Đề đáp án Sát hạch 10D lần 2 2011.THPT Lê Xoay

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TRIS&!$C TIIFT LN XOAY
N^lM HAC 2010 - 2{111

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- 2x - 2 vel*rt 16 y = (m +Zi}x - m -5 (d*), (pt
H tham s6)
1. Ch&!g minh ftigv6i mgi rr thi (d,) luOn cIt (P) tai or$t di$m cO A!*.

Cf,u

I:

A/ly'tCho prabal (P): y

x2

2. Tim i A(d,) sit (Plt?r h$ di6m A, B sao cln AB = t€.
Ciu II: (3 iliem)
1. ciei b.it phuong tinh: .FI>.ffiT
- f.
2. cieihQphuongrinh:
e
CSu

Itrfl=zJv
[Jt +./sY =3

(v,ye R)

III: (I itid;l.4Cho qb, c duong thda mifn a2+b1+c2=3. Tim gi6 tri,nhd nnit cria bi6u thrlc
bt - "t
P:LJzuz +l J2c2 +t Jza'+7

Ciu IV: (2 iti6m)
1.

2.

*
Cho hinh thang ABCDwdng tei A ve D, c6 AB/ICD, AB a, AD =2a vi BC = 2a&
Tinh dign tich hinh thang ABCD.
Chfmg minh rlng trong mgi tam gi6c ABC, ta c6 (r' -&z1sinC = c2 sin(.2{ - Bl .

.

Ciu V: (2 iIiAfi
r
1. fiong m4t ph*ng vdi h€ to? dS Oxy, cho tlu&ngtren (C) : xt+y2+2x-8y-g=0. Vi6t
phuons trinh etuang th*ng song song v$i dudrng thios d: 3x*y-2=0 vi cit du&ng tron
cungi6 do dei be,e 6.
it ro Jot ddy-phini
O*y, cho t"* gi6c ABC bi6t hai canh c6 phuong trinh. h
2. Tr€n mAt

AB:5x -Zi+6=O va AC:Ax+7y-21=0. Vi& phuong trtnh c4nh BC, biiit reng
trgc t6m crla tam gi6c ABC tnrngvdi gfo tqa d0-

n6t----


l-6l'll

CAU

ISOI

"flrudfg

DUNS

Srfi froiinhdQ girols6n
*2 -2x -l'-(m+2)x - m-5c+

I

.

[r=l

r

#

*wlr

'

-(ar +4)x+..m+3 =0
l,O

-<31

l

(rdfu

[x=m+3

vdi x'*1 thl y -

cir'(f;}Jrt A$ i:39 rii di{rh.
2.- ffieo
voi msi m'thl ffiff.fufu atit?)' At'hai dffi ?f( h-3Xif
B(m+3 ;(rn+2[m+3)-m-5).
-3. v6v

ti4

{$)

ABL' (ar* 2)e + (n+ e)' r.2,€{,o + 2}' - t

*rr.
6T>ffiT-t{$

*l;:

0.5

-1,

l. DI(

02s

Ts,#f*I

oJs

;ffi;i;t#rFTt;;i
<+

n
€

.n'?

0,25

- 6x +5 { 0 <+ x e{}51,

02s.

2DK:x+yi0,x-y>0,y>0'

ifi6m1

"T(lle

zr+qffi

=4y<,*,r[fi =ty-x

0;25

0

(3)

lSY'=4xY

(4)

fZy-.r

<+{

Pf(4),tty*.g v 5y = 4x
Vdi y = O SrA,v*o t*T{e),ta o6 x,+ 9 (Ktdnsr&men dk (3})
Vdi 5y = 4x th6vio PT(Z) ta cd G *?..F = 3 <+ r = I
Tiir

K!: ffif
Ta c6

a?

&3

m
(I dilm)

e6

0.5

t whi?tr tx;y)

=(t;f)

,Jffi
e

- 2a2
3"

bJzc'+7

- 2b2

>

0,5
0,5

Os
0,25

0,5

ct

"Jffi
9
JLaz +l

:

swra

-

2;cz

3

p*qlqn.ilry''W>r

M6t khda

.s5


a{8fr.b,m
=---T ;Jffi

9

s;JWffi=1
t_

P > l. B&ig &fe xiv ra khi aafi=c=l, Viv P-.- = I trhi *stu**:l
l. Trl gi4 flridt suy ra BD =".,fr.
Ggi H h hinh chi6u cia B l€n CD suy ra HC = 2a zuy ra DC=3a.
Do d{6, di$n tich hiah thang Sr*o = 4a2.
Suy rs

IV

1.0

a2-b2_sin2,
0.5

,i"tz:r};il(rua-sil(x:rl.
- 6)siTr(l + .6} * sry{r{ - 4}
--]i"il
ri,t?

_ s-r{t(.{

0.5

I. Dudng tron (C) c0

trri'ng;fie;s [songsons

"di

d c6 d?['s

Theo gie thi6t suy ra d(r, a ) = 4c>

v

3il;J;:0.--*-**--

lgl=

4 (+

./10

l* =-1+_ aJi6'

l_*

coZdudnstt'& A dtdmett
Li 3x+/-I+4Ji =0 vi 3x-l-I-4r[=0.

=*t

4"25

0.5

4._/in

0.25
0.5

urxrg rg ouCIng cao tu {Ilnh U co phuong trinh 2x + 5y =0.
I
Sw ra CG5/2-71
r__*..._-J--:-_1-*
Phuong tti"t auffidThru Bc ra y = -;*"

a.2s
0.2s