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INDRAPRASTHA INSTITUTE OF INFORMATION TECHNOLOGY DELHI ECE321521 LECTURE – 7

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Indraprastha Institute of ECE321/521
Information Technology Delhi

Lecture – 7 Date: 28.01.2017

• Admittance Smith Chart
• High Frequency Network Analysis (intro)
• Impedance, Admittance and Scattering Matrix
• Matched, Lossless, and Reciprocal Networks

Indraprastha Institute of ECE321/521
Information Technology Delhi

Admittance Transformation

• RF/Microwave network, similar to any electrical network, has impedance elements
in series and parallel

• Impedance Smith chart is well suited while working with series configurations
while admittance Smith chart is more useful for parallel configurations

• The impedance Smith chart can easily be used as an admittance calculator

zin (z)  1   z  yin  z   Yin  z   1/ Zin  z   1  1
1z Y0 1 / Z0 Zin  z  / Z0 zin  z 

• Hence, yin  z  1   z 1 e j   z 
1  z yin  z    j

1e z


It means, to obtain normalized admittance → take the normalized impedance
and multiply associated reflection coefficient by -1 = e-jπ → it is equivalent to
a 180⁰ rotation of the reflection coefficient in complex Γ-plane

Indraprastha Institute of ECE321/521
Information Technology Delhi

Example – 1

• Convert the following normalized input impedance 𝑧𝑖𝑛′ into normalized
input admittance 𝑦𝑖𝑛′ using the Smith chart:

zin'  1 j1  2e j( /4)

First approach: The normalized admittance can be found by direct inversion as:

yin'  '1  1  1 e j( /4)  1  j 1
zin 1 j1 2 22

Alternative approach:

• Mark the normalized impedance on Smith chart
• Identify phase angle and magnitude of the associated reflection coefficient
• Rotate the reflection coefficient by 180⁰
• Identify the x-circle and r-circle intersection of the rotated reflection

coefficient

Indraprastha Institute of ECE321/521
Information Technology Delhi

Normalized
Example – 1 (contd.) impedance (zin’) is the
intersection of r-circle
Quick investigation of 1 and x-circle of 1
shows that the
normalized Rotate this by 180⁰
to obtain normalized
impedance (yin’ ) is
the intersection of admittance
r-circle of 1/2 and

x-circle of -1/2

To denormalize, multiply
with the inverse of Z0.

Yin  yin' 1  Y0 yin'
Z0

Indraprastha Institute of ECE321/521
Information Technology Delhi

Example – 2

Given: zin'  1 j2

• Find the normalized admittance l/8 away from the load

Steps:


1. Mark the normalized impedance on Smith Chart
2. Clockwise rotate it by 180⁰
3. Identify the normalized admittance and the phase angle of the

associated reflection coefficient
4. Clockwise rotate the reflection coefficient (associated with the

normalized admittance) by 2βl (here l = λ/8)
5. The new location gives the required normalized admittance

Indraprastha Institute of ECE321/521
Information Technology Delhi
zin'  1 j2
Example – 2 (contd.)
180⁰ clockwise
yin'  0.20  j0.40 rotation

Clockwise rotation by

l

2l  4  
l

yin'  0.2  j0.4

l  l / 8  2l  90o

Indraprastha Institute of ECE321/521
Information Technology Delhi


Admittance Smith chart

• Alternative approach to solve parallel network elements is through 180⁰
rotated Smith chart

• This rotated Smith chart is called admittance Smith chart or Y-Smith chart
• The corresponding normalized resistances become normalized

conductances & normalized reactances become normalized suceptances

r  R  g  G  Z0G
Z0 Y0

x  X  b  b  Z0B
Z0 Y0

• The Y-Smith chart preserves:
• The direction in which the angle of the reflection coefficient is
measured
• The direction of rotation (either toward or away from the generator)

Indraprastha Institute of ECE321/521
Information Technology Delhi
Angle of reflection
Admittance Smith chart (contd.) coefficient

Negative Values of
Suceptances


→Inductive Behavior

Open Circuit Positive Values of
Suceptances
→Capacitive
Behavior

Short Circuit

In this chart, admittance is represented in exactly the Real Component of Admittances
same manner as the impedance in the Z-smith Chart Decrease from Left to Right

