Khám phá kỹ thuật giải quyết nhanh gọn đề thi Đại học môn Hóa học: Phần 2

O CHl/dNG VI

CfiC DE THi t>6l HOC THfiM KH^O
DE SO 1
D E T H I T U Y E N S I N H D A I H O C N A M 2013
M o n t h i : H O A , k h o i A - M a de : 374
Cho biet nguyen tii khoi cua cac nguyen t o ' :
H = 1; C = 12; N = 14; O = 16; Na = 23; M g = 24; A l = 27; S = 32; CI = 35,5;
P = 31; Ca = 40; Cr = 52, Fe - 56; Cu ^ 64; Zn = 65; Br = 80; Ag=108; Ba = 137.
I. P H A N C H U N G C H O T A T C A T H I S I N H
(40 cdu, tic cdu 1 den cdu 40)
C a u 1: H o n hcfp X gom 3,92 gam Fe, 16 gam Fe203 va m gam A l . Nung X d
nhiet do cao trong dieu kien khong c6 khong k h i , thu diioc h6n hop chat ran
Y. Chia Y thanh hai phan bang nhau. Phan mot tac dung vcri dung dich
H2SO4 loang (dii), t h u diicfc 4a mol k h i H2. Phan hai phan ufng vdri dung dich
NaOH duf, t h u diicfc a mol k h i H2. Biet cac phan ufng deu xay r a hoan toan.
Gia t r i cua m la
A. 5,40

B. 3,51

C. 7,02

D . 4,05

C a u 2: Trong dieu kien thich hop, xay ra cac phan ufng sau
(a) 2H,S04 + C ^ 2SO2 + CO, + 2H2O
(b) H2SO4 + Fe(0H)2 ^ FeS04 + 2H2O
(c) 4H0SO4 + 2FeO ^ Feo(SO.,)a + SO2 + 4H2O
(d) 6H2SO4 + 2 F e ^ Fe2(S04)3 + 3SO2 + 6H2O

Trong cac phan ufng t r e n , phan ufng xay ra vdi dung dich H2SO4 loang la
A. (a)

_

B. (c)

C. (b)

D . (d)

C a u 3: Trong mot b i n h k i n chufa 0,35 mol C2H2; 0,65 mol H2 va mot i t bot N i .
Nung nong b i n h mot thcri gian, t h u difdc h6n hop k h i X c6 t i khoi so vdri H2
bang 8. Sue X vao li/gng diT dung dich AgNOs trong N H 3 den phan ufng hoan
toan, t h u dtfgc h6n hgp k h i Y va 24 gam ket tua. H 5 n hgp k h i Y phan ufng
vCra du vdi bao nhieu mol Br2 trong dung dich?
A. 0,10 mol.

B. 0,20 mol.

C. 0,25 mol.

D . 0,15 mol

C a u 4: O dieu kien thich hgp xay r a cac phan ufng sau:
(d) 3C + 4A1 -> A I 4 C 3

(c) C + CO2 -> 2 C 0

(b) C + 2H2

(a) 2C + Ca

CaC2

CH4

128


Trong cac phan iJng tren, t i n h khuf cua cacbon the hien d phan ufng
A. (c)

B. (b)

C. (a)

D. (d)

Cau 5: Len men m gam glucozo de. tao thanh ancol etyhc (hieu suat phan ufng
bang 90%). Hap thu hoan toan liiong k h i CO2 sinh ra vao dung dich Ca(0H)2
dif, thu duoc 15 gam ket tiia. Gia t r i ciia m la
A. 15,0
B. 18,5
C. 45,0
D. 7,5
Cau 6: H 6 n hop X gom Ba va A l . Cho m gam X vao nvidc dii, sau k h i cac phan
ijfng xay ra hoan toan, t h u ducfc 8,96 Ht k h i H2 (dktc). M a t khac, hoa t a n
hoan toan m gam X bang dung dich NaOH, thu duoc 15,68 l i t k h i H2 (dktc).
Gia t r i cua m la

A. 29,9
B. 24,5
C. 19,1
D. 16,4
Cau 7: Khol Itfcmg Ag thu dugfc k h i cho 0,1 mol C H 3 C H O phan ufng hoan toan
vdi li/ong dtf dung dich AgNOa trong NH3, dun nong la
A. 10,8 gam
B. 43,2 gam
C. 16,2 gam '
D. 21,6 gam
Cau 8: Cho hot Fe vao dung dich gom AgNOs va Cu(N03)2. Sau k h i cac phan
ufng xay ra hoan toan, thu duoc dung dich X gom hai muo'i va chat ran Y
gom hai k i m loai. H a i muo'i trong X va hai k i m loai trong Y Ian iLfgt la:
A. Cu(N03)2; Fe(N03)2 va Cu; Fe
B. Cu(N03)2; Fe(N03)2 va Ag; Cu
C. Fe(N03)2; Fe(N03)3 va Cu; Ag
D. Cu{N03)2; AgNOg va Cu; Ag
Cau 9: Cho 100 m l dung dich amino axit X nong do 0,4M tac dung viTa dij vdi
80 m l dung dich NaOH 0,5M, thu ducfc dung dich chufa 5 gam muoi. Cong
thufc cua X la
A. NH2C3H6COOH

B. NH2C3H5(COOH)2

C. (NH2)2C4H7COOH

D. N H 2 C 2 H 4 C O O H

Cau 10: Cho 1,37 gam Ba vao 1 l i t dung dich CUSO4 0,01 M . Sau k h i cac phan
ufng xay ra hoan toan, khoi liicfng ket tua thu di/oc la

A. 3,31 gam

B. 2,33 gam

.

C. 1,71 gam

D. 0,98 gam

Cau 11: K h i di/cfc chieu sang, hidrocacbon nao sau day t h a m gia phan ufng the
vdi clo theo t i le mol 1 : 1 , thu diioc ba dan xuat monoclo la dong phan cau
tao cua nhau?
A. isopentan.

B. pentan.

C. neopentan.

D. butan.

Cau 12: Oxi hoa hoan toan 3,1 gam photpho trong k h i oxi duf. Cho toan bo san
pham vao 200 m l dung dich NaOH I M den k h i phan ufng xay ra hoan to^n,
thu di/gc dung dich X. Khoi liiong muo'i trong X la
A. 14,2 gam
B. 11,1 gam
C. 16,4 gam
D. 12,0 gam
Cau 13: Cho X la hexapeptit Ala-Gly-Ala-Val-Gly-Val va Y la tetrapeptit GlyAla-Gly-Glu. Thijy phan hoan toan m gam h 6 n hop gom X va Y t h u difoc 4
amino axit, trong do c6 30 gam glyxin va 28,48 gam alanin. Gia t r i cua m la

A 77,6
B. 83,2
C. 87,4
D. 73,4

129


C a u 14: O t r a n g t h a i ccf b a n , cau h i n h electron cua n g u y e n tuf N a ( Z = 11) l a
A . Is22s22p'^3s-

B. Is22s22p''3s'

C. ls^2s"2p''3s^

D . Is^2s22p'=3s^

C a u 15: H6n h a p X chufa ba a x i t cacboxylic deu don chufc, m a c h h d , gom m o t
a x i t no va h a i a x i t k h o n g no deu c6 m o t l i e n k e t doi (C=C). Cho m gam X
tac d u n g viTa du vori 150 m l d u n g d i c h N a O H 2 M , t h u dirge 25,56 gam h o n
h o p muo'i. D o t chay h o a n t o a n m g a m X , h a p t h u t o a n bo s a n p h a m chay
b k n g d u n g d i c h N a O H duf, kho'i liJgng d u n g d i c h t a n g t h e m 40,08 gam. Tong
k h o i lu'gng cua h a i a x i t cacboxylic k h o n g no t r o n g m g a m X l a
A . 15,36 g a m

B. 9,96 g a m

C. 18,96 g a m

D . 12,06 g a m

C a u 16: D u n g d i c h a x i t axetic p h a n ufng diigc vdri t a t ca cac c h a t t r o n g day nao
sau day?
D . N a O H , Cu, N a C l

C. N a O H , N a , CaCOg

B. N a , CuO, H C l

A . N a , N a C l , CuO

C a u 17: T e n t h a y t h e (theo l U P A C ) cua (CH3)3C-CH2-CH(CH3)2

la

D. 2,4,4-trimetylpentan

C. 2 , 4 , 4 , 4 - t e t r a m e t y l b u t a n

B. 2 , 2 , 4 , 4 - t e t r a m e t y l b u t a n

A. 2,2,4-trimxetylpentan

C a u 18: T o n i l o n - 6 , 6 l a san p h a m t r u n g ngUng cua
A. etylen glicol va hexametylendiamin
B. a x i t a d i p i c v a g l i x e r o l
C. a x i t a d i p i c v a e t y l e n g l i c o l .

