Tải bản đầy đủ (.ppt) (13 trang)

GIAO AN DAY TOAN BANG TIENG ANH LOP 8

Bạn đang xem bản rút gọn của tài liệu. Xem và tải ngay bản đầy đủ của tài liệu tại đây (435.19 KB, 13 trang )

<span class='text_page_counter'>(1)</span><div class='page_container' data-page=1></div>
<span class='text_page_counter'>(2)</span><div class='page_container' data-page=2>

1

<sub>2</sub>

<sub>3</sub>



</div>
<span class='text_page_counter'>(3)</span><div class='page_container' data-page=3></div>
<span class='text_page_counter'>(4)</span><div class='page_container' data-page=4>

<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>



We have:


n3 - 8n2 + 20n - 13 = (n - 1)(n2 - 7n +13)


Because n3 - 8n2 + 20n - 13 are prime numbers


2


1 1


7 13 is
<i>n</i>


<i>SO</i>


<i>n</i> <i>n</i> <i>a prime</i>
 



 

 2
1 is
or


7 13 1



<i>n</i> <i>a prime</i>
<i>n</i> <i>n</i>




  



<b>Problem 1</b>: How many positive integers n are
A= prime numbers

<i>n</i>

3

8

<i>n</i>

2

20

<i>n</i>

13



</div>
<span class='text_page_counter'>(5)</span><div class='page_container' data-page=5>

2


1 1


If



7

13 is

2



<i>n</i>



<i>n</i>

<i>n</i>

<i>a prime</i>

<i>n</i>







 





2

1 is



If

3 or

4



7

13 1



<i>n</i>

<i>a prime</i>



<i>n</i>

<i>n</i>


<i>n</i>

<i>n</i>


 



 







<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>



</div>
<span class='text_page_counter'>(6)</span><div class='page_container' data-page=6>

<b>Problem 2: Solve the following exercises:</b>



If a, b, c are real numbers so that a2 + 4b = 7;


b2 +8c = -10 and c2+ 6a = -26. Find T = a2+ b3+ c4.


<b>Solution</b>




2


2 2 2 2


2


4 7


8 10 a + 4b+b +8c+c +6a = 7+(-10)+(-26)


6 26


<i>a</i> <i>b</i>


<i>We have</i> <i>b</i> <i>c</i>


<i>c</i> <i>a</i>
  

  


 


 a2+ 4b + b2+ 8c + c2+ 6a + 29 = 0


</div>
<span class='text_page_counter'>(7)</span><div class='page_container' data-page=7>

 (a + 3)2+ (b + 2)2+ (c + 4)2= 0





2
3
4


2 3 4


9



3 0

3



2 0

2

8



4 0

4

<sub>256</sub>



a

b

c 9 8 256 257


<i>a</i>



<i>a</i>

<i>a</i>



<i>b</i>

<i>b</i>

<i>b</i>



<i>c</i>

<i>c</i>

<i><sub>c</sub></i>




 








<sub></sub>

 

<sub></sub>



<sub></sub>




<sub> </sub>

<sub></sub>



<sub></sub>




( a2+ 6a + 9) + ( b2+ 4b + 4) + (c2 + 8c + 16) = 0


<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>



</div>
<span class='text_page_counter'>(8)</span><div class='page_container' data-page=8>

<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>



<b>Problem 3:</b> Find the balance polynomial divided by
polynomial P(x) =5 + x + x3 + x9 + x27 + x81 for


polynomial Q(x) = x2 - 1


<b>Solution</b>



We have:


</div>
<span class='text_page_counter'>(9)</span><div class='page_container' data-page=9>

<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>



= x(x2 - 1) + x(x8 - 1) + x(x26- 1)+x(x80 - 1) + 5x + 5


Note that a2n – b2n(a - b) from n<sub></sub>N.So (x2n-1)<sub></sub>(x2 - 1)


 P(x) : Q(x) balance polynomial 5x + 5.


Therefore balance polynomial divided by



polynomial P(x) for polynomial Q(x) is 5x +5.


</div>
<span class='text_page_counter'>(10)</span><div class='page_container' data-page=10>

<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>



Let balance polynomial divided by polynomial P(x) for
polynomial Q(x) is R(x) = ax + b (a; b  R)


We have: P(x) = (x2 - 1). A(x) + ax + b


(A(x) is quotient polynomial).


 



or .
1 10
5
1 10


<i>Apply the Bezout the em</i>
<i>We have</i>


<i>P</i> <i>a b</i>


<i>a</i> <i>b</i>


<i>P</i> <i>a b</i>


</div>
<span class='text_page_counter'>(11)</span><div class='page_container' data-page=11>

<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>




<b>Similar exercises:</b>



Find the balance polynomial divided by polynomial
P(x) = x81 + x49 + x25 + x9 +x + 1


</div>
<span class='text_page_counter'>(12)</span><div class='page_container' data-page=12>

<b>PRACTICE PROBLEMS ON POLYNOMIALS</b>



<b>V) Homework</b>

:



- Review all the exercises that we do today
- Solve the following exercises:


<b>Question 1</b>: Find the numbers of different positive
integer triples (x; y; z) that satisfy equations


x2 + y - z = 100 and x + y2 - z = 124.


<b>Question 2</b>: Find the natural numbers x; y; z that
satisfy the following conditions:


x3 + y3 = 2z3 x + y + z is a prime number


</div>
<span class='text_page_counter'>(13)</span><div class='page_container' data-page=13></div>

<!--links-->

×