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. /0"1!0D23,!4!0%5%678
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F
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<)!0J78*AB>C:C>-*AE>C"
*+,
)-!!./01234(56(./0!738
2.1. Tải trọng bản thân của KCPT và các bộ phận khác (DC
1
)
!3 9./7:
KLM<:NOIP?A
;<=>7?@A>?@>7?@B>C?@@D
EF
70%4 K2Q3<G"RS!Q"T*C"
C
*C>A-
B
""
C
U23<)QV<&P*=-"*=>A-
E
""
2Q3W;5PQ"T*C
γ
2F37XYZF[(*C? \"
@
A*C>A-
B
]=>A-
E
]C]C? ]+>^A]A-
.+
*B^B= 23
2.2. Trọng lượng lớp phủ và lan can (DW)
_*2_
A
9_
C
3
_
A
7XYT!XPF[0`WP!X
_
C
7XYT!XPPF[(XJa>
_*+,^A{-,-?]=-]2AE,^:-,?3]C@ 9C]A ]=-}
*ACBBBA^23
2.3. Hoạt tải (LL) và tải trọng bộ hành (nếu có)
Kb%c]dPM<<!VI7NYPW!
Ae/M<<dd2UU39M<7XV<dd2+>@\"3
Ce/!<782UU39M<7XV<dd2+>@\"3
@+-f]2-C]/M<<dd2UU392CXV3M<7XV<dd+>@\"3
U
*"]]UU
70%4
UU*"!]2UU
A
,UU
C
,UU
@
3
=G"H@I(-J.//I$I
KLM<:NOIP?A
* Trường hợp 1:2UU
A
3A]/<dd9M<7XV
UU
A
*AE?2A9g
A
39@?>g
C
9
C
@,+ xL
+E,-
=-
@,E.=-
A
A
==
Y
^==,-
=-
@,E.@,E.=-
A
C
==
Y
⇒
UU
A
*B@=E+?23
* Trường hợp 2 (LL
2
)A]/C789M<7XV
UU
C
*AA-2A9g39
C
@,+ xL
?E@BA-
+^@,-
=-
C,A.=-
A
C
A
=⇒
==
LL
Y
KLM<:NOIP?A
* Trường hợp 3 (LL
3
)-,+2C]/M<9M<7XV3
UU
@
*-,+hAE?2A9g
A
9g
E
9g
?
39@?2g
C
9g
@
39+,@>Ui
g
A
*
+E,-
=-
@,E=-
=
g
C
*
^==,-
=-
@,E.@,E.=-
=
g
@
*
=^B,-
=-
A?.=-
=
g
E
*
=CE,-
=-
@,E.A?.=-
=
g
?
*
BB@,-
=-
@,EC].A?.=-
=
⇒
UU
@
*A-=CE?^23
,KC.-J./%L,
M<7 O< g< O<]g<
e/M<<d
d
AE? A AE?
AE? -,+E A@B,@
@? -,^== @-,=
'j*`]"] AB?=E^=
e/!<78
AA- A AA-
AA- -,+^@ A-^
'j*H]"] AEA@@^B
C]/M<<d
d
AE? A AE?
AE? -,+E A@B,B
@? -,^== @-,=
@? -,=^B C=,?A
AE? -,=CE A-E>+^
AE? -,BB@ +B>A@?
'j*]"] CB?^A@-
M<7
XV
+,@ ->?]UW2UW3 *+>@]->?]UW]"]*
C=^^E
KLM<:NOIP?A
k*+>@]UW]"]*AB+C>B
UU
"!]
