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✣❸■ ❍➴❈ ❚❍⑩■ ◆●❯❨➊◆
❚❘×❮◆● ✣❸■ ❍➴❈ ❑❍❖❆ ❍➴❈
▲Þ ❱❿◆ ✣Ù❈
P❍×❒◆● P❍⑩P ●■❷■ P❍×❒◆● ❚❘➐◆❍
❇❻❚ P❍×❒◆● ❚❘➐◆❍ ❈❍Ù❆ ▲❖●❆❘■❚
❱⑨ ❈⑩❈ ❇⑨■ ❚❖⑩◆ ▲■➊◆ ◗❯❆◆
▲❯❾◆ ❱❿◆ ❚❍❸❈ ❙ß ❚❖⑩◆ ❍➴❈
❚❍⑩■ ◆●❯❨➊◆ ✲ ◆❿▼ ✷✵✶✹
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✣❸■ ❍➴❈ ❚❍⑩■ ◆●❯❨➊◆
❚❘×❮◆● ✣❸■ ❍➴❈ ❑❍❖❆ ❍➴❈
▲Þ ❱❿◆ ✣Ù❈
P❍×❒◆● P❍⑩P ●■❷■ P❍×❒◆● ❚❘➐◆❍
❇❻❚ P❍×❒◆● ❚❘➐◆❍ ❈❍Ù❆ ▲❖●❆❘■❚
❱⑨ ❈⑩❈ ❇⑨■ ❚❖⑩◆ ▲■➊◆ ◗❯❆◆
▲❯❾◆ ❱❿◆ ❚❍❸❈ ❙ß ❚❖⑩◆ ❍➴❈
❈❤✉②➯♥ ♥❣❤➔♥❤✿ P❍×❒◆● P❍⑩P ❚❖⑩◆ ❙❒ ❈❻P
▼➣ sè ✻✵✳✹✻✳✵✶✳✶✸
◆❣÷í✐ ❤÷î♥❣ ❞➝♥ ❦❤♦❛ ❤å❝
●❙✳ ❚❙❑❍✳ ◆●❯❨➍◆ ❱❿◆ ▼❾❯
❚❍⑩■ ◆●❯❨➊◆ ✲ ◆❿▼ ✷✵✶✹
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▼ö❝ ❧ö❝
▼ð ✤➛✉
✸
✶ ❚➼♥❤ ❝❤➜t ❝õ❛ ❤➔♠ sè ❧♦❣❛r✐t ✈➔ ❝→❝ ❦✐➳♥ t❤ù❝ ❧✐➯♥ q✉❛♥ ✺
✶✳✶
❚➼♥❤ ❝❤➜t ❝õ❛ ❤➔♠ sè ❧♦❣❛r✐t ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✺
✶✳✷
❈→❝ ✤à♥❤ ❧þ ❜ê trñ
✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✼
✶✳✸
▲î♣ ❤➔♠ t✉➛♥ ❤♦➔♥ ✈➔ ♣❤↔♥ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤ ✳ ✳ ✳ ✳
✶✵
✶✳✸✳✶
▲î♣ ❤➔♠ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✶✵
✶✳✸✳✷
▲î♣ ❤➔♠ ♣❤↔♥ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✶✶
✷ P❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ✈➔ ❤➺ ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛
❧♦❣❛r✐t
✶✸
✷✳✶
✷✳✷
✷✳✸
P❤÷ì♥❣ ♣❤→♣ ❣✐↔✐ ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t
✳ ✳ ✳ ✳ ✳ ✳ ✳
✶✸
✷✳✶✳✶
P❤÷ì♥❣ ♣❤→♣ ♠ô ❤â❛ ✈➔ ✤÷❛ ✈➲ ❝ò♥❣ ❝ì sè ✳ ✳ ✳ ✳
✶✸
✷✳✶✳✷
P❤÷ì♥❣ ♣❤→♣ ✤➦t ➞♥ ♣❤ö ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✶✺
✷✳✶✳✸
P❤÷ì♥❣ ♣❤→♣ ❤➡♥❣ sè ❜✐➳♥ t❤✐➯♥ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✷✷
✷✳✶✳✹
P❤÷ì♥❣ ♣❤→♣ ❤➔♠ sè ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✷✺
✷✳✶✳✺
Ù♥❣ ❞ö♥❣ ✤à♥❤ ❧þ ▲❛❣r❛♥❣❡✱ ✤à♥❤ ❧þ ❘♦❧❧❡
✳ ✳ ✳ ✳
✷✾
✷✳✶✳✻
P❤÷ì♥❣ ♣❤→♣ ✤✐➲✉ ❦✐➺♥ ❝➛♥ ✈➔ ✤õ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✸✸
✷✳✶✳✼
P❤÷ì♥❣ ♣❤→♣ ✤→♥❤ ❣✐→ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✸✺
P❤÷ì♥❣ ♣❤→♣ ❣✐↔✐ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t ✳ ✳ ✳ ✳ ✳
✸✻
✷✳✷✳✶
P❤÷ì♥❣ ♣❤→♣ ♠ô ❤â❛ ✈➔ ✤÷❛ ✈➲ ❝ò♥❣ ❝ì sè ✳ ✳ ✳ ✳
✸✻
✷✳✷✳✷
P❤÷ì♥❣ ♣❤→♣ ✤➦t ➞♥ ♣❤ö ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✸✽
✷✳✷✳✸
P❤÷ì♥❣ ♣❤→♣ ❤➔♠ sè ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✹✷
✷✳✷✳✹
P❤÷ì♥❣ ♣❤→♣ ✤✐➲✉ ❦✐➺♥ ❝➛♥ ✈➔ ✤õ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✹✹
✷✳✷✳✺
P❤÷ì♥❣ ♣❤→♣ ✤→♥❤ ❣✐→ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✹✺
P❤÷ì♥❣ ♣❤→♣ ❣✐↔✐ ♠ët sè ❤➺ ❝❤ù❛ ❧♦❣❛r✐t ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✹✻
✐
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✷✳✸✳✶
P❤÷ì♥❣ ♣❤→♣ ❜✐➳♥ ✤ê✐ t÷ì♥❣ ✤÷ì♥❣ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✹✻
✷✳✸✳✷
P❤÷ì♥❣ ♣❤→♣ ✤➦t ➞♥ ♣❤ö ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✹✽
✷✳✸✳✸
P❤÷ì♥❣ ♣❤→♣ ❤➔♠ sè ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✹✾
✷✳✸✳✹
P❤÷ì♥❣ ♣❤→♣ ✤✐➲✉ ❦✐➺♥ ❝➛♥ ✈➔ ✤õ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✺✶
✷✳✸✳✺
P❤÷ì♥❣ ♣❤→♣ ✤→♥❤ ❣✐→ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✺✸
✸ ❈→❝ ❜➔✐ t♦→♥ ❧✐➯♥ q✉❛♥ ✤➳♥ ❤➔♠ sè ❧♦❣❛r✐t
✸✳✶
P❤÷ì♥❣ tr➻♥❤ ✈➔ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❤➔♠ tr♦♥❣ ❧î♣ ❤➔♠
❧♦❣❛r✐t
✸✳✷
✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✺✻
✸✳✶✳✶
P❤÷ì♥❣ tr➻♥❤ ❤➔♠ tr♦♥❣ ❧î♣ ❤➔♠ ❧♦❣❛r✐t
✳ ✳ ✳ ✳ ✳
✺✻
✸✳✶✳✷
❇➜t ♣❤÷ì♥❣ tr➻♥❤ ❤➔♠ tr♦♥❣ ❧î♣ ❤➔♠ ❧♦❣❛r✐t ✳ ✳ ✳
✻✹
