Trắc nghiệm Sinh Lý Bênh Miễn Dịch

012456768449
78
684
8476804
 !"#$%##"!&'()
7*
+
,
./
0
1
2
3
4
3
5
4
6
7089
:
;
0<=>6 @ABCEFGHBCEIJKBCLMBCNOCPBIQ

RS TKBCLMUVMCWMBXBY
ZS TKBCLMUVM[MCP
\S TKBCLMUV]^_E^`OCQaObcBYMdeM[OCfGgGHBC
hS TKBCLMOieBYGgEFE^`B
0<=j6 @ABCEFGHBCEIJKBCLMOieBYGgMCQkABCUAlB
RS \mMBY^_lBBCnBUIbAV^oAHBYn_GHBC
ZS pCN[BYqCmqqCmOCAHBGHBC
\S rskeQGgGHBCtGHBCuAvBGAPBiekeQ

hS pCN[BYqCmqwxOiyGHBC
0<=z6 {^eBBAHJGHBCOC|Ao}M~baAqCOC^cMUIQ
RS €isBCbcqCmOOiAfBoABCOPOC|Ao}b
ZS €isBCbcUXBCetqCQBYOMO`q]^mBMdeOC|Ao}b
\S €isBCbcMC‚eGlBCMdeMmMOCƒ_OC^„M…OC|Ao}b
hS €iAPOCLMMdeOC|Ao}b
0<=†6 ‡CLMqCN[BYˆKBY
RS €C‰MMCŠOEI‡CLMM~Oi^_VBMde€i^BY{^„M
ZS ˆN‹MO~BYC‹qOŒBCAV^BVB‡CLMoCmMBCe^MdeMmMBNMqCN[BYˆKBY
\S h‰eOilBOCIBC]^Ž‡CLMM~Oi^_VBMdeMmMBNMqCN[BY€n_
hS h‰eOilB‡CLMCAlBbaAMdeqCN[BY€n_S
0<=;6 eBM^BYMŠqYE^MQkMCQJm^MCd_P^G‘BYMmMC
RS €CQmACeYE_MQYB
ZS €nBOaQYE^MQkOŒqiQOAu
\S €nBOaQYE^MQkOŒeMAuG’Q
hS €aQE^MQkOŒeMAuEeMOAM
0<=“6 €iAH^MCWBYw^ŠOCAHBkJBCŠOUIOCN|BYY”qoCAYE^MQkJm^YAŽJBC•
RS TŠOOCXBYG‘BYtMCBYJ”O
ZS \–BMIQGBY


01 3456789
9

499
845
1 5
4
9
9

!" $484%%9&9
'()9&
(*9&6(+
,
-8
9
4.9
-
/1 /4%01
21 39&4
4%
01 4&4
4%
1 3
4&4
4%
5" 6,447894
:
;4
8484%59
5<9
-
/1 /03=
21 3

>49
01 /%
4949
1 6
%

4949
?" @
4%
7()9&8
A9;9

/1 B8CD4
21 $(+9&8
4%E9)
F
01 $(+9&8
449G&9
1 H
A9I9&%C
J8
4%G)
F
KL"3I9&9&
+88
4%9
-M
*4DN9E
/1 3
*4DN0O9
8
P0Q9

21 0(*9&79R9
01 3
*4DNS49


(M9&
1 3
475;
KK"24F
4Q9
T9
-G94R569&M&4469S9&
76,9&5

/1 U(9&
21 V
01 689&
1 3E6W()4
KX"24F
4Q9
(*9&
-9
-G94R5D
4
F9S9&&4469S9&

7Y9
5

/1 U(9&
8
Z
21 V5[

01 3456789



1 


7
57854567
 !"0$%&'5%
8()

*

5+&,

*-
.1 /0
1)

&2$

3'$
41 5)

26

87,89
01 5)

5%&,85
19:&;
935

1 5)

0(
9
305:
 <"45+
)

5
5+=05+0
>9$(?5@A*-
.1 5&0B

5+,,C0D
1?0%

5+&975&26


41
E
7

,F5:9
01 GH76

1
57,87


1 0@9@5+
&6
?

@5+

F,3F=05+0

 I"J+8+7