*UU
@
⇒
UU*UU
@
*A-=CE^-23
⇒
U
*->B?]E]A-=C>E^*C=^^E 23
2.4. Lực hãm xe (BR)
Hl*-,C?2AE?]C9@?3]"]
< "*-,B?2mn@3
*E
Hl*CAAC?-23
I!%o%;<m<%IFGQ
Hl
*AB>C9->@9C>C*A^>=2"3
2.5. Tính tải trọng bản thân của trụ (DC
2
)
<!78VCP
.O"78*?CC-2""3
.OJ78,!*:?CC-*AEC ?CC-*^+^-2""3
OJ78aP70XV?? 2""32/0"10)
Vp"*=>?"3
*+70:M
"
*^,=B?>A-
A-
2""
@
3
⇒
"
*^=,B?2"
@
3
KLM<:NOIP?A
J
*2?A ]@ :A ]A ]C3]^+^-
*A>A+]A-
AA
2""
@
3
∑
*C-B,B?2"
@
3
C
*>
γ
F[(]+,^A*?-B^-+A23
2.6. Tải trọng nước (WA)
- Lực đẩy nổi
_
`
*A ]+,^A22?A ]@ :A >A >C3]?? 9AAC ]^C ]C 3>A-
.+
*C?A+?-C>@23
.qPX1QoMQ/0dDPQ<
2Q3GW;MT!78*A>E2m%78m(3
a;<dd,/0X<dd2"\W3
P*?,AE>A-
.E
>
Q
>
@
Q
*A,E
P*?,AE>A-
.E
>
Q
>
@
*-,-A+EO!
_`
C
*->-A+E]2@ ]?? 9^C >C 3*B@+CC-23
I!%oXVQ
_`C
*A>B@"
.qPX1/0<)!78
_`*?>AE]A-
.E
]2X3]
@
70%4
_`qPX1QoM/0<)Q7823
2X3GW;MT!78/0<)!
QoM7rs2X3*-s_`*-
2.7. Tải trọng gió (Ws, W
L
)
• Tải trọng gió ngang
_W23*-, B]
C
]`
>
Q
<!VID<G&X1<4!V<)PU!!2_KA3t"T
2_KC3t782_K@3tJ782_KE3
Q
*A,E
*@?"\W
Q
*E
`
A
*-,@>=-*CA"
C
`
C
*C,C>=-*A?E"
C
`
@
*?,CC]@*A?,BB"
C
`
E
*@]2AE>C:?>CC:?>?3*A->EE2"
C
3
O
Q
*A,-@`uA,^`
_KA23*A>^]`
A
*@=^
.I!%oXVQ
A
*AB>C9->@9C>C9->A?*A^>^?"
_KC23*A>^]`
C
*C==C
.I!%oXVQ
C
*AB>C9->@9A>A*A=>B"
_K@23*A>^]`
@
*C^A^^
.I!%oXVQ
@
*AB>C.?>CC9?>CC\C*A@>?+"
KLM<:NOIP?A
_KE23*A>^]`
E
*A^=+C
.I!%oXVQ
E
*2AB>C.?>CC:=>?3\C9=>?*+>CE"
⇒
_K23*A,^`*@BA+^-23
• Tải trọng gió dọc
._WQ*-,C?_23*++C=-23
I!%oXVQ
_KQ
*A?>^?"
• Tải trọng gió td lên xe ( WL3
9_U
Q
*A,?UW*A-?23
9_U
*-,=?]AE,^*AA,A23
I!%oXVQ
_U
*A^>="
UaPFM'YPM<7
*GW;]2
A
9_9UU9
C
:O
`
3
.56(./0
vFM7[
"!]
*A+A=+@BA23
!"#LN#./O,0
PL1Q0
1.1 Chọn cao độ mũi cọc
J/3R$-,)S$-,@,-"T32UD:S*(V3&("'%L,W
wUPAKx,"V]I"mV,J% ,7yI<z!{>KO*CB
.H)QVXP%DXVC>?">
.!0%5"RXPAXV->-",!0%5%IXV.C>?">
.70XPV%#<dVXDmV<G"-A"|%D[Qy,<I7&"5W;
6<[bX}%Y<70FM'YP
wUPCKxP!,"V]I",7yI<Q~0")">KO*B>=?