D . a x i t adipic v a h e x a m e t y l e n d i a m i n

C a u 19 : HQn hop X gom N a , B a , Na20 va BaO. Hoa t a n hoan toan 21,9 gam X
vao nxidc, t h u diigc 1,12 l i t k h i H2 (dktc) va dung dich Y , t r o n g do c6 20,52 gam
Ba(0H)2. H a p t h u h o a n t o a n 6,72 l i t k h i CO2 (dktc) vao Y , t h u di/gc m gam ket
tiia. G i a t r i ciia m l a
A. 23,64

B. 15,76

C. 21,92

D . 39,40

C a u 20: H g p c h a t X c6 t h a n h p h a n g o m C, H , O chufa v o n g benzen. Cho 6,9
g a m X vao 360 m l d u n g dich N a O H 0,5 M (diT 2 0 % so vdti li/gng can phan
ufng) d e n p h a n ufng h o a n t o a n , t h u difgc d u n g dich Y . Co can Y t h u dugc m
g a m chat r a n k h a n . M a t k h a c , dot chay h o a n t o a n 6,9 gam X can vi^a du
7,84 l i t O2 ( d k t c ) , t h u dirge 15,4 g a m CO2. B i e t X c6 cong thufc p h a n t i f t r i m g
v d i cong thufc don g i a n n h a t . G i a t r i ciia m. l a
A . 13,2

B. 12,3

C. 11,1

D . 11,4

C a u 21: B i e t X l a a x i t cacboxylic don chufc, Y l a ancol no, ca h a i chat deu mach
h o , CO Cling so n g u y e n t i r cacbon. D o t chay h o a n t o a n 0,4 m o l h o n hgp gom X
v a Y ( t r o n g do so m o l cua X Idm h o n so' m o l cua Y ) can vira du 30,24 l i t k h i
O2, t h u dirge 26,88 l i t k h i CO2 va 19,8 g a m H-.O. B i e t t h e t i c h cac k h i do d

dieu k i e n t i e u c h u a n . Kho'i liTgng Y t r o n g 0,4 m o l h6n h g p t r e n l a
A . 17,7 g a m

B . 9,0 g a m

C. 11,4 g a m

D . 19,0 g a m

130


Cau 22: Tien hanh ca!c t h i nghiem sau
(a )Suc k h l etilen vao dung dich KMn04 loang.
(b) Cho hcfi ancol etylic di qua hot CuO nung nong.
(c) Sue k h i etilen vao dung dich Br2 trong CCI4.
(d) Cho dung dich glucozo vao dung dich AgNOa, trong N H 3 di/, dun nong.
(e) Cho FeoOs vao dung dich H2SO4 dac, nong.
Trong cac t h i nghiem tren, so' t h i nghiem c6 xay ra phan ufng oxi hoa - khijf la
A. 5.

B. 2

C. 3

D. 4

Cau 23: Cho so do cac phan ijfng:
X + NaOH - ^ - ^

Y + Z

X + NaOH (ran)
T
Q + H2O —

> T + P

) Q + H2
>

Z

Trong so do tren, X va Z Ian liicft la
A. HCOOCH-CHa va HCHO

B. CH3COOC2H5 va C H 3 C H O

C. C H 3 C O O C H - C H 2 va C H 3 C H O

D. C H 3 C O O C H = C H 2 va H C H O

Cau 24: t f n g vdri cong thiifc phan tuf C4H10O c6 bao nhieu ancol la dong phan
cau tao cua nhau?
A. 3

B. 5

C. 4

D. 2

Cau 25: Cho m gam Fe vao b i n h chiJa dung dich gom H2SO4 va H N O 3 , thu
difgc dung dich X va 1,12 l i t k h i NO. Them tiep dung dich H2SO4 dif vao
binh thu dtfctc 0,448 l i t k h i NO va dung dich Y. Biet trong ca hai tri/cfng hop
NO la san phan khijf duy nhat, do d dieu kien tieu chuan. Dung dich Y hoa
tan vifa het 2,08 gam Cu (khong tao thanh san pham khiif ciia N*^). Biet cac
phan uTng deu xay ra hoan toan. Gia t r i cua m la
A. 2,40
B. 4,20
C. 4,06
D. 3,92
Cau 26: Lien ket hoa hoc gifla cac nguyen tijf trong phan tii H C l thuoc loai lien ket
A. cong hoa t r i khong cifc

B. ion

C. cong hoa t r i c6 cifc

D. hidro

Cau 27: Thiic hien cac t h i nghiem sau
(a) Cho dung dich H C l vao dung dich Fe(N03)2
(b) Cho FeS vao dung dich H C l .
(c) Cho Si vao dung dich NaOH dac.
(d) Cho dung dich AgN03 vao dung dich NaF.
(e) Cho Si vao b i n h chijfa k h i F2.
131

(f) Sue k h i S02vao dung dich H2S.
Trong cac t h i nghiem tren, so t h i nghiem xay ra phan ijfng la
A. 6

B. 5

C. 4

D. 3

C a u 28: Hoa tan hoan toan m gam A l bang dung dich HNO3 loang, thu di/oc
5,376 l i t (dktc) hon hop k h i X gom N2, N2O va dung dich chOfa 8m gam
muoi. T i khol ciia X so vdi H2 bang 18. Gia t r i cua m la
A. 17,28
B. 19,44
C. 18,90
D. 21,60
C a u 29: Cho h6n hop X gom 0,01 mol A l va a mol Fe vao dung dich AgNOa
den k h i phan ufng hoan toan, thu diiOc m gam chat ran Y va dung dich Z
chufa 3 cation k i m loai. Cho Z phan ufng vdri dung dich NaOH d\i trong dieu
kien khong c6 khong k h i , t h u di/oc 1,97 gam ket tua T. Nung T trong khong
k h i den khol Itfcfng khong doi, thu difOc 1,6 gam chat ran chi chufa mot chat
duy nhat. Gia t r i cua m la
A. 8,64

B. 3,24

C. 6,48

D. 9,72

C a u 30: Chat nao sau day k h o n g tao ket tua k h i cho vao dung dich AgNOs?
A. H C l

B. K3PO4

C. K B r

D. H N O 3

C a u 31: Phenol phan Ofng dufoc vdri dung dich nao sau day?
A. NaCl.

B. K O H .

C. NaHCOg.

D. H C l .

C a u 32: Cho cac can bang hoa hoc sau:
(a) H2 (k) + h (k) <

> 2 H I (k).

(c) 3H2 (k) + N2 (k) <

(b) 2NO2 (k) <

> N2O4 (k).

> 2NH3 (k). id) 2SO2 r^;+02 (k) <

> 2SO3 (k).

0 nhiet do khong ddi, k h i thay doi ap suat chung cua moi he can bang, can
bang hoa hoc nao cr tren k h o n g bi chuyen dich?
A. (a).

.

B. (c).

C. (b).

D. (d).

C a u 33: K i m loai sat tac dung vdri dung dich nao sau day tao ra muoi saUH)?
A.

B. HNO3 dac, nong, di/.

CUSO4.

C. MgSOn.

_

D. H2SO4 dac, nong, dii.

C a u 34: Hoa t a n hoan toan 1,805 gam hon

dung dich H C l , thu diioc 1,064 l i t k h i
1,805 gam h5n hop tren bang dung dich
k h i NO (san pham khtjf duy nhat). Biet
tieu chuan. K i m loai X la
A. A l .

B.Cr.

hop gom Fe va k i m loai X vao bkng
H2. Mat khac, hoa tan hoan toan
H N O 3 loang (dif), thu dLfOc 0,896 lit
cac the tich k h i deu do d dieu kien

C. Mg.

D. Zn.

C a u 35: Cac chat trong day nao sau day deu tao ket tua k h i cho tac dung vdi
dung dich AgNOs trong N H 3 dii, dun nong?
A. vinylaxetilen, glucozo, andehit axetic.
132


B. glucozcf, d i m e t y l a x e t i l e n , a n d e h i t axetic.
C. v i n y l a x e t i l e n , glucozcf, d i m e t y l a x e t i l e n .
D. v i n y l a x e t i l e n , glucozo, a x i t pr opion ic .
Cau 36: T i e n h a n h d i e n p h a n dung d i c h chijfa m g a m h o n hap C U S O 4 v a N a C l
(hieu suat 100%, dien ciic trcf, m a n g ngan xop), den k h i nifcfc b ^ t dau h i d i e n
phan 0 ca h a i dien ciic t h i ngCtog dien p h a n , t h u dJcfc dung d i c h X v a 6,72 l i t
khi (dktc) a anot. D u n g dich X hoa t a n t o i da 20,4 g a m AI2O3. G i a t r i cua m l a

A. 25,6.

B . 23,5

C. 5 1 , 1 .

D . 50,4.

Cau 37: C h a t nao sau day k h i d u n n o n g vdri d u n g d i c h N a O H t h u di/oc san
pham CO a n d e h i t ?
A. CH3-COO-C(CH3)=CH2.

B.

C. CH2=CH-COO-CH2-CH3.

D . C H3- C O O - C H2 - C H= C H 2.

CH3-COO-CH=CH-Cir3.

Cau 38: D u n g d i c h nao sau day l a m p h e n o l p h t a l e i n d o i mau?
A. g l y x i n .

B. m e t y l a m i n .

C. a x i t axetic.

D. alanin.

Cau 39: Cho 0,1 m o l t r i s t e a r i n ((Ci7H35COO)3C3H5) tac d u n g h o a n t o a n v d i

dung d i c h N a O H d i i , d u n n o n g , t h u diTcfc m g a m g l i x e r o l . G i a t r i cua m l a
A. 27,6.

B . 4,6.

C. 14,4.

D . 9,2.

Cau 40: Day cac chat deu tac d u n g difoc vdri d u n g d i c h Ba(HC03)2 l a :
A. HNO3, Ca(0H)2 v a Na2S04.

B . HNO3, C a ( 0 H ) 2 v a K N O 3 .

C. HNO3, N a C l v a Na2S04.

D . N a C l , NagSO^ v a Ca(OH)2.

