EIE209 Basic Electronics
Diode circuits
Contents
• Diode models
• Typical diode circuits & applications
• Load line concepts for nonlinear load analysis
Prof. C.K. Tse: Diode circuits
1
What is a diode?
Simplest view (no physics):
— a unidirectional device
that allows current to flow in
one direction but not the
other.
Ideally, we regard a diode as
short circuit when voltage
applied to it in the forward
manner is positive.
Prof. C.K. Tse: Diode circuits
2
Ideal characteristic
Bias conditions
Forward bias : vd > 0 — current can flow and id > 0.
Reverse bias : vd < 0 — current cannot flow and id = 0.
id
id
Ideal diode
with finite forward drop
(more realistic)
vd
Prof. C.K. Tse: Diode circuits
0.7V
vd
3
Real characteristic
Take a closer look at the characteristic around the
turning point.
The i-v characteristic is an exponential function.
id
From physics, we have
id = I ss (e q vd
/kT
Also, the diode can only stand the
negative voltage up to a certain
threshold VBD , beyond which
the diode conducts reverse
current (breakdown).
- 1)
–VBD
breakdown
Prof. C.K. Tse: Diode circuits
vd
0.7V
4
Which model to use?
The choice depends on the external voltage magnitudes.
Ideal model:
id = 100/100 = 1 A
With 0.7V drop:
id = (100–0.7)/100
= 0.997 A
Ideal model:
id = 10/100 = 100 mA
With 0.7V drop:
id = (10–0.7)/100
= 93 mA
Prof. C.K. Tse: Diode circuits
Ideal model:
id = 2/100 = 20 mA
With 0.7V drop:
id = (2–0.7)/100
= 13 mA
5
Example: rectifier circuit
The ideal model is valid if the external voltages are well above 0.7V.
What is the magnitude of vr ?
Crude — 50 V
Better — 50 – 1.4 = 48.6 V
Prof. C.K. Tse: Diode circuits
6
Application examples
clamper
dc restorer
half-wave doubler
Prof. C.K. Tse: Diode circuits
full-wave doubler
7
A nonlinear circuit problem
Suppose we wish to find vd , given that the external voltage Vs is not large
enough to validate the use of the ideal diode model.
??
Prof. C.K. Tse: Diode circuits
8
Step 1 : locating the operating points
Recall: The characteristic curve/line for a device actually defines where the point (v, i) can lie.
We know
1
the operating point (vd,
id) is somewhere on the
diode characteristic curve
2
the operating point (vR, iR)
is somewhere on the
resistor characteristic curve
Prof. C.K. Tse: Diode circuits
9
Step 2 : KVL & KCL constraints
We also know
from KCL : id = iR
AND
from KVL : vd + vR = Vs
= Vs
O
+
=
Prof. C.K. Tse: Diode circuits
10
Step 3 : enforcing KVL & KCL
Method:
flip the resistor curve horizontally; and
push the two curves together horizontally until the y-axes are Vs apart.
push
push
add to Vs
Prof. C.K. Tse: Diode circuits
11
Solution : load line
The flipped resistor line is called the LOAD LINE.
Prof. C.K. Tse: Diode circuits
12
General problem
+ vR –
How to find vd and id ?
iR
id
R
:)
Vs
+
_
id
+
vd
–
nonlinear device
vd
Prof. C.K. Tse: Diode circuits
13
Basic load line construction
+ vR –
iR
i
R
:)
Vs
+
_
id
+
vd
–
slope = –1/R
id
device
characteristic
nonlinear device
vd
Prof. C.K. Tse: Diode circuits
v
Vs
14
Alternative construction
+ vR –
iR
i
R
:)
Vs
+
_
id
+
vd
–
id when
device is
short-circuit
nonlinear device
device
characteristic
load line
v
vd when
device is opencircuit
Prof. C.K. Tse: Diode circuits
15
Tutorial problem
Find the operating point.
Prof. C.K. Tse: Diode circuits
16