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<b>BAUTI/TAICHfNH </b>
<i><b>^ </b></i>
<i>tuy^t ddi Id bao nhieu so vdi BDS so sdnh. Mat khiic, viec tinh todn cdc liicfng gidm tdctng </i>
<i>ddi cUng khong co y nghia thdc tien. Td do, toe gid de xudt sd dung cdng thdc khde thay </i>
<i>the cho cong thdc diige dp dung trong Phu lue 03, Tieu chuan 07 ve phdctng phdp so sdnh </i>
<i>trong thdm dinh gid do Bg Tdi chinh ban hdnh. </i>
De tham dinh gia BDS, phttdng p h a p dttdc stt
dung phd bien n h a t h i e n nay la phUdng p h a p
vdi gia giao dich la B = 11,5 trieu ddng/m^
Gia stt BDS so s a n h cd hai diem k h a t biet so
vtti BDS t h a m dinh:
- Yeu td thtt n h a t la dd rpng ngo: yeu td dp
rdng ngo cua BDS so s a n h tdt hdn BDS t h a m
dinh nen lam cho gia ban cua BDS so s a n h
cao hdn BDS t h a m dinh: ve sd tttdng ddi la
10%, sd tuyet ddi la A*10% (1)
- Yeu td thtt hai la dien tich 16 dat: yeu td dien
tieh 16 dat cua BDS so sanh tdt hdn BDS t h a m
Gia stt can t h a m d i n h mdt Id d a t t r d n g ma
gia tri thi trttttng Im^ la A (la mttc gia chtta
<i>biet, t h a m dinh vien can dde t i n h ) , qua thu </i>
thap thong tin t r e n t h i trttttng, t h a m d i n h
vien tim dttttc mdt BDS tttdng ttt cd t h e so
sdnh dttdc, vtta dttttc giao dich t r e n thi trttdng
Theo httdng dSn d Phu luc 03, Tieu t h u a n 07
t u a Bd Tai chinh, qua t r i n h dieu t h i n h phai
t i n h toan dttdt stt k h a t biet tiia mdi mot yeu td
lam cho gia tri ciia BDS t h a m dinh gia khac
biet bao nhieu so vdi gia ban cua BDS so s a n h .
O day, ehung ta can lam ro mpt diem h e t sttc
<b>I l l DAU Tir TAI CHINH </b>
quan trpng, k h i t i e n h a n h dieu c h i n h mdt yeu
to, t a p h a i cd d i n h cac yeu to t d n lai, coi nhtt
k h d n g cd stt k h a c biet. Nhttng cac yeu t d k h a c
se cd d i n h nhtt t h e nao? Vi qua t r i n h dieu c h i n h
t u a n theo nguyen tttc, lay BDS t h a m d i n h gia
- Do yeu td' dd rdng ngo, gia t u a BDS so s a n h
eao h d n BDS t h a m dinh la 10%. Vi yeu td dien
t i t h Id dat dttdt t d dinh nhtt t r a n g t h a i t u a BDS
t h a m dinh, n e n gia t u a BDS so s a n h theo gia
dinh nay se khdng phai la B = 1.150 trieu ddng
ma la B I (B chiu a n h httdng bdi hai n h a n td dp
rdng ngo va dien tich 16 dat, cdn B I chiu a n h
httttng cua moi n h a n to dp rpng ngo). Do dd:
B I = A + A*10% = A ( l -H 10%)
Suy ra, A = Bl/(1+10%) = B 1 * [ 1 - H 1 / ( 1 - H 1 0 % ) - 1]
Nhtt vay, do yeu td' dp rdng ngo, gia eua BDS
t h a m dinh (A) giam so vtti gia eua BDS so
s a n h (BI - xet t r o n g t r a n g t h a i chi cd mot stt
k h a c biet la n h a n t d dp rpng ngo) la:
H- Ve sd tttdng ddi:
[1/(1 -H 10%)] - 1 = -0,091 (4a)
H- Ve Ittdng tuyet ddi:
Bl*[l/(1-H 10%)-1]=B1*(-0,091) (4b)
- Do yeu t d dien tich 16 dat, gia cua BDS so