.H)QVXP%DXVAB>^">
.!0%5"RXPCXV.C>?",!0%5%IXP@XV.A+>@">
.70XPV%#<dVXDmV<G"AA"|%D[Qy,<I7&"5W;
6<[bX}%Y<70FM'YP
wUP@KxP!,"V]I"mV,[% ,7yI<{>KO*@B>=
.H)QVXP@XVnAE>=">
.!0%5"RXP@XV.A+>@"
KLM<:NOIP?A
.70XPV%#<dVXDmV<G"-E"|%D[Qy,<I7&"5W;
6<[bX}%Y<70FM'YP
XN12-C.Y/8G3O,!3&("'
A&(L A&(L) A&(LV
ZLR[/8
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%D 7; 7 F,
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/ * ->+E+ n ->= %D
7•<),%Dd>
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I
< ->AE u ->C?> %D
7yI<z!{>
L
I
< ->?B n->?> %D
7yI<Q~0")">
L
I
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uu
C
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@
>
N %5 X1 Q
X,&X1;>
uu
C
< CA>@ \"@>
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uu
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%5X1QX,&X1
;>
;-"KS,8C0L,--:M/0^:-3&("'LV"_K$.X#
3[0,-"T:M/032EUD:
1.2 Chiều dài cọc
<)QV<0IU
2!Z<)WJV"mV0FG3
U
*!H:*-,-:2.=-3*=-">
<)QV<0IU
U*U
9!*=-9A*=A">2<!XV<)QV<aP70FG3
1.3 Mặt cắt ngang
KLM<:NOIP?A
C> =N#./70O,0"G
KLM<:NOIP?A
C>A Theo vật liệu
Chọn vật liệu làm cọc như sau:
• H[(•
‚
c
*@-P!
• ;xPQC-!ƒ@C,•
y
*EC-P!,`
st
*^A?""
C
0&X1Q78X[4Z0<6&x,Q0%4
Công thức tính toán:
l
r
*„l
n
70%4 l
r
K{IQ780I>23
l
n
tK{IQ78Q!%&>23
l
n
*-,^>…-,^?>•
‚
c
2`
.`
W
39•
y
>`
st
†
2;<m<D<G;%!<N3
‡GW;W{IXDFˆ-,=?>
`
g
<G"RS[2""
C
3
`
st
<GA;xP2""
C
3
•
y
XVN%5&x0T!xP2O!3>
•
‚
c
XVN%5$%&T!F[0‰'<C^V>2O!3
!4`
*@>AE]A?
C
]A\E*A=B=AEB2""
C
3
`
W
*C-]^A?""
C
C
AB@^-
->+@f ->^f2 \ 3
@>AE A? \ E
st
g
A
t m
A
= = >
×
K7!K{IQ!%&Q78T!0/0T!maX<G
l
*->^?]…->^?]@-]2A=B=AEB.C-]^A?39EC-]C-]^A?†
l
n
*`VUU@D
a
a=N#./70O,0\-143/Z
l
r
*->=?]@>^^]A-
=
*V)a)@D
U
KLM<:NOIP?A
C>C Theo đất nền
*Ma sát thành bên
PNW
us
Sq ×=
α
α
GW;QFI">
u
S
N%5S(0I2O!3>
Ku->CsŠ*->??
Chiều dày tính ma sát
L
1
= 2-1.5=1(m)
L
2
= 16.8 (m)
L
3
= L
c
-L
1
–L
2
-D = 70-1-16.8-1.5 =50.7(m)
A> A
si
=
i
D L
π
× ×
( với D= 1500mm)
C> Q
si
= A
si ×
q
si
@> Q
sri
= Q
si
×
�
si
Kết quả được trình bày trong bảng sau:
>
[
%D
<)
QV2"3
K2
P!3
\@-
"
Š $
W<2P!3
<)QV
"!