→ without 180⁰ rotation

Indraprastha Institute of ECE321/521
Information Technology Delhi
Red: Z – Smith Chart
Combined Z- and Y- Smith Charts

Blue: Y – Smith Chart

Indraprastha Institute of ECE321/521
Information Technology Delhi

Example – 3

• Identify (a) the normalized impedance z’ = 0.5 + j0.5, and (b) the normalized
admittance value y’ = 1 + j2 in the combined ZY-Smith Chart and find the
corresponding values of normalized admittance and impedance


y'  1 j1 z'  0.5  j0.5

z'  0.2  j0.4 y' 1 j2

Indraprastha Institute of ECE321/521
Information Technology Delhi

High Frequency Networks

• Requirement of Matrix Formulation

Current/Voltage or directional coupler Current/Voltage or
Incident/Reflected (more than one port) Incident/Reflected

Traveling Wave Traveling Wave

NO!! These are called Can we characterize this
networks using an impedance or

What is the way? admittance!
Impedance or Admittance Matrix. Right?

In principle, N by N impedance matrix completely characterizes a linear N-
port device. Effectively, the impedance matrix defines a multi-port device the

way a ZL describes a single port device (e.g., a load)

Linear networks can be completely characterized by parameters measured at
the network ports without knowing the content of the networks.


Indraprastha Institute of ECE321/521
Information Technology Delhi

Multiport Networks

• Networks can have any number of ports – however, analysis of a 2-port,
3-port or 4-port network is sufficient to explain the theory and the
associated concepts

I1 I2

Port 1 + 2 Port + Port 2
V1 Network V2
- -

• The ports can be characterized with many parameters (Z, Y, S, ABCD). Each
has a specific advantage.

• For 2-port Network, each parameter set is related to 4 variables:
o 2 independent variables for excitation
o 2 dependent variables for response

Indraprastha Institute of ECE321/521
Information Technology Delhi

The Impedance Matrix Four identical TLs
used to connect
• Let us consider the following 4-port network: this network to the
outside world
This could be a I2 (z2 ) 

simple linear device V2 (z2 ) I3 ( z3 )
or a large/complex 
Port-2 z2  z2P V3 ( z3 )
linear microwave 
system Z0 Port-3
z3P
Either way, the I1 ( z1 ) Port-1 Z0
network can be fully  z3  Each TL has
V1 ( z1 ) 4-port specific location
described by its  Z0 Linear Microwave z4  z4P that defines input
impedance matrix impedances to
z1 Network
the network
 z1P
Z0

Port-4

I4 (z4 ) 
V4 (z4 )

The arbitrary locations are known as ports of the network

Indraprastha Institute of ECE321/521
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The Impedance Matrix (contd.) Vn (zn  znP ) In (zn  znP )

• In principle, the current and voltages at
the port-n of networks are given as:


• However, the simplified Vn  Vn (zn  znP ) In  In (zn  znP )
formulations are:

• If we want to say that there exists a non-zero I2  I3  I4  0

current at port-1 and zero current at all other I1  0

ports then we can write as:

need to measure/determine the associated voltages and currents at • In order to define the elements of impedance matrix, there will be Z21  IV2
the respective ports. Suppose, if we measure/determine current at 1
port-1 and then voltage at port-2 then we can define:

• Similarly, the trans-impedance Z31  V3 Z41  V4 Trans-impedance
parameters Z31 and Z41 are: I1 I1

• We can also define other trans-impedance parameters such as Z34 as the ratio

between the complex values I4 (the current into port-4) and V3 (the voltage at

port-3), given that the currents at all other ports (1, 2, and 3) are zero.

Indraprastha Institute of ECE321/521
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The Impedance Matrix (contd.)

• Therefore, the more generic Zmn  Vm (given that Ik = 0 for all k≠n)
form of trans-impedance is: In


How do we ensure that all but one port current is zero?

• Open the ports I  0  V2  Port-2

where the current 2 Z0
needs to be zero: I1
I3  0

 4-port Linear  The ports should
V1 Z0 Microwave Z0 V3 be opened! not
 Network the TL connected

Port-1 to the ports
Port-3

I4  0 Z0 Port-4
 V4 

• then define the respective Z  Vm (given that all ports k≠n are open)

mn
trans-impedances as: In

Indraprastha Institute of ECE321/521
Information Technology Delhi

The Impedance Matrix (contd.)

