Đề& đáp án ĐH-CĐ năm 2010./.
Bạn đang xem bản rút gọn của tài liệu. Xem và tải ngay bản đầy đủ của tài liệu tại đây (534.28 KB, 18 trang )
!"#$%(không kể thời gian phát đề)
&'()*+,-./0123
45-/0123
!!"#$%&'(
)*#+#$%&',-./#+0123#4
5'6
#78(29
:+ + <
45-/0123
;0<=>-*
:
'
π
+ + +
÷
=
+
;?0<=>-*9
−
≥
− − +
45-/0123 )@@019
A
B B
C D
B
+ +
=
+
∫
456-/0123*30EFGH3#FGH*!8I>/';JK!LM<N
-8>#+&'/FG!FHOP>'#+&'L!HKGEP!8I>>3!QR0S>
FGH!EP
'
)@+@(30EHLK!(>>T''#<U>S>HK!
EB'
456-/0123&;20<=>-*
: V A
: : W
x x y y
x y x
+ + − − =
+ + − =
∈X
&'(78)-
&9:;<=!>?5@
456&"!
)->R0S>J'#4Oxy'#<U>S>D
9
A+ =x y
!D
9
Ax y− =
;J)#<U>
-Y0Z!QD
/F,D
/'#+G!''>FG!8I>/G[0<=>-*
&')'>FG3D2@\>
!#+F3#4D<=>
)->(I>>'J'#4Oxyz#<U>S>
9
x y z− +
∆ = =
−
!R0S>]9−^A
;J>'#+&'∆!Q]K#+84∆)@(>_K#]K
`
456&""#)*0M&'0a^
z i i= + −
A&9:;<=!>?4!;":
456&B!
)->R0S>J'#4Oxy'>FG1/F3#bA`O`#<U>S>#c8'-8>#+
&'/AB!AC30<=>-*x + y
−
:A)*J'#4#bB!C#+dO−
\- #<U>'#c8'#bC&''>#6
)->(I>>'J'#4 Oxyz#+ AAOAO −!#<U>S>
9
x y z+ − +
∆ = =
)@
(>_A#∆[0<=>-*RM81A,∆/'#+B!C'BCe
456&B-0123&
G;Hfg)
g7@)a
0a^5'6
i
z
i
−
=
−
)*I#8&'0a
z iz+
AC)+
459
)h0#%Xi
:OiA⇔A'
:
O
x
y
→−∞
= −∞
!
x
y
→+∞
= +∞
−∞ A
:
∞
i
A− A
∞
−∞g
V
W
−
)
P#$>- −jOAO
:
OjO>%- AO
:
P#/#//AOAO#/+8/
:
O
:
V
W
−
k
` :x −
OlA⇔
g+8C
O
W
g$%9
]<=>-*#4>'#+&'#$%!-.9
A⇔
A
⇔'>
A
;J
>2&'0<=>-*[Q#78(2:mA'39
O
H#3 8M8<=>#<=>!Q9
: A
> A
:
+ >
= − ≠
+ + <
⇔
:
A
> −
− ≠
+ − <
⇔
:
A
> −
≠
+ <
⇔
:
A
> −
≠
<
⇔
:
A
− < <
≠
45g78(29
Ax
≠
!'
