Thực tập địa chất công trình
Bạn đang xem bản rút gọn của tài liệu. Xem và tải ngay bản đầy đủ của tài liệu tại đây (1.62 MB, 32 trang )
!
∀#∃%&∋(
)%∃∗+
!,!
−./0123∋∃4542
!∀#∃!%&∋(∃#)!∗#!∀#+,
−)!
./(01234 !5/%&∋(∃#)!∗#
6 78!%9#3#:;!∀#∃!%&∋(∃#)!∗#
6 .∀#∃!#<=>∋?=#+56
6 <=>≅Α8#8!Β6
6 <=>≅Α8#Χ∆
66 <=>!Ε#!∃∆
6∆ <=>Φ45;!#+∋:%∋∆
∆ .∀#∃!#<=>#+∋4Γ#<=>∆
−./016354)%∃∗+7
.∃!Η5;!!<!Ι!∀#∃!%∋%&∋(∃#)!∗#!∀#+,ϑ
8!Κ2)!(Λ#Μ∋#?)!∗#%Ν!ϑ
6 34 !5/!∋=!%∋%&∋(∃#)!∗#ϑ
6 :#+<!∃!1>%&∋(∃#ϑ
6 Ο∃!)! (Π%&∋(∃#Θ
∆ 5/4∃4%∋%&∋(∃#)!∗#!∀#+,Ρ
∆ 5/4∃4%∋#ΑΡ
∆ 5/4∃4%∋+ΛΗΣ>∃ΑΤ
ϑ Υ#Η)%∋?Α8#Ε!∋Μ#ςΤ
ϑ Υ#Η)%∋Τ
ϑΩ∃Α%∋Ο7ΞΨ
ϑ∃4%∋Ψ
ϑ6.%∋
ϑ∆ΩΖ%∋
ϑϑΥ#Η)2∗Α>[
ϑΘ∴]!]#∃∋2Ε4⊥ΠΜ!%∋∆
ϑ Α8#Ε!∋Μ#∀ϑ
Θ 5/4∃42∗Α>[?Η&∋&>[Θ
Θ 5/4∃42∗Α>[Θ
Θ 5/4∃4Η&∋&>[Θ
_ .∀#∃!!Φ4:%∋_
Ρ %Υ##+,>ς#=4%∋Ρ
−./0183∃499∗:2;
6 <=>≅Α8#8!Β#Τ
6 Υ#Η)#<=>Τ
6 Υ?#<=>Ψ
66 .2α%Υ#&
6∆ βχ]!∃!%Υ#&#<=>
6 <=>≅Α8#Χ6
6 δ∗ !6
6 Α82α#<=>∆
66 Υ#Η)#<=>∆
6∆ Υ?#<=>Θ
6ϑ ΟΛ2α?#+,Η?Α%Υ#&Θ
−./01<3449∗6=
∆ Ο∃!)χ#+ε!Ι∗##+∋4Γ#<=>Ρ
∆ Ο∃!)ςΒ>!Ι∗#Ρ
∆6 Ο∃!);Μφ##γ+Ηγ+!Ι∗#Ρ
∆∆ Ο∃!)#?4Μ#!Ι∗#Ρ
∆ϑ Ο∃!)(Κ!!:!Ε#!Ι∗#Ρ
∆Θ Ο∃!)#<Φ2η!Ι∗#Ρ
∆_ Ο∃!)ς!ι##8!Β!Ι∗#Ρ
,956;
!
!∀#
∀#∃%&∋()∗+∃#,−.+/#0
(1)20)34−56/7+%8#%/−
.9:9;+#1,<=>=?≅9ΑΒ=∃4Χ%:4
%>56/7∋)∆9049091%∃%8=9/%Ε%−).
