Giải toán về căn thức

http://violet.
vn/thanhliem24

Ph©n tÝch thµnh nh©n tö
3
3
−+
−+
2715 ,c
6 b, 105 ,a
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vn/thanhliem24

Ph©n tÝch thµnh nh©n tö
)2 5.(5
5.2 5.5
2.5 )5(
105 ,a
2
+=
+=
+=
+
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vn/thanhliem24

Dòng
Th×n
Hµ
Ng©n
)(2715 ,c

)2(3323.6 b,
)25(5105 ,a
2533
13
+=−+
−=−=−
+=+
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vn/thanhliem24

ViÕt c¸c biÓu thøc sau d íi d¹ng b×nh
ph ¬ng cña mét tæng hoÆc hiÖu
3512 g, 14-9 ,f
158 e, 56 ,d
22
22
−
++
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vn/thanhliem24

Dòng
Th×n
Hµ
Ng©n
; 1)5(
1.152)5(
1 5 5 56 ,d
2
22

+=
++=
++=+ 22
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vn/thanhliem24

Dòng
Th×n
Hµ
Ng©n
2
22
)35(
)3(3.52)5(
3 5.3 5 158 ,d
22
+=
++=
++=+
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vn/thanhliem24

Dòng
Th×n
Hµ
Ng©n
2
2
22
2

22727
2272
)57(3512 g,
)27(
)(.)(
14 14-9 ,f
−=−
−=
+−=
+−=
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vn/thanhliem24

33214 g, 212- 10 ,f
42213 i, 1829 h
−
++
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vn/thanhliem24

33214 g, 212- 10 ,f
)76(
)7(7.6.2)6(7 6.726 42213
chän 1376 lo¹i 23212 i¹lo 17143
6.72.213.1442 cãta 42213 i,
)3 6( 1829 h
2
22
2
−

+=
++=++=+
=+=+=+
====+
+=+
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vn/thanhliem24

Bµi 2
63-x6x ,c
2102-7 b,
324 ,a
thøc biÓu gän Rót
++
+
+
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vn/thanhliem24

522
2222
222
222
11
1
2
2
2
=+−=
+−=+−=

++=
++=+
+=+=
+=+
5
5)5(
)(5.2-)5(
5.22-5102-7 b,
3 3
)3( 324 ,a
2
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vn/thanhliem24

33-x
33-x)33-x(
33.3-x2.)3-x(
93.3-x2.3-x
63-x6x ,c
2
22
+=
+=+=
++=
++=
++
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vn/thanhliem24

Bµi 3 Ph©n tÝch ra thõa sè

xy-x b, aa-a ,a
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vn/thanhliem24

)yx(x
y.x)x(
xy-x b,
)a-a(1 aa-a ,a
−=
−=
=
2
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vn/thanhliem24

Bµi 3 Ph©n tÝch ra thõa sè
yx-y-x d,
xyyx ,c
−
−
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vn/thanhliem24

)yx).(yx(
)yx()yx).(yx(
)yx()y()x(
yx-y-x d,
)yx(y x
x) y(y) x( xyyx ,c
22

1
22
−−+=
+−+−=
+−−=
−
−=
−=−
2
)a(a 0;a Víi =≥
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vn/thanhliem24

Bµi 3 Ph©n tÝch ra thõa sè
3
a-1 ,g
aa2-1 f,
0)a (víia -1 ,e
+
>
2
)a(a 0;a Víi =≥
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vn/thanhliem24

)aa)(a(
)a(-1a-1 ,g
)a(
)a(a aa2-1 f,
0)a (víi )a)(1a-(1

)a(-1a -1 ,e
33
2
++−=
=
−=
+−=+
>+=
=
11
1
121
3
2
22
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vn/thanhliem24

Bµi 4
2367 r»ng hmin Chøng
1a1-a
r»ng minh chøng 1a Cho
1a1a
r»ng minh chøng 0a Cho
−<−
−>
≥
+>+
>
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vn/thanhliem24

0a ra khi yx¶ "" DÊu
0a víi0 a1a
)a()1a(
aaa nnª
0a mäi víia cã ta
aa)a(
a)1a( cã Ta
==
≥≥+≤+=>
+≤+
+≥++
≥≥
++=+
+=+
1
1
112
0
121
1
22
2
2
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vn/thanhliem24

1a do 0 a1-a
)a()1-a(

)a(a
aaa)a()1-a(
aa)a(
a)1-a( cã Ta
≥≥−≥=>
−≥=>
≥−=−=
−+−−=−−
+−=−
−=
1
1
01222
1211
121
1
22
22
2
2
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vn/thanhliem24

dónglµ minh chøng iph¶ diÒu VËy
ra bµi theo óng
1a 1 a a
)a(aa
aaa
aaa
)a()1-a((1) nnª

0 a vµ 1-a cã Ta (1) a1-a

≥<=>≥<=>−≥<=>
−+≥<=>
+−≥<=>
+−≥−<=>
−≥<=>
≥−≥−≥
10
12
22
121
1
101
22
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vn/thanhliem24

1a do )a(a
aaa)a()1-a(
aa)a(
a)1-a( cã Ta
≥≥−=−=
−+−−=−−
+−=−
−=
01222
1211
121
1

22
2
2
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vn/thanhliem24

Ph©n tÝch ra thõa sè
3x2-x ,e
8x6x ,d 6x5-x c,
9xy2-yx b,
yx1xy ,a
−
+++
−+
+++
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vn/thanhliem24

)1x)(1y(
)1y()1y(x
)y1()xxy(
yx1xy ,a
++=
+++=
+++=
+++