GIÁO ÁN TOÁN SONG NGỮ SỐ HỌC 6 CẢ NĂM- Chuẩn

Preparing date: 31/3
Teaching date: 6/4/16
Period 12. PRACTICE
I. AIM:
1.Knowledge- Sts know powers definition
- Sts have skill finding reciprocals calculating division of fractions, finding variables.
2. Skill : -Train students to be careful and accurate(chinh xac) when solving problems.
II. Method :
Practice, discuss difficutly problems.
III. Matirial:
Colour chalk, sheet of paper
IV. Procedure
1 Organization: 6A
2.Warm-up

Teacher’s ativities
Activity 1:
+ Teachers put test questions
St1: Correct 78 (Workbook).
St 2: Write the sum of the following numbers
as product.
5 + 5 + 5+ 5+ 5; a + a + a+ a+ a+ a
+ Tc: The sum of equals terms we can write
shorthands by can using product. So the
product of many factors equally how we write?
III. New lessons:
Teacher’s activities

Students’ ativities

St 1:

aaa

: a = 111

abab

:

ab

abcabc

= 101

abc

:
= 1001
St2: 5 + 5 + 5+ 5+ 5 = 5 . 5
a + a + a+ a+ a+ a = 6 . a

Student’s activities

Activity 2 :
1,Power of natural number :
+ Tc :We can write shorthands :
2.2.2.2.2.2 =2^5
a.a.a.a=a^4
HS: 7.7.7 = 73

b.b.b.b = b4

Similaly, write the following product:

a .a... a
ntthwasè

a .a... a
ntthwasè

7.7.7; b.b.b.b;
) (n≠0)
+ Tc : Intruct students how to read 3^7 reading
is 3 to the power of 7 or 3 to the seventh or the
seventh power of 3
+3 is called the base, 7 called is the
exponent.Similarly, read b4 , a4 , an
. Plese onlythe base and the exponent ?
+ Tc : Plese outlined(neu ra) the nth power of a
. Write the general formula.
+ Tc: Muntiplication of many same factors is
called raising to a power.
+ Tc: Ask students to perform ?(Called each
students to read results fill in the blank on the
side paned)
+ Tc: Emphasize(nhÊn m¹nh).
In a power of natural numbers(different from
0) :

- Said base value by a factor of several.
- Said exponent number of the factors are
equal.
+ Tc : Note
- a2 is also called a squared (or the square of a)
- a3 is also called a cubed (or the cube of a)
- a1 =a
Activity 3 :
2. Muntiplying two powers with the same
base
+ Tc: Write the product of the two following
powers as a power:
a 23 . 22; b) a4 . a3
+ Tc: What I can comment on the exponent of

= an (n≠0)
Sts : paying attention
Sts: Standing still read, clearly
indicating the base and exponent.
Sts: (Framed section textbook P.26)

?1
Power Base

72
23
34

7
2

3

Expone Value
nt
of
power
2
49
3
8
4
81

Students attention in textbook.

2 Students go to the board:
St1: 23 . 22 = (2.2.2).(2.2)=25.
St2: a4 . a3 = (a.a.a.a).(a.a.a)=a7.
St: When multiplying two powers
with the same base:
- We preserve the base


th result with the exponent of the exponential.
- Add the two exponent
+ Tc:How do you want to multiply two powers St read notes on textbook (P.27).
the same base?
Tc: am.an =?
IV. Consolidation
Activity 4 : Practice

+ Tc: Asking questions
1Repeat the nth power of a and write the
a2=25=52 ⇒ a=5
formula
a3=27= 33 ⇒ a=3
Find natural number x,given that: a2=25; a3=27. St repeat the definition :
2. Compute: a3.a2.a5.
a3.a2.a5=a3+2+5 =a10
E xercise 56 on textbook P.27)
St go to the board doing the exercise
(Called 4 students go to the board)
56a,b,c,d
5. Homework
+ Exercise 57 -> 60 (P .28) Textbook ; 86-90 (P13) workbook
+ Preview the exercises in the practice
-----------------------------------------------------------------------------------------------------

Preparing date: 13/9/2016
Teaching date: 6AB: 20/9/2016

Priod 13: Practice
A.Aim :
1. Knowledge:
- St distinguish between base and exponent
-St understand defined powers
- St know shorthand a product of equal factors by using power.
2. Skill: - Skill training implemential exponential calutions with naturul exponent
proficient
3. Attitude: - Exercise logical thinking ability student.
Teacher’s Activities

