Test bank For Mechanics of Materials 8th Edition by Russell C Hibbeler
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2–1. An air-filled rubber ball has a diameter of 6 in. If the air
pressure within it is increased until the ball’s diameter becomes
7 in., determine the average normal strain in the rubber.
d0 = 6 in.
d = 7 in.
pd - pd
e=
0=
= 0.167 in./in. Ans. pd0 6
2–2. A thin strip of rubber has an unstretched length of
15 in. If it
is stretched around a pipe having an outer diameter
of 5 in., determine the
average normal strain in the strip.
L0 = 15 in.
L = p(5 in.)
L - L0
e = L0
5p - 15
=
15 = 0.0472 in.>in.
Ans.
2–3. The rigid beam is supported by a pin at A and wires BD and CE. If the load P on the
beam causes the end C to be
D
displaced 10 mm downward, determine the normal strain
E
developed in wires CE and BD.
4m
P
¢LBD
¢LCE
3
=
7
¢L BD =
A
B
C
3 (10)
7
= 4.286 mm
2m
3m
¢LCE
10
Ans. eCE = L = 4000 = 0.00250 mm>mm
¢LBD
Ans. eBD = L = 4000 = 0.00107 mm>mm
2m
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2–6. Nylon strips are fused to glass plates. When moderately
heated the nylon will become soft while the glass stays
approximately rigid . Determine the average shear strain in the
nylon due to the load
P when the assembly deforms as
indicated.
y
2 mm
3 mm
P
5 mm
3 mm
5 mm
3 mm
g = tan
-1
2
x
Ans.
a10 b = 11.31° = 0.197 rad
2–7. If the unstretched length of the bowstring is 35.5 in.,
determine the average normal strain in the string when it is
stretched to the position shown.
18 in.
6 in.
18 in.
Geometry: Referring to Fig2. a, the stretched length of the string is
2
2
L = 2L¿ = 2 18 + 6 = 37.947 in.
Average Normal Strain:
=
e
avg
L - L0
L0
37.947 - 35.5
=
35.5
= 0.0689 in.>in.
Ans.
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1
0
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