ADECH02 SOLUTION PROB4 1
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HANOI UNIVERSITY OF MINING AND GEOLOGY
ADVANCED PROGRAM IN CHEMICAL ENGINEERING
Subject : ADECH02- Petroleum Refining
SOLUTION PROB 4.1
Dai Duong Van K4 – 2017
100,000 BPD ( API = 36)
-
Light vacuum gas oil ( 650-850°F)
Heavy vacuum gas oil (850-1050°F)
Vacuum residue ( 1050+°F)
We must calculate the mass flow rate and the sulphur content ( lb/hr).
TBP(°R) = {( . ln
−𝐿𝑉%
API = -0.0004 𝑉% + .
.
+ }
𝑉% − .
Light vacuum gas oil ( 650-850°F) cut
(4.1)
𝑉% +
(4.2)
IBP = 650 °F = 343.33°C = 1109.67°R
EBP= 850°F= 454.44°C= 1309.67°R
Substituting in eq ( 4.1) to get LV% at IBP and EBP :
Cut vol % = 42.30 - 39.09=3.21%
Cut mid volume = 40.695
Substituting the cut mid volume in eq (4.2) to get API= 38.18, we get SG = 0.834
Cut volume = 0.0321(100,000)= 3210 BPD
Cut amount = 3210(SG)(14.60)=3210(0.834)(14.60)=39,086.244 lb/h
Calculate of sulphur content :
M= 42.965[exp(2.097×
M= 355.55 lb/lb mol
−
𝑏
− .
𝑏
𝐺+ .
=
+
.
−
×
+
−
𝑏
𝐺 ]
=
.
𝑏
.
𝐺
.
I=2.266×
n=
+ 𝐼
−𝐼
/
−
exp .
= 1.466
−
×
𝑏
+ .
𝐺− .
𝑖
m= M(n – 1.475) = -3.19995
=
−
×
−
𝑑
𝑏
𝐺
𝑏
.
𝐺−
.
= .
= .
since M> 200
sulphur wt% = -58.02+ 38.463
𝑖
− .
+
.
sulphur amount = 0.01083(39,086.244) = 423.3 lb/h
𝐺 = .
𝑤𝑡%
Heavy vacuum gas oil (850-1050°F) cut
IBP = 850 °F = 454.44°C = 1309.67°R
EBP= 1050°F= 565.56°C= 1509.67°R
Substituting in eq ( 4.1) to get LV% at IBP and EBP :
Cut vol % = 44.91 – 42.30=2.61%
Cut mid volume = 43.605
Substituting the cut mid volume in eq (4.2) to get API= 37.25, we get SG = 0.839
Cut volume = 0.0261(100,000)= 2610 BPD
Cut amount = 2610(SG)(14.60)=2610(0.839)(14.60)=31,971 lb/h
Calculate of sulphur content :
M= 42.965[exp(2.097×
−
𝑏
− .
𝑏
M= 534.86 lb/lb mol
I=2.266×
n=
+ 𝐼
−𝐼
/
−
exp .
= 1.469
×
−
𝑏
𝐺+ .
=
+ .
+
.
𝐺− .
−
−
×
𝑏
+
×
−
𝐺 ]
𝑏
.
.
𝐺
=
𝑏
𝐺
𝑏
.
𝐺−
.
= .
𝑖
m= M(n – 1.475) = -3.21
=
−
𝑑
= .
since M> 200
sulphur wt% = -58.02+ 38.463
𝑖
− .
+
sulphur amount = 0.01214(31,971) = 388.13 lb/h
.
𝐺 = .
𝑤𝑡%
Vacuum residue ( 1050+°F) cut
Cut vol % = 100– 44.91=55.09%
Cut mid volume = 72.455
Substituting the cut mid volume in eq (4.2) to get API= 16.45, we get SG = 0.956
Cut volume = 0.5509(100,000)= 55,090BPD
Cut amount = 55,090(SG)(14.60)=55,090(0.956)(14.60)=768,924 lb/h