• Once we have defined the trans-impedance terms by opening various ports, it is

time to formulate the impedance matrix

• Since the network is linear, the voltage at any port due to all the port currents is
simply the coherent sum of the voltage at that port due to each of the currents

• For example, the voltage at port-3 is: V3  Z34I4  Z33I3  Z32I2  Z31I1

• Therefore we can generalize the N

voltage for N-port network as: Vm   Zmn In  V = ZI
n1

• Where I and V are T T
vectors given as:
V = V1, V2, V3, ...., VN  I = I1, I2, I3, ...., IN 

 Z11 Z12 Z1n 
 • The term Z is matrix given by: Z   Z21 
  Impedance Matrix

 
Zm1 Zm2 Zmn 

• The values of elements in the impedance  Z11() Z12 () Z1n () 
 Z () 
matrix are frequency dependents and often it Z(  )   21 
 
is advisable to describe impedance matrix as: 
Z () Z ()
 m1 m2 Zmn ()


Indraprastha Institute of ECE321/521
Information Technology Delhi

The Admittance Matrix

• Let us consider I2 (z2 )  z2  z2P This can be
the 4-port V2 (z2 ) characterized using
network again: Port-2 admittance matrix – if
Z0

I1(z1) Port-1 Port-3 I3(z3) currents are taken as

 4-port Linear dependent variables
Microwave  instead of voltages
V1 ( z1 ) Z0 Network Z0 V3 ( z3 )

 

z1  z1P z3  z3P

Port-4 Z0 z4  z4P The elements of admittance
matrix are called trans-
I4 (z4 ) 
V4 (z4 ) admittance parameters Ymn

• The trans-admittances Y  Im (given that Vk Important: Ymn  1
Ymn are defined as: mn Vn = 0 for all k ≠
Z mn
n)


Indraprastha Institute of ECE321/521
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The Admittance Matrix (contd.) I2 V2  0 Port-2
Z0
• the voltage at all but one port
must be equal to zero. This can I1 I3
be ensured by short-circuiting
the voltage ports.  4-port Linear Z0 V3  0
V1 Z0 Microwave
The ports should be short-  Network
circuited! not the TL
Port-1 Port-3
connected to the ports
I4 Port-4 Z0
V4  0

• Now, since the network is linear, the current at any one port due to all the port
voltages is simply the coherent sum of the currents at that port due to each of
the port voltages.

• For example, the current at port-3 is: I3  Y34V4  Y33V3  Y32V2  Y31V1

• Therefore we can generalize the N

current for N-port network as: Im  YmnVn  I = YV

n1


Indraprastha Institute of ECE321/521
Information Technology Delhi

The Admittance Matrix (contd.)

• Where I and V are V = V1, V2, V3, ...., VN T T

vectors given as: I = I1, I2, I3, ...., IN 

• The term Y is matrix given by: • The values of elements in the admittance
matrix are frequency dependents and
Y11 Y12 Y1n  often it is advisable to describe
Y  Y21  admittance matrix as:

   Y11 ( ) Y12 () Y1n () 
   Y(  )  Y21() Ym2 () 
Ym1 Ym2 
Ymn   
 
Admittance Matrix Ym1 ( )
Ymn ()

You said that: Ymn  1
Z mn
Answer: Let us see if
Is there any relationship between we can figure it out!
admittance and impedance matrix of a

given device?


Indraprastha Institute of ECE321/521
Information Technology Delhi

The Admittance Matrix (contd.) I = YV

• Recall that we can determine the inverse of a matrix. Denoting
the matrix inverse of the admittance matrix as Y−1, we find:

 Y1I = Y1 YV  Y1I = Y1Y V Y1I = V

• We also know: V = ZI Z = Y1 OR Y  Z 1

Reciprocal and Lossless Networks

• We can classify multi-port devices or networks as either lossless or lossy;
reciprocal or non-reciprocal. Let’s look at each classification individually.

Lossless Network

• A lossless network/device is simply one that cannot absorb power. This does not
mean that the delivered power at every port is zero; rather, it means the total
power flowing into the device must equal the total power exiting the device.

• A lossless device exhibits an impedance matrix with an interesting Re(Zmn )  0
property. Perhaps not surprisingly, we find for a lossless device
that the elements of its impedance matrix will be purely reactive: For a lossless
device



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