take 60% of external wall area ; 10% of internal wall
area.
7. Power, water factor :
- 0,32 working hour per 1m2 of floor.
8. Construction plan and location of building
a) Construction plan

Figure 10. Construction plan

Figure 11. Building location on construction plan
X1 = 10 + 5n = 10 + 5 × 6 = 40(m)
n
6
X 2 = 15 + = 15 + = 18(m)
2
2
Y1 = 10m + n = 10 ×1 + 6 = 16(m)
Y2 = (m + n) ×10 = (1 + 6) ×10 = 70(m)

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

CHAPTER 1. CONSTRUCTION SCHEDULE
A. FOUNDATION CONSTRUCTION
1. List of tasks
Main ask:
1. Machanical excavation.
2. Manual excavation (fixing).
3. Pouring lean concrete of foundations and ground beams.
4. Installing foundation, ground beam and column reinforcement.
5. Installing foundation and ground beam formwork.
6. Pouring foundation and ground beam concrete.
7. Dismantling foundation and ground beam formwork.
8. Installing column formwork.
9. Pouring column concrete.
10. Dismantling column formwork.
11. Brickwork (foundation wall)
12. Installing plinth beam formwork
13. Installing plinth beam reinforcement
14. Pouring plinth beam concrete
15. Dismantle plinth beam formwork
16. Back-filling phase
17. Foundation sand
18. Pouring lean concrete for 1st floor ground base
19. Installing reinforcement for 1st floor ground base
20. Pouring concrete for 1st floor ground base
2. Construction method and the calculation of work volumn
2.1.

Excavation

2.1.1. Selection of soil excavation method
Select the dimensions of ground beam : 45 x 20(cm)
Total depth of the excavation: Hd = 3 × 45 + 10 =145 (cm) = 1,45 (m)
Slope factor: m = 1:0,25 (soil grade II)
Distance B d = 0,25 × H d = 0, 25 ×1, 45 = 0,3625(m) à Choose Bd = 0,4 (m)
STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

Excavation dimensions:
- Bottom pit:
• Axis A&E:
• Axis B&D:
• Axis C:
- Top pit:
• Axis A&E:
• Axis B&D:
• Axis C:

ad1 = a1 + 2 × 0,5 = 1, 4 + 2 × 0,5 = 2,4(m)
bd1 = b1 + 2 × 0,5 = 1,0 + 2 × 0,5 = 2(m)
ad2 = a2 + 2 × 0,5 = 1,7 + 2 × 0,5 = 2,7(m)
bd2 = b2 + 2 × 0,5 = 1,2 + 2 × 0,5 = 2,2(m)
ad3 = a3 + 2 × 0,5 = 1,5 + 2 × 0,5 = 2,5(m)
bd3 = b3 + 2 × 0,5 = 1,05 + 2 × 0,5 = 2,05(m)

a1 ' = ad1 + 2 Bd = 2, 4 + 2 × 0.4 = 3,2(m)
b1 ' = bd1 + 2 Bd = 2 + 2 × 0.4 = 2,8(m)
a2 ' = ad2 + 2 Bd = 2,7 + 2 × 0.4 = 3,5(m)
b2 ' = bd2 + 2 Bd = 2,2 + 2 × 0.4 = 3(m)
a3 ' = ad3 + 2 Bd = 2,5 + 2 × 0.4 = 3,3(m)
b3 ' = bd3 + 2 Bd = 2,05 + 2 × 0.4 = 2,85(m)

The figure below shows the dimensions of a typical foundation.

A

2

2

Figure 12. Excavation pit for isolated footing axis A-2
STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

B

2

2

Figure 13. Excavation pit for isolated footing axis B-2

2

C

2

Figure 14. Excavation pit for isolated footing axis C-2
STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

When not considering the excavation for the construction of ground beams, we
have a excavation plan of isolated footings as flollow:

B

A

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

B
Figure 15. Excavation plan

1

2

3

4

5

Figure 16. Section A-A

STUDENT: HOANG XUAN THIEN LONG

15

18

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C0NSTRUCTION ORGANIZATION PROJECT

A

B

C

D

E

Figure 17. Section B-B
According to figure 15, 16 and 17, although soil left after digging foundation pits
following to axis A and B, D and E are large with 2.45m length, that after digging
foundation pits axis B, C and D are small with 0.6m lenth. In addition, soil left
after digging foundation pit following to axis 1,2,3,…,21 are also small with 0.3m
length. Moreover, ground beams are located on the surface of 1 st step of isolated
footing.
⇒ Excavation method: Mechanical combined with manual method. The
method is divided into 2 phases:
• 1st phase: Excavating pond dig from ground level (-0,9 m) to bottom of lean
concrete of ground beam level (-1,9 m)
• 2nd phase: Excavating holes for 2nd level of footing from bottom of concrete
of ground beam level (-1,9 m) to bottom of lean concrete of isolated footing
level (-2.35 m)
• The foundation pits are flattened by labour and roller.
� I have excavation plan as blow:

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

1

2

3

4

5

6

7

8

9

10

11

12

13

14

Figure 18. 1st phase excavation plan

STUDENT: HOANG XUAN THIEN LONG

17

15

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C0NSTRUCTION ORGANIZATION PROJECT

B

A

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

B
Figure 19. 2nd phase excavation plan

STUDENT: HOANG XUAN THIEN LONG

18

16

17

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C0NSTRUCTION ORGANIZATION PROJECT

1

2

3

4

5

Figure 20. Section A-A

A

B

C

D

E

Figure 21. Section B-B
2.1.2. Calculation of soil volume
Recalculate the pit excavation dimension:
a) 1st phase: Excavating pond dig from ground level (-0,9 m) to bottom of lean
concrete of ground beam level (-1,9 m)
- Pit bottom:
1, 2
A = 20B + 2 × 0,5 + + tan(90° −15°) × 0,9
2
1, 2
= 20 × 3,3 + 2 × 0,5 + + tan(90°−15°) × 0,9 = 68,26m

2
B = 2(L1 + L2) + 2 × 0,5 + 2 × 0,7 + tan(90 −15) × 0,9
= 22,26m
- Pit top:
C = 2 × 0,55 × tan(90 − 75) + A = 68,8m
D = 2 × 0,55× tan(90 − 75) + B = 22,8m
 Excavation volume:
V1 =

H
6

[A × B + (C + A) × ( B + D) + D × C ]

1

= [68,26 × 22,26 + (68,26 + 68,8) × (22,8 + 22,26) + 22,8 × 68,8]
6

=1555(m3 )
b) 2nd phase: Excavating holes for 2nd level of footing from bottom of concrete
of ground beam level (-1,45 m) to bottom of lean concrete of isolated
footing level (-2.35 m)
STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

Excavating holes for axis A, E: There are 42 pit holes.
A = 2,65(m)
B = 2,25(m)
 Excavation volume:
V2 = 42 × A × B × H
=42 × 2,65 × 2, 25 × 0, 45

= 112,7m3
Excavating holes for axis B, D: there are 42 pit holes
A = 2,945(m)
B = 2, 25(m)
 Excavation volume:
V3 = 42 × A × B × H
=42 × 2,945 × 2, 25 × 0, 45

= 125,2m3
Excavating holes for axis C: there are 21 pit holes
- Pit bottom:
A = 2,75(m)
B = 2,05(m)
 Excavation volume:
V3 = 42 × A × B × H
=42 × 2,75 × 2, 25 × 0, 45

= 116,9m3
 Total excavation volume:

V = V1 + V2 + V3 + V4 = 1555 +112,7 + 125,2 +116,9 = 1909,8(m3 )
- Excavation volume by machine:
Vm = 0,9 ×V = 0,9 ×1909,8 ×1,2 = 2062,6(m3 )

- Excavation volume by manual method:
Vmm = 0,1×V = 0,1×1909,8 ×1,2 = 229.176(m3 )
2.1.3. The selection of excavator
a) Excavator selection
Base on volume of soil excavated, we select Backhoe excavator EO-3322B1
with the following parameters:

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

-

Bucket volume: q= 0,5(� 3)
Maximum radius: R=7,5 (m)
Maximum dumping height: h= 4,8 (m)
Maximum digging depth: H=4,2 (m)
Slewing cycle: t= 17 (s)
Productivity:
N = q × K d × nck × Ktg
In which:
q = 0,5 m3: Bucket volume
Kd = 1: Factor of full-filling bucket
Ktg = 0,75: Time factor
nck =


3600
3600
3600
=
=
= 192,51
Tck
tck × K vt × K quay 17 ×1,1×1

N = q × K d × nck × Ktg = 0,5 ×1×192,51× 0,75 = 65,16(m3 / h)

3
Productivity of backhoe per shift: N = 65,16 × 8 = 521,3(m / shift )

Number of shifts for the excavation:
STUDENT: HOANG XUAN THIEN LONG

n=

Vm 2062,6
=
= 3,95
N 521,3
(shifts)
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C0NSTRUCTION ORGANIZATION PROJECT

 Select one machine with 4 shifts for excavation process

 Using a excavator, the working time 1 shift/day and work for 4 days
 Method of digging soil:
The machine stands on high to put the bucket under the foundation pit to dig the
ground. When the bucket is full of soil, turn the bucket from the digging position
to the pouring position, and the car is standing next to it.
b) Dump truck selection
Assume that distance from site to the material gathering yard about 30km. Velocity
of the truck is about 70km/h.
Time for truck to do a cycle:

t1 =

2 × 30
= 0,86(h)
70

t2 = 0,5(h)

Bufer time:

Number of cycle a truck can do in a shift:

n1 =

8
= 5,88(cycles) = 6(cycles)
0,86 + 0,5

 The truck can do 6 cycles in a shift
Select dump truck VEAM VM-551605 with following parameters:

3
ã Bucket volume: P = 4, 44 ì 2, 28 ì1,54 = 15,6(m )
ã Body weight: P = 20 (T)

3
Volume of soil that one truck can do in a shift: V = 6 ×15,6 = 93,6(m )

Number of trucks needed in a shift:

n=

521,3
= 5,57(trucks)
93,6

 6 trucks needed for the transportation in 1 shift
Select 6 trucks with 4 shifts for excavation process
2.2.