9Φ(56/7∃2=∗452:Β192
%ΓΗΙ:)ϑΒ%499−72−,<6/4
6/Χ:=∃#1Κ#(2%∃
Α/6(−,</9Λ=∃=72ΜΓ−
%Μ%∆#1+#Β∗%ΕΓ.7Ν(%17∃−%(
−56/74%ΦΧ=Β%>56/71%
/∗:−Ο916/Α9
.+9.Β,<%−∗Γ.5+/4%.−Β%
,=Λ9#1 + (%1 56/74 −)+2,− Χ
Κ/%>20−−2−2#1)∗≅+)+2,−ΧΚ%Γ
#Π≅02−∗)∗#56/7
∃ %&∋∀()∗+,&−.+/0123.− 4(+05−+,&−670#
∃8∀ 40+0∀&#
Θ+2,−%:%%.956/7=∃ΡΛ
∗2#Χ∗)∗#56/7Θ92
)Λ%∗−)+2,−%7∀=Γ≅9=∃/Σ
∀/Τ2≅9#%Φ%.9:#ϑ56/7 %4%
ΕΥ4%1)Χ)ϑ4ς,;ΓΧ9#Ω)+2,−Ξ
Κ − )+2 ,− % Κ %> . ) # 2
∃ %2: ∗ )∗4 56/ 7 / 9 ,<
Κ>−)+2,−Γ.%>∗,2,2#∃%2:
56/7
ΑΧ9#Ω)+2,−%ΨΘΖ2∗)∗419Γ
72Λ#∗)∗=4(%Λ7/Χ1Θ%>
[
Λ)+2,−,2:+27Χ9#Ω)+2,−%#%>(%Λ
7/Χ
−Θ22Λ%>ΧΤ2−%2:
Ξ#∃− %2:∗)∗ Θ%2: ∃∗ )∗,∋4Θ
%2:∗)∗,∋4Θ%2:∗)∗)3#Θ%2:∗)∗
+#;Θ#ϑ56/7%8%>5−%Γ.Σ≅%2:
)+2,−∃∗)∗,∋
∃∃93: ;<=> ∗+?9&/0123.− 4(+05−#
−=Χ=≅%∗)#7)∗56/7 Μ%4%
4%9:24%(/#&4−#%1#1%=04ϑ
=∴(%%−
ΑΧ9#Ω)+2,−%4−,<=Χ=≅%∗%Φ%.9
9Φ]4)∗4&,⊥7Ω
∃≅ΑΒ∀+!∀/Χ−0∀=− ∆)Ε+,&−.+/0123.− 4(+05−#
0123.− 4(+05−&( 2Φ−6?Ε+−0Γ−/Γ+93:#
Θ∗ ≅+ )+2 ,− ∋ %2: / 7∀ =9 ,∋ 2 ≅/ 2: # =
−2%2:)+2,−∗Τ2
−−,−/∗<%1)Χ%
Θ+&<ϑ9−>=∴−56/7
−=2:9ΓΓ)+&,⊥7Ω2
!∀#∀∃∀%∃&
46ϑ4Ε>−=Χ%8Γ=≅%∗)#56/
7
0123.− 4(+05−&( 2Φ−0Γ−/Γ+93:#
_ΩΘ(%2:∗)∗,∋=,<=Χ#1%Λ4
Μ%Λ4ϑ=∴(%%−4∃7∃%4=9,∋2#Χ=
=Ξ#)∗−−9Γϑ>
−%,6<(−=∃%%−Τ27Χ#1,6
−%%Φϑ=∴(−=∃%49∃Λ9#%−−,
#1)+&&9Π(∃%<#∃19Γ
α
−−,)+&+4ϑβ=Μ(−=∃%%−
−−,−Χ>%=>+∋%∗−
<%2,6#)∗−−<%Υ
!∀∃∀%∃&
Θ2)∗>ϑΧ94=/9?%.9+%#6Λ%