WI
`W<2""C
3
‹
W<
23 „
W<
‹
W7<
23
A Kx C>?
->-E^
+
CB ->??
->-C^^+
?
A E=AC@^^ A@BABE ->B? ^^?-B
C
Kx
P!
AB>^
->-CA
@
B>=? ->??
->-AA=A
?
AB>^
=+AB^A@
E
+C=E?? ->B? B-C^E?
@
Kx
P!
?->=
->-E+
=
@B>= ->??
->-C=@@
?
?->=
C@^,+]A-
B
B?@-@@
C
->B? ECE?]A-
@
K{I"!WI0I E+@B23
*Sức kháng mũi cọc
.;<m<&M<7Q787%DQ,W{I%bm&"<Q!%&
T!0!2O!34ZW!
$
P
*
K
ŒE
‰%J
*BhA9->C23i*BC•+
KLM<:NOIP?A
⇒
*+
⇒ $
P
*->C?]+*C>C?
C
E
p
D
A
π
×
=
*A>==×10
6
2""
C
3
v%4%Y
pr p p pr
Q A q
ϕ
= × ×
*->B?×A>==×10
6
×2.25 =2 589(kN)
=N#./O,0\-"'Q32W
R sr pr
Q Q Q= +
*E+@B9C?^+*=?C?23
=N$!-!O,0"G>
K{IQ78T!%b%Y]I%<W!
"< 2 t 3
tt vl dn
R R R=
*"<2@C^C-t=?C?3*=?C?23
ŽŽŽ> 0L3%6012C0-:K
A> 0L3%60
K;XYWbF5%Y/0({W!
*C>??
W;<ddXV*B
>
70%4
l
UVW{&M<1T!%b>23>
UVX1•%{0Iy<J"%I%#JGW;>23
KLM<:NOIP?A
4500
1100
1850
4500
d=1500
)0-:K
I%YF;7/0{X<(m(7["RFˆmV0V0V•
%{7["R%{,m<I(W;
• 'W;70"4*B
• K;V/0PbQ*C
0MI<"IV/0PbQ*E? ""t
• K;V/0Pb!"*@
0MI<"IV/0Pb!*E? ""t
• 0MIv<"0V<r%d"xPFG/0M!<PbQmV!
A
*AA ""
C
*A^?-""
bcdecfgdhgij]k
/_:-!LN$!70O,0"G
a. Tính nội lực tác dụng đầu cọc
KzQ8b7•H:OŽklE!%Y5<X1T!W!
O70‘/X<//K!<
O70‘/!"/00!0<
O70‘/"!!/7"’"
0"P/QF
O70‘/Q/W7<P<0
lllllllllllllllllllllllllllllllllllllllllllll
lllllm/,3,@/::Ln-,333-,7,L\Llllll
llllloefplllll
KLM<:NOIP?A
lllllllllllllllllllllllllllllllllllllllllllll
f\L3q(\,3\A-,7-:Co/3\
lll,@/::(/3\n-\Llll
,@L\,/)7/\/-DrsaetD)Dr
,@L\,/V7/\/-ED)`DetDD)
,@:-:\,C-),@/LED`Ur)etD)ED)
,@:-:\,C-V,@/LEDV`)etD`EDr
,@,@/,3n-\EDVasetD`D)
,@-L/-,3n-\Drs)`eED)ED)
,@7\:,7u,(,/q,/-DVD)UetDDDV
4q
!]m
<Vas>?J/1#0L)
C. Kiểm toán sức kháng dọc trục của cọc đơn
({<Z"0I
"!] tt
N N R+ ∆ ≤
70%4
"!]
5<X1XDIQ8X[%2X1Q783>
N∆
7XYFMJ%b24]x%dX1%“'<323
l
K{IQ78T!%b23>
!4l
*=?C?23
*U
>K
0
>2”
F
:”
3>A-
.+
*=- ]
C
A?