s a n h cao h d n BDS t h a m d i n h la 5%. Vi yeu
<i>td dp rdng ngo d\iac cd d i n h nhtt t r a n g t h a i </i>
t u a BDS t h a m dinh, n e n gia tiia BDS so s a n h
theo gia dinh n a y se k h 6 n g p h a i la B = 1.150
trieu ddng m a la B2 (B chiu a n h httdng bdi h a i
n h a n td dp rpng ngo va dien tieh 16 dat, cdn
B2 chiu a n h huttng cua mdi n h a n t d dien tieh
16 dat). Do do: B2 = A -h A*5% = A ( l -i- 5%)
Suy r a , A = B2/(l + 5%) = B2*[l-h 1/(1-H 5%) - 1]
Nhtt vay, do yeu t d dien tich 16 dat, gia cua
BDS t h a m dinh (A) giam so vtti gia cua BDS
so s a n h (B2 - xet t r o n g t r a n g t h a i chi cd m d t
stt k h a t biet la n h a n t d dien tich 16 d a t ) la:
-(- Ve sd tttttng ddi: |
[ 1 / ( 1 - H 5 % ] - 1 = -0,048 (5a)
H- Ve Ittttng t u y e t ddi :
B 2 * [ l / ( l + 5 % ) - 1] = B2*(-0,048) (5b)
Qua p h a n t i t h d t r e n , chttng t a ed t h e t i n h toan
dttdt, do stt k h a o b i e t eua mdi n h a n to, gia tua
BDS t h a m d i n h g i a m m o t so' tttttng ddi so vdi
gia t u a B D S so s a n h l a bao n h i e u p h a n tram
Doi chieu vtti httttng d i n t r o n g P h u luc 03,
Tieu c h u a n 07 t u a Bp T a i t h i n h , gia t r i BDS •
t h a m d i n h g i a m m p t Ittdng so vtti gia cua BDS
so s a n h la (theo t a t h t i n h cua Bp T a i chinh):
- Do stt k h a t b i e t eua dp r d n g n g o :
+ Lttdng g i a m tttdng ddi:
[1/(1-Hl0%)]-1= -0,091 (6a)
H- Lttdng g i a m t u y e t ddi:
B*[iy(l+10%)-l]=ll,5*(-0.091)=-1.0465trieu/m2
(6b)
- Do stt k h a t b i e t t u a d i e n t i e h Id d a t :
-I- Lttdng g i a m tttdng ddi:
[ l / ( l + 5 % ) ] - l = -0,048 (7a)
+ Lttdng g i a m t u y e t ddi:
B*[iy(l + 5%)-l] =ll,5*(-0,048)=-0,552 trieu/m^
(7b)
- T d n g lttdng g i a m tttdng ddi do a n h httdng
bdi h a i n h a n td':
[1/(1 + 10%)] + [1/(1 + 5%)] - 2 = -0,139 (8)
- T d n g Ittdng g i a m t u y e t ddi do a n h httttng bdi
h a i n h a n td':
-1,0465 - 0,552 = - 1.5985 t r i e u d d n g (9)
- Gia b a n tttte t i n h 1 m^ d a t cua BDS t h a m dinh:
A = 11,5*(1 - 0,139) = 9.9015 trieu ddng/m^ (10)
Ro r a n g each t i n h t o a n t h e o P h u luc 03 la
k h d n g c h i n h xac. Vi each t i n h n a y khdng
t u a n t h e o n g u y e n t a c l a k h i x e t stt k h a c biet
t u a m p t yeu td, t a p h a i cd d i n h cac yeu td
k h a c k h 6 n g ddi t h e o t r a n g t h a i cua BDS
t h a m d i n h , do v a y ke't qua (6b) v a (7b) khac
vtti (4b) va (5b), la ke't qua p h a n a n h stt co'
dinh cua t a t yeu t d k h a t k h i xet r i e n g mdt
yeu td. Mat k h a t cdng thttc (8) dttng de t i n h
tdng Ittdng giam tttdng ddi (gpi la t d n g ty le
dieu chinh) la k h 6 n g td y nghia, vi ttt (4b) va
(5b), 1% cua BI khac 1% cua B2 va do dd chttng
ta khong the cdng hai gia tri nay lai vtti nhau.