❈→❝ ❜➔✐ t♦→♥ ✈➲ ❞➣② sè ✈➔ ❣✐î✐ ❤↕♥ ❞➣② sè s✐♥❤ ❜ð✐ ❤➔♠
❧♦❣❛r✐t
✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
❑➳t ❧✉➟♥
❚➔✐ ❧✐➺✉ t❤❛♠ ❦❤↔♦
✻✼
✼✺
✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳
✐✐
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✺✻
✼✻
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▼ð ✤➛✉
P❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❧➔ ♠ët tr♦♥❣ ♥❤ú♥❣ ♥ë✐ ❞✉♥❣ ❝ì ❜↔♥
✈➔ q✉❛♥ trå♥❣ ❝õ❛ ❝❤÷ì♥❣ tr➻♥❤ t♦→♥ ❜➟❝ tr✉♥❣ ❤å❝ ♣❤ê t❤æ♥❣✳
✣➦❝ ❜✐➺t ❧➔ ❝→❝ ♣❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t ❧➔ ♥❤ú♥❣
♥ë✐ ❞✉♥❣ ❤❛② ✈➔ ❦❤â ✤è✐ ✈î✐ ❤å❝ s✐♥❤ ✈➔ ❝❤ó♥❣ t❤÷í♥❣ ①✉➜t ❤✐➺♥ tr♦♥❣
❝→❝ ✤➲ t❤✐ t✉②➸♥ s✐♥❤ ✤↕✐ ❤å❝✱ ❝❛♦ ✤➥♥❣ ✈➔ ✤➲ t❤✐ ❤å❝ s✐♥❤ ❣✐ä✐✳ ❱✐➺❝
❣✐↔♥❣ ❞↕② ❤➔♠ sè ❧♦❣❛r✐t ✤➣ ✤÷ñ❝ ✤÷❛ ✈➔♦ ❝❤÷ì♥❣ tr➻♥❤ ❧î♣ ✶✷ tr♦♥❣ ✤â
♣❤➛♥ ❦✐➳♥ t❤ù❝ ✈➲ ♣❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t ❝❤✐➳♠
✈❛✐ trá trå♥❣ t➙♠✳
❚✉② ♥❤✐➯♥ ❞♦ t❤í✐ ❣✐❛♥ ❤↕♥ ❤➭♣ ❝õ❛ ❝❤÷ì♥❣ tr➻♥❤ ♣❤ê t❤æ♥❣ ♥➯♥ tr♦♥❣
s→❝❤ ❣✐→♦ ❦❤♦❛ ❦❤æ♥❣ ♥➯✉ ✤÷ñ❝ ✤➛② ✤õ ✈➔ ❝❤✐ t✐➳t t➜t ❝↔ ❝→❝ ❞↕♥❣ ❜➔✐
t♦→♥ ✈➲ ♣❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t ✈➔ ❝→❝ ❜➔✐ t♦→♥ ❧✐➯♥
q✉❛♥✳ ❱➻ ✈➟② ❤å❝ s✐♥❤ t❤÷í♥❣ ❣➦♣ ♥❤✐➲✉ ❦❤â ❦❤➠♥ ❦❤✐ ❣✐↔✐ ❝→❝ ❜➔✐ t♦→♥
♥➙♥❣ ❝❛♦ ✈➲ ♣❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t tr♦♥❣ ❝→❝ ✤➲
t❤✐ ✤↕✐ ❤å❝✱ ❝❛♦ ✤➥♥❣ ✈➔ ✤➲ t❤✐ ❤å❝ s✐♥❤ ❣✐ä✐✳ ▼➦❝ ❞ò ✤➣ ❝â ♥❤✐➲✉ t➔✐ ❧✐➺✉
t❤❛♠ ❦❤↔♦ ✈➲ ❧♦❣❛r✐t ✈î✐ ♥ë✐ ❞✉♥❣ ❦❤→❝ ♥❤❛✉ ♥❤÷♥❣ ❝❤÷❛ ❝â ❝❤✉②➯♥ ✤➲
r✐➯♥❣ ❦❤↔♦ s→t ✈➲ ♣❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t ♠ët ❝→❝❤
❤➺ t❤è♥❣✳
✣➦❝ ❜✐➺t✱ ♥❤✐➲✉ ❞↕♥❣ t♦→♥ ✈➲ ✤↕✐ sè ✈➔ ❧♦❣❛r✐t ❝â q✉❛♥ ❤➺ ❝❤➦t ❝❤➩
✈î✐ ♥❤❛✉✱ ❦❤æ♥❣ t❤➸ t→❝❤ rí✐ ✤÷ñ❝✳ ◆❤✐➲✉ ❜➔✐ t♦→♥ ❝❤ù❛ ❧♦❣❛r✐t ❝➛♥ ❝â
sü trñ ❣✐ó♣ ❝õ❛ ✤↕✐ sè✱ ❣✐↔✐ t➼❝❤ ✈➔ ♥❣÷ñ❝ ❧↕✐✳
❉♦ ✤â✱ ✤➸ ✤→♣ ù♥❣ ♥❤✉ ❝➛✉ ✈➲ ❣✐↔♥❣ ❞↕②✱ ❤å❝ t➟♣ ✈➔ ❣â♣ ♣❤➛♥ ♥❤ä
❜➨ ✈➔♦ sü ♥❣❤✐➺♣ ❣✐→♦ ❞ö❝✱ ❧✉➟♥ ✈➠♥ ✧P❤÷ì♥❣ ♣❤→♣ ❣✐↔✐ ♣❤÷ì♥❣ tr➻♥❤✱
❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t ✈➔ ❝→❝ ❜➔✐ t♦→♥ ❧✐➯♥ q✉❛♥✧ ♥❤➡♠ ❤➺ t❤è♥❣
❝→❝ ❦✐➳♥ t❤ù❝ ❝ì ❜↔♥ ✈➲ ♣❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t ❦➳t
✸
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ữỡ t q số rt
ữỡ tr t ữỡ tr tr ợ rt
t số ợ số s rt
tọ ỏ t ỡ s s ố ợ sữ s
ồ ữớ t trỹ t ữợ t
tr t ỳ ự tổ
ổ t ỡ t ổ tr
ỏ t trữớ ồ ồ ồ rữớ
P ỗ ú ù t tổ
t
ỵ ự
Footer Page 6 of 128.
Header Page 7 of 128.
❈❤÷ì♥❣ ✶
❚➼♥❤ ❝❤➜t ❝õ❛ ❤➔♠ sè ❧♦❣❛r✐t ✈➔ ❝→❝
❦✐➳♥ t❤ù❝ ❧✐➯♥ q✉❛♥
✶✳✶ ❚➼♥❤ ❝❤➜t ❝õ❛ ❤➔♠ sè ❧♦❣❛r✐t
f (x) = loga x, 0 < a = 1 ✤÷ñ❝ ❣å✐ ❧➔ ❤➔♠ sè ❧♦❣❛r✐t ❝ì sè a✳
◆❤➟♥ ①➨t r➡♥❣ t➟♣ ①→❝ ✤à♥❤ D = (0; +∞) ✈➔ t➟♣ ❣✐→ trà I = R✳
❚r♦♥❣ ❝→❝ ♣❤➛♥ t✐➳♣ t❤❡♦✱ t❛ ❣✐↔ sû 0 < a = 1✳
◆❤➟♥ ①➨t r➡♥❣ ❤➔♠ sè f (x) = loga x ❧✐➯♥ tö❝ ✈➔ ❝â ✤↕♦ ❤➔♠ ✈î✐ ♠å✐
x > 0✱ ❤ì♥ ♥ú❛
1
f (x) =
.
x ln a
❚❛ ❦❤↔♦ s→t t➼♥❤ ✤ì♥ ✤✐➺✉ ❝õ❛ ❤➔♠ sè f (x) = loga x tr♦♥❣ ✷ tr÷í♥❣ ❤ñ♣✳
✲ ❚r÷í♥❣ ❤ñ♣ ✶✿ a > 1✳
❑❤✐ ✤â✱ ln a > 0 ♥➯♥ s✉② r❛
1
f (x) =
> 0, ∀x > 0.
x ln a
❱➟②✱ ❦❤✐ a > 1 t❤➻ f (x) = loga x ❧➔ ❤➔♠ ✤ç♥❣ ❜✐➳♥ tr➯♥ ❉✳
❚❛ ❧↕✐ ❝â f (1) = 0, f (a) = 1 ✈➔ lim loga x = −∞; lim loga x = +∞.
+
❍➔♠ sè
x→+∞
x→0
❚❛ ❝â ❜↔♥❣ ❜✐➳♥ t❤✐➯♥ s❛✉✿
x
0
1
1
y = loga x
0
−∞
✺
Footer Page 7 of 128.
a
+∞
+∞
Header Page 8 of 128.
0 < a < 1✳
❚r♦♥❣ tr÷í♥❣ ❤ñ♣ ♥➔② f (x) < 0, ∀x ∈ D ✳
❱➟②✱ ❦❤✐ 0 < a < 1 t❤➻ f (x) = loga x ❧➔ ❤➔♠
✲ ❚r÷í♥❣ ❤ñ♣ ✷✿
sè ♥❣❤à❝❤ ❜✐➳♥ tr➯♥ ❉✳
❚❛ ❝â ❜↔♥❣ ❜✐➳♥ t❤✐➯♥ s❛✉✿
x
0
+∞
1
a
+∞
0
y = loga x
1
−∞
❚➼♥❤ ❝❤➜t ✶✳✶✳ f (x) = logax
✈➔ ♥❣❤à❝❤ ❜✐➳♥ ❦❤✐
❧➔ ❤➔♠ ✤ç♥❣ ❜✐➳♥ tr➯♥
D = R+
❦❤✐
a>1
0 < a < 1.
