Đề thi thực hành HSG quốc gia THPT môn Sinh học năm 2016

BQ

crAo

DUC

vA oAo rAo

rV rm cHgN Hec srlm cr6r:eu6c

ofl tnr CHiNH THUC

GrA THpr NAvr zoro
M6n thi: THI/C nANn SINH HQC
Thiri gian lim biri: 90 phdtt (khdng kd thdi gian giao di)

/

Ngiy thiz 08/01/2016
(Di thi gim 3 trang)

HAI{ flE{iIiE+
nAr

rni NcutEvr r. (0,7s fridm)
Xfc ilinh ndn$

SQ

dung dich prdt6in trong mfru dqa vio miu sfrc cfra phin rlng biurG

1. Gi6i thiQu

*rfn biiSt li6n kiit peptit trong phdn trl pr6t6in. V6i mQt
(v6t)
lugng nh6
CuSOa trong m6i trudrng ki6m khi c6 m{t li6n kiSt peptit thi ph6n irng biur6 t?o ra
phtlc c6 mdu. Tiry thqQc vio dQ dii crla m4ch peptit (s6 hqng fien k6t) mi miu cta phrlc thay d6i
tir xanh tim di5n tim d6. Dga vio tlQ tt6m nh4t ctla mlu sEc c6 th6 x6c dinh itugc n6ng dQ dung
dich pr6t6in c6 trong ni6u.
Phdn tmg biur6 lh phan fmg dung A6

2. Mfru v$t, h6a ch6t

- I gi6 d6 6ng

+
+

vi

dqng cg (cho

I thi sinh)

nghiQm g6m c6:

I

6ng nghiQm c6 nhEn NaOH l0%.

I

5ng nghiQm c6 nhdn CuSOr l%.

- 2 c6ng to hrit c6 v4ch.
Lryu !:,Thi.st1h
!Ad* tra cdn thQn cdc mdu vQt, h6g clrdt vd dEng cu thf nghiQm ifd ihro. c cung
cdp, niu cdn thi6u, gio tay bdo cho cdn bQ coi thi ad UA sung.
3. Quy trinh thf nghigm

- Stl dung c6ng to hft c6 v4ch hrit ldrofuig lml dung dich NaOH 10% rdi cho vdo ttmg 5ng
nghigm A,B, C, D dA cfuo. c chuAn b! s8n, sau d6 nhg nhing l6c ct6u.
- B6 sung 5 giqt dung dich CuSOa l% vio timg 6ng nghiQm, nhq nhAng
khoang 10 phft vd qdan s6t mdu.

lic

tIAu,

rdi d6 yen

Sau hhi hodn thdnh cdc bwdc trhn, tht sinh gio tay bdq cho cdn bQ coi thi il6n xdc nhfin vd
ghi vdo Phin 1: X6c nh$n ki ntrng thgc hin[ tr6n Phi6u tl6nh ei6 v] trf, I]i cfra thi sinh.
Trrt

bt ctic cdu hdi drtt tffiy vdoPhi6u

d6nh ei{

vi trfi Di.

C6u h6i t.l. (0,30 di$m). Hey diAn c6c chtl cdi A, B, C, D tuong {mg v6i ndng dQ dung dich
prdt6in dpa vio dO dflm nh4t cria miu sic vAo phi6u d6nh gi6 vi trA lbi. Bi6t r6ng 4 ting nghiQm
tlugc chu6n b! c6 ndng dQ dung dlch protoin tuong rmg

li 0,01%; O,lYo; lyo vh" l0%.

CAu hdi 1.2. (0,25 die@ HEy cho bi6t c6c di6u kign d6 thlrc hiQn rtugc phin tmg biur6 tr6n.


Cfiu h6i 1.3. (0,20 diAd Thu6c thri X c6 khf, ntuig nhgn bi6t c6c hqp ch6t c6 chrla nh6m amin
tp do (NHz). eiilt rang thui5c thrir X c6 miu xanh tim khi phan img v6! hqrp chAt c6 chta nh6m
amin tg do vi c6 miu ndq do vdi hqp ch6t kh6ng c6 nh6m amin ty do.

He, cho bi6t khi srt dqng thu6c thri X vi ph6n img miu biur6 c6 th6 nhfln bi6t hgrp ch6t nio
trong crtc d6y dung dich du0i tlfly. Ddnh a6u ({) vdo phi6u d6nh gi6vdtA lui.
A. Nudc, dung dich anit amin glixirL d[ch chi6t dgu tuong.
B. Nudc, dung dich alrit amin glixin, dung dlch NH4NO3 10%.
C. Nudc, dich chi6t dgu tuong, dung dlch NHaN

q

rcyo.

