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1
LU
-
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2
PH LC
LU
1
I. CHI T S TRUYN 4
1. Chn. 4
2. i t s truyn 5
3. Lp bng h thng s liu : 6
II. T K B TRUY 8
1. Chn lo t di 8
2. ca b truyn : 8
3. nh s 9
4. nh lu lc: 10
III. T K HAI B TRUY 11
1. Chn vt liu 11
2. nh ng xu 12
3. p nhanh: B truy 14
4. p chm: B truy 20
III. T K TRC 26
1. Chn vt liu ch to trc 26
2. c. 26
3. nh kho t lc. 27
4. ti trc I : 29
5. ti trc II : 32
6. ti tr trc III : 35
7. Kim nghim trc v bn m 38
IV. 46
1. m nghi bn ca then 46
2. 46
V. H 52
1. t cu ca v hp : 52
2. p gim tc : 53
3. Lu chnh s p : 53
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4. c cn t cu tp gim tc : 53
5. C nh trc trc : 56
6. Mt s kt c : 56
7. Dung sai l 59
U THAM KHO 61
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4
I. CHN I T S TRUYN
1. Chn.
a. (P
t
):
b.
td
):
ti trc sau:
P
1
=0,8T
P
2
= T
t
1
=0,6t
ck
t
2
=0,2t
ck
t
= 5,6 kW
c. Hiu sut truy
Tra b
- Hiu sut khp ni :
- Hiu sut 1 cp :
- Hiu sut 1 c
- Hiu sut b truy
u sut truyng chung
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5
d. t cn thin (P
ct
) :
e. Chn :
T s truy (u
t
):
u
t
= u
h
.u
Chn u
=3: t s truy
u
h
=8: t s truyn ca hp gim tc.
u
t
= 8.3 =24
S a tr
lv
):
S (n
sb
)
n
sb
= n
lv
.u
t
= 48,48.24 =1163,52 (v/ph)
Ch
> P
ct
Vi n
sb
= 1163,52(v/ph) chn t quay
Tra bng P1.2 ph lu [1],
vi : P
ct
= 5,46 kW n
n DK52-4
: P
= 7 kW > P
ct
= 5,46 kW
n
= 144
2. i t s truyn
T quay ca tr (n) : n =48,48 (v/ph)
T s truyn chung :
:
n
n tc quay c
n
t quay ca tr
M vi :
u
s truyn c
u
n
s truyn cp nhanh
u
c
s truyn c p chm
T :
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6
u = u
n
.u
c
.u
x
= u
h
.u
Ta chn u
= 3 cho :
Kim tra t s truyn chung:
: u = u
n
.u
c
.u
m bp gim tc bu ta chn :
u
n
= 1,2.u
c
Vi : u
h
= u
n
.u
c
M : u = u
n
.u
c
.u
= 3,45.2,87.3 = 29,705 (**)
Kim tra sai lch ca t s truyu :
(**) = 29,7 29,705 = 0,05
V p nh s truyn :
u
n
= 3,45
u
n
= 2,87
3. Lp bng h thng s liu :
D
t
h dc :
a. Ct c :
:
+ Trc IV :
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7
P
4
=P
t
= 5,6 kW
+ Trc III :
+ Trc II :
+ Trc I :
b. S c:
: n
= 144
u
= 3
Trc I :
Trc II :
Trc III :
Trc IV :
n
IV
= n
lv
c. c:
ng
Trc I :
Trc II :
Trc III :
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8
Trc IV :
Kt qu ng sau :
Trc
I
II
III
IV
t P
(kW)
6,38
6
5,83
5,66
5,6
T s truyn u
u
nt
= 1
u
n
= 3,45
u
c
= 2,87
u
= 3
S
1440
480
139,1
48,47
48,48
Momen xon T
(N.mm)
42311,8
119375
400262,4
1115184,7
1103135,3
II. T K B TRUY
1. Chn lot di:
Ta chn tit ding. u A do t u ki c:
+ n =1440 (v/ph)
+ P
ct
= 6,55 kW
+ u
= 3
+ Ch .
2. ca b truyn :
- c tit din:
b
t
= 11 mm
b = 13 mm
h = 8 mm
y
0
= 2,8 mm
- Dit din(A)
A = 81 mm
2
a. (d
1
):
d
1
Ta chn d
1
= 110mm
- Chii hn(l):
l
- Vn t
Thu kin v
1
= 10,55 m/s < v
max
= 25 m/s
n (d
2
)
c 4.2, vi h s t = 0,02
d
2
= d
1
.u.(1- ) = 140.3.(1- 0,02) = 411,6 mm
Theo bng 4.26 chn d
2
= 400mm
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y t s truyn thc t:
u nm trong pha t s truyn.
b. Khoc (a):
= 3, d
bng 4.14 u [1]
Tr s a phi thu kin sau:
0,55(d
1
+d
2
1
+d
2
)
Vi a = 400mm thu ki
c. Chi
c 4.4 trang 54 u [1]
Tra bng 4.13 trang 59 u [1]
, chn chin l = 1700 mm.