Student’s activities
Activities 1 :
+ Tc : Check for student.
+St1 : Write the definition of a degree n St1: Speech and writing defined general


exponential and general formular.
+ Calculate :
33.34 ; 52.57 ; 75.7

III.New lesson:
Teacher ‘activities
Activity 2 : Form 1: Write a natural by
the power
Exercise 61 (P.28 Textbook).
(Tc call sts go to the board, under the
whole class working together and
comment.
Exercise 62 ( P.28 Textbook).
+ Tc call 2 sts go to the board, each
student do one sentence.
+ Tc collection and scroing fast exercise
of 5 sts.
+Tc : What do you comment form the
exponent of power with digit 0 after
digit 1 in value of powers ?

Activiy 3 : Form 2: True or False.
Exercise 63 (P.28 textbook).
+ Tc call sts stand in place answer and

explain, why true? Why false?
Activity 4 : Form 3 : Multiplying
powers
+ Tc call 4 sts go to the board at the
same time do 4 calculations.

formula as textbooks
102=10.10=100; 53=5.5.5=125
St2: General writing such as textbooks
33.34 = 33+4 =37
52.57= 52+7 =59.
75.7 =75+1=76.
Student’activities

St go to the board

St1: 102=100; 103=1000; 104=10000
105=100000; 106=1000000.
St2: 1000=103 ; 1000000=106
1 tØ =109;
00
 ... 0
12chuso

1
= 1012
St: Exponent of base 10, how much is the
value of exponential contraction after
flying more digits 0 digits 1.1

Sentence
23. 22 = 26
23 . 22 = 25
54 . 5 = 54
a 29
b 1010
c x6

True
x


d a10
Activity 5 : Form 4 : Compare 2
number.
Exercise 65 (P.29 Textbook).
Teachers guide the students work in
groups and commented how each team.
Exercise 66(P.29 Textbook).
+Ask students to read carefully and
anticipate threads
11112=?
+ Call 2 sts answer then the class use
computer and check result.

a 23=8; 32=9.
but 8<9 hence 23 <32.
b) 24=16 ; 42=16
Hence 24= 42.
c) 25=32 ; 52=25.

but 32>25 hence 25> 52
d) 210=1024>100
St:11112=1234321
The base have 4 digit 1, midle digit is 4
sides of the digits decreases in the number
1

IV. Consolidation
- Repeat definition the nth power of a.
St answers techer’question
- When multiplying two powers with the
same base, how we do?
V. Homework:
+ Do Exercise 90-93 (P.13workbook) , Exercise 95(P.14) SBT spend
for ells
+ Read before: Dividing two powers with the same base
---------------------------------------------------------------------------------------------------Preparing date: 20/9/2014
Teaching date: 6AB: 22/9/2014

Priod 14: DIviding two powers with the same base
A.Aim:
1. Knowledge :
- St understand formula of diving of two powers with the same base,
convention a0=1(a≠0).
- St know dividing of two powers with the same base
2. Skill::


- Training for students when applying accuracy rules exponentially
multiply and divide two base same

3. Attitude :
- Exercise logical thinking ability student.
B. Prepare :
Tc : Side-table
St: Group-table
C. Method:
Training and practice, work in group
D. Procedure:
1
I: Organization: 6A
2
II. Warm-up
Teacher’s activities
Activity 1 :
+ Tc : Question :
- When multiplying of two powers
with the same base, how we do ?
- Write form in general ?
- Exercises 93(P.13)workbook.
III. New lesson :
Teacher’activities
Activity 2 :
1. Example :
+Tc:St read and do exercise 1(P.29)
textbook .
+ Tc call st go to the board and explain .
+ Tc request st compare between the
base of the dividend,divisor and the base
of quotient .
+ Let perform a9 : a5 and a9 : a4 what we

need conditions?Why?

Student’s activities
St: Write the general as textbook
Exercise 93(P.13)Workbook
a) a3.a5=a8
b) x7.x.x4=x12.

Student’activities
?1:
57 : 53 =54(=57-3) v× 54. 53=57
57 : 54 =53(=57-4) v× 54. 53=57
a9 : a5 = a4(=a9-5 ) v× a4 . a5 = a9
a9 : a4 = a(=a9-4 ) v× a5. a4 = a9
- The exponent of quotient equal brand
exponent of the dividend and divisor .
-a≠0 because the divisor can’t divided by
0.