n
'op
])⇔
'
x x x x
x
x
+ + +
=
+
⇔
x x x x
x x
x x
+ + +
=
+
A
:
V
W
−
A
A
W
` `
x x x x
x x x loai hay x
x k hay x k k
⇔ + + = ⇔ + =
⇔ − − = ⇔ = = −
π π
⇔ = − + π = + π ∈ ¢
g78(2qA
G?0<=>-*⇔
A
− − + − +
≥
− − +
rKs8tA⇔
− + >
⇔
mA+
H#3?0<=>-*⇔
− − + − +
uA
⇔
− + ≤ − + +
⇔
A
A
− + + ≥
− + − + ≤
⇔
A
A
− + + ≥
− + ≤
⇔
= −
⇔
{
A
≤ ≤
= −
⇔
{
A
A
≤ ≤
− + =
⇔
A
V
≤ ≤
±
=
⇔
V
−
=
(9
g78(2≥A
L1
v
B
w
9
A
:
x x x
− − + = − − + ≤ − <
÷
⇔
x x x x− ≤ − − +
xA(I>'
y
xmA9
x x
x
x
⇔ − ≤ − + −
÷
x x
x
x
⇔ + − ≤ − +
÷
gz
v
t x x t
x
x
= − ⇒ + = +
'
n
9
x
t
t t
t t t
≥ −
+ ≤ + ⇔
+ ≤ + +
x
A A t t t t− + ≤ ⇔ − ≤ ⇔ =
A
V
` V V
:
V
x x x
x
x
x
x loai
⇔ − = ⇔ + − =
− +
=
− −
⇔ ⇔ = =
− −
=
45&
A A A
x x x
x x
x e e e
I dx x dx dx
e e
+ +
= = +
+ +
∫ ∫ ∫
D
A
A
O
x
I x dx= = =
∫
A
x
x
e
I dx
e
=
+
∫
E
A
x
x
d e
e
+
+
∫
E
A
x
e+
e+
÷
[1
v
C
e+
+
÷
456
E
LHK
V
e
a a a
a a
− − =
÷
#!D⇒[
ELHK
V V
e :
a a
a =
#!
V
:
a a
NC a= + =
)'3'>!8I>FKH!LH\>'8
L
·
·
NCD ADM=
!hHK!8I>L
[h)'39
V V
a a
DC HC NC HC
a
= ⇒ = =
)'3'>EP!8I>/P!(5'>&'HK!E@78'!"_P->'>
EP
L
V {
:
{
a
h
h HC SH a a a
= + = + = ⇒ =
456g9
:
x ≤
gz
v
8O
V v y= −
]-=
y
'
n
88
!!
⇔8p!8
8!!
A⇔uv
L>|
}
''
n
9
A
:
V
V :
x
x y
x
y
≤ ≤
= − ⇔
−
=
]-=
y
'
n
:
V
` : : W x
:
x x x− + + − =
~B
w
'
n
I
w
:
V
: ` :
:
f x x x x= − + + −
-
AO
:
:
• : :
:
f x x x
x
= − −
−
tA
Kz
v
('
w
9
W
f
=
÷
x
w
>
v
D81
w
!'
n
[1
v
v
w
>
v
D81
w
!'
n
&9:;<=!>?5@
456&"
F∈D
⇒F'O
a−
'mA
]Fc8'F⊥D
9
: Ax y a− − =
F∩D
−'O
a−
]FGc8'F⊥D
9
Ax y a+ + =
FG∩D
G
O
a a
− −
÷
÷
:
GF
H
P
K
L
E
O O O
O O 9
ABC
S BA BC a A C
Tâm I IA Pt T x y
∆
= ⇔ = ⇔ = ⇒ − − −
÷ ÷
−
⇒ − = = ⇒ + + + =
÷
÷ ÷
¡
OO∈∆
∈]⇒A⇒⇒OO
KOO
K
`⇔
`⇔`
`⇔±
⇔A'
[hK
OAOOK
OOA
DK
]
A
` `
− −
=
ODK
]
: A
`
`
− + +
=
456&"
^ = + −
+ −
V +
⇔
^ V = −
⇒]M&'0a^
−
A&9:;<=!>?4!;":
456&B
]<=>-*#<U>'FP9``A⇔A
;J>'#+&'C€!FP!QC€9:A8-'>2&'2
{
A
:
− =
+ =
⇒O
-8>#+&'FP⇔
{
P F
P F
: `
: `
= − = − = −
= − = − = −
⇔PpOp
]<=>-*G9A⇔:A
;JGOp:∈G
HP-8>#+&'G⇒p:OOdOp
)'39
d V O = + − −
uuur
!8I>>3!Q
GF ` O A= − +
uuur
⇒V`pAA
⇒
A⇒A'p`
[hG
AOp:O
p:OA'G
p`OO
Op`
∆c8'KpOOp[)]
' OO=
r
O
FK OO = − −
uuuur
⇒
' FK WO OA∧ = − −
r uuuur
⇒DF∆
' FK
:{ : AA V
W
: { :
'
∧
+ +
= =
+ +
r uuuur
r
["GP!8I>>3!Q∆
)'39GP
G
:
=
∆FPG⇒X
V :V
`
W W
+ =
V
]<=>-*E9
^ V+ + + =
456&B
^
−
=
−
π π
− = − + −
÷
⇒
( )
e − = −π + −π
e−
⇒
e e
^ : :
− − +
= = = − −
−
⇒
^ ^ : : : :+ = − − + − +
e − +
⇒
^ ^ e + =
$%&'($%&)*
+, -.)/'$)01$234456443
)70%&)809+#
V
A
!"#$%(khơng kể thời gian phát đề)