❚➼♥❤ ❝❤➜t ✶✳✷✳
❱î✐ ♠å✐
❚➼♥❤ ❝❤➜t ✶✳✸✳
❱î✐ ♠å✐
a > 0✱ a = 1 ✈➔ x1 , x2 ∈ (0; +∞)✱
x1
loga (x1 x2 ) = loga x1 + loga x2 ✱ loga = loga x1 − loga x2 .
x2
a > 0✱ a = 1
✈➔
x > 0✳
❱î✐
α
t❛ ❝â
❜➜t ❦ý✱ t❛ ❝â
loga xα = αloga x.
❚➼♥❤ ❝❤➜t ✶✳✹✳
❱î✐ ♠å✐
0 < a = 1, 0 < c = 1
loga x =
❚➼♥❤ ❝❤➜t ✶✳✺✳
❍➔♠ sè
❚➼♥❤ ❝❤➜t ✶✳✻✳
❱î✐ ♠å✐
✈➔
x > 0✱
t❛ ❝â
logc x
.
logc x
f (x) = loga x (0 < a = 1) ❝â ✤↕♦ ❤➔♠ t↕✐ ♠å✐
1
✤✐➸♠ x ∈ (0; +∞) ✈➔ (loga x) =
. ◆➳✉ ❤➔♠ sè u = u(x) ❝â ✤↕♦ ❤➔♠
x ln a
tr➯♥ ❦❤♦↔♥❣ J ∈ R t❤➻ ❤➔♠ sè y = loga u(x)✱ (0 < a = 1) ❝â ✤↕♦ ❤➔♠
u (x)
tr➯♥ ❏ ✈➔ (loga u(x)) =
.
u(x) ln a
•
❑❤✐
a>1
•
❑❤✐
0
t❤➻
a > 0✱ a = 1
x1 , x2 ∈ (0; +∞)✱
loga x1 < loga x2 ⇔ x1 < x2 .
t❤➻
loga x1 < loga x2 ⇔ x1 > x2 .
✻
Footer Page 8 of 128.
✈➔
t❛ ❝â
Header Page 9 of 128.
✶✳✷ ❈→❝ ✤à♥❤ ❧þ ❜ê trñ
✣à♥❤ ❧➼ ✶✳✶✳
c ∈ (a; b)
t❤➻ tç♥ t↕✐
✣à♥❤ ❧➼ ✶✳✷✳
y = f (x) ❧✐➯♥
❝❤♦ f (c) = 0✳
◆➳✉ ❤➔♠ sè
s❛♦
◆➳✉ ❤➔♠ sè
tö❝ tr➯♥
[a; b]
✈➔
f (a).f (b) < 0
y = f (x) ❧✐➯♥ tö❝ tr➯♥ [a; b]✱ f (a) = A, f (b) = B
t❤➻ ❤➔♠ sè ♥❤➟♥ ♠å✐ ❣✐→ trà tr✉♥❣ ❣✐❛♥ ❣✐ú❛ ❆ ✈➔ ❇✳
❍➺ q✉↔ ✶✳✶✳
◆➳✉ ❤➔♠ sè
y = f (x)
❧✐➯♥ tö❝ tr➯♥
[a; b]
t❤➻ ♥â ♥❤➟♥ ♠å✐
❣✐→ trà tr✉♥❣ ❣✐❛♥ ❣✐ú❛ ❣✐→ trà ❧î♥ ♥❤➜t ✈➔ ❣✐→ trà ♥❤ä ♥❤➜t✳
✣à♥❤ ❧➼ ✶✳✸
[a; b]✱
✳
❝â ✤↕♦ ❤➔♠ tr➯♥ ❦❤♦↔♥❣
s❛♦ ❝❤♦
f : [a; b] → R t❤ä❛ ♠➣♥ ❢
(a; b) ✈➔ f (a) = f (b) t❤➻ tç♥
✭❘♦❧❧❡✮ ❈❤♦ ❤➔♠ sè
❧✐➯♥ tö❝ tr➯♥
t↕✐
c ∈ (a; b)
f (c) = 0✳
❈❤ù♥❣ ♠✐♥❤✳
❱➻
f (x) ❧✐➯♥ tö❝
tr➯♥
[a; b] ♥➯♥ t❤❡♦
✤à♥❤ ❧➼ ❲❡✐❡rstr❛ss
f (x) ♥❤➟♥ ❣✐→
trà
[a; b]✳
tr➯♥ [a; b]✱
❧î♥ ♥❤➜t ▼ ✈➔ ❣✐→ trà ♥❤ä ♥❤➜t ♠ tr➯♥
M = m t❛ ❝â f (x) ❧➔ ❤➔♠ ❤➡♥❣
❞♦ ✤â ✈î✐ ♠å✐ c ∈ (a; b)
❧✉æ♥ ❝â f (c) = 0✳
✲ ❑❤✐ M > m✱ ✈➻ f (a) = f (b) ♥➯♥ tç♥ t↕✐ c ∈ (a; b) s❛♦ ❝❤♦ f (c) = m
❤♦➦❝ f (c) = M ✱ t❤❡♦ ❜ê ✤➲ ❋❡r♠❛t s✉② r❛ f (c) = 0✳
✲ ❑❤✐
❍➺ q✉↔ ✶✳✷✳
◆➳✉ ❤➔♠ sè
f (x)
❝â ♥ ♥❣❤✐➺♠ ✭♥ ❧➔ sè ♥❣✉②➯♥ ❞÷ì♥❣ ❧î♥ ❤ì♥ ✶✮ tr➯♥
♥❤➜t
n−1
(a; b)✳
♥❣❤✐➺♠ tr➯♥
❍➺ q✉↔ ✶✳✸✳
❍➺ q✉↔ ✶✳✹✳
f (x) ❝â ✤↕♦ ❤➔♠
f (x) ❝â ♥❤✐➲✉ ♥❤➜t
◆➳✉ ❤➔♠ sè
✈æ ♥❣❤✐➺♠ tr➯♥
(a; b)
(a; b) ✈➔ f (x)
(a; b) t❤➻ f (x) ❝â ➼t
❝â ✤↕♦ ❤➔♠ tr➯♥ ❦❤♦↔♥❣
t❤➻
◆➳✉ ❤➔♠ sè
f (x)
✶ ♥❣❤✐➺♠
n+1
✣à♥❤ ❧➼ ✶✳✹
tr➯♥ ✤♦↕♥
♥❣❤✐➺♠ tr➯♥
✳
✭▲❛❣r❛♥❣❡✮
[a; b]✱
(a; b)✳
f : [a; b] → R t❤ä❛ ♠➣♥
(a; b)✱ ❦❤✐ ✤â ∃c ∈ (a; b) :
❈❤♦ ❤➔♠ sè
❦❤↔ ✈✐ tr➯♥ ❦❤♦↔♥❣
f (c) =
f (b) − f (a)
.
b−a
✼
Footer Page 9 of 128.
(a; b) ✈➔ f (x)
(a; b) t❤➻ f (x) ❝â
❝â ✤↕♦ ❤➔♠ tr➯♥ ❦❤♦↔♥❣
❝â ♥❤✐➲✉ ♥❤➜t ♥ ♥❣❤✐➺♠ ✭♥ ❧➔ sè ♥❣✉②➯♥ ❞÷ì♥❣✮ tr➯♥
♥❤✐➲✉ ♥❤➜t
(a; b) ✈➔ f (x)
tr➯♥ (a; b)✳
tr➯♥ ❦❤♦↔♥❣
❢ ❧✐➯♥ tö❝
Header Page 10 of 128.
