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Lecture no33 process of developing project cash flows

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Process of Developing Project Cash Flows
Lecture No.33
Chapter 10
Contemporary Engineering Economics
Copyright © 2016

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Contemporary Engineering Economics, 6 edition
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Chapter Opening Story

 Eclipse has spent $1.4 billion to develop its six-seat 550 twin engine jet.
o Base price: $2,895,000
o Fuel efficiency: 59 gallons per hour
o Flying range: 430 miles
o Operating cost: $648 per hour
o Demand: unknown
At Issue: How would you determine the cash flows from this jet investment?

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Contemporary Engineering Economics, 6 edition
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Key Elements of Investment Decision

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Types of Cash Flow Elements in Project Analysis

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Example 10.1: When Projects Require Only Operating and Investing
Activities

Given: Financial Data

o Investment: $125,000
o Project life: 5 years
o Salvage value: $50,000
o Annual labor savings: $100,000

o Annual manufacturing costs
o Labor: $20,000
o Materials:$12,000
o Overhead:$8,000

o Depreciation method: 7-year MACRS
o Income tax rate: 40%
o MARR: 15%

 Find: Determine the project cash flows

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Contemporary Engineering Economics, 6 edition
Park

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Solution

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Contemporary Engineering Economics, 6 edition
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Return on Invested Capital

The firm earns a 27.62% return on funds that remain internally invested
in the project.

n=0

Beginning

n =1

n=2

n=3

n=4

n=5

−$125,000

−$116,380

−$100,279

−$83,231

−$63,974

−$34,525

−$32,144


−$27,697

−$22,988

−$17,670

$81,619

Balance

Return on
Investment
(27.62%)
Payment

−$125,000

$43,145

$48,245

$44,745

$42,245

Project

−$125,000


−$116,380

−$100,279

−$83,231

−$63,974

Balance

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Contemporary Engineering Economics, 6 edition
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≈0


When Projects Require Working-Capital Investments

What is Working Capital?

Working Capital Equations



Accounting definition:


The amount carried in cash, accounts
receivable, and inventory that is available
to meet day-to-day operating needs.

WC = Current Asset – Current Liabilities
∆WC = ∆CA - ∆CL
where ∆WC = changes in working capital



How to treat working capital investments:

∆CA = changes in current assets

just like a capital expenditure except that

∆CL = changes in current liabilities

no depreciation is allowed.

If ∆WC > 0, working capital requirement. With the net change being
positive, the firm has a net requirement of working capital that has
to be financed during the year. Therefore, the WC requirement
appears as uses of cash in the cash flow statement.
If ∆WC < 0, working capital release. If this amount were negative,
there would have been a cash inflow from working capital release,
which could add to the sources of cash.

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Contemporary Engineering Economics, 6 edition

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When Projects Require Working-Capital Investments

What is working capital?
Definition: The amount carried in cash,
accounts receivable, and inventory that is
available to meet day-to-day operating needs.

How to treat working capital investments
Just like a capital expenditure except that no
depreciation is allowed

Working Capital Equations

oAccounting definition

WC = Current Asset −
Current Liabilities
ΔWC = ΔCA − ΔCL
where ΔWC = changes in
working capital
ΔCA = changes in current
assets
ΔCL = changes in current
liabilities


oIf ΔWC > 0, working capital
requirement.

oIf ΔWC < 0, working capital
release.
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Example 10.2: Working Capital Requirements

 Given: Elements of Working Capital

Find: Working capital requirement
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Solution

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Contemporary Engineering Economics, 6 edition
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Example 10.3: Cash Flow Statement with Working Capital

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Changes in Profitability

 Changes in Profitability
o

NPW without the Working
Capital Requirement
PW(15%) = $43,152

o

NPW with the Working
Capital Requirement

PW(15%) = $31,420

 Difference: $11,732

(lost earnings due to funds
tied up in working capital)

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When Projects Results in Negative Taxable Income

Negative taxable income (project
Regular

loss) means you can reduce your

Project

Business

Combined
Operation

taxable income from regular business

operation by the amount of loss,
which results in a tax savings.

Taxable

$100M

(10M)

$90M

$35M

?

$31.5M

income
Income
taxes
(35%)

Tax savings

Tax Savings = $35M − $31.5M
= $3.5M
Or (10M)(0.35) = −$3.5M

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Example 10.5: Project Cash Flows for a Cost-Only Project

Project Nature: Installing a cooling-fan at Alcoa Aluminum’s McCook plant to reduce the
work-in-process inventory buildup

 Given: Financial facts
o Required investment: $536,000
o Service life: 16 years
o Salvage value: 0
o Reduction of WIP (working-capital release): $2,121,000
o Depreciation Method: 7-year MACRS
o Annual electricity cost: $86,000
o Income tax rate:40%
o MARR: 20%
 Find: Develop the project cash flow

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Contemporary Engineering Economics, 6 edition
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Cash Flow Statement

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Analysis

o
o
o

PW(20%) = $991,008

o
o

RIC = 241.87% >20%

i* = 4.24% and 291.56%
A nonsimple and mixed
investment
Good investment

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Contemporary Engineering Economics, 6 edition

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When Projects Are Financed with Borrowed Funds

• Key issue: Interest payment is a tax-deductible

• What about principal payments?
• As the amount of borrowing is NOT viewed as

expense.

• What needs to be done
• Once a loan repayment schedule is known,
separate the interest payments from the

income to the borrower, the repayments of
principal are NOT viewed as expenses either—
NO tax effect.

annual installments.

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Contemporary Engineering Economics, 6 edition
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Example 10.4: Loan Repayment Schedule

o
o
o

Amount financed: $62,500, or 50% of total capital expenditure
Financing rate: 10% per year
Annual installment: $16,487 or, A = $62,500(A/P, 10%, 5)

End of

Beginning

Year

Balance

Interest Payment

Principal Payment

Ending
Balance

1


$62,500

$6,250

$10,237

$52,263

2

52,263

5,226

11,261

41,002

3

41,002

4,100

12,387

28,615

4


28,615

2,861

13,626

14,989

5

14,989

1,499

14,988

0

$16,487

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Contemporary Engineering Economics, 6 edition
Park

Copyright © 2016 by Pearson Education, Inc.
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Solution


 Effects of debt financing on
profitability

o
o

MARR = 15%, debt interest rate = 10%
NPW without debt financing (100% equity)
PW(15%) = $31,420

o

NPW with debt financing (50% debt)
PW(15%) = $44,439

o

The debt financing increases the present worth by
$13,019. This result is largely caused by the firm’s
being able to borrow the funds at a cheaper rate
(10%) than its MARR of 15%.

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Contemporary Engineering Economics, 6 edition
Park

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