Activity3 :
2. In general:.
St: am : an= am-n (a≠0)
+ Tc have am : an with m>n th× ta sÏ cã
KQ nh thÕ nµo?
+Tc: Convention a0=1
St: a10 : a2 =a10-2=a8
+ Tc: Calculate: a10 : a2
Sr: Stated
+ Tc: When dividing of two powers with ?2: a) 78

the same base, how we do?( call st
a x3
answer question)
b 1
+ Tc request st do exercise ?2
textbookSGK
Activity4 :
3. Note:
St: Paying attention
+ Tc instructors st write the number2475
in the form of sum of powers of 10.
2475=2.1000+4.100+7.10+5
= 2.103+4.102+7.10+5.100.
Groups do exercise ?3
+ Tc:Note: l 2.103 is the sum 103+103.
+ Teachers ask students to group
activities once?3 (representative group
and whole class presentations comment)
IV.Consolidation:
Activity 5 :Practices
Exercise 69 (P.30) textbook
St answers:
Exercise 71(P.30) textbook
(Called 2 students go to the board)
St go to the board:
a c=1
b c=0
V. Homework:
+Study of the general form Dividing of two powers with the same
base

+Do exercise 68,70,72 (P.30,31) Textbook
exercise 99-103 (P.14) workbook
+ Research article: “Order of doing operrations”.


* TC: Introduce students to the main methods and guidance for students do
past a and b in exercise 72 (P.31) Textbook:
13 + 23 = 1 + 8 = 9 is a perfect square ( because 9 = 32)
-----------------------------------------------------------------------------------------------------

Preparing date: 20/9/2014
Teaching date 6AB: 23/9/2014

Period 15: Order of doing operrations
A. Aim :
1. Knowledge : - St understand convention about order of doing operations.
- St know apply conventions to calculate the value of expressions.
2. Skills : - Training skill to calculate.
3. Attatude : - Training to calculate carefully for sts.
B. Compare :
Tc : Side-table
St: Group-table
C. Method :
Training and practice, work in group.
D. Procedure:
1
I: Organization: 6A
2
II. Warm-up
Teacher’s activities

Activity1 :
Correct exercise 70(P.30)textbook
Call st comment exercise in the board
III. New lesson:
Teacher’s activities
Activity 2 : 1. Repeat exprestion:
+ Tc:Give some examples about expressions.
+ Tc: Repeat the note in textbook.

Student’s activities
1 st go to the board and do:
987=9.102+8.10+7.100.
2564=2.103+5.102+6.10+4.100.

Student’s activities
St give an example about expressions

St read again te past note in textbook.


Activity3 : 2. Order of doing oparetions in
exprestion.
+Repeat order of doing operations learned
+ Tc: Order of doing operation in epression.
We comment each case:
a) With the eprestion don’t have parenthese
+ Tc: Request st repeat order of doing
operations.
If division have both additon,
subtraction, multipication , what do we

do?
+ Tc: Calculate:
a 48-32+8
b 60:2.5.
+ Tc:If there are additions, subtractions,
multiplication, division and exponent, what
do we do?
+ Calculate the parenthese:
a) 4.32-5.6. 33.10+22.12
b) For expression have parenthese, what do
we do?
+ Calculate the value of expresstions:
a 100:

{ 2[ 52 − (35 − 8)]}

[130 − (12 − 4) ]
2

b 80(Tc collection and scroing fast exercise of 5
sts).
+ Tc Request sts do exercise ?1
+ Tc: Request st groups activities practice
(Representative group and whole class
presentations comment )

St repeat order of doing operations

St repeat as textbook

+) 2 st go to the board ,under the class
doing together.
a) 24.
b) 150.
St repeat as textbook
St1: a) 6.
St2: b) 318.
St : Statement as textbook

St1: a) 2.
St2: b) 14.
+) St do exercise:
a 62: 4.3 + 2.52 = 36:4.3 + 2.25
=9.3 + 2.25 = 27 + 50=77
b 2(5.42-18)
= 2( 5.16 - 18)
=2(80-18)
= 2.62 =124
?2. Find the number x:
a ( 6x – 39 ) : 3 = 201.
x
=3
b) 23 + 3x
= 5 6 + 53
x
= 34.


