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Control Structures

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2003 Prentice Hall, Inc. All rights reserved.
1
Chapter 2 - Control Structures
Outline
 Control Structures
 if Selection Structure
 if/else Selection Structure
 while Repetition Structure
 Formulating Algorithms: Case Study 1 (Counter-Controlled
Repetition)
 Formulating Algorithms with Top-Down, Stepwise Refinement:
Case Study 2 (Sentinel-Controlled Repetition)
 Formulating Algorithms with Top-Down, Stepwise Refinement:
Case Study 3 (Nested Control Structures)
 Assignment Operators
 Increment and Decrement Operators
 Essentials of Counter-Controlled Repetition
 for Repetition Structure
 switch Multiple-Selection Structure
 do/while Repetition Structure
 break and continue Statements
 Logical Operators
 Confusing Equality (==) and Assignment (=) Operators
 Structured-Programming Summary

2003 Prentice Hall, Inc. All rights reserved.
2
Control Structures
• Sequential execution
– Statements executed in order


• Transfer of control
– Next statement executed not next one in sequence
• 3 control structures (Bohm and Jacopini)
– Sequence structure
• Programs executed sequentially by default
– Selection structures
• if, if/else, switch
– Repetition structures
• while, do/while, for

2003 Prentice Hall, Inc. All rights reserved.
3
Control Structures
• C++ keywords
– Cannot be used as identifiers or variable names
C++ Keywords

Keywords common to the
C and C++ programming
languages

auto

break

case

char

const


continue

default

do

double

else

enum

extern

float

for

goto

if

int

long

register

return


short

signed

sizeof

static

struct

switch

typedef

union

unsigned

void

volatile

while


C++ only keywords

asm


bool

catch

class

const_cast

delete

dynamic_cast

explicit

false

friend

inline

mutable

namespace new

operator

private

protected


public

reinterpret_cast


static_cast

template

this

throw

true

try

typeid

typename

using

virtual

wchar_t





2003 Prentice Hall, Inc. All rights reserved.
4
if Selection Structure
•inC++
If student’s grade is greater than or equal to 60
Print “Passed”
if ( grade >= 60 )
cout << "Passed";
true
false
grade >= 60
print “Passed”
A decision can be made on
any expression.
zero - false
nonzero - true
Example:
3 - 4 is true

2003 Prentice Hall, Inc. All rights reserved.
5
if/else Selection Structure
• if
– Performs action if condition true
• if/else
– Different actions if conditions true or false
• Pseudocode
if student’s grade is greater than or equal to 60
print “Passed”
else

print “Failed”
• C++ code
if ( grade >= 60 )
cout << "Passed";
else
cout << "Failed";

2003 Prentice Hall, Inc. All rights reserved.
6
if/else Selection Structure
• Ternary conditional operator (?:)
– Three arguments (condition, value if true, value if false)
• Code could be written:
cout << ( grade >= 60 ? “Passed” : “Failed” );
truefalse
print “Failed” print “Passed”
grade >= 60
Condition Value if true Value if false

2003 Prentice Hall, Inc. All rights reserved.
7
Nested
if/else
structures
•Example
if ( grade >= 90 ) // 90 and above
cout << "A";
else if ( grade >= 80 ) // 80-89
cout << "B";
else if ( grade >= 70 ) // 70-79

cout << "C";
else if ( grade >= 60 ) // 60-69
cout << "D";
else // less than 60
cout << "F";

2003 Prentice Hall, Inc. All rights reserved.
8
if/else Selection Structure
• Compound statement
– Set of statements within a pair of braces
if ( grade >= 60 )
cout << "Passed.\n";
else {
cout << "Failed.\n";
cout << "You must take this course again.\n";
}
– Without braces,
cout << "You must take this course again.\n";
always executed
•Block
– Set of statements within braces

2003 Prentice Hall, Inc. All rights reserved.
9
while Repetition Structure
•Example
int product = 2;
while ( product <= 1000 )
product = 2 * product;

product <= 1000
product = 2 * product
true
false

2003 Prentice Hall, Inc. All rights reserved.
10
Formulating Algorithms (Counter-Controlled
Repetition)
• Counter-controlled repetition
– Loop repeated until counter reaches certain value
• Definite repetition
– Number of repetitions known
•Example
A class of ten students took a quiz. The grades (integers in
the range 0 to 100) for this quiz are available to you.
Determine the class average on the quiz.

2003 Prentice Hall, Inc.
All rights reserved.
2 // Class average program with counter-controlled repetition.
3 #include <iostream>
4 using std::cout;
5 using std::cin;
6 using std::endl;
7 // function main begins program execution
8 int main()
9 {
10 int total; // sum of grades input by user
11 int gradeCounter; // number of grade to be entered next

12 int grade; // grade value
13 int average; // average of grades
14 // initialization phase
15 total = 0; // initialize total
16 gradeCounter = 1; // initialize loop counter
17 // processing phase
18 while ( gradeCounter <= 10 ) { // loop 10 times
19 cout << "Enter grade: "; // prompt for input
20 cin >> grade; // read grade from user
21 total = total + grade; // add grade to total
22 gradeCounter = gradeCounter + 1; // increment counter
23 }

2003 Prentice Hall, Inc.
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24 // termination phase
25 average = total / 10; // integer division
26 // display result
27 cout << "Class average is " << average << endl;
28 return 0; // indicate program ended successfully
29 }
Enter grade: 98
Enter grade: 76
Enter grade: 71
Enter grade: 87
Enter grade: 83
Enter grade: 90
Enter grade: 57
Enter grade: 79
Enter grade: 82