ϑΧ95/χ%>∗5Τ);Β−<)2]9
5− %,∗ %ΕΕ ≅− 1 7/ ( − =∃ %# %Ξ (
Μ
6ϑΓ09,<9?∃%Φ
0123.− 4(+05−&( 2Φ−0Γ−/Γ/Χ−0∀=−#
_Ω%ϑΘ%2:∗)∗)3=%Λ/%(#∗#1
,<=ΧΜ%4−Ο=∴(%%−4∃7∃%%.ϑ2−
∗)∗19Γ
∀∋
6∗−=∃%%−
Φ%.9(%(/#&
−Χ>=>(%%<#∃#Χ56/7
6ϑΛΓ0(−9?∃%.%−−)+&&
9Π#<β
!∀∃∀%∃%(∀)∀
Θ2)∗>ϑΧ94=/9?%.9+%#6Λ%
ϑΧ95/χ%.,<=Χ2∗)∗9Γ0
δ∆∃7∃%%.5−%∗%∗%Ε(9∃χ4
%2−=∃Τ21,6
≅ ,&−.+−0Η&0Ιϑ&2Κ0Ι−6?&#
≅ 0Η&0ΙϑΛ∀ΜΒ−Β∀+0∀ΝΟ#
ϑΧ95/Ρ=ϑΧ95/%%>Χ
2<)24%>7∀=9,∋%.6−=∃%%−45−%%Φ
(%=2:−4:−(%=2:,β45−%#ϑ=∃%%Φ9Η04ϑ
2−)+&+(04Η∗)∗9Γ4ς
ε
ϑΧ9/7∀%.5−%1,67φ)+2,−4%−−)+&
Γ=Σ(%=2:−82Π∃4
≅∃ 0Η&0ΙϑΛ∀ΜΒ−Π0#
ϑΧ95/χΓ.%>Χ%.=9γϑ%Ι(
%Λ4%Φϑ∗7:#,Ξ+(%147ϑ,Ξ+(0
%4ς
ϑΧ9/%>Χ2=∃%7ϑ#%Κ)Ξ
,Σ_Ω%ϑ(ϑΧ9/=%.9%.∗)∗#
−ΛΛ9Γ%,6)=∃
≅≅ 0Η&0Ιϑ+Θ−+.0#
ϑΧ9∆−%>Χ2−=∃%Γ:−φ7η2
919%∗+/2<)2%.5−%,Ξ)−∆)2−∃(%4
]99−Ω#Ω2#Χ∗)∗#−
Λ9Γ%,6)=∃
≅Ρ 0Η&0ΙϑΣ>?Ε+−62&0∆/02(#
ϑΧ9β∃2<)27∀%.5−%ϑ9∃4)+
&Ω∃(%−<Ξη
+(−ϑΧ9=−=/φ%2:<)2]
−Μ/7Ω4,%Γβ∃#2−%2:%%−%>−=/#∃−∗
%−=%∃
Ρ ,&−.+−0Η&0Ιϑ−62&>0Τ&−0Η&0Ιϑ#
−ϑΧ9%>∗2ΠϑΧ9ΚΙ9
ι ϑΧ95−%70(%]−72#Π
ι ϑΧ95−%%Ρ9(%
ι ϑΧ95−%∃:82(%]−,,7Τ
ι ϑΧ95−%∃:7η2(%]−=&
ι ϑΧ95−%Λ:(%]−6/)∗>#∃
−ϕ0)∗
ι ϑΧ95−%,Ξ<∆(%]ϑΧ9∆∗
ι ϑΧ95−%ϑβ=Μ(%]ϑΧ9β9Ω)∋
ι ϑΧ95−%%ΦΡ(%
!
!∀#∃%&!%∋&(∃)∗!+∃∀#∃,−.
∀ #∃%&∋()∗+,
∀ −.+/−01234−5(∗∗.−0123
∀ ∗4),/+)+6)&7∗
∀ 8+)+6)&79)∗4∗:∗4
∀ &;%/<%7)7)+8=6+6)&7
∀ >8,∗474−5?%≅
#/0123∗(4∃5&∃6)∗!+∃%278.