❈❤ù♥❣ ♠✐♥❤✳
❳➨t ❤➔♠ sè
F (x) = f (x) −
f (b) − f (a)
x.
b−a
❚❛ ❝â
F (x) ❧➔ ❤➔♠ ❧✐➯♥
F (a) = F (b)✳
tö❝ tr➯♥ ✤♦↕♥
[a; b]
✱ ❝â ✤↕♦ ❤➔♠ tr➯♥ ❦❤♦↔♥❣
(a; b)
✈➔
c ∈ (a; b) s❛♦ ❝❤♦ F (c) = 0✳
f (b) − f (a)
f (b) − f (a)
F (x) = f (x) −
✱ s✉② r❛ f (c) =
✳
b−a
b−a
❚❤❡♦ ✤à♥❤ ❧➼ ❘♦❧❧❡ tç♥ t↕✐
▼➔
❍➺ q✉↔ ✶✳✺✳
◆➳✉
F (x) = 0 ✈î✐ ♠å✐ ① t❤✉ë❝ ❦❤♦↔♥❣ (a; b) t❤➻ F (x) ❜➡♥❣
❤➡♥❣ sè tr➯♥ ❦❤♦↔♥❣ ✤â✳
✣à♥❤ ❧➼ ✶✳✺✳
✲ ◆➳✉
✲ ◆➳✉
f (x) ❝â ✤↕♦ ❤➔♠ tr➯♥ ❦❤♦↔♥❣ (a; b)✳
f (x) > 0, ∀x ∈ (a; b) t❤➻ f (x) ✤ç♥❣ ❜✐➳♥ tr➯♥ (a; b)✳
f (x) < 0, ∀x ∈ (a; b) t❤➻ f (x) ♥❣❤à❝❤ ❜✐➳♥ tr➯♥ (a; b)✳
✣à♥❤ ❧➼ ✶✳✻
❦ý
❈❤♦ ❤➔♠ sè
✳
✭❇➜t ✤➥♥❣ t❤ù❝ ❈❛✉❝❤②✲❙❝❤✇❛r③✮
a1 , a2 , ..., an
✈➔
b1 , b2 , ..., bn ✳
❈❤♦ ❤❛✐ ❝➦♣ ❞➣② sè ❜➜t
❑❤✐ ✤â
(a1 b1 + a2 b2 + ... + an bn )2 ≤ (a21 + a22 + ... + a2n )(b21 + b22 + ... + b2n ).
❉➜✉ ❜➡♥❣ ①↔② r❛ ❦❤✐ ✈➔ ❝❤➾ ❦❤✐
❈❤ù♥❣ ♠✐♥❤✳
∃k
✤➸
ai = kbi , ∀i ∈ (1, 2, ..., n).
❳➨t t❛♠ t❤ù❝ ❜➟❝ ❤❛✐
f (x) = (a21 +a22 +...+a2n )x2 −2(a1 b1 +a2 b2 +...+an bn )x+(b21 +b22 +...+b2n )
✲ ◆➳✉
a21 + a22 + ... + a2n = 0 ⇔ a1 = a2 = ... = an = 0
❜➜t ✤➥♥❣ t❤ù❝ ❤✐➸♥
♥❤✐➯♥ ✤ó♥❣✳
✲ ◆➳✉
a21 + a22 + ... + a2n > 0✱
t❛ ✈✐➳t
f (x)
❞÷î✐ ❞↕♥❣
f (x) = (a1 x − b1 )2 + (a2 x − b2 )2 + ... + (an x − bn )2 ≥ 0, ∀x ∈ R.
❚❤❡♦ ✤à♥❤ ❧þ ✈➲ ❞➜✉ ❝õ❛ t❛♠ t❤ù❝ ❜➟❝ ❤❛✐ t❤➻
∆ = (a1 b1 + a2 b2 + ... + an bn )2 − (a21 + a22 + ... + a2n )(b21 + b22 + ... + b2n ) ≤ 0
⇔ (a1 b1 + a2 b2 + ... + an bn )2 ≤ (a21 + a22 + ... + a2n )(b21 + b22 + ... + b2n ).
✽
Footer Page 10 of 128.
Header Page 11 of 128.
❉➜✉ ✤➥♥❣ t❤ù❝ ①↔② r❛ ❦❤✐ ✈➔ ❝❤➾ ❦❤✐
∃k
✤➸
a1 x − b 1 = 0
a2 x − b 2 = 0
..................
an x − bn = 0
❤❛② ❦❤✐ ✈➔ ❝❤➾ ❦❤✐
ai = kbi , ∀i ∈ (1, 2, ..., n).
✣à♥❤ ❧➼ ✶✳✼
✳
✭❇➜t ✤➥♥❣ t❤ù❝ ❇❡r♥♦✉❧❧✐✮
(1 + x)α ≤ 1 + αx
(1 + x)α ≥ 1 + αx
❦❤✐
❦❤✐
●✐↔ sû
x > −1✳
❑❤✐ ✤â
0≤α≤1
α ≤ 0 ∨ α ≥ 1.
❈❤ù♥❣ ♠✐♥❤✳
α = 0 ❤♦➦❝ α = 1 t❤➻ t❛ t❤✉ ✤÷ñ❝ ✤➥♥❣ t❤ù❝✳
α
✲ ❑❤✐ α < 0 ❤♦➦❝ α > 1✱ ①➨t ❤➔♠ sè f (x) = (1 + x) − αx − 1✱
x > −1✳
α−1
❚❛ ❝â f (x) = α(1 + x)
− α = α (1 + x)α−1 − 1 ✈➔
✲ ❑❤✐
✈î✐
f (x) = 0 ⇔ x = 0✱ ♥➯♥ f (x) ≥ 0, ∀x > −1 ⇔ (1 + x)α ≥ 1 + αx,
∀x > −1.
✲ ❑❤✐ 0 < α < 1✱ ①➨t ❤➔♠ sè f (x) ♥❤÷ tr➯♥✱ t❛ ❝â
f (x) ≤ 0, ∀x > −1 ⇔ (1 + x)α ≤ 1 + αx, ∀x > −1.
◆❤➟♥ ①➨t ✶✳✶✳
❑❤✐ t❤❛②
x
❜ð✐
x−1
xα + (1 − x)α ≤ 1
xα + (1 − x)α ≥ 1
❱➼ ❞ö ✶✳✶✳
❈❤♦
m>0
t❛ ❝â
❦❤✐
❦❤✐
0≤α≤1
α ≤ 0 ∨ α ≥ 1.
❧➔ sè ♥❣✉②➯♥ ❞÷ì♥❣ ❝á♥
a, b, c
❧➔ ✸ sè t❤ü❝ s❛♦
❝❤♦
a
b
c
+
+
=0
m+2 m+1 m
2
❈❤ù♥❣ ♠✐♥❤ r➡♥❣ ❦❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ax + bx + c = 0
♥❣❤✐➺♠ tr♦♥❣ ❦❤♦↔♥❣ (0; 1)✳
●✐↔✐✳
❳➨t ❤➔♠ sè
a
b
c
xm+2 +
xm+1 + xm
m+2
m+1
m
❧✐➯♥ tö❝ tr➯♥ [0; 1]✳ ❑❤↔ ✈✐ tr♦♥❣ (0; 1) ✈➔
F (x) = xm−1 (ax2 + bx + c).
F (x) =
✾
Footer Page 11 of 128.
❝â ➼t ♥❤➜t ✶
Header Page 12 of 128.
◆❣♦➔✐ r❛
F (0) = F (1) = 0.
⑩♣ ❞ö♥❣ ✤à♥❤ ❧þ ❘♦❧❧❡ ❦❤✐ ✤â
∃α ∈ (0; 1)
s❛♦ ❝❤♦
F (α) = 0
⇔ αm−1 (aα2 + bα + c) = 0
⇔ aα2 + bα + c = 0.
❱➟② ♣❤÷ì♥❣ tr➻♥❤
ax2 + bx + c = 0
❝â ♥❣❤✐➺♠
α ∈ (0; 1)✳
✭✤✐➲✉ ♣❤↔✐
❝❤ù♥❣ ♠✐♥❤✮
❱➼ ❞ö ✶✳✷✳
❈❤ù♥❣ ♠✐♥❤ r➡♥❣
2014
1
1
< ln
<
.
2014
2013 2013
●✐↔✐✳
f (x) = ln x✱ t❛ ❝â
1
f (x) = .
x
❍➔♠ f (x) ❧✐➯♥ tö❝ tr➯♥ ✤♦↕♥ [2013; 2014]✱ ❝â ✤↕♦ ❤➔♠ tr➯♥ (2013; 2014)✳
❚❤❡♦ ✤à♥❤ ❧þ ❧❛❣r❛♥❣❡ tç♥ t❛✐ c ∈ (2013; 2014) s❛♦ ❝❤♦
❳➨t ❤➔♠ sè
f (2014) − f (2013)
1
= f (c) ⇔ ln 2014 − ln 2013 =
2014 − 2013
c
2014 1
⇔ ln
= .
2013
c
c ∈ (2013; 2014) t❛
1
1
1
< <
.
2014
c
2013
❱î✐
❝â
❙✉② r❛
1
2014
1
< ln
<
.
2014
2013 2013
❱➟②✱ t❛ ❝â ✤✐➲✉ ♣❤↔✐ ❝❤ù♥❣ ♠✐♥❤✳
✶✳✸ ▲î♣ ❤➔♠ t✉➛♥ ❤♦➔♥ ✈➔ ♣❤↔♥ t✉➛♥ ❤♦➔♥ ♥❤➙♥
t➼♥❤
✶✳✸✳✶ ▲î♣ ❤➔♠ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤
✣à♥❤ ♥❣❤➽❛ ✶✳✶✳
f (x)
❍➔♠ sè
❝❤✉ ❦ý
a (a ∈
/ {0, 1, −1})
✤÷ñ❝ ❣å✐ ❧➔ ❤➔♠ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤
tr➯♥ ▼ ♥➳✉
✶✵
Footer Page 12 of 128.