D. Nudc, d[ch chi6t dflu tuong, dung dich caz€in (sfur phAm tir stia).

gAr

tHi NcHTEUI z. (r,2s did@

i

l

Xflc ilinh tlic tli6m dung dich dga viro hiQn tugng co nguy0n sinh vh phf,n co nguy6n sinh
1. Gi6i thiQu

Co nguy6n sinh O t6 bao thyc vft ln hiQn tugrg ph6n nguy6n sinh cfrat Ui co lqi vi t6ch
khdi thtuh tiS bio. Khi cho t6 bio bi co nguyOn sinh vio dung dlch nhugc trucrng, phAn nguyen
sinh ch6t tlng dAn vd trOlei the tich ban dAu, d6 ln phan co nguy6n sinh. Dya trOn hiQn tugng co
nguy6n sinh vi phan co nguy6n sinh, thi sinh c6 thi! x6c dlnh dugc c6c dung dlch nhuqc trucrng,
uu truong vn 2. Mf,u v$t, h6a ch6t

TT

vi

dgng cg (cho

MIu vft,

I thi sinh)

h6a chdt, dgng cg

56 lugng, tlon vi

I

Ct hantr tim

2

Lam kfnh (phi6n klnh)

5 c6i

3

Lamen (H kinh m6ng)

10 c6i

4

Dao lam (dao mdng tt6

5

Dia ddng trd lOyng 2-3 mldung dich !, 2, 3, 4)

4 cdi

6

Kim mfii m6c

1

7

Cdng to hrit dE dugc ct6nh sd

8

Gi6y th6m

5 mtuh

9

Kinh hiOn vi

1 chiiSc

2 ctt

i

cit m6u)

1 c6i

1,2,3,4

LTu yt,fnisty\lctdm tra cdn thQn cdc mdu vQt, h6g clriit vd &1ng
cdp, nAu cdn thi6u, gio tay bdo cho cdn b0 coi thi ad Ud sung.

c6i

4 cdi

cqt

thi nghiQm dd iltgc cung


3.Quy trinh thi nghiQm
Thi sinh h6y tii5n hdnh thi nghiQm theo c6c budc
BuOc L'

Liy

5 lam kinh

vi

sau:

dirng brit viet kinh ghi s0 O, 1,2,3, 4 l6n ttmg lam kinh.

Btrdc 2r Dtrng kim mfli mdc b6c lcrp biOu bi m{t ngodi cria vdy hanh tim vd dft l6n lam
kinh s5 0 dE c6 sEn mQt giqt nudc c6t. Ofly lamen vir quan s6t du6i kinh hi6n vi cho dOn khi thdy
rO lcrp tO bao

miu hdng.

Budc 3: Dtrng kim mtii m6c b6c lcrp biCu bi mat ngoai cua vdy henh tim vi dflt l6n lam
kinh s6 1 dd c6 sEn mQt gigt dung dich 1 .'Dqy lamen vd qttan sdt ngay droi kinh hi€n vi,

Buoc 4: Litm tuong tu nhu bu6c 3 eOi vOi c6c lam kinh 2, 3, 4 cdn l4i v6i c6c gigt dung
dich 2, 3, 4 tt clc il,addng h6 tucmg tmg dO x6c dinh trang th6i cua t6 bdo ch6t.

(Chtilr

O budc 3 vd 4, cdc m6nh bi6u bi phAi dugc lAy tu cirng niQt vAy hdnh tim o mfit

ngoAi cfia cri hnnh).

Sau khi hodn tkdnh ctic buhc tr1n, lhi sinh gio ta1, 66o cho cdn bQ coi thi ddn xtic nhfin vd
ghi vdo Phf,n L: Xic nhfln k! nlng thgc hirnh tr6n Phi6u .I{nh si6 vA tri loi cfia thi sinh.

ifty vdo Phi6u cl6nh ei6 vi tri loi.
Ciu h6i 2.1, (0,25 didfi Sip x6p nho duoi d6y ld dring theo thir tU n6ng dQ t6ng dAn cria cdc
dung dich? Danh AAu (r/) vdo phiOu ddnh gi6 vd td loi.
Trd ldi ctic cdu hdi drhi

A.1,2,4,3
8.2, 4,3, I

c.3,1,2,4
D.4,3,1,2
Cfiu h6i 2.2. (0,25 diA@ Trong c6c dung dlch l,
truong? EAnh O6u (r/) ydo phi6u tt6nh gi6 vi ti loi.