Α+8+80123Β86−.<∃%&∋
()∗(∗∗.−0123
=6∗Χ∗,6∗Χ∗+,5.8∗?%&∋()
∗(∗∗.−&∆0123Ε5.−+6)%/+6)
&7∗ΦΓ%1∗:0123Α
∀ #8∗∗.−0123Η∗ΧΙ<09−−6∗2%Χϑ2Β−
ϑ#8%ΧϑΚΛ∗28#8%Β−ϑ+6ΜΛ∗
;4
∀ #8∗∗.−0123Η);Β−.,4&Φ
−6∗(+,&∆01235.%∗%)Χ)Λ∗%
7:7#,2ΝΝ%∗28
#,2,/−.<∃%&∋()∗(∗∗.−&∆012
3%Β8),/%∗4+6)&7)
9 −:/;2%/#/<:=>?≅8#Α:Β#∃5/)∗!)/;:=>?≅8#.
Ο/−.+/−8+8,4−5Φ7012
30=∗:0123Α%Β8
#85∗?%/+6)&7∗,%/8+84−5ΦΓ
ΕΒ∗5∗:0123Α∗.−+6);
8∗?&∗(∗∗.−&∆0123&∆Π)
,/%∗4+6)&7∗?+)Θ<∗Β2∗Φ,+8
Ρ
Χ ∆ΕΦ)ΑΓ#&7/<%&!%∋&(∃)∗!+∃∀#∃,−.
ΧΗΙ∃,)/;:%∋&(∃.
Σ2,)=−<Β−=ΘΦ,∗/+/∗
+,−%Θ+)67?%≅Γ7;+)
7∗.−+6)&7∗?;ϑ9),−5,)(−,0123
5.−+6)7;ϑ7∗.−+6)&73Α
−ΤΛΙ;ϑ7∗.−+6)&7
Υ;+)Μ−3ςΩ%2−Ξ∗∗.09−<−Ξ+23(<Φ
28∗.07∗()∗Β
Υ;+)+Ψ−Ζ∗ϑ%2−Ξ23(∗.%−ϑ/−07
∗7Ω%≅Φ∗
Υ;025.3Σ02[∴])Λ02⊥∴]∗.
07∗ &∃+7 ∗Β−Ε02[=< −&7_<, Ω&;
Φ∗
ϑ&ΦΚ3Κ∃/022ΛΜΧΝΟΟΠΘ6!&Ρ#Ν∀#∋&∃
∗!2Ε∃Σ,4;ϑ −(%ΑΜ−3ςΗ∗)(+6)&7)8+8+Ψ
;,Α∗4+/∗∃(<=Θ,(26−,Α
∗%Π<%Π%/+)67+)Καβ∀χβ−
;,Α∗4+/∗<+7=Θ<+7(2
6−,Α%Π+∗4+)67+)Κχβ∀!β−
δ
;,Α∗4+/∗∗6<%)(Κ+)6
7+)Κ!β∀δ!−
ΧΤ)∗/Α2(>2%∋&(∃.
4&1+6) &7∴ 4 &1; +)<;02<ε]6%Α ,Σ
φ ( Υ
3Α −5 α− ΟΣ φ ( +8 Π + 5
βα
)∗5
∃&φ3)6Θ12
∃&φ3)Θ%?61Φ7%Α∗12
! Ι/7/:Β#∀#∴−5∗<−5Μ<−5γ]
4&1;+),4&1;02∗?07∗&
α
−4&1+)+6)&7∗;,Α−5
)∗5
+
4&1;+)
0
4&1;02
−
4&1−5
Υ
4&1,Σφ(
;,Α−5γ<−5Μ),Σφ(Υ5.∗?
07∗&
o #84∗3Α−5%∗&φΥ
ηι−ϕβκ!
o #84∗3Α−5%∗7Υ
ηδ−ϕβκ!