M ⊂ D(f )
✈➔
Header Page 13 of 128.
∀x ∈ M ⇒ a±1 x ∈ M,
f (ax) = f (x), ∀x ∈ M.
❱➼ ❞ö ✶✳✸✳
f (x) = sin(2πlog2 x)✳
+
❤♦➔♥ ♥❤➙♥ t➼♥❤ ❝❤✉ ❦ý ✷ tr➯♥ R ✳
+
±1
+
❚❤➟t ✈➟②✱ t❛ ❝â ∀x ∈ R t❤➻ 2 x ∈ R ✈➔
❳➨t ❤➔♠ sè
❑❤✐ ✤â
f (x)
❧➔ ❤➔♠ t✉➛♥
f (2x) = sin(2πlog2 (2x))
= sin(2π(1 + log2 x))
❱➼ ❞ö ✶✳✹✳
= sin(2πlog2 x) = f (x), ∀x ∈ R+ .
❈❤♦ ✈➼ ❞ö ✈➲ ❤➔♠ sè ❧✐➯♥ tö❝ ✈➔ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤ ❝❤✉
❦ý ❝ì sð ✺✿
f (5x) = f (x), ∀x > 0.
●✐↔✐✳
❚❛ ❝â
∀x ∈ R+ ⇒ 5± x ∈ R+
✈➔
log5 (5x) = 1 + log5 x ⇔ 2πlog5 (5x) = 2π + log5 x.
✣➦t
f (x) = cos[2πlog5 x], ∀x > 0,
s✉② r❛
f (5x) = cos[2πlog5 (5x)]
= cos[2π+2πlog5 x]
= cos[2πlog5 x] = f (x)
❱➟②✱ ❤➔♠ sè
t➼♥❤ ❝❤✉ ❦ý
f (x) = cos(2πlog5 x), ∀x > 0 ❧➔ ♠ët ❤➔♠ sè t✉➛♥ ❤♦➔♥ ♥❤➙♥
+
❝ì sð ✺ tr➯♥ R ✳
✶✳✸✳✷ ▲î♣ ❤➔♠ ♣❤↔♥ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤
✣à♥❤ ♥❣❤➽❛ ✶✳✷✳
f (x)
❍➔♠ sè
t➼♥❤ ❝❤✉ ❦ý
a (a ∈
/ {0, 1, −1})
✤÷ñ❝ ❣å✐ ❧➔ ❤➔♠ ♣❤↔♥ t✉➛♥ ❤♦➔♥ ♥❤➙♥
tr➯♥
M
♥➳✉
M ⊂ D(f )
∀x ∈ M ⇒ a±1 x ∈ M,
f (ax) = −f (x), ∀x ∈ M.
✶✶
Footer Page 13 of 128.
✈➔
Header Page 14 of 128.
❱➼ ❞ö ✶✳✺✳
❈❤♦ ✈➼ ❞ö ❤➔♠ sè ❧✐➯♥ tö❝ ✈➔ ♣❤↔♥ t✉➛♥ ❤♦➔♥ ♥❤➙♥ t➼♥❤ ❝❤✉
❦ý ❝ì sð ✸✿
f (3x) = −f (x), ∀x > 0.
●✐↔✐✳
❚❛ ❝â
∀x ∈ R+ ⇒ 3± x ∈ R+
✈➔
log3 (3x) = 1 + log3 x ⇔ πlog3 (3x) = π + πlog3 x
✣➦t
f (x) = cos[πlog3 x],∀x > 0
s✉② r❛
f (3x) = cos[πlog3 (3x)]
= cos[π + πlog3 x]
= −cos[πlog3 x] = −f(x).
f (x) = cos(πlog3 x),
+
❝ì sð ✸ tr➯♥ R ✳
❱➟②✱ ❤➔♠ sè
t➼♥❤ ❝❤✉ ❦ý
❧➔ ♠ët ❤➔♠ sè ♣❤↔♥ t✉➛♥ ❤♦➔♥ ♥❤➙♥
✶✷
Footer Page 14 of 128.
Header Page 15 of 128.
❈❤÷ì♥❣ ✷
P❤÷ì♥❣ tr➻♥❤✱ ❜➜t ♣❤÷ì♥❣ tr➻♥❤ ✈➔
❤➺ ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t
✷✳✶ P❤÷ì♥❣ ♣❤→♣ ❣✐↔✐ ♣❤÷ì♥❣ tr➻♥❤ ❝❤ù❛ ❧♦❣❛r✐t
✷✳✶✳✶ P❤÷ì♥❣ ♣❤→♣ ♠ô ❤â❛ ✈➔ ✤÷❛ ✈➲ ❝ò♥❣ ❝ì sè
✶✳ P❤÷ì♥❣ ♣❤→♣ ❝❤✉♥❣✳
✣➸ ❝❤✉②➸♥ ➞♥ sè ❦❤ä✐ ❧♦❣❛r✐t t❛ ❝â t❤➸ ♠ô ❤â❛ t❤❡♦ ❝ò♥❣ ♠ët ❝ì sè ❝↔
❤❛✐ ✈➳ ❝õ❛ ♣❤÷ì♥❣ tr➻♥❤✳ ❈❤ó♥❣ t❛ ❧÷✉ þ ❝→❝ ♣❤➨♣ ❜✐➳♥ ✤ê✐ ❝ì ❜↔♥ s❛✉✿
• loga f (x) = b ⇔
0
.
f (x) = ab
• loga f (x) = loga g(x) ⇔
0
f (x) = g(x) .
✷✳ ❈→❝ ✈➼ ❞ö✳
❱➼ ❞ö ✷✳✶✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
logx (x2 + 4x − 4) = 3
✭✷✳✶✮
●✐↔✐✳
✣✐➲✉ ❦✐➺♥
√
x > −2 + √8
x + 4x − 4 > 0 ⇔
0
x < −2 − 8
0
2
✶✸
Footer Page 15 of 128.
⇔
√
8 − 2 < x = 1.
✭✷✳✷✮
Header Page 16 of 128.
❚❛ sû ❞ö♥❣ ♣❤➨♣ ❜✐➳♥ ✤ê✐✿
3 = logx x3
❑❤✐ ✤â
(2.1) ⇔ logx (x2 + 4x − 4) = logx x3 ⇔ x2 + 4x − 4 = x3
x=1
3
2
2
⇔ x − x − 4x + 4 = 0 ⇔ (x − 1)(x − 4) = 0 ⇔ x = 2
x = −2
x = −2 ❦❤æ♥❣
❧➔ x = 1, x = 2✳
❚r♦♥❣ ✤â
♥❣❤✐➺♠
❱➼ ❞ö ✷✳✷✳
t❤ä❛ ♠➣♥ ✤✐➲✉ ❦✐➺♥ ✭✷✳✷✮✳ ❱➟②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â
❳→❝ ✤à♥❤ ♠ ✤➸ ♣❤÷ì♥❣ tr➻♥❤
2log4 (2x2 − x + 2m − 4m2 ) + log 1 (x2 + mx − 2m2 ) = 0
✭✷✳✸✮
2
❝â ♥❣❤✐➺♠
x1 , x2
t❤ä❛ ♠➣♥
x21 + x22 > 1✳
●✐↔✐✳
❚❛ sû ❞ö♥❣ ♣❤➨♣ ❜✐➳♥ ✤ê✐✿
1
log4 (2x2 − x + 2m − 4m2 ) = log2 (2x2 − x + 2m − 4m2 )
2
log 1 (x2 + mx − 2m2 ) = −log2 (x2 + mx − 2m2 ).
2
❑❤✐ ✤â✱ ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✸✮ ❝â ❞↕♥❣
log2 (2x2 − x + 2m − 4m2 ) − log2 (x2 + mx − 2m2 ) = 0
⇔ log2 (2x2 − x + 2m − 4m2 ) = log2 (x2 + mx − 2m2 )
x2 + mx − 2m2 > 0
⇔
2
2x2 − x + 2m − 4m2 = x2 + mx − 2m
2
x + mx − 2m2 > 0
x2 + mx − 2m2 > 0
⇔
⇔
.
x = 2m
x2 − (m + 1)x + 2m − 2m2 = 0
x1 = 1 − m
2
✣➸ ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✸✮ ❝â ♥❣❤✐➺♠
❧➔✿
x1 , x2
(2m)2 + m(2m) − 2m2 > 0
(1 − m)2 + m(1 − m) − 2m2 > 0 ⇔
(2m)2 + (1 − m)2 > 1
✶✹
Footer Page 16 of 128.
t❤ä❛ ♠➣♥
x21 + x22 > 1
✤✐➲✉ ❦✐➺♥
−1 < m < 0
2
1 .