IV. Consolidation
Activity 4 : Practice

-Repeat order of doing operations in
epression (don’t have parenthese, have
parenthese)
+Tc use side-table exersise 75(P.32)
textbook(call st go to the board).

St repeat framed section
Exercise 75:
+3
x4
12
15
60
a)

b)

5

x3

15

-4

11

Exercise 76: St read exercise listen
tc guide .
+ Tc request st do exercise 76(P.32) textbook. 22 : 22 = 1.

2 : 2 +2: 2 = 2.
- Request st read exercise carefully.
( 2 + 2 + 2 ) : 2 = 3.
- Guide st the first sentence:
2 . 2 . 2 : 2 = 4.
2.2-2.2=0 hoÆc 22-22=0 hoÆc 2-2+2-2=0
- Similar,call 4 sts go to the do with result
equal 1,2,3,4(note : have different way)
V. Homework
+ Study of the farmed section
+ Do exercise 73,74,77,78(P.32,33)Textbook,104,105(P.15)
workbook
+ Preview exercises in the practice
+ Prepare calculator in after period.
----------------------------------------------------------------------------------------------------Preparing date: 20/9/2014
Teaching date 6AB: 27/9/2014

Period 16: Practice
A. Aim :
1. Knowledge: - St know how to apply the rules of order of doing
operations in expressions to calculate the value of expression.
2. Skills : - Training skill to calculate.
3. Attatued : - Forge for st carefullyand accurately while calculating.


B. Prepare :
Tc: Side-table, calculator
HS: Gangs, makers, calculator
C. Method :
Suggesttive questioning

D. Procedure
1
I: Organization: 6A
2
II. Warm-up
Teacher’s activities
Activity 1 :
St 1:
*Express order of doing operations in
expressions don’t have parenthese.
* Correct exercise 74(a,c)Textbook
St 2:
* Express order of doing operations
in expressions have parenthese.
* Correct exercise 77b textbook
St 3:
* Correct exercise 78b textbook
+ Tc request sts comment.
.
III. Practice
Teacher’s activities
Activity 2 :
+ Exercise 79
+Call 1 st stand in place and answer the
questions
+ Tc explain: the book is 18000.2:3
+ From result exercise 78 how much is
an envelope?
Exercise 80:
+ Tc request sts groups activity do

exercise
+ Tc request sts comment .

Students’ activities
St 1:
* Answer as textbook
* Exercise: a) x=24
c) x=17
St 2:
* Answer as textbook
* Exercises: b) 4
St 3:
* Correct exercise 78: b) 2400
*St comment exercise which is on the
board.

Students’ activities
St read exercise.
St: The envelope is 2400 dong
Exercise 80:
12 = 1.
22 = 1 + 3.
32 = 1 + 3 + 5.

13 = 12 - 02.
23 = 32 - 12
33 = 62 - 32.
43 = 102 – 62

( 0 + 1)2 = 02 + 12

Exercise 81:
+ Tc guide sts how to use computer to
calculate the value of expressions as
textbook.
+ Request sts apply do exercise 81.
(Call 2 sts go to the board)

( 1 + 2)2 > 12 + 22
( 2 + 3)2 > 22 + 32
Exercise 81:
St listen explain.
Sts use calculator.
St1:
274

+

318

x

6

=
3552

Exercise 82:
+ Tc: Can calculate in many ways.

IV. Consolidation
-Repeat order of doing operations in
expressions (have parenthese, don’t have
parenthese).

St2:
34

x

M+

MR

29

M+

14

1476

Exercise 82:
Step 1: 34 – 33 = 81-27 = 54.
Step 2: 34 – 33 = 33 (3-1) = 27.2 = 54.
Step 3: Use calculator
St repeat order of doing operations in
expressions.

V. Homework

+ Study of the farmed section.
+ Do exercise 106-109, 110(P.15) workbook.
+ Practice skills learned
Guide exercise110:
102 + 112 + 122
132 + 142
= 10.10 + 11.(10 + 1) + 12.(10+2)
= 13( 10 + 3) + 14( 10 + 4)
= 10( 10 + 11 + 12) + 35
= 10.( 13 + 14 ) + 95
= 10( 27 + 6) + 35
= 10.27 + 95
= 10.27 + 95

x


-----------------------------------------------------------------------------------------------------

Preparing date: 5/10
Teaching date: 11/10

Period 17: Test 45 MINUTES
A. AimS :
1. Knowledge: - Check students’ knowledge
2. Skills : - Training skill to calculate correctly
3. Attatued : Sts honest when do the test.
Sts present clearly.
B. Prepare :
Tc: The tests