- Kim nghim v tui th:
Tui th u kin
-
Vi
a =405,25 mm
d.
1
:
c 4.7 trang 5 u [1]
Vi
1
= 143,43
0
thu kin
3. nh s :
a. S
Tc 4.16
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10
P
1
= P
= 6,38 kW: ng
K
: h s ti trng u, ti trp nhvic 2 ca)
K
= 1,1 + 0,1 =1,2
[P
0
]
C
= 0,89 : h s k n ng c
C
l
= 1: h s ng ca t s truyn ( l=1700mm,l
0
=1700mm => l/l
0
=1)
C
z
= 0,95 : h s ng ca s u ti tr
C
u
=1,14: h s k n ng ca t s truyn
Ta chn z = 3
b. Chiu r
:
B= (z-1).t + 2e
B = ( 3-1).15 +2.10 = 50 mm
c. (d
a
) :
d
a
= d+ 2h
0
Vi h
0
= 3,3
- n: d
a1
=140+2.3,3 =146,6 mm
- dn: d
a2
= 400+2.3,3= 406,6 mm
4. nh lu lc:
a. L
0
P
1
=P
=6,38 kW
F
v
: lF
v
= q
m
.v
2
=0,105.10,55
2
=11,69 (N)
Vi q
m
=0,105kg/m : kh
v= 10,55 m/s : vn t :
b. Lc F
r
:
c
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11
u
Tit di
b
t
b
h
y
0
11
13
8
2,8
Dit din (mm
2
)
A
81
(mm)
d
1
140
Vn t
V
1
10,55
ng n (mm)
d
2
411,6
Chn 400
T s truyn thc t
u
t
2,92
Sai lch t s truyn (%)
u
2,7
Kho (mm)
a
400
Chi
l
1647,96
Chn 1700
S y c
i
6,21
Kho
a
405,25
1
143,43
0
s
K
C
C
l
C
u
C
z
1,2
0,89
1
1,14
0,95
[P
0
]
2,2
S
z
3
Chiu r
B
50
d
a1
d
a2
146,6
406,6
Lu (N)
F
0
223,69
L c (N)
F
r
1274
III. T K HAI B TRUY
1. Chn vt liu
c bim thng nht k,
chn vt liu 2 c
C th,
theo bu [1],
ta chon:
+ nh : i thi ri hn b
b1
= 850 MPa,
gii hn bn ch
ch1
= 580 MPa
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+ n i thi r i hn b
b2
= 750 MPa,
gii hn bn ch
ch2
= 450 MPa
2. nh ng xut cho :
Theo bu [1],
i vi thit rn
Ch r HB
1
= 254 rn HB
2
:
u [1],
t c t i ng sut
khi th v ti
:
truy i tr chu k i, ng su
c 6.7:
:
c l
c = 1
n
1
s
n
1
= 480
u
1
s truyn
u
1
= u
n
= 3,45
ng thc
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13
Vi K
HL
s tui th n ng c a thi gian phc v ti trng ca
b truyn
c ng sut tip
Vi cp nhanh p chm ta u s d tr
th u [1] :
i ng sut
m
F
=6: bc cng cong mi khi th v tin (bng 6.4)
i ng su khi kh v un
c u [1],
vi b truyn quay 1 chiu K
FC
=1,75 ta
c:
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14
ng su
:
3. p nhanh: B truy
a. khoc:
:
K
a
s ph thut liu ca c
K
a
= 43
(tra bu [1])
u
1
s truyn
u
1
= u
n
= 3,45
T
1
momen xo ng
T
1
= 119375 Nmm
s
= 0,35
(tra b u [1])
h s k n s u ti tr u r
ti
(tra bu [1])
ng sut ti
[
= 503,65 MPa
:
Chn a
w1
= 142 mm
b. p.