λ
)∗5
%4Φ−5γ)Λ4Φ)3/ϑ−5Μ
)
Ι/7/:Β#(>2Θ:Β#ΥςΦΩΥ)Β#ΩΥ%&!Ξ/Σ
4&1;+),4&1;02∗?07∗&
α
)∗5
+
4&1;+)
0
4&1;02
−
4&1−5
43ΘΝ−)∗
Υ
4&1,Σφ(
−94&1+)+6)&7∗;,Α−5Θ
#8+6)&7Ι02⊥4&1+6)&7Ω∗?+8Π
+
o ΨΖΟ,+6)&78δ!−Γ∗;,ΑκβΒ)Λ
o ΨΟΟ,+6)&78δ!−Γ∗;,Α)κβΒ
)−ΘΚ?6−∗?Β∗;∗.∗ΒΘ<&+−∗?
Β∗;Χς6+6)&79−δ!−∋Χ−Α∗?+8Π5,2
ι
−Α5.ϑ∗?&∃6ΦΘ<ϑ∗?∗%ΠΦΘ,∗6−6))
µ∗
Ζ [Γ#ΦΦ%&!%∋&(∃)∗!+∃∀#∃,−.
Ζ[Γ#ΦΦ%&!∃!?.
>)2% −3ΖΖ%−,/Ι 2∗63Σ ∗.+),)
Β∗−4−Α∗&1%Α%!−νΡ−
−Χ.οΖΖ+)2
Ζ[Γ#ΦΦ%&!,4!∴#:?.
>)∋Ι−725.73Ζ)−Θ%)(∗∗7,ΗΓ∗&1
+7<3)∗5∗?73Ζ:)7+)+6)&7∗
−ΖΤ72+)0)2πθ∀κ
Π /]∃∗%&!76#2?0∃⊥&5∃)_#.
Π/]∃∗%&!.
κβ
∀ Τ72+)0)2
∀ 7+)
∀ Β+)
∀ ΤΕ+)
∀ 8%2−Ξ
∀ οΖΖ7)%Ν<1(Β+)<−Ε+)
Π?%&!Ταβ.
o ∋χ#%&!.
4&1+)κββ−
Κ+ϑ%ρ+)%Α∗Βκκβ−−
Κ+ϑ%ρ+)&Σδ!−−
Κ+ϑ;+)σα−−
>ϑΑ0τ0Υ] κΡσβ0κβχβ0κσσβ−−
Θ%? !ββ+
o Φδ2!?.
;∗Ζ=2∴χ;∗] κσα<αλ!<!δβ,ςυΠ
43Ζ=2 σ!β−−
+)0;;∗ κ!>#
>6Μ1%;∗ α!>#
;∗1%+56Θ χ−υΠ
o ∋χ#∃ε/30
>6Μ1%;∗∴−;∗<7∗] κβ>#
o ?Γ:
>. Ζ∗Ι−
∗/ δδ%ϑυΠ
ο9&9% ι!%ϑυΠ
ϖ&;∗ κ<αΤ
ϖ&%−,/ β<δΤ
o ∀#(2+∃
&Φ∗39&9% λ<λ>τ
;∗=2 κλββ,ςυΠ
&Φ∗∗/ δ<!>τ
κκ
;∗=2 κσσβ,ςυΠ
ΠΦ%&!.
()Χ−χ1Ιφ)+)6δ−∀λ−<3Σ∗.ΓςΘ<
3127,Κ3Σ∗.1(3ΖΖ
−Π7+)
Π9Ρ%&!.
Β+)%Γ;φρ<∗Β59∗.;,),;,)
−Ε+)+7)%ΝΒ+)54%)(,Α43+7
−φΒ+)
κα
ΠΧγ/%&!.
5 4 %)( −Ε +) ∗? &∋ 3Ζ ,) 7 %)( ∗ +) +7
Ε+)
ΠΖ/]∃∗3+?:η2.
! ιΚ#Κ3+?:η2ϕ!)∀/.
Κ3Σ∗.%27−Ξ+23(Κ<3ΖΖ
25+ϑΑ 3σ!δ−−∴κλ],Ρκβ−−∴ασ],Α∗Κ+ϑ)2
∗µχλκ−−∴κ!]∗8λι−−∴χ!]