II. P H A N R I E N G (10 c a u )
Thi sink chi diic/c lam mot trong

hai phan

(Phan

A hoac

A. T h e o chifofng t r i n h C h u a n (10 cdu, tii cau 41 den cau

Phan

B)

50)

Cau 41: Cho X v a Y l a h a i a x i t cacboxylic m a c h h o , c6 cCing so' n g u y e n tii
cacbon, t r o n g do X d o n chufc, Y h a i chufc. C h i a h 5 n h o p X v a Y t h a n h h a i
phan b a n g n h a u . P h a n m o t tac d u n g h e t vdri N a , t h u di/gc 4,48 l i t k h i H2
(dktc). D o t chay h o a n t o a n p h a n h a i , t h u diigc 13,44 l i t k h i CO2 ( d k t c ) . P h a n
t r a m kho'i lufcfng cua Y t r o n g hSn h a p l a
A. 28,57%

B. 57,14%

C. 8 5 , 7 1 %

D . 42,86%

Cau 42: D o t chay h o a n t o a n h o n h a p X g o m 0,07 m o l m o t ancol da chufc va
0,03 m o l m o t ancol k h o n g no, c6 m o t l i e n k e t d o i , m a c h h d , t h u di/gc 0,23
mol k h i CO2 v a m g a m H2O. G i a t r i ciia m l a
A. 5,40 B . 2,34

C. 8,40

D . 2,70

Cau 43: D a y cac chat deu c6 M f e n a n g t h a m g i a p h a n ufng t h i j y p h a n t r o n g
dung d i c h H2SO4 d u n n o n g l a :
A. fructoza, saccarozo v a t i n h hot

B . saccaroza, t i n h b o t v a x e n l u l o z a

C. glucoza, saccaroza v a fructoza

D . glucoza, t i n h hot v a x e n l u l o z a
133


C a u 44: Cho cac cap oxi hoa - khuf di/cJc sSp xep theo thiif t i i tSng dan t i n h oxi
hoa ciia cac ion kirn loai: AI^VAl; Fe^^/Fe, Sn^VSn; Cu^VCu. Tien hanh cac
t h i nghiem sau:
(a) Cho sat vao dung dich dongdl) sunfat.
(b) Cho dong vao dung dich nhom sunfat.
(c) Cho thiec vao dung dich dongdl) sunfat.
(d) Cho thiec vao dung dich sat(II) sunfat.
Trong cac t h i nghiem tren, nhijfng t h i nghiem c6 xay ra phan I'tag la:
A. (b) va (c)

B. (a) va (c)

C. (a) va (b)

D . (b) va (d)

C a u 45: Cho cac phat bieu sau: .
(a) Trong bang tuan hoan cac nguyen to hoa hoc, crom thuoc chu k i 4, nhom VIB.
(b) Cac oxit cija crom deu la oxit bazcf.
(c) Trong cac hop chat, so' oxi hoa cao nhat ciia crom \k +6
fd) Trong cac phan Ofng hoa hoc, hop chat crom(III) chi dong vai tro chat oxi hoa.

(e) K h i phan iJfng vdi k h i CI2 dii, crom tao ra hcrp chat crom(III).
Trong cac phat bieu tren, nhuTng phat bieu diing la:
A. (a), (b) va (e) B. (a), (c) va (e)

C. (b), (d) va (e)

D . (b), (c) va (e)

C a u 46: T h i nghiem vdi dung dich H N O 3 thi/dng sinh ra k h i doc NO2. De han
che k h i NO2 thoat ra t i / ong nghiem, ngifcfi ta nut dng nghiem bkng:
(d) bong c6 t a m giam an.

(c) bong CO t a m niidrc voi.

(b) bong c6 tarn nifdrc.

(a) bong kho.

Trong 4 bien phap t r e n , bien phap c6 hieu qua nhat la
A. (d)

B. (c)

C.(a)

D . (b)

C a u 47: H 6 n hop X gom H2, C2H4 va CgHe c6 t i khoi so vdri H2 la 9,25. Cho
22,4 l i t X (dktc) vao b i n h k i n c6 sSn mot i t hot N i . Dun nong binh mot thcfi
gian, t h u dtfcfc hon hgp k h i Y c6 t i khoi so vdri H2 b&ng 10. Tong so' mol H2

da phan ijfng la
A. 0,070 mol

B. 0,015 mol

C. 0,075 mol

D . 0,050 mol

C a u 48: Trong cap dung dich CH3-CH2-NH2, H2N-CH2-COOH, HzN-CHz-CHCNHg)COOH, HOOC-CH2-CH2-CH(NH2)-COOH, so dung dich lam xanh quy t i m la
A.4

B.l

C. 2

C a u 49: Cho phucfng t r i n h phan ilng aAl +bHN03

D.3
> cAl(N03)3 + dNO + eHzO.

T i le a : b la
A. 1 : 3

B. 2 : 3

C. 2 : 5

D. 1 : 4

C a u 50: Cho 25,5 gam h6n hop X gom CuO va AI2O3 tan hoan toan trong dung
dich H2SO4 loang, t h u diicfc dung dich chufa 57,9 gam muoi. Phan trSm khoi
lifgfng cua AI2O3 trong X la
A. 40%

B. 60%

C. 20%

D . 80%

134


B. Theo chitofng t r i n h N a n g cao (20 cdu, ti£ cdu 51 den cdu 60)
Cau 51: Cho phtfcfng t r i n h phan ufng:
aFeS04 + bKzCraOv + CH2SO4

> dFe2(S04)3 +6X2804 + {Cr2(S04)3 + gHgO

Ty le a:b la
A.3:2

C. 1:6

B 2:3

D. 6:1

Cau 52: Cho cac phat bieu sau:

(a) De xuf ly thiiy ngan rai vai, ngifcfi ta c6 the dung bot liAi huynh .
(b) K h i thoat vao k h i quyen , freon pha huy tan ozon
(c) Trong k h i quyen, n6ng do CO2 vifot qua tieu chuan cho phep gay ra hieu
ufng nha k i n h .
(d) Trong k h i quyen , nong do NO2 va SO2 viiOt qud tieu chuan cho phep gay
ra hien ti/gng miTa axit
Trong cac phat bieu tren , so phdt bieu dung la:
A.2

B. 3

C. 4

D. 1

Cau 53: Cho cac phat bieu sau:
(a) Glucozo CO kha nang tham gia phan uTng t r ^ n g bac
(b) Sir chuyen hoa t i n h bot trong co the ngifdi c6 sinh ra mantozO
(c) Mantorazo c6 kha nang tham gia phan ufng trang bac
(d) Saccarozo difgc cau tao iii hai go'c p-glucozo va a-fructozcf
Trong cac phat bieu t r e n , so phat bieu dung la:
A.3

B. 4

C. 2

D. 1

Cau 54: Cho 13,6 gam mot chat hCfu ccf X (c6 thanh phan nguyen to C, H , O)

tac dung viTa dii vdi dung dich chijfa 0,6 mol AgNOs trong NH3, dun nong ,
thu diioc 43,2 gam Ag. Cong thijfc cau tao cua X la :

A. C H j - C ^ C - C H O

B. CH, = C = C H - C H O

C. CH = C - C H , - C H O

D. C H S C - [ C H J

-CHO

Cau 55: Peptit X bi thiiy phan theo phiiomg t r i n h phan ilng X + 2H2O -> 2Y + Z
(trong do Y va Z la cac amino axit). Thuy phan hoan toan 4,06 gam X thu diicfc
m gam Z. Dot chay hoan toan m gam Z can vi/a dii 1,68 l i t k h i O2 (dktc), thu
difcfc 2,64 gam CO2; 1,26 gam H2O va 224 m l k h i N2 (dktc). Biet Z c6 cong thufc
phan tijf trung vdi cong thufc don gian nhat. Ten goi ciia Y la
A. glyxin
B. lysin
C. axit glutamic
D. alanin
Cau 58: Trifdng hop nao sau day k h o n g xay ra phan ufng?
(a) CH, = C H - C H 2 - C 1 +

H , 0 ^ ^

(b) C H ^ - C H ^ - C H ^ - C l + H p

>

135


(c) C ^ H , - C ! + N a O H ( d a c ) (d) C ^ H j - C l

+

A. (a)

i

cao.p cao

^ v d i (CeHs- l a go'c p h e n y l )

N a O H ^ ^
B . (c)

C. (d)

D . (b)

C a u 57: Trtfcfng h o p nao sau day, k i m l o a i b i a n m 6 n d i e n h o a hoc?
A. D o t day s&t t r o n g k h i o x i k h o .
B . T h e p cacbon de t r o n g k h o n g k h i a m .
C. K i m l o a i k e m t r o n g d u n g d i c h H C l
D . K i m l o a i sSt t r o n g d u n g d i c h HNO3 l o a n g
Cau

58: C h o 12 g a m h g p k i m ciia bac v a o d u n g d i c h HNO3 l o a n g (dii), dun

n o n g d e n p h a n ufng h o a n t o a n , t h u di/oc d u n g d i c h c6 8,5 g a m AgNOa. P h a n
B . 30%

A. 65%

cua bac t r o n g m a u h o p k i m l a

tram khoi

iLfgrng

C a u 59: Cho so do p h a n ufng C r -

C. 55%
+Cl.dif

^V

D . 45%
+dungj|chNa()H.dir

C h a t Y t r o n g so do t r e n l a
A. NaaCraOv

C. C r ( 0 H ) 3

B . Cr(OH)2

D. Na[Cr(0H)4]

C a u 60: H 6 n h o p X g o m ancol m e t y l i c , ancol e t y l i c v a g l i x e r o l . D o t chay h o a n
t o a n m g a m X, t h u

dLfgc

15,68 l i t k h i CO2 ( d k t c ) v a 18 g a m H2O. M a t khac,

80 g a m X h o a t a n duac to'i d a 29,4 g a m Cu(0H)2. P h a n t r a m k h o i lifgng cua
ancol e t y l i c t r o n g X l a
A. 46%