HS: Knowledge and paper
C. Method :
Check on paper


D. Procedure
I. Organization: 6A

II. Content :
Ma trận:
Cấp độ

Nhận biết

TNKQ TL
Nhận diện
được tập
hợp , phần tử
của tập hợp.
Biết được số
tự nhiên liền
trước của 1
số.
Số câu
3
Số điểm
(C1,2,4)
0.75
2. Các
Nhận

phép tính biết các
cộng ,
phép
trừ , nhân tính về
, chia ,
lũy thừa
nâng lên
(nhân,
lũy thừa. chia)
Chủ đề
1. Tập
hợp . Số
phần tử
của tập
hợp.
Ghi số tự
nhiên

Số câu
Số điểm

2 (C
5,6)

Thông hiểu
TNKQ TL
Tìm được tập
hợp con của
một tập hợp.
Viết được tập

hợp theo 2
cách.

1 (C 3) 1 (B
0.25 1)
1.0
Biết
nhận
dạng
và thực
hiện
các
phép
tính
1 (C 8)
0.25

Vận dụng
Cấp độ thấp
Cấp độ cao
TN
TL
TN
TL

Cộn
g

5
2.0

Vận dụng
các tính
chất của
phép cộng
, nhân,lũy
thừa

Vận dụng
các tính chất
của phép
cộng
,nhân,lũy
thừa

1 (B 2 )
2.0

1 (B 5)

5
1.0 3.75

0.5
3. Thứ tự
thực hiện
các phép

Giải các bài toán
tìm giá trị chưa
biết

Thứ tự thực
hiện các
phép tính có


tính.
Số câu
Số điểm

dấu ngoặc
1(B3) 3

1(C 7) 1 (B 4)
0.25
3.0

Tổng số
câu
Tổngsố
điểm
Tỉ lệ %

5

3

1.25
12,5%

1.0

3
1.5

2
5.25

15%

2.0

52,5%

20%

Đề bài
I. TRẮC NGHIỆM: (4 điểm) Hãy khoanh tròn kết quả em cho là đúng :
∈

Câu 1: Cho a N, số liền trước của số a + 1 là :
A. a – 1
B. a
C. a + 2
D. a + 1
Câu 2: Cho tập hợp A = { a ; 5 ; b ; 7 }
∈

∈

∉

A. 5 A
B. 0 A
C. 7 A
Câu 3: Cho ba tập hợp : M = {1; a ; 5 ; 8 };
1}

⊂

⊂

∉

D. a A
K = {4 ; 5 ; 1 };

⊂

⊂

L= {8;

A. K M
B. L K
C. M K
D. L M
Câu 4: Tập hợp A các số tự nhiên không vượt quá 5 được viết như sau :
A. A = {1; 2; 3; 4; 5};

{ x ∈ N / x ≥ 5}

B. A =

4.25
13
10.0

{ x ∈ N / x < 5}

{ x ∈ N / x ≤ 5}

;

C. A =
;
D. A =
2
Câu 5: Kết quả phép tính : 5 + 5 bằng :
A. 125
B. 27
C. 30
D. 12
2013
2012
Câu 6: Kết quả phép tính : 2 : 2 =
A. 22001
B. 24025
C. 2
D. 6

Câu 7: Tìm số tự nhiên x, biết: 4.( x - 3 ) = 0 thì x bằng :
∅

A. 12
B. 3
C. 0
D.
Câu 8: Kết quả phép tính : 32 . 118 + 882 . 32 là :
A. 12 00
B. 10600
C. 3200
D. 32000
II. TỰ LUẬN: (6 điểm)
Bài 1: (1 điểm)

100
%


Viết tập hợp C các số tự nhiên lớn hơn 6 và nhỏ hơn hoặc bằng 10 theo hai
cách
Bài 2: ( 2 điểm )
Thực hiện phép tính bằng cách hợp lí nhất:
a/ 175 . 16 + 84 . 175
b/ 1024 : ( 17 . 25 + 15 . 25 )
Problem 3: (1 điểm)
Compute:

{

}

248 : ( 368 + 232 ) :120 − 3 + 122 + 20110

∈N

Problem 4: (2 điểm) Find x
such that :
a/ ( x + 17 ) : 21 – 3 = 7
b/ 5 x - 1 – 13 = 612
c/ 71 + (26 – 3x ): 5 = 75
d/ 2x = 32
Problem 5: Given S = 1 + 31 + 32 + … + 399. Prove that : S is divisible by 40.
Đáp án:
I. TRẮC NGHIỆM: (2 điểm) Mỗi câu đúng được 0,25 điểm.
1. B, 2. A, 3. D, 4. D, 5. C, 6. C, 7. B, 8. C
II. TỰ LUẬN: (8điểm
Bài 1: (1 điểm)
(0,5

C = {7; 8 ; 9 ; 10 }

điểm)

∈

≤

C = {x N | 6 < x 10}
điểm)

Bài 2: (2 điểm)
a/ 175 .( 66 + 84 ) = 175.100 = 17500
điểm)
b/ 25 .( 178 – 78 ) = 32.100 = 3200
điểm)
Problem 3: (1 điểm)
- We have
248 : { [ 600 :120 − 3] + 122} + 1
248 : { 2 + 122} + 1
=
- We have :

(0,5
(1
(1

(0,5 điểm)


248 :124 + 1 = 3

Problem 4: (3 điểm)
a/ - We have:
b/ - We have :

(0,5 điểm)
x + 17= 210
x = 193
5 x - 1 = 54
x–1 =4

⇒

(0,5 điểm)
(0,25 điểm)
(0,5 điểm)
x=5

(0,25

điểm)
c/ - We have :

26 – 3x = 20
x=2
x
2 = 25

(0,5 điểm)
(0,25 điểm)
(0,5 điểm)
(0,25 điểm)

d/- We have :
x=5
Problem 5(1 điểm)
We have:
S = (1 + 3 + 32 +33 ) + 34 . (1 + 3 + 32 +33 ) + . . . + 396 .(1 + 3 + 32 +33 )
= 40 . ( 1 + 34 + . . . +396 )
⇒



S 40.
III. Comment
- Collecting all sts
- Tc Comment
IV. Homework:
+ Research article: “Divisibility properties of a sum”

-----------------------------------------------------------------------------------------------------


Preparing date: 10/10
Teaching date: 15/10

Period 18: PRACTICE Divisibility properties of a sum
A.AImS :
1. Knowledge : - Sts know divisibility properties of a sum, a difference.
- Sts know recognize( nhËn ra ) a sum of two or many numbers, a
difference of two or many numbers.




- Know using symbols
,
2 Skill : Training accuracy(tinh chinh xac)when applying the divisibility
properties.
3. Attatued :- Thinking ability training for students.

B. Prepare:
Tc: Side-table
St: Group-table.
C.METHOD
D. Procedure
1
I: Organization: 6A


2

II. Warm-up

Teacher’s activities
Students’activitties
Activity 1 :
+ Tc: When we say number a divisible by
St stand in place answer
number b(b different from 0) ?
Give some examples.
When the number a doesn’t divisible by number
b (b different from 0) ?
Give some example.
III. New lesson :
Teacher’s activities
Activity 2: 1. Repeat relation divisible.
+ Tc:Keep stable(giu nguyen) the generality
and example , introduce about symbol.
. a divisible by b is : a



b


. a doesn’t divisible by b is: a b.
Activity 3 : 2. Property 1 :
+ Tc:Request students do exercise ?1 I textbook
Call 3 sts give examples a/
2 sts give examples b/
+ What do you comment from above examples?
+ Tc introduce about symbol “ ⇒” .








+ If a m ; b m then what do we have?
( Call sts answer)
+ If a

m;b

m then is (a - b) divisible by

m?




Students’activitties



+ If a m ; b m, c m then is
(a + b + c) divisible by m?
+ You stated property 1.

Sts listen the introducing symbol and
record books.
Sts do exercise ?1
Sts: If each terms of a sum are
divisible by the same number then the
sum is divisible by that number.












St: a m ; b m ⇒ (a + b )

( Sts write notebook)
Note: Textbook (P.34).
+) a
+) a

m;b
m;b

m then (a – b)


m, c m then



(a + b + c) m
Property 1: (Framed section ,
Textbook. P.34).



m



m


Activity 4 : 3. Property 2 :
+ Tc: Groups do exercise ?2

+ Comment?

?2: St work in group :
Comment:



If a m ; b m ⇒ a + b m
Chó ý: SGK(Tr.35)

+ The above comments are true for difference ?
Give examples ?