Enter grade: 94
Class average is 81

2003 Prentice Hall, Inc. All rights reserved.
13
Formulating Algorithms (Sentinel-Controlled
Repetition)
• Suppose problem becomes:
Develop a class-averaging program that will process an
arbitrary number of grades each time the program is run
– Unknown number of students
– How will program know when to end?
• Sentinel value
– Indicates “end of data entry”
– Loop ends when sentinel input
– Sentinel chosen so it cannot be confused with regular input
• -1 in this case

2003 Prentice Hall, Inc. All rights reserved.
14
Formulating Algorithms (Sentinel-Controlled
Repetition)
• Top-down, stepwise refinement
– Begin with pseudocode representation of top
Determine the class average for the quiz
– Divide top into smaller tasks, list in order
Initialize variables
Input, sum and count the quiz grades
Calculate and print the class average


2003 Prentice Hall, Inc. All rights reserved.
15
Formulating Algorithms (Sentinel-Controlled
Repetition)
• Many programs have three phases
– Initialization
• Initializes the program variables
–Processing
• Input data, adjusts program variables
– Termination
• Calculate and print the final results
– Helps break up programs for top-down refinement

2003 Prentice Hall, Inc. All rights reserved.
16
Formulating Algorithms (Sentinel-Controlled
Repetition)
• Refine the initialization phase
Initialize variables
goes to
Initialize total to zero
Initialize counter to zero
• Processing
Input, sum and count the quiz grades
goes to
Input the first grade (possibly the sentinel)
While the user has not as yet entered the sentinel
Add this grade into the running total
Add one to the grade counter
Input the next grade (possibly the sentinel)


2003 Prentice Hall, Inc. All rights reserved.
17
Formulating Algorithms (Sentinel-Controlled
Repetition)
• Termination
Calculate and print the class average
goes to
If the counter is not equal to zero
Set the average to the total divided by the counter
Print the average
Else
Print “No grades were entered”

2003 Prentice Hall, Inc. All rights reserved.
18
Nested Control Structures
• Problem statement
A college has a list of test results (1 = pass, 2 = fail) for 10
students. Write a program that analyzes the results. If more
than 8 students pass, print "Raise Tuition".
• Notice that
– Program processes 10 results
• Fixed number, use counter-controlled loop
– Two counters can be used
• One counts number that passed
• Another counts number that fail
– Each test result is 1 or 2
• If not 1, assume 2


2003 Prentice Hall, Inc. All rights reserved.
19
Nested Control Structures
• Top level outline
Analyze exam results and decide if tuition should be raised
• First refinement
Initialize variables
Input the ten quiz grades and count passes and failures
Print a summary of the exam results and decide if tuition
should be raised
•Refine
Initialize variables
to
Initialize passes to zero
Initialize failures to zero
Initialize student counter to one

2003 Prentice Hall, Inc. All rights reserved.
20
Nested Control Structures
•Refine
Input the ten quiz grades and count passes and failures
to
While student counter is less than or equal to ten
Input the next exam result
If the student passed
Add one to passes
Else
Add one to failures
Add one to student counter


2003 Prentice Hall, Inc. All rights reserved.
21
Nested Control Structures
•Refine
Print a summary of the exam results and decide if tuition should
be raised
to
Print the number of passes
Print the number of failures
If more than eight students passed
Print “Raise tuition”
• Program next

2003 Prentice Hall, Inc.
All rights reserved.
1 // Fig. 2.11: fig02_11.cpp
2 // Analysis of examination results.
3 #include <iostream>
4 using std::cout;
5 using std::cin;
6 using std::endl;
7 // function main begins program execution
8 int main()
9 {
10 // initialize variables in declarations
11 int passes = 0; // number of passes
12 int failures = 0; // number of failures
13 int studentCounter = 1; // student counter
14 int result; // one exam result

15 // process 10 students using counter-controlled loop
16 while ( studentCounter <= 10 ) {
17 // prompt user for input and obtain value from user
18 cout << "Enter result (1 = pass, 2 = fail): ";
19 cin >> result;

2003 Prentice Hall, Inc.
All rights reserved.
20 // if result 1, increment passes; if/else nested in while
21 if ( result == 1 ) // if/else nested in while
22 passes = passes + 1;
23 else // if result not 1, increment failures
24 failures = failures + 1;
25 // increment studentCounter so loop eventually terminates
26 studentCounter = studentCounter + 1;
27 } // end while
28 // termination phase; display number of passes and failures
29 cout << "Passed " << passes << endl;
30 cout << "Failed " << failures << endl;
31 // if more than eight students passed, print "raise tuition"
32 if ( passes > 8 )
33 cout << "Raise tuition " << endl;
34 return 0; // successful termination
35 } // end function main

2003 Prentice Hall, Inc.
All rights reserved.
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 2
Enter result (1 = pass, 2 = fail): 2

Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 2
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 2
Passed 6
Failed 4
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 2
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Enter result (1 = pass, 2 = fail): 1
Passed 9
Failed 1
Raise tuition

2003 Prentice Hall, Inc. All rights reserved.
25
Assignment Operators
• Assignment expression abbreviations
– Addition assignment operator
c = c + 3; abbreviated to
c += 3;

• Statements of the form
variable = variable operator expression;
can be rewritten as
variable operator= expression;
• Other assignment operators
d -= 4 (d = d - 4)
e *= 5 (e = e * 5)
f /= 3 (f = f / 3)
g %= 9 (g = g % 9)

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