5
2
Header Page 17 of 128.
✷✳✶✳✷ P❤÷ì♥❣ ♣❤→♣ ✤➦t ➞♥ ♣❤ö
▼ö❝ ✤➼❝❤ ❝õ❛ ♣❤÷ì♥❣ ♣❤→♣ ♥➔② ❧➔ ❝❤✉②➸♥ ❝→❝ ❜➔✐ t♦→♥ ✤➣ ❝❤♦ ✈➲
♣❤÷ì♥❣ tr➻♥❤ ❤♦➦❝ ❤➺ ♣❤÷ì♥❣ tr➻♥❤ ✤↕✐ sè q✉❡♥ ❜✐➳t✳
✷✳✶✳✷✳✶ ❉ò♥❣ ➞♥ ♣❤ö ❝❤✉②➸♥ ♣❤÷ì♥❣ tr➻♥❤ ❧♦❣❛r✐t t❤➔♥❤ ♠ët
♣❤÷ì♥❣ tr➻♥❤ ✈î✐ ♠ët ➞♥ ♣❤ö
✶✳ P❤÷ì♥❣ ♣❤→♣ ❝❤✉♥❣
❚❛ ❧÷✉ þ ❝→❝ ♣❤➨♣ ✤➦t ➞♥ ♣❤ö t❤÷í♥❣ ❣➦♣ s❛✉✿
❉↕♥❣ ✶✿
◆➳✉ ✤➦t
t = loga x
✈î✐
x>0
t❤➻
logka x = tk ,
1
logx a = ✈î✐ 0 < x = 1.
t
❉↕♥❣ ✷✿ ❚❛ ❜✐➳t r➡♥❣ alogb c = clogb a ✱ ❞♦ ✤â ♥➳✉ ✤➦t t = alogb x t❤➻ t = xlogb a ✳
log x
❚✉② ♥❤✐➯♥ tr♦♥❣ ♥❤✐➲✉ ❜➔✐ t♦→♥ ❝â ❝❤ù❛ a b ✱ t❛ t❤÷í♥❣ ✤➦t ➞♥ ♣❤ö ❞➛♥
✈î✐ t = logb x✳
✷✳ ❈→❝ ✈➼ ❞ö
❱➼ ❞ö ✷✳✸✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
(x − 2)log3 [9(x−2)] = 9(x − 2)3 .
✭✷✳✹✮
●✐↔✐✳
✣✐➲✉ ❦✐➺♥
x − 2 > 0 ⇔ x > 2.
▲➜② ❧♦❣❛r✐t ❝ì sè ✸ ❤❛✐ ✈➳ ♣❤÷ì♥❣ tr➻♥❤
✭✷✳✹✮✱ t❛ ✤÷ñ❝✿
log3 [(x − 2)log3 [9(x−2)] ] = log3 [9(x − 2)3 ]
⇔ [log3 [9(x − 2)]].log3 (x − 2) = 2 + log3 (x − 2)3
⇔ [2 + log3 (x − 2)].log3 (x − 2) = 2 + 3log3 (x − 2).
✣➦t
t = log3 (x − 2).
❑❤✐ ✤â ✭✷✳✺✮ ❝â ❞↕♥❣✿
(2 + t)t = 2 + 3t ⇔ t2 − t − 2 = 0 ⇔
•
❱î✐
t = −1
•
❱î✐
t=2
t❛ ❝â
t❛ ❝â
7
log3 (x − 2) = −1 ⇔ x = .
3
log3 (x − 2) = 2 ⇔ x = 11.
✶✺
Footer Page 17 of 128.
t = −1
t=2 .
✭✷✳✺✮
Header Page 18 of 128.
❱➟②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â ♥❣❤✐➺♠
❱➼ ❞ö ✷✳✹
x=
7
3
✈➔
x = 11.
✳
✭✣➲ t❤✐ ✣↕✐ ❤å❝ ❚❤→✐ ◆❣✉②➯♥ ❑❤è✐ ❉ ♥➠♠ ✶✾✾✽✮ ●✐↔✐ ♣❤÷ì♥❣
tr➻♥❤
1
loga (ax).logx (ax) = loga2 ( ), 0 < a = 1.
a
✭✷✳✻✮
●✐↔✐✳
✣✐➲✉ ❦✐➺♥✿
ax > 0
0 < x = 1 ⇔ 0 < x = 1.
❇✐➳♥ ✤ê✐ ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✻✮ ✈➲ ❞↕♥❣
1
(loga a + loga x).(logx a + logx x) = − loga a
2
1
1
+ 1) = − .
⇔ (1 + loga x).(
loga x
2
✣➦t
t = loga x✳
✭✷✳✼✮
❑❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✼✮ ❝â ❞↕♥❣
1
1
(1 + t).( + 1) = − ⇔ 2t2 + 5t + 2 = 0 ⇔
t
2
•
❱î✐
t=−
1
2
t❛ ❝â
1
1
loga x = − ⇔ x = √ .
2
a
•
❱î✐
t = −2
t❛ ❝â
loga x = −2 ⇔ x =
❱➟②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â ♥❣❤✐➺♠
1
x=√
a
✈➔
1
t=− .
2
t = −2
1
.
a2
x=
1
.
a2
✷✳✶✳✷✳✷ ❉ò♥❣ ➞♥ ♣❤ö ❝❤✉②➸♥ ♣❤÷ì♥❣ tr➻♥❤ ❧♦❣❛r✐t t❤➔♥❤ ♠ët
♣❤÷ì♥❣ tr➻♥❤ ✈î✐ ♠ët ➞♥ ♣❤ö ♥❤÷♥❣ ❤➺ sè ✈➝♥ ❝❤ù❛ ①
✶✳ P❤÷ì♥❣ ♣❤→♣ ❝❤✉♥❣✳
❚❛ ❧÷✉ þ ❝â ♥❤ú♥❣ ♣❤÷ì♥❣ tr➻♥❤ ❦❤✐ ❧ü❛ ❝❤å♥ ➞♥ ♣❤ö ❝❤♦ ♠ët ❜✐➸✉
t❤ù❝ t❤➻ ❝→❝ ❜✐➸✉ t❤ù❝ ❝á♥ ❧↕✐ ❦❤æ♥❣ ❜✐➸✉ ❞✐➵♥ ✤÷ñ❝ tr✐➺t ✤➸ q✉❛ ➞♥ ♣❤ö
✤â ❤♦➦❝ ♥➳✉ ❜✐➸✉ ❞✐➵♥ ✤÷ñ❝ t❤➻ ❝æ♥❣ t❤ù❝ ❜✐➸✉ ❞✐➵♥ ❧↕✐ q✉→ ♣❤ù❝ t↕♣✳
❑❤✐ ✤â t❛ ❝â t❤➸ ✤➸ ♣❤÷ì♥❣ tr➻♥❤ ð ❞↕♥❣✿ ✧❝❤ù❛ ➞♥ ♣❤ö ♥❤÷♥❣ ❤➺ sè ✈➝♥
❝❤ù❛ ①✧✳
✶✻
Footer Page 18 of 128.
Header Page 19 of 128.
❚r♦♥❣ tr÷í♥❣ ❤ñ♣ ♥➔② t❛ t❤÷í♥❣ ✤÷ñ❝ ♠ët ♣❤÷ì♥❣ tr➻♥❤ ❜➟❝ ❤❛✐ t❤❡♦
➞♥ ♣❤ö ✭❤♦➦❝ ✈➝♥ t❤❡♦ ➞♥ ①✮ ❝â ❜✐➺t sè
✷✳ ❈→❝ ✈➼ ❞ö
❱➼ ❞ö ✷✳✺✳
∆
❧➔ ♠ët sè ❝❤➼♥❤ ♣❤÷ì♥❣✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
lg2 x − lg x.log2 (4x) + 2log2 x = 0.
✭✷✳✽✮
●✐↔✐✳
✣✐➲✉ ❦✐➺♥
x > 0✳
❇✐➳♥ ✤ê✐ ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✽✮ ✈➲ ❞↕♥❣
lg2 x − (2 + log2 x) lg x + 2log2 x = 0.
✣➦t
t = lg x✱
❦❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ t÷ì♥❣ ✤÷ì♥❣ ✈î✐
t2 − (2 + log2 x).t + 2log2 x = 0
∆ = (2 + log2 x)2 − 8log2 x = (2 − log2 x)2 .
❙✉② r❛
t=2
t = log2 x .