κχ
43σ!δ−−,Ρκβ−− Κ+ϑ)χλκ−−νλι−−
−ΜοΖΖ%2−ΞΓ∗
ιΚ#Κ3+?:η2∃6:κ#Θ∃/λ!33(!:Φ3ϑ,Σ.
Κ∗?3Σ∗.%2−Ξ23(>ϑΑ3ΖΖΚ
3Σ ∗Κ+ϑ)δΡ−−∴χβδκ],∗Κ+ϑ)%δχ−−∴αλδ!]
543ιββ−−
)( 3ΖΖ25 ∗Κ +ϑ ) 2 ∗µ !κ−−∗8δΡ−− ,
4 3 2 ∗µ δββ−− ∗8 ιββ−− ∴ 3Α ∗12] π9− 8
ωωΥξαβδ,ωΤοκ!λδ
−ΟοΖΖ%2−Ξ−ψ
ιΚ#Κ3+?:η2Φ/∃∃∀#ΘΦ/(∃&(!:Φ3ϑ,Σ.
ΟΑ∗ &φ,ΖΧϑ 285.3Σ3ΖΖ %2−Ξ<
Χ−5−;−ψ)5
κσ
−οΖΖ%2−Ξ
οΖΖ%2−Ξ∗?Ν,)∗Β3ΑΦ−Β+)ρ<−Β
+))∗=&;Βρ∗.∗4Ν∗ΒΙ,/(
3ΖΖ%2−Ξ0;∗72%ρ+),Α∗?;Η,ϑ3Α
5∗/−∗.ΜΑ,−6,Ζ+ψ,);>
∗?(φ,)∗(∗72;<87);,;∗?∗5,)∗)∗Φ
83Φ12Κ∗?;%((∗Ω;,)
∗?+φ)%−Λ∗<−Ε;−Ξ,∗?7)<%2∗∗Θ+ϑ
ΠΠιΚ#Κ∃&3⊥ΦΩ>#5Ρ%&!Ω:γ/%&!.
∀ >4−∗7∴]
∀ >ζ=2Β∴]
∀ >4−0ϑ∴]
∀ 7∴3]
∀ >4−6%4∴9]
∀ Τψ%8Μ∴]
κ!
−οΖΖ7)%Ν
Π#2?0∃⊥&5∃)_#.
κΡ
φ [Γ#ΦΦ3+?:η276∋&δ2∋:η2.
φ[Γ#ΦΦ3+?:η2.
! η2#2?0≅5#Θµ≅/(∃2,ϑ≅(!:Φ3ϑΣ
−Ξ5+8<∗⊥−,(7;∗∗7Η(7
.8%2−Ξ23( &∋3Ζ8%2−Ξ
−ψ
++)∗8∗&1Β%2−Ξ89)7Α
&
−&(∗72;+)Ι7%Α
2−Ε+)Ι8%2−Ξ−ψ
Υ(;%2−Ξ0;∗8∗72;+),8%2−Ξ
#1%,7);%2−Ξ+ψΒ+)
6)3{−Ξ
η2%∀##2?0≅5#Θι/(∃2,ϑ≅(!:Φ3ϑΣ.
−Ξ5+8,∗⊥−Φ∗+ςΓ∗?(7
∗Β.8%2−Ξ+23(5.&∋3Ζ8
%2−ΞΓ∗)Λ%2−ΞΙ7Ζ−Ξε
φΗ∋&δ2∋:η2)+∃.
κδ
ΤΞ∗23(&+∗?%2%+ψ−/;+)Β&∋%≅
9)&
οΣ =9 ( ψ − Β ∗ Η ∗Β ; %2 −Ξ − ∗)(
+)6κβ−−
µ _ 5 62 % Β ∗ Θ ψ Η ∗Β ; ∗. Γ
2∗⊥−Φ−Ξ∗
Τ−Ξ∗,))7−777Ν8−Λ
Κ
ΤΞ∗23(Β∗,4ςϑ/−&Α−;∗.