B . 16%

C. 23%
DAP

54C

53A

52C--

5 ID

45B

44B

43B

42A

41D

35A

34A

33A

32A

31B

25C

24C

23C

22D

21C

15D

14D

13B

12A

IIB

5A

4A

3D

2C

IC

D . 8%

AN
6B

55A

58D

57B

56D

49D

48C

47C

46B

40A

39D

38B

37B

36C

30D

29A

28D

27B

26C

20B

19B

18D

17A

16C

lOA

9A

8B

YD

59D

50C
60C

BAI GIAI C H I T I E T
C a u 1: T a c6 so m o l Fe203 = 0,1 m o l
V i p h a n 2 t a c d u n g vdri d u n g d i c h N a O H dii g i a i p h o n g H2 chufng t o Fe203 da
p h a n ufng h e t t h e o p h a n ufng:
2A1
0,2mol

> AI2O3 + 2Fe

+ Fe203

0,1 m o l

0,2mol

3 92
V a y h 6 n h o p sau n h i e t n h o m g o m A l d i i v a (—
1-0,2) = 0,27 m o l F e .
56
136


Theo de, F e d m o i p h a n g i a i p h o n g (4a - a) = 3 a m o l H2 n e n
—

= 3a o

2

a = 0 , 0 4 5 (mol)

Do a = 0,045 ( m o l ) n e n A l d i i a m o i p h a u = ^

'

- 0,03 mol.

Vay m = 27(0,2 + 2.0,03) - 7,02 g a m . Vay chon C.
Cau 2: L o a i A , C, D v i H2SO4 l o a n g k h o n g t h e o x i h o a F e ( I I ) t h a n h F e ( I I I ) .
Vay chon C
Cau 3: T a c6 n x = 1 m o l v a ny =

26.0,3.^ + 2.0,65

= 0,65 m o l

Do do so' m o l H2 da p h a n ufng = 1 - 0,65 = 0,35 m o l
Chu y r a n g do C2H2 con d i i 0 , 1 m o l n e n x e m n h i / c h i c6 (0,35 - 0,10) = 0,25
mol C2H2 tac d u n g vdi H2.
Vi 0,25 m o l C2H2 c6 k h a n a n g t a c d u n g to'i d a vdri 0,5 m o l H2 n e n h o n h o p Y
con CO k h a n a n g t a c d u n g t o i d a v(5i (0,5 - 0,35) = 0,15 m o l H 2 , tufc cung 0,15
mol Br2. V a y c h o n D
Cau 4: T r o n g p h a n ijfng C + CO2

> 2 C 0 t h i C c6 so' o x i h o a t a n g sau p h a n

iJng n e n C d o n g v a i t r o c h a t khijf. V a y c h o n A
Cau 5: TCf p h u o n g t r i n h CeHizOe

> 2C2H5OH + 2CO2

Ta tha'y cuf 180 g a m glucoza se t a o 2 0 0 g a m ke't t u a , do do
m =

15.180.100
200.90

= 15,0. V a y c h o n A

Cau 6: G o i a, b l a so' m o l B a v a A l t r o n g X . C h i i y r k n g cr t h i n g h i e m v<5i d u n g
dich N a O H d i i t h i X t a n h e t , n h i i n g a t h i n g h i e m vdri nifdrc dii, c h i c6 B a t a n

het con A l t a n m o t p h a n , t a c6 h e :
a+

3b
7

= 0,7

<=>

a + 3a = 0 , 4

a = 0,l
b = 0,4

Vay m - 137a + 27b = 24,5. V a y c h o n B
Cau 7: T a c6 m A g = 0,1.2.108 = 21,6 g a m . V a y c h o n D
Cau 8: C h u y r k n g vofi d a n g b a i t a p n a y , k i m l o a i t h u Axioc l a cac k i m l o a i c6
t l n h khtf m a n h n h a t , con muo'i t h u diioc l a muo'i cua nhufng k i m l o a i c6 t i n h
khijf ye'u n h a t . V a y d u n g d i c h X g o m Cu(N03)2 v a Fe(N03)2, con r S n Y g o m
Cu va A g . V a y c h o n B
Cau 9: V i n x =

nxaOH

n e n X c6 m o t n h o m C O O H
137


T a p h a i c6

n,nu6i

- n^aon = 0,04 m o l n e n Mn

0,04

V a y M x = 125 - 22 = 103, tufc X l a NHaCgHsCOOH.

= 125.

Vay chon A

C a u 10: T h e o de t a c6:
n

, =0,01mol

-0,01mol

n

=0,02mol

n^^^

n^^., = 0 , 0 1 m o l
Vay nikettua = m,,__^„^ +mcu,ou,, = 233.0,01 + 98.0,01 = 3,31 (gam). V a y chon A
C a u 11: P e n t a n CH3CH2CH2CH2CH3 tao difcrc 3 dfin x u a t monoclo l a :
CH3CH2CH2CH2CH2CI; CH3CH2CH2CHCICH3 v a CH3CH2CHCICH2CH3

Vay chon B
C a u 12: T a c6 so m o l P - so m o l H3PO4 = 0, 1 m o l ; So m o l N a O H = 0,2 m o l .
V a y t h u ducfc d u y n h a t 0 ,1 m o l Na2HP04 tufc 14,2 g a m m u o i
Vay c h o n A
C a u 13: G o i x , y I a n lifcft l a so m o l X , Y
2x + 2y = ^ = 0,4
Ta

CO h e :

2 x . y = ^ . 0 , 3 2
89

x = 0,12
y = 0,08

V a y m = m x + m y = 472.0,12 + 332.0,08 = 83,2 (gam). V a y c h o n B
C a u 14: (J t r a n g t h a i co b a n , cau h i n h e l e c t r o n ciia n g u y e n tuf N a ( Z = 11) la
ls22s'2p^3s\y c h o n D
C a u 15: G o i cong thijfc a x i t n o l a CnH2n02; cong thufc t r u n g b i n h 2 a x i t chUa no
l a C „ H 2 „ , 2O2.
G o i a l a so m o l a x i t n o ; b l a so m o l 2 a x i t chi/a no.

a+b=a3

a = 0,15

T a c o he: i a ( 1 4 n + 54) + b(14m + 52) = 25,56

«

< b = 0,15

4 4 ( n a + b m ) + 18(an + b m - b ) = 4 0 , 0 8

an + b m = 0 , 6 9

R u t r a n + m = 4,6.
C h u y r a n g t a p h a i c6 m ^ 3 n e n c h i c6 n = 1; m = 3,6gam l a p h u h o p .
Vay

m2axUkh6ngno

= b ( 1 4 m + 30) = 0,15(14.3,6 + 30) = 12,06 g a m .

Vay chon D
138


Cau 16: D u n g d i c h C H 3 C O O H tac d u n g diidc vdri N a O H ; N a v a CaCOa.
Vay chon C
Cau 17: T e n t h a y t h e (theo l U P A C ) cua (CH3)3C-CH2-CH(CH3)2 l a
2,2,4-trimetylpentan
Vay chon A
Cau 18: T o n i l o n - 6 , 6 l a san p h a m t r u n g n g t f n g cua a x i t a d i p i c
va hexametylendiamin.
Vay chon D
Cau 19: G o i a, b , c, d I a n lifot l a so' m o l ciia N a ; N a 2 0 ; B a v a B a O .
23a + 6 2 b + 137c + 153d = 21,9
20

Theo de t a c6 he: <

Vay

52

171

a
1,12
- + c =
= 0,05
2
22,4
23(a + 2c) + 91(c + d ) + 6 2 ( b + d ) = 21,9

a + 2c = 0 , l

23(a + 2 b ) + 137(c + d ) + 16(b + d ) = 21,9

c + d = 0,12

c + d = 0,12

b + d =

a + 2c = 0 , l

a + 2 b = 0,14

nMaOH = a + 2b

= 0,14

0,14

mol

Suy r a d u n g d i c h sau hoa t a n r a n X c6 chufa 0,12 m o l Ba^"^
v a (0,14 + 2.0,12) = 0,38 m o l O H '
Theo de n,,„ = 0 , 3 m o l n e n n
<:<>:

Ma n

.

'

, =n
CO-,

= 0,12 m o l n e n n„

- n „ , = 0,38 - 0,3 = 0,08 m o l .
oil

CO,

'

'

'

= 0,08 m o l , tufc mtettua = 197.0,08 = 15,76 g a m .

Vay chon B
Lilu

y

+ Khi dung

cong thiic

nen sd dung
U day dieu kien
con

n

dieu kien kiem chiing

nay thoa ui n^^, = 0,3

, =n

COV

n^,^^, = n^^^^ " " c o

OH

- n „ , , = 0,08
C^":

mol,

Id n^^^, ^ n^^, .
mol,
tiic

n

, < n„,, .

COi

l^":

n
+ Hoac chl dung

cong thiic

n^^^, = n^^^^ - n^^.^^ khi

1<

< 2.