•
❱î✐
t=2
•
❱î✐
t = log2 x
t❛ ❝â
lg x = 2 ⇔ x = 100.
t❛ ❝â
❱➟②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â ❤❛✐ ♥❣❤✐➺♠
❱➼ ❞ö ✷✳✻✳
lg x
⇔ lg x = 0 ⇔ x = 1.
lg 2
x = 100, x = 1.
lg x = log2 x ⇔ lg x =
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
lg2 (x2 + 1) + (x2 − 5). lg(x2 + 1) − 5x2 = 0.
✭✷✳✾✮
●✐↔✐✳
✣➦t
t = lg(x2 +1)✱ ✤✐➲✉ ❦✐➺♥ t ≥ 0 ✈➻ x2 +1 ≥ 1 ♥➯♥ lg(x2 +1) ≥ lg 1 = 0.
❑❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✾✮ t÷ì♥❣ ✤÷ì♥❣ ✈î✐
t2 + (x2 − 5).t − 5x2 = 0
∆ = (x2 − 5)2 + 20x2 = (x2 + 5)2 .
❙✉② r❛
t=5
t = −x2 .
✶✼
Footer Page 19 of 128.
Header Page 20 of 128.
•
❱î✐
t=5
•
❱î✐
t = −x2
t❛ ❝â
√
lg(x2 + 1) = 5 ⇔ x2 + 1 = 105 ⇔ x = ± 99999.
t❛ ❝â
lg(x2 + 1) = −x2 ⇔
❱➟②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â ❜❛ ♥❣❤✐➺♠
lg(x2 + 1) = 0
⇔ x = 0.
x2 = 0
√
x = ± 99999
✈➔
x = 0.
✷✳✶✳✷✳✸ ❉ò♥❣ ➞♥ ♣❤ö ❝❤✉②➸♥ ♣❤÷ì♥❣ tr➻♥❤ ❧♦❣❛r✐t t❤➔♥❤ ♠ët
❤➺ ♣❤÷ì♥❣ tr➻♥❤ ✈î✐ ✷ ➞♥ ♣❤ö
✶✳ P❤÷ì♥❣ ♣❤→♣ ❝❤✉♥❣
❇➡♥❣ ✈✐➺❝ sû ❞ö♥❣ tø ❤❛✐ ➞♥ ♣❤ö trð ❧➯♥ ✭❣✐↔ sû ❧➔ ✉✱ ✈✮✱ t❛ ❝â t❤➸
❦❤➨♦ ❧➨♦ ✤÷❛ ✈✐➺❝ ❣✐↔✐ ♣❤÷ì♥❣ tr➻♥❤ ✈➲ ✈✐➺❝ ①➨t ♠ët ❤➺✱ tr♦♥❣ ✤â✿
•
P❤÷ì♥❣ tr➻♥❤ t❤ù ♥❤➜t ❝â ✤÷ñ❝ tø ♣❤÷ì♥❣ tr➻♥❤ ✤➛✉ ❜➔✐✳
•
P❤÷ì♥❣ tr➻♥❤ t❤ù ❤❛✐ ❝â ✤÷ñ❝ tø ✈✐➺❝ ✤→♥❤ ❣✐→ ♠é✐ q✉❛♥ ❤➺ ❝õ❛ ✉✱
✈✳
✷✳ ❈→❝ ✈➼ ❞ö
❱➼ ❞ö ✷✳✼✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
3 + log2 (x2 − 4x + 5) + 2 5 − log2 (x2 − 4x + 5) = 6.
✭✷✳✶✵✮
●✐↔✐✳
✣✐➲✉ ❦✐➺♥
x2 − 4x + 5 > 0
3 + log2 (x2 − 4x + 5) ≥ 0 ⇔ x2 − 4x + 5 ≤ 25 ⇔ x2 − 4x − 27 ≤ 0
2
5 − log
√ 2 (x − 4x + 5)
ó 0
⇔ 2 − 29 ≤ x ≤ 2 + 29.
✣➦t
u=
v=
3 + log2 (x2 − 4x + 5)
,
5 − log2 (x2 − 4x + 5)
✤✐➲✉ ❦✐➺♥
✶✽
Footer Page 20 of 128.
u, v ≥ 0✳
Header Page 21 of 128.
❑❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✶✵✮ ✤÷ñ❝ ❝❤✉②➸♥ t❤➔♥❤
u = 6 − 2v
⇔
2
2
(6
−
2v)
+
v
=
8
u=2
v=2
u = 6 − 2v
v=2
2
.
u=
14 ⇔
5
v=
14
5
v=
5
u + 2v = 6
u2 + v 2 = 8 ⇔
⇔
•
u = 6 − 2v
5v 2 − 24v + 28 = 0
❱î✐
3 + log2 (x2 − 4x + 5) = 2
u=2
⇔
v=2
5 − log2 (x2 − 4x + 5) = 2
⇔ log2 (x2 − 4x + 5) = 1 ⇔ x2 − 4x + 5 = 2
x=1
⇔ x2 − 4x + 3 = 0 ⇔ x = 3 .
•
❱î✐
3 + log2 (x2 − 4x + 5) = 52
u = 52
⇔
v = 14
5 − log2 (x2 − 4x + 5) = 14
5
5
⇔ log2 (x2 − 4x + 5) = − 71
25
71
2
− 71
25
⇔ x − 4x + 5 = 2
⇔ x2 − 4x + 5 − 2− 25 = 0.✭✈æ
♥❣❤✐➺♠✮
❱➙②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â ❤❛✐ ♥❣❤✐➺♠ ♣❤➙♥ ❜✐➺t✳
❱➼ ❞ö ✷✳✽✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
log2 (x −
x2 − 1) + 3log2 (x +
x2 − 1) = 2.
●✐↔✐✳
✣✐➲✉
✣➦t
2
x −√1 ≥ 0
❦✐➺♥
x − √x2 − 1 > 0 ⇔ x ≥ 1.
2−1 >0
x + x√
u = log2 (x − √ x2 − 1)
.
v = log2 (x + x2 − 1)
◆❤➟♥ ①➨t r➡♥❣
u + v = log2 (x −
= log2 (x −
x2 − 1) + log2 (x +
x2 − 1).(x +
= log2 1 = 0.
✶✾
Footer Page 21 of 128.
x2 − 1)
x2 − 1)
Header Page 22 of 128.
❑❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ✤÷ñ❝ ❝❤✉②➸♥ t❤➔♥❤
u+v =0
u = −v
u = −1
u + 3v = 2 ⇔ 2v = 2 ⇔ v = 1
√
√
x − √x2 − 1 = 12
log2 (x − √x2 − 1) = −1
⇔
⇔
⇔ x = 45 .
2
log2 (x + x2 − 1) = 1
x+ x −1=2
❱➟②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â ♥❣❤✐➺♠
5
x= .
4
✷✳✶✳✷✳✹ ❉ò♥❣ ➞♥ ♣❤ö ❝❤✉②➸♥ ♣❤÷ì♥❣ tr➻♥❤ ❧♦❣❛r✐t t❤➔♥❤ ♠ët
❤➺ ♣❤÷ì♥❣ tr➻♥❤ ✈î✐ ✶ ➞♥ ♣❤ö ✈➔ ♠ët ➞♥ ①
✶✳ P❤÷ì♥❣ ♣❤→♣ ❝❤✉♥❣
❇➯♥ ❝↕♥❤ ❝→❝ ♣❤÷ì♥❣ ♣❤→♣ ✤➦t ➞♥ ♣❤ö tr➯♥✱ t❛ ❝â t❤➸ sû ❞ö♥❣ ♣❤÷ì♥❣
♣❤→♣ ✧❝❤✉②➸♥ ♣❤÷ì♥❣ tr➻♥❤ t❤➔♥❤ ❤➺ ❣ç♠ ❤❛✐ ➞♥ ❧➔ ♠ët ➞♥ ♣❤ö ✈➔ ➞♥
①✧ ❜➡♥❣ ❝→❝❤ t❤ü❝ ❤✐➺♥ t❤❡♦ ❝→❝ ❜÷î❝✿
❇÷î❝ ✶✿
❇✐➳♥ ✤ê✐ ♣❤÷ì♥❣ tr➻♥❤ ✈➲ ❞↕♥❣✿
❇÷î❝ ✷✿
✣➦t
u = ϕ(x)✱
f [x, ϕ(x)] = 0.
t❛ ❜✐➳♥ ✤ê✐ ♣❤÷ì♥❣ tr➻♥❤ t❤➔♥❤ ❤➺✿
u = ϕ(x)
f (x, u) = 0 .
✷✳ ❈→❝ ✈➼ ❞ö
❱➼ ❞ö ✷✳✾✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
log22 x +
log2 x + 1 = 1.
●✐↔✐✳
✣➦t
u = log2 x.