'()*+,
45#+Cho hàm s y =
+
+
#
1. Khảo sát sự biến thiên và vẽ đồ thò (C) của hàm số đã cho.
)*#+#<U>S>p,#$%/'#+012FG''>•FG3
D2@\>
•>J'#4
Câu IIAđiểm
;0<=>-*A
;0<=>-*
` : e Ax x x x+ − − + − − =
∈X
45A#+)@@01C
e
x
dx
x x+
∫
456A#+*z>-.'>#78FGFiGii3FG'>3>T''R0S>FiG
!FG\>`A
A
;J;-J>1'>FiG)@+@(z>-.#6!@(@
RM8>/0aD2;FGB'
456A#+(I>1'5'69')*>-%5?&'+8
aK'
'
''
a b c+ +
'(78)-F/0123
GH;I0<J;KL22M>:!"$N-$N:O;A3
&9:;<=!>?5@
456&"A#+
)->R0S>J'#4•'>FG!8I>/F3#bp:O01>->>3F3
0<=>-*VA[0<=>-*#<U>S>GD2@'>FG\>:!
#bF3#4D<=>
)->(I>>'J'#4•^#+FOAOAGAOOAAOAO->#3D<=>!
R0S>]9^A~#%!R0S>FG!8I>>3!QR0S>]!
(>_#+•#R0S>FG\>
456&"A#+)->R0S>J'#4•*h0N0#++8D‚0a^5'69
z i i z− = +
A&9:<=!>?4!":
456&BA#+
)->R0S>J'#4•#+FO
!B0d9
x y
+ =
;Jƒ
!ƒ
8#+
&'dƒ
3#41OK>'#+38>#4D<=>&'#<U>S>Fƒ
!QdOL#+
#a>&'ƒ
c8'K[0<=>-*#<U>-Y>/0'>FLƒ
`
•
p
pp
−
V
)->(I>>'J'#4•^#<U>S>∆9
x y z−
= =
~#%J'#4#+K- -.
'(>_K#∆\>•K
456&BA#+
;b'20<=>-*9
>
:
− =
+ =
∈X
AC)+
'()*+,
45&
{ }
( )
„
… O A
D y x D
x
= − = > ∀ ∈
+
¡
)g9p!*
x x
y y
− +
→− →
= +∞ = −∞
O)L9!*
x
y
→±∞
=
P#$>- −∞O−!−O∞P(I>3-%
pjpj
i
j
pj
]<=>-*#4>'#+&'!#<U>S>p
( ) ( )
: A x
x
x m x m x m
x
+
= − + ⇔ + − + − =
+
!*p(I>>2
]<=>-*x3
e Am m∆ = + > ∀
D8I,/#+FG)'39
( ) ( )
OAB A B B A A B B A
S x y x y x x m x x m
∆
= ⇔ − = ⇔ − + − − + =
( ) ( )
A B A B
m x x m x x⇔ − = ⇔ − =
e
:
m
m
+
⇔ =
:
e :e A : m m m m⇔ + − = ⇔ = ⇔ = ±
45&
A
⇔
A
⇔A
⇔A⇔A
⇔
k
π
π
+
⇔
:
k
π π
+
(∈†
W
