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sd
cmo
DUC
vA DAo
TAo
oAr r,Ar
or
csiNn
rnrlc
1Oi thi cd 01 trang)
Bni 1. <sub>1l,O </sub>diAml
KY
rHr
cHeN
Hec
srr\rH
cr6r
rimr
NAMHQrug
vrON:
roAN
Lop
9
<sub>- </sub>
THCs
Thdi gian ldm bdi; 150
philt
(khdng kd phdt
di)
Ngdy thi:
l0l4l20l9
r)
2)
Rrit gen bi6u thric O <sub>= </sub>
(,.
r..61ffi
ciai
he phucrng
t
inr.,
-
{'G
-!**t2J;
-s=
vJi
L,
-zJi
-t=2Ji
Bni 2. <sub>1l,O </sub>aieml
l)
Chophuongtrinh x2
<sub>-4x=21*-21-*-5 </sub>
(voi
m
ldthamsO;.
fm
titcecdcgiit
1ri cria
m
d}phuong trinh d6 cho c6 b6n nghiQm phdn biQt.
2)
Trong mat phang
vdi
he top iIQ
oxy,
mQt dudrng thang
d
c6 hQ si5 g6c
fr
di qua
di6m tr,I(0;3) vd
cit
parabol (P)
1!
=
x2
tqihai
tli6m A5
B.
Ggi
c,
D
mn luqt ld hinh
chiiSu vu6ng g6c
cta
,\B
16n
tryc Ox.
Vi6t phucrng
trinh
dudrng thang
d,
biiit
hinh
thang ABDC c6 diQn tich bdng 20.
Bni 3. (4,0 di€m)
l)
Tim tilt cbc6c c{p sd nguy6n
(x;il
th6a mdn 2x2 + y2 +2xy
+6x+
4y
<sub>-20.</sub>
2)
Tim tdt circ6c sO t.u nhi6n c6 b6n
cht
s6, bii5t rang s6 OO bang l4p phuong cria t6ng
cac cnu so cua no.
BAi 4. (4,0 diAm)
Cho tli6m A
nim
ngodi ducrng trdn (O). VE hai titip tuyiin AB, AC (B, C ld titip rtii5m)
vd mQt c6t tuyiSn
ADE
cria
(o)
sao cho ADE nam gitra hai tia
Ao
vd
AB;
D,
r
e
(o)
.
Dudmg tharrg qua D vd song song vdi BE cat BC, AB l6n tuqt tpi P, <sub>Q.</sub>
l)
Gqi H ld giao tti€m cfia BC v6i OA. Chrmg minh OEDH
ldtl
giilcnQi tii5p.
2)
Gqi K ld di6m e6i xfmg cria B qua E. Chung minh ba cli6m A, P, K thang hang.
Bii
5. (2,0 didm)
Cho hinh vu6ng
ABCD.
Trcn cric c4nh CB,
CD
tan
tuqt
l6y
cdc
rlicm
<sub>M </sub>
N
(M
S6rg
trung
vdi B
vd
C;
N
kh6ng trung
vdi
C vd D ) sao cho
ffi:+So.
Chimg
minh
'
rlng dulng ch6o
BD
chia tam giSc
AMN
thanh hai phAn c6 diQn tfch bAng nhau.
BAi 6. (2,0 di€m)
Cho a, b,
c
ldc6c sO thgc ducrng th6a mdn a + b +
c=
3. Chimg minh rdng
a+l b+l
<sub>r.]r.]--2</sub>
c+l
b2
+l'
c'
+l'
a2
+l
o
Th{ sinh kh6ng duqc s* dttng tdi li€u vd mdy tinh cim tay.
o
Cdn b0 coi thi khdng gidi thich gi thAm.
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