139


'
.
n
0 38
O day dieu kien nay thoa vi " " = —— = 1,26.
0,3
CO,
C a u 20: Goi cong thufc X la CxHyO^ (a mol), ta c6 phan ufng chay:
CxHyO, + (x + y^ ~ - ) 0 ,

Ta

CO

Rut ra

he:

X

^

XCO2 + ^ H , 0

a/. = 0 , i 5

ax = 0,35

ay = 0,3

a(12x + y + 16z) = 6,9 <=>

ax = 0.35

a(x + ^ - - ) = 0,35
4 2

: y : z = 7 : 6 : 3. Vay X c6 cong thufc C7H6O3.

So mol X =

6,9
138

= 0,05 mol.

Goi b la so mol NaOH da phan ufng vdi X, ta c6 b + 0,2b = 0,18 <=> b = 0,15.
Do nx :

nxaOH

= 1 : 3 nen X phai c6 cau tao H C O O C 6 H 4 O H .

Phan ufng xay ra:

HCOOC6H4OH + 3NaOH

> HCOONa + C6H4(ONa)2 + 2H2O

0,05mol

0,lmol

Bao toan khoi liTdng cho m^n = 6,9 + 40.0,18 - 0,1.18 = 12,3 (gam).
Vay chon B
C a u 21: Dat cong thuc X la CxHt02; Y la CxHgx + 20k
Goi cong thufc trung binh cua h6n hgrp la CxHyOj, (a mol), ta c6 phan uftig chay:
CxHyO, + (x + ^ - - ) 0

Ta

CO

he:

XCO2+ ^ H , 0

y = 5,5

0,4x = l , 2

x =3

0 , 4 ( x + ^ - - ) = l,35
4 2

z=2

0 , 4 ^ = 0,55
2

Do so O t r u n g b i n h = 2 ma X c6 2 0 nen Y cung c6 2 0 .
Vay Y 1^ C3H8O2

Do so H trung b i n h = 5,5 ma Y c6 8 H nen ta phai c6 t < 5,5.
Vay Y la C3H4O2 hoac C3H2O2

Goi a, b la so mol X, Y trong 0,4 mol hon hop.
140


a + b = 0,4
Neu chon Y la C 3 H 2 O 2 , ta c6 he:

2a + 8b

a =

= 5,5

0,4

(loai v i

naxit <

a + b = 0,4
Vay Y la C3H4O2 va ta c6 he

b =

4a + 8b _ g ^ « <
0,4

30
7_
30

Hancol)

a = 0,25
b = 0,15

Do do m = 76.0,15 = l l , 4 g a m . Vay chon C
Cau 22: Cac t h i nghiem c6 xay ra phan ufng oxi hoa - khuf la: —
- Sue k h i etilen vao dung dich KMn04 loang.
- Cho hoi ancol etylic d i qua hot CuO nung nong.
- Sue k h i etilen vao dung dich Br2 trong CCI4.
- Cho dung dich glucoza vao dung dich AgN03, trong N H 3 duT, dun nong.
Vay chon D
Gau 23: X la CHsCOOCH^CHa. That vay:
CH3COOCH=CH2 + NaOH
CHsCOONa + NaOH
2CH4

I5(m"t

C2H2 + H2O

^ CH3C00Na + C H 3 C H O

-

-> CH4 + Na2C03

^ C2H2 + 3H2
- ^ ^ ^ CH3CHO

Vay chon C
Cau 24: Co 4 dong phan ancol C4H10O la dong phan cau tao eua nhau:
CH3CH2CH2CH2OH; C H 3 C H ( C H 3 ) C H 2 0 H ; CH3CH2CH(CH3)OH va C(CH3)30H
Vay chon C.
Cau 25: De y rang Fe cuoi bai da b i oxi hoa toan bo thanh Fe^*
Tong so mol NO = 0,05 + 0,02 = 0,07; So mol Cu = 0,0325
NHAN

CHO
Fe — -> Fe"^ + 2e
a mol
Cu —
0,0325mol

2a mol

N^^ +

3e
0,21mol

T+2

N^

0,07mol

Cu^^ + 2e
0,065mol

Vay 2a + 0,065 = 0,21 mol < » a = 0,0725 mol.
Do do m = 56.0,0725 = 4,06 (gam)
Vay chon C
141


C a u 26: Lien ket hoa hoc giOTa cac nguyen tis trong phan tuf H C l thuoc loai lien
ket cong hoa t r i c6 c\ic. Vay chon C
C a u 27: Cac t h i nghiem c6 xay ra phan ufng la:
- Cho dung dich H C l vac dung dich Fe(N03)2
- Cho FeS vao dung dich H C l .
- Cho Si vao dung dich NaOH dac.
- Cho Si vao binh chufa k h i F2.
- Sue k h i SO2 vao dung dich H2S.
Vay chon C
C a u 28: Ta c6 so mol N2 = so mol N2O = 0,12 mol.
Gia sijf mudi thu diigc gom A1(N03)3 va x mol NH4NO3, ta c6

213 — + 80x = 8m «
27

x= m
720

Bao toan electron cho 3 — = 0,12.10 + 0,12.8 + 8<=> m = 21,6 (gam)
27
720
Vay chon D
C a u 29: Theo de, dung dich Z gom 0,01 mol Al''^; X mol Fe^* va y mol Fe3+.
Ran Y chi la Ag.
De y rang 1,97 gam ket tua gom x mol Fe(0H)2 va y mol Fe(0H)3; 1,6 gam
ran la 0,01 mol Fe203, ta c6 he:
[y = 0,01

x + y = 2.0,01 = 0,02

f x = 0,01

90x + 107y = 1,97

NhLf vay hon hop X ban dau da cho (0,01.3 + 2x + 3y) = 0.08 mol electron va
Ag^ da nhan 0,08 mol nay tao 0,08 mol Ag. Do do m = 108.0,08 = 8,64.
Vay chon A
C a u 30: Dung dich AgN03 tao ket tua difcrc vdi HCl; K3PO4 va KBr. Vay chon D
C a u 31: Phenol phan ufng di/gc vdi dung dich K O H . Vay chon B
C a u 32: Can bang hoa hoc H2 (k) + h (k) <

> 2 H I (k) c6 tong so mol k h i a 2

ve b a n g nhau nen k h i thay doi ap sua't chung cua he, can b a n g hoa hoc tren
k h o n g b i chuyen dich. Vay chon A
C a u 33: Fe tac dung v(5i dung dich CUSO4 tao mudi Fe^"^. Vay chpn A
C a u 34: Goi n la hoa t r i cua X va a, b la so mol cua Fe va X, ta c6 he:
'56a + bX = 1,805

a = 0,025

2a + bn = 2 ^ ^ = 0,095 « ^ bX = 0,405
22,4
bn = 0,045
22,4
Rut ra X = 9n (Al). Vay chon A

142


Cau 35: Cac chat trong day vinylaxetilen, glucozcf, andehit axetic deu tao ket tua
khi cho tac dung vcfi dung dich AgNOs trong NH3 dif, dun nong, trong do
vinylaxetilen tao ket tua AgC = C - C H = C H ^ , hai chat con lai tao ket tua Ag.
Vay chon A
Cau 36: Gpi a, b la so mol

CUSO4

va NaCl trong dung dich ban dau

Vi dung dich sau dien phan hoa tan diicfc toi da 0,2 mol Al20;j nen dung dich
nay chi'/a 1,2 mol

hoac 0,4 mol O H

+ Neu dung dich dung dich sau dien phan chiifa 1.2 mol H ^
Catot (-)

Anot (+)

so;;cr ;H.O
2 CI

> CI2

b

Cu^" + 2e

+ 2e

0,5b

2H2O

Cu'";Na^;Hp

a

b

> 4H"

O2

+

l,2mol

> Cu

2a

+ 4e

0,3mol

Loai vi anot thoat ra 22,4(0,5b + 0,3) > 6,72 h t .
+ Neu dung dich dung dich sau dien phan chifa 0.4 mol OH"
Anot (+)

Catot {-)

so;

;C1 ; H p

2Cr

> CI2

+ 2e

0,5b

b

b

Cu'

;Na^H,0

Cu^" + 2e
a

> Cu

2a

2H2O + 2e 0,4mol
Ta

CO

he:

2a + (),4 = b

> 20H

+ H2

0,4raol

a = 0,l
b = 0,6

[0,5b = 0,3

Vay m = 160a + 58,5b = 51,lgam. Vay chon C
Cau 37:
Ta CO CH3COOCH=CH-CH2

+ NaOH - ^ - >

CHgCOONa 1- CH3CH2CHO

Vay chon B
Cau 38: Dung dich metylamin lam phenolphtalein tii khong mau hoa hong.
Vay chon B
Cau 39: Ta c6

ngUxeroi

= 92.0,1 - 9,2 gam. Vay chon D

Cau 40: Cac phan ufng:
Ba(HC03)2 + HNO3

> Ba(N03)2 + 2CO2 + 2H2O

143


Ba(HC03)2 + Ca(OH)2

Ba(HC03)2 + Na2S04 -

-> BaCOa + CaCOa + 2H2O
-» BaS04 + 2 N a H C 0 3

Vay c h o n A
C a u 41: G p i n l a so' C m o i a x i t va a, b I a n liicft l a so m o l 2 a x i t t r e n , t a c6 he:
- + b = 0,2
9
na + n b = 0,6
De y r a n g ~ +

o

< a + b < a + 2b n e n 0,2 < a + b < 0,4

0,6
0,6
0,6
^ - > a^+—
0,2
b > 0,4

<=> 3 > n > 1,5

V a y n = 2 tufc X l a CH3COOH v a Y l a H O O C - C O O H
T h a y n = 2 vao he t r e n g i a i difpc a = 0 , 2 m o l ; b = O , l m o l .
Do do % H O O C - C O O H =

