THI GIAI TOAN CASIO NAM 2012 CO DAP AN

<span class='text_page_counter'>(1)</span>PHONG GrAo DUC - DAo T~O BlNH TAl'JHUONG DAN cHAM GrAr ToAN TREN MAy TlNH cAM TAY Nam hoc: 2012-1013. .Dt. PHONG GIAo Dl,JC - DAo TAO HUY€N SiNH TAN. I. I. DE CHiNH'THUC. THI GIAI ToAN TREN MAy TiNH CAM TAY Narn hoc: 2012 - 2013 Thai gian lam bai: 120 phut Thi sinh lam bal tren d~ thi. Cnu 'I: Cec ket qua lam iron den cnir s6 th(Jp phan ttur 6. l.oai may tinh thl sinh SLr dunq: ...Casio fx-570ES ...: Cau 1: Tfnh a) A = tg3S015'-1 =. I - 0,549249. Cos67°20'. l... (O,5d) b) S = 3 - Cotg62°1O' = 2 - Sin42°35'. j. l. (O,5d). 1,868015. Cau 2: Cho bi~u thirc f(x,Y) = X2 + 2y2- xy - 1. Tlnh gia tri bi~u thuc khi a) f(x = 0,123; Y =. !). =. I. 0,047879. ~(O,5d) b) f(x = -1,52; Y = ~) =. Cau 3: Cho biet n 113 s6 tu nhien. Tinh tong T = 1 + 1.. +. .. I. + _1 2n khi n =1_:...=0. 2. - X. cso 5: Tim. Ket qua r = ... x biet. 5 - 0,25. x3J5. 1,999023. I. = Vi. +! =>. x'. (1,Od)..... 1. 15,25. ....(1,Od).... _l = Vi 4 Loi giai. 5:3j{. 1.... + 1 va g(x) = 2x - 3. Tim s6 du r trong phep chia f(x). cho g(x) 2. _. r-r-. Ket qua T = .. I Cau 4: Cho hai da thuc f(x) = 2x3 + 4x2. I... (O,5d). 15,745956. =. Ket qua. Js(~2:~)=> Js(~2:~) x. =3. (O,5d). (O,5d). x. =1. 1,031845. Cau ,6: Tim gia tri cac chlJ' s6 a,b,c,d,e,f sac cho abc x def4 = 820216, biet rang a 100nhon b 4 don vi (a,b 113 s6 tl,l' nhien nho hon hoac bang 9; dau chi thu tl,l' cac chlJ' so) Loi giai Ket qua Theo d~ bai thl c = 4 hoac c = 9. (O,5d). *) c = 4 thl abc chi co th~ 113: 954; 844; 734; 624; 514; 404. a=. 6.... d = ..1 .. b= c=. 2... 9.... e = ..3 . f = ..0 .. (O,5d). **) c = 9 thl abc chi co th~ 113:959; 849; 739; 629; 519; 409 Lay 820216 I~n luot chia cho cac s6 tren duoc ket qua. Cau 7: MQt rnanh thep hinh vuonq earth 5 dm bi cat mot mieng hinh tam qiac d~u nhu hinh ve. Tlnh dien tlch phan con lai cua rnanh thep, Lai giai ·0·ten tlIC h t am qrac ., d>-a2 eu can hi'a a S 1 = -A. J3. 4 2 Dien tich hinh vuong canh a 113 S2 = a . Dien tich phan con lai:. (O,25d). 2. S = S2 - S1 = a2 - a ; S = 14,174682. .. Ap dunq. voi a = 5 dm ta duoc. (O,5d) (O,25d). Ketqua. S=. I. 14,174682. I.

<span class='text_page_counter'>(2)</span> Cau 8: Hlnh thang vuonq ABCD c6 ABIICD, canh g6c vuonq AD = 7 cm, dU'ang cheo AC = 10cm, g6c 13 = 540. Tlnh dien tlch hlnh thang D Loi giai AH = DC = .Jl02 _72. HC. HB = -. tgB. SABCD. 1 2. = -(2. => *. =. '1. J5i; HC = AD. =7. (O,25d). E. u t'--. 1. = - (DC + AB)AD = - (DC + AH + HB)AD. SABCD. 2. 2. HC tgB. 1 2. DC + -)AD. c: +. = -(2x-v51. 7 )7 tg54°. Cau 9: Tim cac so nquyen duonq x, y sac cho: 3x2 + Loi giai Ta c6: = 1999 - 3x2 > => 0< X < 25,81. (0,5d). l. 2. => Y = .J1999 - 3x Ta c6 k~t qua: x. .. =. (O,5d). =. (0,5d). x=. 21. .. Y=. 26. .. Tinh U20bi~t Uo = 1023. K~t qua. U1 = Uo + 0,1%Uo. U2 = U1 + 0,1%U1 = Uo + 0,1%Uo + 0,1%(Uo + 0,1%Uo) = Uo + 2. 0,1%Uo + (0,1%)2 Uo= Uo(1 + 0,1%f U3 = U2 + 0,1%U2 = Uo(1 + 0,1%)2 + 0,1%Uo(1 + 0,1%)2 = Uo(1 + 0,1%f(1 + 0,1%) = Uo(1 + 0,1%f Un = Uo(1 + 0, 1%)n. Ap dunq voi Uo = 1023; n = 20 ta duoc (£)ung hoan toan cho 1,Od) Thi sinh lam each khac dung cho diE§mtU'O'ngdU'O'ng. --- H~t ---. (0,25d) S = .1----'--6-7,-79-0-2-9-1 --,. K~tqua. Cho x nhan cac qia tri 1; 2; 3; ... ; 25 21; Y 26. Cau 10: Cho day so Un = Un-1 + 0,1 %Un-1. n = 0, 1, 2, Lai giai. K~tqua. = 1999.. °. l. H. A. U20 =. I. 1043,655541.

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