E
π
×
]2C? A 3]+>^A]A-•.+
*A^C-23
a
NN
max
∆+
*?B=A23
≤
l
*=?C?>3<v]J
)/_:-!LN$!70O,K:0
({<Z"0IW{IQ78T!4"
2 3 2 3c gr gr c gr d
V Q Q Q
≤ = +
'X1Jx4"%#JGW;>
‹
7
K{I%–Q780IT!4">
‹
723
K{I%–Q78T!0I4"F‰<%DI>
KLM<:NOIP?A
‹
72Q3
K{I%–Q78T!0I4"F‰<%DQ>
‹
72Q3
*"<2‹7At
‹7C3
70%4
o ‹7A*n
c
x η x ( φs
1
x Qs
1
+ φs
2
x Qs
2
+ φs
3
x Qs
3
)= C× @×
->B?×E+@B *A+C?-23
70%4—*->B?2m\Q*@3
o ‹7C*φ
g
[2(X+Y)x (z
1
Su
1
+ z
2
Su
2
+z
3
Su
3
] + XY N
c
K
70%4
e <)QV<T!4"2v"xP!<
0V<r32""3
g <)75T!4"2v"xP!<
0V<r32""3
˜ <)WJT!4"2""3
GW;P85™W;˜\e
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g*A]E? 9A? *B ""
˜*E 2""3
˜\e*= \A-? *B>B=nC>?
*=>?2A9->C3*=>?2A9->C3*A->AC?
≫ ‹7C*->B×2C×10500+2×6000)×(0.0489 x1 +0.0213x 16.8+ 0.0497
x50.7) +10500x 6000 x10.125 x0.25x 10-3 =217414 (kN)
4qw>7?<:/xwSw)y
*"<2A+C?-t 217414 3*A+C?-23
≫‹7*‹7239‹72Q3*-9A+C?-*A+C?-23
<Z"0I
2 3 2 3c gr gr c gr d
V Q Q Q≤ = +
!4A+A=+uA+C?-2y3
KLM<:NOIP?A
bcdecfgdhg=z;{
A>
!"#"T3|5"#
0XP&X1TZXVXPWx,({Xšr5mV0"{%5;
d
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->-
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F
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⇒ <
A
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7XYZ1<[T!XPA2\"
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@
3
A
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C
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@
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.B
• *->EC@2P!3
KLM<:NOIP?A
eA*e9CA\E*CCA
gA*g9CA\E9A=B
⇒ *->-E+2P!3
⇒ 5Xš*KA
⇒ KA*A^>A=""
) !"#q_1#,O,"0
Điều kiện : u
max
≤ 38 mm
( Theo tiêu chuẩn thiết kế 22TCN-272-05 phần nền và móng )
Sử dụng chương trình FB – PIER V4 ta tính được
*********************************************
***** Final Maximums for all load cases *****
***** PIER # 1 *****
*********************************************
Result Type Value Load Comb. Pile
*** Maximum pile head displacements ***
Max displacement in axial 0.4056E-02 M 1 0 5
Max displacement in x 0.1441E-01 M 1 0 1
Max displacement in y -0.1669E-06 M 1 0 6
Ta thấy chuyển vi ngang ở đầu cọc lớn nhất:
- Theo phương x: U
xmax
= 0.01441 m = 14.41 mm <
38mm => Đạt
- Theo phương y: U
ymax
= -0.1669 x10
-6
m = 0.1669 x10
-3
mm < 38mm => Đạt
}cd~•oc€
/_:-!1Q:P:\>
!>"0"/y<"RS<Z"0I>
KLM<:NOIP?A
5<X1%2]I%&vb70I5<X1%3b{
m<M<
7IQ8X[%I"4‰N%5%#JGW;2/0•H.P</73
A
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Ÿ`•
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C.@^?A>-
@.C^^=>E
E.C^?A>A
?.@^?A>-
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