= 42,86(%)
6 0 . 0 , 2 + 90.0,1

Vay chon D
C a u 42: G o i n , m I a n l i i g t l a so' C cua ancol da chufc ancol k h o n g no, c6 mot
l i e n k e t d o i , m a c h h o da cho.
T h e o de t a c6 0,07n + 0,03m = 0,23.
C h u y r a n g t a p h a i c6 n > 2 va m > 3 n e n c h i c6 n = 2 va m = 3 l a p h u hop.
V a y h 6 n h o p g o m 0,07 m o l C2H6O2 va 0,03 m o l C3H6O,
do do m„jec = 18(0,21 + 0,09) - 5,4 g a m . V a y chon A
C a u 4 3 : D a y cac c h a t deu c6 k h a n a n g t h a m gia p h a n uTng t h u y p h a n t r o n g
d u n g d i c h H2SO4 d u n n o n g l a : saccarozcr, t i n h bot v a xenlulozcf. V a y chon B
C a u 44: Cac p h a n ijfng x a y r a l a :

> S n S O , + Cu

S n + CUSO4

> FeSOi

Fe + CUSO4

+ Cu

V ^ y chon B
C a u 4 5 : NhOfng p h a t b i e u d u n g l a :

- T r o n g b a n g t u a n hoan cac nguyen to hoa hoc, crom thupc chu k i 4, n h o m VIB.
- T r o n g cac h p p c h a t , so' o x i hoa cao n h a t cua c r o m l a +6
- K h i p h a n ufng vdri k h i CI2 dii, c r o m tao r a h o p c h a t c r o m d H ) .
V a y chon B
C a u 46: Do NO2 l a o x i t a x i t n e n ngiicfi t a d u n g b o n g c6 t a m nifofc v o i t r o n g la
bazo de giOT b d t l a i NO2 k h o n g cho t h o a t r a ngoai. Vay c h o n B

144


Cau 47: Ta c6 nxMx = nyMy nen ny = " ^ ^ ^ _ 1.0,925.2 ^ Q,925mol
MY
10.2
Do do so mol Hg da phan ufng = 1 - 0,925 = 0,075mol. Vay chon C
Cau 48: Cac dung dich lam xanh quy tim la
CH3-CH2-NH2, H2N-CH2-CH(NH2)-COOH. Vay chon C
Cau 49:
Ta CO phan ufng Al + 4 H N O 3

> A1(N03)3 + NO + 2H2O nen a : b = 1 : 4 .

Vay chon D
Cau 50: Goi a, b la so mol CuO va AI2O3 thi a, b cung la so mol C U S O 4 va Al2(S04)3.
Vay ta c6 he:

80a + 102b = 25,5

Ja = 0,255

160a + 342b = 57,9

l b = 0,05

Do do %Al203 ^>02.0,05.100 ^ 20(%). Vay chon C
25,5
Cau 51: Ta c6 phan ufng:
6FeS04 + KzCrzOy + 7H2SO4

> 3Fe2(S04)3

+ K2SO4

+ Cr2(S04)3 + 7H2O

Vay a : b = 6 : 1. Vay chon D
Cau 52: Cac phat bieu diing la:
- De xijf ly thuy ngan roi vai, ngifdi ta c6 the diing bot liJU huynh .
- Khi thoat vao khi quyen , freon pha huy tan ozon
- Trong khi quyen, nong do CO2 viiOt qua tieu chuan cho phep gay ra hieu
ling nha kinh.
- Trong khi quyen , nong do NO2 va SO2 vi/cft qua tieu chuan cho phep gay
ra hien tifcfng mifa axit
Vay chon C
Cau 53: Cac phat bieu dung la:
- Glucozcf CO kha nang tham gia phan ufng trang bac
- Sif chuyen hoa tinh bot trong ca the ngufcJi c6 sinh ra mantozcf
- Mantorazo c6 kha nang tham gia phan ufng trang bac
Vay chon A
Cau 54: Vi 0,6 mol Ag* phan ufng nhtfng chi tao 0,4 mol Ag chufng to day 1^
andehit dcfn chufc c6 noi ba dau mach.

Theo de 13,6 gam tufc 0,2 mol C H s C - C H ^ - CHOda phan ufng viia du vdi
dung dich chufa 0,6 mol AgNOa trong NH3 theo phufomg trinh:
CH = C - C H , - CHO + SAgNOa + 4NH3 + H2O
> CAg = C - C H , - COONH4 + 3NH4NO3 + 2Ag
Vay chon C
145


Cau
Ta

55: Dat. cong thufc Z la CxHyO^Nt
CO

nc - 0,06 m o l ; n n - 0,14 m o l ;
n N = 0,02 m o l v a no - (0,06.2 + 0,07) - 2.0,075 - 0,04 m o l

Do do X : y : z : t = 0,06 : 0,14 : 0,04 : 0,02 = 3 : 7 : 2 : 1
V a y Z CO cong thufc p h a n tuf C3H7NO2 vd?i so' m o l = 0,02 m o l
P h a n ijrng x a y r a :

0,04mol

0,02mol

2H2O

X

+

> 2Y

+

0,04mol

Z
0,02mol

4.06 + 0.04.18-89.0,02
Rut r a M Y = —
= 75 . V a y X l a g l y x i n . V a y chon A
0,04
57: T h e p cacbon de t r o n g k h o n g k h i a m b i a n m o n d i e n hoa do c6 sif tao

Cau

56: C h o n D

Cau

p i n d i e n hoa F e - C , t r o n g do Fe l a ciJc a m v a C l a cifc diiong. V a y c h o n B
C a u 58: V i d u n g d i c h c6 chuTa 0,05 m o l AgNOs chuTng to da c6 0,05 m o l A g bi
oxi hoa.
Vay %Ag =
Cau

108.0,05.100
12

59: T a c6 sa dd C r

- 4 5 ( 7 r ) . Vay chon D

"'"'•'"^ > C r C l ,

^M'-I'N"""-^-^

) Na[Cr(OH) J

V a y chon' D
Cau

60: G o i a, b, c I a n lifat l a so' m o l 3 ancol t r e n t r o n g m g a m X . T a c6 he:
a + 2 b + 3c = 0,7

a = 0,05

2a + 3 b 4 4c = l

b = 0,10

3 2 k a + 4 6 k b + 9 2 k c = 80 <=^

c-0,15
k = 4,0

Vay %C2H50H- =

3 2 , 0 , 0 5 + 4 6 . 0 , 1 + 92.0,15

3 2 a + 4 6 b + 92c

46.0,1.100

46b. 100

= 23(%)

Vay chon C

146


JDE S O 2
DE THI TUYEN SINK DAI HOC NAM

2013

M 6 n t h i : H O A , k h o i B - M a d e : 537
Cho b i e t n g u y e n tuf k h o i cua cac n g u y e n to':
H = 1; L i = 7; Be = 9; C = 12; N = 14; O = 16; N a - 2 3 ; M g = 2 4 ; A l = 2 7 ;
S = 32; CI = 35,5; K = 39; Ca ^ 40; Fe - 56; Cu = 64; Z n = 65; B r

^

80; Rb = 85;

Sr = 88; A g = 1 0 8 ; Cs = 133; B a = 137.

I. P H A N C H U N G C H O T A T C A T H I S I N H

(40 cau, tic cau 1 den cau

4G)

Cau 1: H 6 n hop X gom ancol metyhc, e t y l e n gUcol. Cho m g a m X - p h a n l i i i g hoan
loan vdi N a d i i , t h u dtfcfc 2,24 lit k h i H2 (dktc). D o t chay hoan t o a n m g a m X ,
thu di/oc a g a m CO2. G i ^ t r i cua a la
A. 8,8

B . 6,6

C. 2,2

D . 4,4.

Cau 2: Cho 0,76 g a m h 6 n h o p X g o m h a i a m i n dcfn chijfc, c6 so' m o l b ^ n g n h a u ,
phan

Lfng

h o a n t o a n vdfi d u n g d i c h H C l dif, t h u difgc 1,49 g a m m u o i . I v h d i

lifcrng cua a m i n c6 p h a n tijf k h o i nho h o n t r o n g 0,76 g a m X l a
A. 0,45 g a m .

B . 0,38 g a m .

C. 0,58 g a m .

D . 0,31 g a m .

Cau 3: H o n h o p X g o m FeO, FezOg v a Fe304. Cho k h i C O qua m g a m X n u n g
nong, sau m o t thori g i a n t h u dtfoc h o n h o p c h a t r a n Y v a h o n hcfp k h i Z. Cho
toan bo Z vao d u n g d i c h C a ( 0 H ) 2 dil, d e n p h a n urng h o a n t o a n , t h u dtfcfc 4
gam k e t t i i a . M a t k h a c , hoa t a n h o a n t o a n Y t r o n g d u n g d i c h H2SO4 dac,
nong (dif), t h u dufcfc 1,008 l i t k h i SO2 ( d k t c , san p h a m khijf duy n h a t ) v a d u n g
dich chufa 18 gam m u o i . Gia t r i ciia m l a
A. 7,12.

B . 6,80.

C. 5,68.

D . 13,52.

Cau 4: H o a t a n h o a n t o a n 1,28 g a m Cu vao 12,6 g a m d u n g d i c h HNO3 6 0 % t h u
diroc dung d i c h X ( k h o n g c6 i o n N H ^ ) . Cho X tac d u n g h o a n t o a n vdfi 105
ml dung d i c h K O H I M , sau do loc bo ke't t u a diicfc d u n g d i c h Y . Co can Y
di/gc chat r S n Z. N u n g Z d e n k h o i lirgng k h o n g d o i , t h u duac 8,78 g a m chat
ran. N o n g do p h a n t r a m cua Cu(N03)2 t r o n g X l a
A. 28,66%.