❑❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ✭✷✳✶✶✮ ✤÷ñ❝ ❝❤✉②➸♥ t❤➔♥❤
u2 +
√
u+1=1
✣✐➲✉ ❦✐➺♥
u+1≥0
1 − u2 ≥ 0 ⇔ −1 ≤ u ≤ 1.
√
√
✣➦t v =
u + 1✱ ✤✐➲✉ ❦✐➺♥ 0 ≤ v ≤ 2
✷✵
Footer Page 22 of 128.
s✉② r❛
v 2 = u + 1.
✭✷✳✶✶✮
Header Page 23 of 128.
❑❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ✤÷ñ❝ ❝❤✉②➸♥ t❤➔♥❤ ❤➺
u2 = 1 − v
⇒ u2 − v 2 = −(u + v)
v2 = u + 1
u+v =0
⇔ (u + v)(u − v + 1) = 0 ⇔ u − v + 1 = 0 .
•
❱î✐
v = −u✱
t❛ ✤÷ñ❝
√
1− 5
u=
2
2√ .
u −u−1=0⇔
1+ 5
u=
2
√
1+ 5
❚r♦♥❣ ✤â u =
❦❤æ♥❣ t❤ä❛ ♠➣♥ ✤✐➲✉ ❦✐➺♥ −1 ≤ u ≤ 1✳
2
√
√
√
1− 5
1− 5
1− 5
u=
⇔ log2 x =
⇔x=2 2 .
2
2
•
❱î✐
u − v + 1 = 0✱
2
t❛ ✤÷ñ❝
u +u=0⇔
u=0
u = −1 ⇔
❱➟②✱ ♣❤÷ì♥❣ tr➻♥❤ ❝â ♥❣❤✐➺♠ ❧➔
❱➼ ❞ö ✷✳✶✵✳
log2 x = 0
log2 x = −1 ⇔
√
1− 5
x = 2 2 ,x = 1
✈➔
x=1
1 .
x=
2
x=
1
2
✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
7x−1 = 6log7 (6x − 5) + 1.
●✐↔✐✳
5
6x − 5 > 0 ⇔ x > .
6
y − 1 = log7 (6x − 5).
✣✐➲✉ ❦✐➺♥
✣➦t
❑❤✐ ✤â ♣❤÷ì♥❣ tr➻♥❤ ✤÷ñ❝ ❝❤✉②➸♥ t❤➔♥❤ ❤➺
7x−1 = 6(y − 1) + 1
⇔
y − 1 = log7 (6x − 5)
✷✶
Footer Page 23 of 128.
7x−1 = 6y − 5
.
7y−1 = 6x − 5
✭✷✳✶✷✮
Header Page 24 of 128.
rứ t ữỡ tr ừ t ữủ
7x1 + 6x = 7y1 + 6y.
t số
f (t) = 7t1 + 6t
ỡ tr
f (x) = f (y) x = y.
y1
õ ữỡ tr 7
= 6x 5 õ 7x1 6x + 5 = 0.
x1
t số g(x) = 7
6x + 5
õ ữủ t ữợ
5
D = ( ; +).
6
g (x) = 7x1 . ln 7 6
g (x) = 7x1 .ln2 7 > 0, x D
r g (x) ỗ tr
t ỵ ữỡ tr
g(x) = 0
õ ổ q
tr
t r
g(1) = g(2) = 0
ữỡ tr õ
ú ỵ
x=1
x = 2
ố ợ ữỡ tr rt õ ởt t õ
sax+b = clogs (dx + e) + x +
ợ
d = ac +
e = bc +
ợ ữỡ tr t tỹ ữ s
0
dx + e > 0 .
ay + b = logs (dx + e).
t
ứ õ tỹ ữợ tữỡ tỹ ữ ử
Pữỡ số t
Pữỡ
ị tữ ừ ừ ữỡ ỗ
ỷ ử số ử s õ t t số
Footer Page 24 of 128.
Header Page 25 of 128.
❜✳ ◆➳✉ ♣❤÷ì♥❣ tr➻♥❤ ❝â ❝❤ù❛ t❤❛♠ sè ♠✱ t❛ ❝â t❤➸ ❝♦✐ ♠ ❧➔ ➞♥✱ ❝á♥ ① ❧➔
t❤❛♠ sè✱ s❛✉ ✤â t➻♠ ❧↕✐ ① t❤❡♦ ♠✳
✷✳ ❈→❝ ✈➼ ❞ö
❱➼ ❞ö ✷✳✶✶✳
●✐↔✐ ♣❤÷ì♥❣ tr➻♥❤
lg4 x + lg3 x − 2lg2 x − 9 lg x − 9 = 0.
●✐↔✐✳
x > 0✳
t = lg x✱ t❛ ✤÷ñ❝
✣✐➲✉ ❦✐➺♥
✣➦t
t4 + t3 − 2t2 − 9t − 9 = 0 ⇔ 32 + 3t.3 − t4 − t3 + 2t2 = 0.
✣➦t
u = 3✱
t❛ ✤÷ñ❝
u2 + 3t.u − t4 − t3 + 2t2 = 0.
❚❛ ①➨t ♣❤÷ì♥❣ tr➻♥❤ ❜➟❝ ❤❛✐ t❤❡♦ ✉✱ ✤÷ñ❝
∆ = 9t2 + 4(t4 + t3 − 2t2 ) = (2t2 + t)2 ✱ s✉② r❛
−3t − (2t2 + t)
3 = −t2 − 2t
u = −t2 − 2t
u=
2
⇔
⇔
3 = t2 − t
u = t2 − t
−3t + (2t2 + t)
u=
2
√
1
±
13
⇔ t2 − t − 3 = 0 ⇔ t =
.
2
√
√
√
1 + 13
1 + 13
1 + 13
2
• ❱î✐ t =
t❛ ✤÷ñ❝ lg x =
⇔ x = 10
.
2
2
√
√
√
1 − 13
1 − 13
1 − 13
2
• ❱î✐ t =
t❛ ♥ tö❝ tr➯♥ R+
t❤ä❛ ♠➣♥ ✤✐➲✉ ❦✐➺♥
x
f ( ) = f (x) − f (y), ∀x, y ∈ R+ .
y
✭✸✳✸✮
❳→❝ ✤à♥❤ ❝→❝ ❤➔♠
●✐↔✐✳
✣➦t
x
= t✳
y
❑❤✐ ✤â
x = ty
✈➔
(3.3) ⇔ f (t) = f (ty) − f (y)
⇔ f (ty) = f (t) + f (y), ∀t, y ∈ R+ .
❚❤❡♦ ❦➳t q✉↔ ❝õ❛ ❱➼ ❞ö ✸✳✶✱ t❤➻
f (x) = b ln x, ∀x ∈ R+ , b ∈ R
tò② þ✳
❑➳t ❧✉➟♥✿
f (x) = b ln x, ∀x ∈ R+ , b ∈ R
❱➼ ❞ö ✸✳✸✳
tò② þ✳
❚➻♠ t➜t ❝↔ ❝→❝ ❤➔♠ sè
f :R→R
t❤ä❛ ♠➣♥ ✤✐➲✉ ❦✐➺♥
f (5x) = f (x), ∀x ∈ R
✭✸✳✹✮
●✐↔✐✳
●✐↔ sû ❢ ❧➔ ❤➔♠ sè t❤ä❛ ♠➣♥ ✤➲ ❜➔✐✱ ❦❤✐ ✤â t❛ ❝â ✭✸✳✹✮✳
•
x > 0✱ ✤➦t x = 5u ✭❤❛② u = log5 x✮✳ ❚❤❛② ✈➔♦ ✭✸✳✹✮ t❛ ✤÷ñ❝
f (5u+1 ) = f (5u ), ∀u ∈ R.
u
✣➦t f (5 ) = g(u), ∀u ∈ R✳ ❑❤✐ ✤â g(u + 1) = g(u), ∀u ∈ R. ◆❤÷ ✈➟②
❣ ❧➔ ❤➔♠ sè t✉➛♥ ❤♦➔♥ ❝❤✉ ❦ý ✶ tr➯♥ R✱ ❝❤➥♥❣ ❤↕♥ g(x) = cos(2πx),
∀x ∈ R. ❚❛ ❝â
❑❤✐
f (x) = f (5u ) = g(u) = g(log5 x), ∀x ∈ (0; +∞).
❚❤û ❧↕✐✿ ❱î✐ ♠å✐
x ∈ (0; +∞)✱
❦❤✐ ✤â
f (5x) = g(log5 (5x)) = g(1 + log5 x) = g(log5 x) = f (x).
❱➟②✱ ❦❤✐
✶ tr➯♥
x>0
t❤➻
f (x) = g(log5 x)
R✮✳
✺✼
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✭❣ ❧➔ ❤➔♠ sè t✉➛♥ ❤♦➔♥ ❝❤✉ ❦ý