87ϑ/−07∗7Ω%≅Φ∗
−976)=6−Ξ
ν ∀#∃#/ςΦΙ%&!.
.Ν−∗?ΝΝ∗);+)<,∗49)3|φ
%=Θ,/φΖ.&
;/−Ξ∗
9 &1%2−Ξ
Χ Τ6−Ξ∗ >−6ΒΠ≅Γ∗4&
∀ οΑ:62(⊥.Β−&ΝΦ285ϑ∗(.%Α<8
9)%7−ΖΦ∗Κ3Σ∴%)<,1<∗.−<Α]
∗ψ%),<07−,10<∗ψΑ,ε
κλ
∀ οΑ7Ε∃=ϑ3η../|7ΒΖ+7,ΑΒΦ
28 Γ<−Ζ7<µ7<µ&φ<3Μ−&(<7+)7,3}
)5ε
∀ οΑ∃,5#∃/. /∃<∋∃< 3∼)∃< 3∼) −4−<3∼)
62,62∴∗3ϑ],+<ϑ⊥−<⊥−<:)ς∴∗Κ]
Ζ Ω&;Φ−Ξ∗
Μ π#%]∃δ2/∃,−:_∃/<Φ%&!.
−/+))Χ−χΑϑ&
Η.8+)∗8,ϑΒ%2−Ξ23(
Η.2−Ε+)Ι8%2−Ξ−ψ,8%2−Ξ
Η9.8∗5&+%2−Ξ23(
−Χ−/+)
!∀
! ∀#∃%&∃!∋(∋)(%∗∗!)∋!+∗,!−.
#∃%&∋()∗+,−./.012&∋344.∋
51.456718910/):;<./
= ∋1>∃∋;5
= ?.,≅%9%(Α∃Β≅%∃8.5Χ
= ∆%..Ε1)∗Φ(Γ.Η≅.)9≅1.−;5≅)#
∃%&∋Ι384%.Ε)#ϑ1)∗10
/!01!.
∋ /!012+∋!3+45.
0/ ;Κ# 1%∋3%∃44 1Λ(∗∃4.5
.Ε%∋,3Μ.Χ∃8≅∗∃4Ν.≅.5.−.)?,−
Χ∃8∗∃4Ο4∃4ΟΠΠ11.−!Θ611,∃48Ε
4891(,0.Χ∃84ΡΣ11≅Τ(Ε,ΠΥ∃ς1
0 67 .
, &∋ ( ∗ Ω ; Ξ!711≅ .Χ ∃8 4
Π! !Π
≅
.Χ∃84
6Ξ !Π
Ψ16, ,12≅,?≅,.,∗
8,&∋
,;ΑΚϑ.,&∋;Κ./Ζ∃&∋3.
[2 &∋ 0 Μ ; ∋ .Ν ∴ ΣΠ11= ΥΠ11≅ .Χ ∃8 4
6Π 7!Π
≅Μ;∋(]Ζ
ΣΠ 7ΣΠ
≅03%(]Ζ
7
!Θ Σ6
Σ7
,?ϑ.,&∋;ΡΠ711=ΥΠ711;Κ./#1>
.∃&∋34.,?Ψ1Σ,Ω(50/%41⊥;Λ;≅
.,ϑ,?0_./(ΖΩ3Α,123,∗
;Κ./∗3Α,∃4≅0Μ;!ΥΠ114,
∋0∗831Μ3(4%.Χ∃86ςΞ./α?∃
4.,&∋≅5−1>4β%?512&∋3./4%
Α4β%&∋
∀ 9:∋;<.
+.0;Κ./54χ(Ε.012&∋34.4Ψ1 βΟ
+≅Ζ+3,;>+
δ<ε&4∋≅Η
Θ6Π !
≅0(α8?1./+0
/Ε;4_4,;>
;Κ./?5+1%.≅φ1++;4
∴.4,−
./.Αϑ+
=/>!.
891.Ε−4∗∃4∋)∃−(∋
1>−)
8=
891&∋γ
Σ!