:
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15
Theo bu [1],
ta ch
1
= 2
nh s
Ch = 10
0
u [1],
n z
1
= 31
S n :
n z
2
= 106
s truyn thc s :
:
Suy ra :
c. Kim nghi bn ti :
u [1],
thng sut tit
:
:
s k u cp
(tra b u [1])
h s k ng b mt ti
Vi :
Suy ra :
u [1],
s k ng b mt ti:
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16
s p dc
vi
D
u [1]
s k n s
p c
M
u [1],
= 1,66
d
w1
:
u [1], ta n t
Vi theo bng
b u [1], vi c ta chn
(K
s k n s u ti trng th
khp)
u [1],
Vi:
s k n ng c p
(tra bu [1])
s k n ng ca sai l
(tra bu [1])
u [1]
s k n ti
trng xut hip K
Hv
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17
Vi:
h s k n s u ti trchiu rh
1,03
u [1],
s ti trng khi
tiK
H
vc:
ng sut ti :
Vi: v = 1,61 m/s < 2,5 m/s,
Vi cng hn c mc ti n gia
a
Z
R
= 0,95
d
a
< 700 mm, khi K
xH
= 1
theo u [1]
y
, , gim chiu r
Chn b
w
= 46 mm
d. Ki m nghi bn un:
m b bn ung sut un sinh ra t
tr
:
K
= 1,12
(Tra b u [1])
Vi v < 2,
F
=1,37
(bu [1])
u [1],
:
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Vi :
h s k n ng c p
(tra bu [1])
s k n ng ca sai l
(tra bu [1])
u [1]
s k n ti
trng xut hip K
Fv
Vi:
s k n s u ti tru r
1,08
Theo c 6.45 trang 109 u [1],
s ti trng khi
unK
F
(Y
s k n s p cY
s k
S :
Theo b :
Vi m =2
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19
Vi d
a
xF
= 1
K
xF
s bn un.
liu [1],
ng
sut u
F
]
c :
v thc :
<
=269,61 MPa
e. Kim nghi i :
ng sut tip ci
:
Vi h s i
:
Suy ra :
ng sut un c
y b truyu v i.
f. c b truyn :
Khoc : a
w1
= 142 mm
: m
1
= 2
Chiu r : b
w1
= 46 mm
T s truyn : u
m1
= 3,42
:
1
= 15,247
0
S : z
1
= 31 z
2
= 106
H s dch chnh : x
1
= 0 x
2
= 0
c trong bu [1]
c:
chia:
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20
4. p chm: B truy
a. khoc:
:
K
a
s ph thut liu ca c
K
a
= 43
(tra bu [1])
u
1
s truyn
u
2
= u
c
= 2,87
T
2
momen xo ng
T
2
= 400262,4 Nmm
s
= 0,45
(tra b u [1])
s k n s u ti tru r
ti
(tra b u [1])
ng sut ti
[
= 503,65 MPa
:
Chn a
w2
= 197 mm
b. p.
:
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21
:
Theo bu [1],
ta ch
2
= 3
nh s
Ch = 10
0
u [1],
nh
n z
1
= 33
S n :
n z
2
= 94
s truyn thc s :
:
Suy ra :
Khoc gia 2 trc:
c. Kim nghi bn tip :
u [1],
ng sut tit
:
:
s k u cp
(tra bu [1])
s k ng b mt ti
Vi :
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22
Suy ra :
u [1],
s k
ng b m t ti
s p
dc
Vi b
w
=
s k
p c
M
u [1],
= 1,753
d
w2
:
n t
Vi theo b .
Theo bu [1], vi c ta chn
(K
s k n s u ti tr ng th
khp)
u [1],
Vi:
s k n ng c p
(tra bu [1])
s k n ng ca sai l
(tra bu [1])
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23
u [1]
s k n
ti trng xut hip K
Hv
Vi:
h s k n s u ti tru r
1,03
c 6.39 trang 106 u [1],
s ti trng khi
tiK
H
vc:
ng sut ti :
Vi: v = 0,74 m/s < 2,5 m/s,
Vi cng hn c mc ti n gia
a
Z
R
= 0,95
d
a
< 700 mm, khi K
xH
= 1
u [1]
y
, , gim chiu r
Chon b
w
= 66 mm
d. Ki m nghi bn un:
m b bn ung sut un sinh ra t
tr
u [1],
:
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24
:
K
= 1,32
(Tra bu [1])
Vi v < 2,
=1,37
(Tra b u [1])
u [1],
:
Vi :
s k n ng c p
(tra bu [1])
s k n ng ca sai l
(tra bu [1])
u [1]
s k n ti
trng xut hip K
Fv
Vi:
s k n s u ti trng tru r
1,32
u [1],
s ti trng khi
unK
F
(Y
s k n s p cY
s k
S :
Theo b u [1]
:
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25
Vi m =2,5
Vi d
a
xF
= 1
K
xF
s bn un.
u [1],
c
ng sut u
F
]
c :
vc :
<
=262,295 MPa
e. Kim nghi i :
ng sut tip ci
Vi h s i
:
Suy ra :
ng sut un c
y b truyu v i.
f. c b truyn :
Khoc : a
w2
= 197 mm
: m
2
= 3
Chiu rng : b
w2
= 66 mm