+ Please stating generality?
+) a m ; b m ⇒ a - b m
+Give examples about the sum of 3 numbers
≠
(a>b, m 0)
and one of the 3 numbers is divisible by 3, then



two remaining numbers are divisible by 3. Is
+) a
m;b m⇒ a-b m
that sum divisible by 3.
≠
What do we comment about above example ?

(a>b, m 0)
+ If the sum of 3 terms , including 2 terms



+)
a
m
;
b
m,
c
m th×
aren’t divisible by any numbers, the remaining

≠
number divisible by that number. So is that sum
(a + b + c) m ( m 0)
divisible by that number ?
Give examples ?
+ Applying do exercises ?3. ?4 SGK (P.35)
Property 2 (Framed section
Textbook.)
?3, ?4: 2 sts go to the board.
IV. Consolidation:
Activity 5 : Practice :
+ Repeat 2 properties divisibility of a sum
+ Exercise 86 Textbook (P.36)
Sentence
Tru Fals

e
e
a) 134.4 + 6 divisible by 4
b) 21.8 + 17 divisible by 8.
c) 3.100 + 34 divisible by
6
+ Do exercise 115(P.17)

,

+ 2 sts stand in place and repeat 2
properties.
Exercise 86:
a True
b False
c False
Exercise 115( Workbook):
We have: 12
3.



3, 15



3, 21



Hence A



3 then x



3(x

N)

V. Homework:
+ Study 2 properties textbook
+Do exercise 83-85 textbook (P.35, 36), 114,116,117,119 Workbook(P.17)
*Guide exercise 119: Call 3 consecutive natural numbers are: a; a +


1; a + 2 ( a N).
When: a + (a + 1) + (a + 2) = 3a + 3
+ Research article: Rules of divisibility by 2, by 5
----------------------------------------------------------------------------------------------------Preparing date: 5/10
Teaching date: 14/10

Period 19: Rules of divisibility by 2, by 5
A. aimS:
1. Knowledge : - HS hiểu đợc cơ sở lý luận của các dấu hiệu chia hết cho 2, cho
5 dựa vào kiến thức đã học ở lớp 5.
- HS biết vận dụng các dấu hiệu chia hết cho 2, cho 5 để nhanh

chóng nhận ra một số,một tổng, một hiệu có hay không chia hêt cho 2,
cho 5.
2. Skills: - Rèn luyện cho học sinh khi phát biểu và vận dụng giải các bài toán về
tìm số d, ghép số.
3. Attitude: - Rèn khả năng t duy và suy luận lôgic cho HS
B. prepare:
Tc : Side-table,colored chalk.
St : Group- table.
C. method :
Training and practice, work in group
D. Procedure:




I. Organization: 6A :
II. Warm-up
Teacher’s activities
Activity 1 :
+ Tc: Call 2 sts go to the board.
St1: Correct exercise 121 (workbookP.17).
St 2: 246 + 30 + 15. Don’t compute given
is this sum divisible by 6? What do we
apply property ? State?
+ Collecting some exercise.
+ Call sts comment.
III. New lesson :
Teacher’s activities
Activity 2 : 1. Comment
+ Tc share the class into 2 blocks, find

some example numbers ended by digit 0.
Are that number divisible by 2, by 5 ?
Why?
Activity 3 : 2. The rule of divisibility by
2
+ In the one-digit number, any number
divisible by 2?
43*

+Consider number n=
by which digit
can we replace the sign * so that n is
divisible by2?
+So how the numbers then divisible by 2?
+ By which digit can we replace the sign *
so that n is divisible by 2?
+ Give a statement on the rule of
divisibility by 2.
+ Do exercise ?1
Activity 4 :

Students’ activities
St1:

abcabc = abc.1001 = abc.11.9111

St 2:246 + 30 + 15
6, 15







6 sinse 246 6, 30

6.

Students’ activities
Sts give example and comment.
Comment: ( P.37)

St: Aswer 0; 2; 4; 6; 8
43 *

n=
=430 + *
If we replace the sign * by one of the


digits 0,2,4,6,8 then 0; 2; 4; 6; 8 th× n 2
Conclusion 1: Textbook – P.37
Conclusion 2: Textbook – P.37
Sts stated:
?1:
328; 1234 divisible by2.
1437; 895 aren’t divisible by2.