Lean concrete construction

Lean concrete is mixed at construction site and then transported to the foundation
pit by manner. The lean concrete volume is estimated by the following table:

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

Table 2. Lean concrete volume
LEAN CONCRETE
Quantit
y

Volume (m3)

(5)

(6)

(7)=(3)x(4)x(5)x(6
)

1,2

0,1

42

8,064

1,9

1.4

0,1

42

11,172

Foundation

1,7

1,15

0,1

21

4,105

AB. DE

Ground
beam

4,85

0,4

0,1

42

8,148

BC, CD

Ground
beam

3,35

0,4

0,1

42

5,628

A,E1,2,…,21

Ground
beam

2,675

0,4

0,1

40

4,28

B,D1,2,
…,21

Ground
beam

2,5

0,4

0,1

40

4

C1,2,…,21

Ground
beam

2,675

0,4

0,1

20

2,14

Ground
floor

66

19,6

0,1
5

1

194,04

Axis

Componen
t

Dimension (m)

(1)

(2)

(3)

(4)

A, E

Foundation

1,6

B, D

Foundation

C

Total concrete volume (m3)
2.3.

241,57

Isolated footing and gorund beam construction

2.3.1. Calculation of concrete, reinforcement, formwork volume for
isolated footings and ground beams
Table 3. Foundation concrete volume
Axis

Element

Dimension (m)

Quantit
y

Volume

42

26,46

(m3)

Length Width Height
A, E

Spread
footing

2nd
step

STUDENT: HOANG XUAN THIEN LONG

1,4

1

0,45

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C0NSTRUCTION ORGANIZATION PROJECT

B, D

C

1st step

0,9

0,625

0,45

2nd
step

1,7

1,2

0,45

1st step

1,025

0,8

0,45

2nd
step

1,5

1,05

0,45

1st step

0,9

0,625

0,45

Spread
footing

Spread
footing

10,62
42

38,55
15,5

21

14,88
5,31

A, E

Column

0,45

0,25

0,45

42

1,65

B, C, D

Column

0,5

0,25

0,45

63

2,84

AB, DE

Ground beam

5,425

0,2

0,45

42

20,5

BC, CD

Ground beam

3,6

0,2

0,45

42

13,61

A,E1,2,…,21

Ground beam

3,05

0,2

0,45

40

10,98

B,D1,2,
…,21

Ground beam

3,05

0,2

0,45

40

10,98

C1,2,…,21

Ground beam

3,05

0,2

0,45

20

5,49

Total concrete volume (m3)

177,37

Table 4. Foundation reiforcement
FOUDATION REINFORCEMENT
Axis

Component

Volumn (m3) Ref. Unit
Weight
(kg/m3)

Ref.
Ratio
(%)

Mass per
unit

A, E

2nd step

26,46

7850

2

4154,22

1st step

10,62

7850

2

1667,34

2nd step

38,55

7850

2

6052,35

1st step

15,5

7850

2

2433,5

2nd step

14,88

7850

2

2336,16

1st step

5,31

7850

2

833,67

Column

1,65

7850

2

259,05

B, D

C

A, E

STUDENT: HOANG XUAN THIEN LONG

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C0NSTRUCTION ORGANIZATION PROJECT

B, C, D

Column

2,84

7850

2

445,88

AB, DE

Ground beam

20,5

7850

2

3218,5

BC, CD

Ground beam

13,61

7850

2

2136,77

A,E1,2,…,21 Ground beam

10,98

7850

2

1723,86

B,D1,2,
…,21

Ground beam

10,98

7850

2

1723,86

C1,2,…,21

Ground beam

5,49

7850

2

861,93

Total reinforcement mass (kg)

27847,09

Table 5. Foundation formwork area
Axis

A, E

B, D

C

A, E

Element

Spread
footin
g

Spread
footin
g

Spread
footin
g

Lengt
h

Widt
h

Heigh
t

Area
per
unit
(m2)

2nd
ste
p

1,4

1

0,45

2,12

1st
ste
p

0,9

0,625

0,45

1,22

2nd
ste
p

1,7

1,2

0,45

2,66

1st

ste
p

1,025

0,8

0,45

1,44
5

2nd
ste
p

1,5

1,05

0,45

2,3

1st
ste
p

0,9

0,625

0,45

1,22

0,45

0,25

0,45

0,23

Column

Dimension (m)

STUDENT: HOANG XUAN THIEN LONG

Quantit
y

Area
(m2)

42

89,04

51,24

42

111,72

60,69

21

48,3

25,26

42

9,66
25