Trờng thcs Cảnh Hoá. bài kiểm tra 15 . Môn: Hình 9 Chơng IV
Họ và tên: . . . . . . . . . . . . . . . .. . . .
Điểm
Lớp: 9 Ngày ...tháng 04 năm 2011
Lời phê của Thầy, Cô giáo
Đề 01
Tính thể tích và diện tích bề mặt của vật thể theo kích thớc đã cho l cm ( nửa hình cầu và
hình nón) Ly s pi l 3,14 v lm trũn kt qu cui cựng n ch s thp phõn
th nht n v l cm
Bài làm
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Hớng dẫn chấm đề 01
a)
2
2
3
3
Vbáncầu= π .r = π .6,9 = 219, 06π (cm3) (1,5đ)
3
3
1
1
2
2
Vnón= π .r .h = π .6,9 .20 = 317,4π (cm3) (1,5đ)
3
3
Thể tích của hình là:
219, 06π + 317,4π = 536, 46π = 1684,5(cm3) (2đ)
b) Diệ tích bề mặt là:
Sbán cầu = 2π 6,92 = 95, 22π = 95,22.3,14 = 298,99 (1,5đ)
S nón = π rl = π 6,9. 202 + 6,9 2 = π 6,9. 447, 61 = 458,38 (2đ)
S = 298,99 + 458,38 = 757,37 (cm2) (1,5đ)