(gpi la mttc dieu chinh theo Phu luc 03) thi khdng
t i n h dttdc vi thieu thong tin t a t gia tri B I va B2.
Viec tinh t a t mttc dieu t h i n h nhtt t6ng thttt (6b)
va (7b) la kh6ng t h i n h xac.
- C6ng thttc (9) dttdt stt dung de tinh tdng Ittdng
giam tuyet ddi (gpi la tdng dieu t h i n h thuan) la
khong t h i n h xat vi tdng thttt (9) dttdt suy ra ttt
tdng thttc (6b) va (7b).
- Tdng Ittdng giam tttdng ddi cua gia tri BDS
t h a m dinh so vdi gia tiia BDS so sanh dttdt tinh
nhtt tdng thttt (8) la khong chinh xat, vi ttt (4b)
va (5b), 1% cua B I khac 1% cua B2 va do dd
thttng ta kh6ng the tong hai gia tri tttdng ddi
nay lai vtti nhau dttdt. Thttc te, ttt cdng thttc (3)
ta tinh dttdc Ittdng giam tttdng ddi la: [1/(1-1- 10%
<i>-I- 5%) - 1] - -0,130, day la each tinh chinh xac. </i>
Tom lai, each tinh theo httdng dan cua Phu luc
03, Tieu chuan 07 vtta kh6ng chinh xac, lai vtta
phttc tap va khd hieu. Do vay, tac gia de xua't,
de ttdc tinh gia tri cua BDS tham dinh, nen stt
dung c6ng thttc (3) vi cong thttc nay c6 UU diem la
chinh xac, each tinh toan ddn gian va de hieu"
Tai lieu tham khao
<i>;. B6 Tdi chinh ( 2005, 2008), Tieu chudn thdm dinh gid </i>
<i>so 06 - Nhiing nguyen tdc kinh te chi phdi hoat dong thdm </i>
<i>dinh gid, ban hdnh theo Quyet dinh sd 77/2005/QB-BTC; </i>
<i>Tieu chudn so 07- Phuang phdp so sdnh, ban hdnh theo </i>
<i>Quyet dinh so 129/2008/QB-BTC. </i>
<i>2. Bo Tdi chinh (2005, 2008), Tdi lieu boi duang vi thdm </i>
<i>dinh gid, lUu hdnh noi bo. </i>
<i>3. Cdc vdn bdn phdp quy: Phdp lenh gid 2002, Luat Bdt </i>
<i>dai 2003 </i>
<i>4. Nguyen Minh Hodng (2008), Binh gid tdi sdn vd gid tri </i>
<i>doanh nghiep, Nhd xudt bdn Lao dgng - Xd hgi. </i>
<i>5. Dodn Vdn Trudng (1999), Cdc phuang phdp thdm dinh gid </i>
<i>bdt dgng sdn, Nhd xudt bdn Khoa hgc - Ky thuat Hd Ngi. </i>
<i>6. Tieu chudn thdm dinh gid quoc te, IVSC, 2003 vd 2005 </i>
Ke't luan
- Co the tinh dttdc stt khac biet cua mdi mot
nhan td lam cho gia tri cua BDS t h a m dinh giam
bao nhieu phan t r a m so vtti gia ban cua BDS so
sanh (gpi la ty le dieu chinh theo each gpi trong
Phu luc 03) nhttng lttdng giam ve m a t tuyet ddi