2,3

vit 4, dung dich

nio

li

dung dich ding

A. I

8.2
c.3
D.4
Cflu h6i 2.3. (0,50 dtdfiQuan sdt, vE hlnh th6i t6 tctri vd t6 bio bi6u bi tr6n vdy hanh tim, kdm
theo chrl thich dAy dfi.
Cf,u hdi 2.4. (0,25 did@ Mhu tlm cta
Adu ({) vio phi6u danh gi6 vd trA ldi.

viy

hanh tfm dugc t4o ra b&i ch6t

A. Antoxianin
B. Car0ten6it
C. Xant6phin

D. Vi6la
o
o

Th[ sinh lchdng s* dltng tdi li?u.

Cdn bQ coi thi khdng gidi thich gi thAm.

nio dudi

ttay? D6nh


BO

crAo

DUC

vA DAo

Ot fiU CfriNn

r4o

xV rnr cHeN Hec srNH ct6l QuOc GIA rHPr NAtu zor0
Mdn thi: THUC nAnn SINH HQC
Ngny thiz 08/01/2016

rHtlC

PHTEU OANTT GIA VA TRA

I,OI

Lwu i,:

- Thf sinh fffONC ghi s6 b6o danh, hg tOn, cht ky vdo phi6u niy.
- Cdn bf coi thi phhi ghi x6c nhQn(khilng etuqc W) vdo phAn x6c nhfln
ki n[ng thsc hdnh phia dudi. N6u thi sinh kh6ng thUc hiQn thi ghi ki
hiQu 0, thgc hiQn nhtmg kh6ng hoin thanh hoflc lim d6 vd dpng cp thi
nghiQm ghi ki hiQu -, hoan thdnh thi nghiQm ghi ki hiQu 0.

pnAN r: XAC NIIAN

ri

NANC THII. C HAI{H (d}rnh cho cdn

bQ coi

thi)

X6c nhfln
(cdn bQ coi thi ghi cdc b!,hiQu: 0 hodc -hoqc
BAi thf nghiQm 2
BAi thi nghiQm I

KI nlng thpc hhnh

TT

56 phdch
(Do HE chdm thi ghi)

1

Kh6ng thUc hi€n.

2

Thpc hiQn nhmg kh6ng hoan thinh

l)

hoflc ldm tt6 vd dpng cp thi nghiQm.
3

Hohn thinh thi nghiQm

rft

euA rlri NGITIEM
nAr mri ncnrsnr r. (0,7s aidm)
PHAN z:

X6c ilinh ndng dQ dung dich pr6t6in trong mfru dr;a

vio mlu sic crla phin

r?ng

biur6

CAu h6i l.l, (0,3 did@). HAy diAn c6c chil c6i A, B, C, D tuang ung vdi ndng tIQ dung dlch
prdt6in dga vho tl$ t16m nhat cria mAu sic .
Ndng iIQ dung dich prdt6in (%)

0,0lyo

0,loA

Nhin 5ng nghiQm
CAu hdi 1.2. (0,25 dierd C6c diAu kiQn dC thpc hiQn phdn img biurO

t%

t0%


CAu h6i 1.3, (0,2 did@ Thu6c thir X vd phan ring miu biur0 c6 th6 nhfln biiSt hqp ch6't ndo trong
cilc ddy dwrg d!ch. Eanh O6u ({) vdo c6u tra lqi.

A
CAu trf,

nAr

rni

B

D

C

lli

NcnrEnn z. e,zs itidm)

X6c tlinh tl[c tliGm dung dich dga vio hiQn tugng co nguy0n sinh vir phin co nguy6n sinh

Cfiu 2.1. (0,25 did@ Sep xdp c6c dtrng dich 1, 2, 3, 4, theo thri ty ndng
({) vao cdu ff6lsi.

Sip x6p dung dich
CAU

tri

lr2r413

2,4,3, I

3, t',2,4

dO

t6ng Oan. Oann Oau

4,3, L,2

ldi

Ciu2.2. (0,25 diem) Trong c6c dung dlch

1,

2,3,4 thl dung dlch

ndo ld cleng truong? Eturh

diu

1./1vao c6utrf, loi.

Dung dich
CAU

I

2

3

4

tri ldi

CAu 2.3. (0,50 di€m) Quan s6t vi vE c6u truc khi kh6ng (16 khi) trdn vAy hinh tim g6m c6: 2
bAo b6o v0, 2 t6 bdo php 1t6 Uao kdm) vi2 t€'bdo bi6u bi bao quanh kem chti ttricn AAy dr:.

Ciu 2.4. (0,25 dia@ Mdu tim cfia r'6y
rio c6u te loi.

hanh tim dugc tpo ra bqi chAt ndo du6i d6y? E6nh a6u (rl)

A

Cflu

tri

Di6m

B

lcri

bii thi thr;c hhnh:

t+5

Tdng tli6m: brng

s6

bing chtt

C

D