=
Ζ.Η−891≅5.,&∋.−.)?891%;
,∃46.451.45!Π1
=
0+≅+Ο;45.4ΥΘ11−1)∗+.0.Ε)∃
&∋1.45!Π1∗+ϑ.45).ΕΤ()#∃%
&∋γη%ιϕκ
=
λ∴&∋≅(∋12&∋(∃µ1Η.≅%412&∋3β)%
1Ο.412&∋
891)ν.Ε;(5∃!4%.Μ).?∋&Ο∋
Ν)∗+.041.45(ΑΠ7+
ο.0.Ε!77+
π1>∃;∋/)∃.ο.0!7+(<
π1>.ο&∋ΡΠ13∃351%.Μ
?4≅2/!ΑΒ.
θ−βΟ891∴9Χ.ΕΦ(Γ_4∴∗∃45
1.)?8918)#∃%&∋≅%ι(Ν)∗+ϑ
.45&∋)Κ
%?∗0/Ο⊥.−∃−βΟ891
o
∃4.Ε(1)544≅%1Κ∃40/α4
∗1>3Ω∃.01>(1χ)∗+
o
θ−ϑ.%ϑ∋;4%(.%∃/ϑΑ4
∗∃44Η):;<1;;β%15
o
+∃;44Η∃):;<,;>+
o
:;<.,12&∋∃.+γ≅,∃4Ηβ
.4Η,∃4β%;
o
θ&∋34%(Α%1∋%<ο4εΑ≅%(Α(
⊥(?∗&∋Ο1?∋)χ#Χϑ#)α
9
_4_∃3_ρ.Μ9Φ%ι_4/#
o
ισιϕι−ιϕτ!Π+ς671
o
ισ!Πυ7Πϖηιϕ=!Πκι−ιϕω!Π+ς671
Χ∆(Ε∀Φ∀2/!ΑΒ!∃%.
∋ ΓΦ∀;1Η!,Ι∀?! ∀ϑ4≅∀Κ∋;Λ!.
ΣΣ
6ΙΜΝ;Λ!)Ο.
ξ%ι
θ∗(Ε/
8ης1
6
κ
ξ01)%ψ
Η
.∗λζ
5%
7=!7 !Σ=!Θ ΣΠ=67 Π=67 ∆∗
!7=67 !Ρ=!Ξ 67=6Σ 67=Θ7 Η3∴
67=Π7 !Θ=Σ7 6Σ=Ρ7 Θ7=Ξ7 Η
ωΠ7 !Ξ=Σ6 Ρ7=ΡΠ ωΞ7 {Η
_4 θ _ρ≅ _∃≅ [_∋_4|≅ λ_1 3 1 )∗ % Ο ∃%
βα0 1)% 43)#∃%&∋γ0 /.Ε&%.
_4#)
!Σ
Α
!Π ΣΠ
}9−∃−10ϑ∆2.Ο&%.01)%4
ϑ%χ#34%ι
ξ%ι !7 !Θ ΣΣ 67 Ρ7 Θ7
ξ01)%4
ψ
67 6Σ 6Ρ 6Θ 6Ξ Ρ7
6ΙΜΝ;Λ!(.
ξ%ι )9 βη∃ξς1
Σ
κ
τΣ Ο∋ τ7ΣΠ
Σ=Ρ λ∼4Ο∋ 7ΣΠ=7Π
Ρ=Ξ λ∼4 7Π=!7
Ξ=!7 # !7=Σ7
!Π=67 {Ζ# Σ7=Ρ7
ω67 {Ζ ωΡ7
4.0 β=)#Ω.
0 ΓΦ∀;1Π;!Θ0/(3Ρ.
}9 − ∃− 10 ∆ . # &% . )
6Π7 Π77 (
∀ ,Σ∀∀1!Β∀+ΤΥΤ.
6ΙΜΝ<Π.
_η!∀ΘΣκ.ο.#&%.)#Οϑ._4)∗(9