B . 30,08%.

C. 27,09%.

D . 29,89%.

Cau 5: Cho g i a t r i do a m d i e n ciia cac nguy.en t o : F (3,98); O (3,44); C (2,55); H
(2,20); N a (0,93). H o p chat nao sau day l a h o p chat ion?
A. N a F .

B. CH4.

C. H2O.

D . CO2.

Cau 6: Cho m g a m m o t o x i t sSt p h a n uTng viia du vdfi 0,75 m o l H2SO4, t h u difoc
dung d i c h chi chufa m o t m u o i duy n h a t va 1,68 l i t k h i SO2 ( d k t c , s a n p h a m
khijf duy n h a t cua S"^). G i a t r i cua m la
A. 24,0.

B . 34,8.

C. 10,8.

D . 46,4.

147


C a u 7: H6n hap X gom hidro, propen, axit acryUc, ancol anlylic (C3H5OH). Dot
chay hoan toan 0,75 mol X, thu di/gc 30,24 l i t k h i CO2 (dktc). Dun nong X
vdri bgt N i mot thdi gian, t h u dtrgtc h6n hop Y . T i kho'i hcfi cua Y so vdri X
bang 1,25. Cho 0,1 mol Y phan ijfng viia du vdri V l i t dung dich Br2 0,1M. Gia
t r i cua V la
A. 0,6.

B. 0,5.

C. 0,3.

D. 0,4.

C a u 8: Thuy phan hoan toan m i gam este X mach hof bkng dung dich NaOH
dii, thu diigc m2 gam ancol Y (khong c6 kha nang phan ufng vori Cu(0H)2) va
15 gam h6n hop muoi cua hai axit cacboxylic dcfn chOfc. Dot chay hoan toan m2
gam Y bkng oxi dii, thu diicfc 0,3 mol CO2 va 0,4 mol H2O. Gia t r i ctia m i la
A. 11,6.
B. 16,2.
C. 10,6.
D. 14,6.
C a u 9: Cho phan ufng: FeO + HNO3

Fe(N03)3 + NO + H2O.

Trong phuong t r i n h ciia phan ufng tren, k h i he so cua FeO la 3 t h i he so cua
HNO3 la
A. 6.

B. 10.

C. 8.

D. 4.

C a u 10: So proton va so ncrtron c6 trong mot nguyen tuf nhom i'^Al)

A. 13 va 13.

B. 13 va 14.

C. 12 va 14.

Ian liicft Ik

D. 13 va 15.

C a u 11: Amino axit X c6 phan tuf khoi bkng 75. Ten cua X la
A. lysin.

B. alanin.

C. glyxin.

D. valin.

C a u 12: Cho 3,36 l i t k h i hidrocacbon X (dktc) phan ufng hoan toan vdi liigng d\i
dung dich AgNOs trong NH3, thu difdc 36 gam ket tua. Cong thufc phan tijf
ciia X la
A. C4H4.

B. C2H2-

C. C4Hg.

D. C3H4.

C a u 13: Ten goi ciia anken (san pham chinh) thu di/gc k h i dun nong ancol c6
cong thufc (CH3)2CHCH(OH)CH3 vdi dung dich H2SO4 dac la
D. 3-metylbut-2-en.

C. 3-metylbut-l-en.

B. 2-metylbut-l-en.

A. 2-metylbut-2-en.

C a u 14: Trong cac chat: stiren, axit acrylic, axit axetic, vinylaxetilen va butan,
so chat CO kha nang tham gia phan ufng cong hidro (xuc tac N i , dun nong) la
A. 3.

B. 5.

C. 2.

C a u 15: Cho so do phan ufng: C2H2 ^ X

D. 4.

CH3COOH.

Trong so do t r e n m6i mui ten la mot phan ufng, X la chat n^o sau day?
A. CH3C00Na.

C. HCOOCH3.

B. CaH.OH.

D. CH3CHO.

C a u 16: Hoa t a n hoan toan x mol Fe vao dung dich chuTa y mol FeCla va z mol
HCl, thu dufcfc dung dich chi chufa mot chat tan duy nhat. Bieu thufc lien he
giufa X, y va z 1^
A.

X

= y - 2z.

B. 2x = y + z.

C. 2x = y + 2z.

D. y = 2x.

148


Cau 17: Cho cac phat bieu sau:
(a) Cac chat CH3NH2, C2H5OH, NaHCOg deu c6 kha nang phan ting vcfi HCOOH.
(b) Phan (tag the brom vao vong benzen cua phenol (CeHsOH) de hcfn cua benzen.
(c) Oxi hoa khong hoan toan etilen la

phLfcfng

phap hien dai de san xuat

andehit axetic.
(d) Phenol (CsHgOH) tan i t trong etanol.
Trong cac phat bieu t r e n , so' phat bieu dung la
A. 4.

B. 3.

C. 2.

D. 1.

Cau 18: So dong phan amin bac mot, chufa vong benzen, c6 cung cong thufc
phan ttf C7H9N la
A. 3.

B. 5.

C. 2.

D. 4.~"

Cau 19 : Cho cac phat bieu sau:
(a) Trong cac phan ufng hoa hoc, flo chi the hien t i n h oxi hoa.
(b) Axit flohidric la axit yeu.
(c) Dung dich NaF loang diicJc dung lam thuoc chong sau rang.
(d) Trong hgp chat, cac halogen (F, CI, Br, I) deu c6 so oxi hoa:
- 1 , +1, +3, +5 va +7.
(e) T i n h khi^f cua cac ion halogenua tang dan theo thuf tif: F , CF, Br", 1.
Trong cac phat bieu tren, so' phat bieu dung la
A. 2.

B. 4.

C. 3.

D. 5.

Cau 20: Phat bieu nao sau day k h o n g dung?
A. Chat beo la trieste ciia etylen glicol vcfi cac axit beo.
B. Cac chat beo thucfng khong tan trong niidc va nhe hcfn nifcfc.
C. Triolein c6 kha nang tham gia phan ufng cong hidro k h i dun nong c6 xuc
tac N i .
D. Chat beo h i thuy phan k h i dun nong trong dung dich kiem.
Cau 21: Chat nao sau day trong phan tuf chi c6 lien ket dan?
A. Axit axetic.

B. M e t y l fomat.

C. Andehit axetic.

D. Ancol etylic.

Cau 22: Hon hop X gom hai axit cacboxylic dan chufc, mach hcf, ke tiep nhau
trong cung day dong d i n g . Dot chay hoan toan 4,02 gam X, thu dtfcfc 2,34
gam H2O. Mat khac 10,05 gam X phan ufng viia du vdi dung dich N a O H , t h u
difcfc 12.8 gam muoi. Cong thiJc cua hai axit la
A. CgHsCOOH va C4H7COOH.

B. C2H3COOH va C3H5COOH.

C. C2H5COOH va C3H7COOH.

D. C H 3 C O O H va C 2 H 5 C O O H .

Cau 23: Cho phifang t r i n h hoa hoc cua phan ufng: X + 2Y —> Z + T. O thcfi diem
ban dau, nong do ciia chat X la 0,01 mol/1. Sau 20 giay, nong do cua chat X
la 0,008 moLl. Toe do trung b i n h ciia phan ufng t i n h theo chat X trong
khoang t h M gian tren la
149


D . 5,0.10" mol/(l.s).

C. 1,0.10" mol/d.s).

B. 7,5.10" mol/d.s).

A. 4,0.10" mol/(l.s).

C a u 24: T r i p e p t i t X v a t e t r a p e p t i t Y deu m a c h h d . K h i t h u y p h a n h o a n toan
h6n

hop gom

X v a Y c h i tao r a m o t a m i n o a x i t duy n h a t c6 cong thufc

HsNCnHanCOOH. D o t chay 0,05
g a m h o n hcfp g o m CO2,

H2O.

m o l Y t r o n g o x i dif, t h u difgc

va

36,3

D o t chay 0,01 m o l X t r o n g o x i d i i , cho san

p h a m chay vao d u n g d i c h B a ( 0 H ) 2 dtf, t h u dtfgc m g a m ke't t u a . B i e t cac
p h a n ufng deu xay r a h o a n t o a n . G i a t r i cua m l a

A. 29,55.

C. 23,64.

B . 17,73.

D . 11,82.