3. The rule of divisibility by5.
+ Tc organize activities as section 2.
+ Do exercise ?2

Sts answer:
?2: If we replace the sign * by one of the
37 * 

digits 0; 5 then
5
If we replace the sign * by one of the
digits 1; 2;3; 4; 6;7; 8 ;9 then
IV. Consolidation
Activity 5 : Practice
+ Tc :

37 * 

5

Sts answer:


- n is number ended by 0; 2; 4; 6; 8 ⇒n 2


- n is number ended b 0; 5 ⇒n 5
Exercise 91 (Textbook – P.38):

Exercise 92 (Textbook – P.38):

Exercise 128 (Workbook – P.18).
Sts work in group

Exercise 91
St 1:
+ The numbers divisible by 2: 652; 850;
1546.
+ The numbers divisible by 5: 850; 785.
Exercise 92
St2:
a/ 234 ; b/ 1345 ; c/ 4620 ; d/ 2141 vµ 234
Exercise 127
a 650; 560; 506.
b 650; 560; 605.
Wool group representative exercise 127

V. Homework :
+ Study symbols
+ Do exercise 93 – 95 (Textbook – P.38); Exercise 123-126,
128 (Workbook -P.17).
+ Preview the exercises at the practice.
Preparing date: 12/10
Teaching date: 18/10/16

PERIOD 20. RULES OF DIVISIBILITY BY 3, BY 9
I. Aims
1. Knowledge: - Sts know rules of divisibility by 3, by 9 compare with rules of divisibility by 2, by

5.Sts know applying rules of divisibility by 3, by 9 to know the number is or isn’t divisibility by 3, by 9.


2. Skills: - Training exactly when state and apply form exercises.
3. Attitude: - Training thinking ability and logical reasoning.
II. Method :
Practice, discuss difficutly problems.
III. Matirial:
Colour chalk, sheet of paper
IV. Procedure
2 Organization: 6A.
3 Warm-up
Teacher’s ativities
Activity 1:
+ Tc called correct exercise 128
Workbook..
+Call sts comment exercises on the board

Students’ ativities
St 1: Let natural number have two
digits and the same digit as :
Since

aa

4 hence a
- Consider two numbers a = 378; b = 5124
+ Prctice division to what number is
divisible by 9 or not?
+ Find the sum of the digits of a and b?

But

aa

.

divided by 5 with remainder of
∈ { 4;9}

aa 2 ⇒ a ∈ { 0;2;4;6;8}


Thus a = 4 satisfy conditions a 9 , b


a– (3 + 7 + 8) = (a – 18) 9
-

b – (5 + 1 + 2 + 4) = (b – 12)
III. New lesson:
Teacher’s ativities

Students’ ativities

Activity 2 : 1. Firt comment:
+ Tc: All nnumbers are write form of the Sts read comment on textbook.
sum digits of it add a number divisible
by 9.
+ Give an example :

378 = 3. 100+7.10+8



9



9


= 3(99+1)+7(9+1)+8
= (3+7+8) + (3.11.9 + 7.9)


= (Sum of digits) + (Số 9).
+ Request all sts practice with the
number 253
Activity 3:
2. Rule of divisibility by 9.
+Depend on the firt comment, don’t
perform the calculation explain why 378


9?
+ How number is divisible by 9?
+ Is the number 253 divisible by 9?
Why?
+ Consolidation do ?1, request explain.

253 = … = (2.99 + 5.9) + (2 + 5 + 3)
= (number divisible by 9) + (sum of
digits)

Sts : Because 2 terms are divisible by 9
* Conclution 1: (Textbook – P.40)
Number 253 is not divisible by 9 because
one term is divisible by 9, the other is not
divisible by 9
* Conclution 2: (Textbook – P.40)




?1 : 621 9 vì 6 + 2 + 1 = 9 9






1205 9; 1327 9; 6354 9
Activity 4:
3. Rule of divisibility by 3.
+ Tc organized activities such as section
2.

. How number is divisible cho3?
How number is not divisible by 3?

+Consolidation do ?2

2031 = (2 + 0 + 3 + 1)+ (number divisible
by 9)
= 6 + (number divisible by 9)
= 6 + (number divisible by 3)


So 2031 9
* Conclution 1: (Textbook – P.41)
3415 = (3 + 4 + 1 + 5)+ (number divisible
by 9)
= 13 + (number divisible by 9)
= 13 + (number divisible by 3)


So 3415 3
* Conclution 2: (Textbook – P.41)
?2 :