C a u 25: C a c b o h i d r a t nao sau day thuoc l o a i disaccarit?
A. X e n l u l o z o
Cau

26: T h e

C. Saccarozo

B. Glucozo
tich

dung dich N a O I I

D. A m i l o z o

0,25M can cho vao

15 m l d u n g dich

Al2(S04)3 0,5M de t h u du'cfc lifcfng k e t t u a 16n n h a t l a
A. 210 m l

B . 90 m i

C. 180 m l

D. 60 m l

C a u 27: P h a t b i e u nao sau day l a dung?
A. T h a n h p h a n c h i n h ciia supephotphat kep gom h a i muoi Ca(H2P04)2 va CaS04
B. S u p e p h o t p h a t d o n c h i c6 Ca(H2P04)2
C. U r e CO c o n g thufc l a (NH2)2CO
D . P h a n I a n c u n g cap niter cho cay t r o n g .
C a u 28: D i e n p h a n n o n g chay AI2O3 vcri cac dien ciic b k n g t h a n chi, t h u difcfc m
k i l o g r a m A l a catot va 89,6 m'^ (dktc) h6n hop k l i i X a anot. T i k h o i ctia X so vdi
II2 bang 16,7. Cho 1,12 l i t X (dktc) p h a n ijfng v d i dung dich CaCOIDa da, t h u duac
1,5 g a m k e t tua. Bie't cac p h a n ufng xay r a hoan toan. Gia t r i ciia m la
A. 115,2

B . 82,8

C. 144,0

D . 104,4

C a u 2 9 : H a i chat huTu ccf X v a Y, t h a n h p h a n n g u y e n to' deu g o m C , H , O, c6
cCing so n g u y e n t i i cacbon (Mx < My). K h i dot chay h o a n t o a n m 5 i chat trong
o x i du' deu t h u dLfgc so' m o l H2O bSng so' m o l CO2. Cho 0,1 m o l hSn hcfp gom
X v a Y p h a n ufng h o a n t o a n v d i liTcrng d i i d u n g d i c h A g N O s t r o n g N H 3 , t h u
diTdc 28,08 g a m A g . P h a n t r a m k h o i l i i o n g cua X t r o n g h o n h d p b a n dau l a

A. 60,34%

"~

C . 39,66%

B. 78,16%

D 21,84%

C a u 30: K h i h o a t a n h o a n t o a n m g a m m 5 i k i m l o a i vao niidc

d i i , t i i k i m loai

nao sau day t h u d\Jac t h e t i c h k l i i H2 (cung dieu k i e n n h i e t dp va ap suat) la
nho nhat?
A. N a

B . Ca

C. K

D. L i

C a u 31: Cho 200 m l d u n g d i c h B a ( 0 H ) 2 0,1M vao 300 m l d u n g d i c h NaHCOa

0,1M, t h u dLfcfc d u n g d i c h X va k e t t i i a Y. Cho t i i t i i d u n g d i c h H C l 0,25M
vao X d e n k h i bSt dau c6 k h i s i n h r a t h i h e t V m l . B i e t cac p h a n ufng deu
xay r a h o a n t o a n . G i a t r i ciia V l a
A. 80

B.160

C. 60

D . 40

150


Cau 32: H o n hcfp X g o m h a i k i m l o a i k i e m v a m o t k i m l o a i k i e m t h o . H 6 a t a n
hoan t o a n 1,788 g a m X vao nifdrc, t h u difofc d u n g d i c h Y v a 537,6 m l k h i H2
(dktc). D u n g d i c h Z g o m H2SO4 v a H C l , t r o n g do so' m o l cua H C l gap h a i I a n
so' m o l cua H2SO4. T r u n g hoa d u n g d i c h Y b k n g d u n g d i c h Z tao r a m g a m
hon hop m u o i . G i a t r i cua m l a
A. 4,656

B . 4,460

C. 2,790

D . 3,792

Cau 33: H o a t a n h o a n t o a n Fe304 t r o n g d u n g d i c h H2SO4 l o a n g (dii), t h u difcrc
dung d i c h X. T r o n g cac c h a t : N a O H , Cu, Fe{N03)2, K M n 0 4 , BaCla, Ch v a A l ,
so' chat CO k h a n a n g p h a n ijfng difoc v d i d u n g d i c h X l a
A. 7.

B . 4.

C. 6

Cau 3 4 : D u n g d i c h X chufa 0,12 m o l N a ^ x m o l SO;';

D. 5
0,12 m o l - G T

v a 0,05 m o l

N M ; . Cho 300 m l d u n g d i c h B a ( 0 H ) 2 0 , 1 M vao X d e n k h i cac p h a n ufng x a y
ra h o a n t o a n , loc bo ke't t u a , t h u dijgc d u n g d i c h Y . Co c a n Y , t h u dxiac m
gam chat r S n k h a n . G i a t r i cua m l a
A. 7,190

B . 7,020

C. 7,875

D . 7,705

Cau 35: T r o n g cac p o l i m e : t o t a m , scfi b o n g , t o visco, t o n i l o n - 6 , t o n i t r o n ,
nhCfng p o l i m e c6 n g u o n go'c t i f xenlulozor l a
A. t o t a m , sai b o n g v ^ tcf n i t r o n

B . t o visco va t o n i l o n - 6

C. sgi b o n g , t o visco v a t o n i l o n - 6

D . soi b o n g v a t o visco

Cau 36: H o a t a n h o a n t o a n h o n h o p "gom 2,8 g a m Fe v a 1,6 g a m C u t r o n g 500
ml dung d i c h h 6 n hop H N O 3 0 , 1 M v a H C l 0 , 4 M , t h u difoc k h i N O ( k h i duy
n h a t ) v a d u n g d i c h X. Cho X vao d u n g d i c h AgNOs dtf, t h u diioc m g a m c h a t
rin,

Bie't cac p h a n utng deu x a y r a h o a n t o a n , N O l a san p h a m khuf duy n h a t

cua N*^ t r o n g cac p h a n u'ng. G i a t r i cua m l a
A. 29,24

B. 30,05

C. 28,70

D.

34,10

C a u 37: H a p t h u h o a n t o a n 2,24 l i t k h i CO2 ( d k t c ) vao 750 m l d u n g d i c h

Ba(0H)2 0 , 2 M , t h u dugc m g a m ke't t u a . G i a t r i cua m l a
A. 29,55

B. 9,85

C. 19,70

D . 39,40

C a u 38: A x i t cacboxylic X h a i chijfc (c6 p h a n t r a m k h o i lOOng ciia o x i n h o h o n
70%), Y v a Z l a h a i ancol d o n g dSng k e t i e p ( M y < M z ) . Do't chay h o a n t o a n
0,2 m o l h o n hop g o m X , Y , Z can vCra du 8,96 l i t k h i O2 ( d k t c ) , t h u dtfoc 7,84
l i t k h i CO2 (dktc^ v a 8,1 g a m H2O. P h a n t r a m k h d i l i f g n g cua Y t r o n g h o n
hop t r e n l a
A. 15,9%.

B . 12,6%.

C. 2 9 , 9 %

D. 29,6%

C a u 39: M o t l o a i niJdc cufng k h i d u n soi t h i m a t t i n h cufng. T r o n g l o a i nifdfc
cufng n a y c6 hoa t a n nhtjfng h o p chat nao sau day?
A. Ca(HC03)2, Mg(HC03)2

B. Mg(HC03)2,

CaClg

C. CaS04, MgCl2

D . Ca(HC03)2, M g C l g
151


C a u 40: Cho sa do phan uTng: A U C S O J j ^ X ^ Y - > A l . .
Trong scf do t r e n , moi m u i ten la mot phan ufng, cac chS't X, Y Ian Itfgt la
nhiJng chat nao sau day?
A. AI2O3 va A1(0H)3

C. Al(OH)3 va NaAlOa

B. A1(0H)3 va AI2O3

D. NaAlOg va A1(0H)3

11. P H A N R I E N G (10 c a u )
Thi sink chi diiac Idm mot trong hai phan (Phan A hoac Phan B)
A . T h e o chu'orng t r i n h C h u a n (10 cau, tii cau 41 den cau 50)
C a u 41: Mot mau k h i t h a i c6 chufa C O 2 , N O 2 , N 2 va S O 2 difgc sue vao dung dich
Ca(0H)2 d\i. Trong bon k h i do, so k h i b i hap thu la
A. 4.

B. 1.

C.

2.

D. 3.

C a u 42: Cho cac phat bieu sau:
(a) Hidro hoa hoan toan glucozo tao ra axit gluconic.
(b) O dieu kien thiTdng, glucozcf va saccarozcf deu la nhCfng chat r a n , de tan
trong niTdrc.
(c) Xenlulozcf t r i n i t r a t la nguyen lieu de san xuat tcf nhan tao va che tao
thuoc sung khong khoi.
(d) Amilopectin t r o n g t i n h bot chi c6 cac lien ket a-l,4-glicozit.
(e) Sacarozo b i hoa den t r o n g H2SO4 dac.
(f) Trong cong nghiep diicfc pham, saccarozo di/cfc dung de pha che thuoc.
Trong cac phat bieu t r e n , so phat bieu dung la
A. 4.

B. 3.

C. 2.

D. 5.

C a u 43: Este nao sau day k h i phan ufng vdri dung dich NaOH dii, dun nong
khong tao ra hai muo'i?
A. CeHgCOOCeHs (phenyl benzoat). B. CHgCOOCgHs (phenyl axetat).
C. C H 3 C O O - [ C H 2 ] 2 - O O C C H 2 C H 3 .

D. CH3OOC-COOCH3.

C a u 44: Tien ha»h len men giam 460 m l ancol etylic 8° vdri hieu suat bang
30%. Biet k h o l liJgrng rieng cua ancol etylic nguyen chat bang 0,8 g/ml va
ciia nildc bang 1 g/ml. Nong do phan t r a m cua axit axetic trong dung dich

thu di/cfc la
A 2,47%.

B. 7,99%.

C . 2,51%.

D. 3,76%>.

C a u 45 : Amino axit X c6 cong thufc H . N C ^ H Y C C O O H ) ^ . Cho 0,1 mol X vao
0,2 l i t dung dich H 2 S O ^ 0 , 5 M , thu diicfc dung dich Y. Cho Y phan ling vira du
vcri dung dich gom NaOH I M va K O H 3M, thu dtfcfc dung dich chOfa 36,7 gam
muo'i. Phan t r a m khoi liicfng ciia nitcf trong X la
A 9,524%

B. 10,687%

C. 10,526%.

D. 11,966%

152