ĐỀ THI THỬ ĐẠI HỌC 2011 LẦN 2 THÁI PHIÊN_HẢI PHÒNG ppsx

1.
KhAo
s6t
sU'bi6n thi6n
vi ve
d6
thi
(
C
)
cira
hdm
s6.
2.
M
ld di€m
b6tty
o'.tren
(C)
TicpjuytSn
cira
(
C)
tai
M cdt
c6c
dudng
ti€m
c4n
cria
(C)

tai
A vi
B;
gqi
I
ld
giao
di6m 2
duong
tiQrn
c{n.
Tim toa
dQ M
sao cho
dudng
trdn
ngoq.i
tirip
tam
!ij.
iae
c6 di€n
tichbing
2n
CAu II(
2 di€m):
io'crAo
Dvc
&
DAO

TAO
HATPHONG
TIIU,ONG
THPT
THAI
PHTEN
i. PHAN
CFILN{G
CHO
TAT
CA
THi
SINH
,
'^
7
Lau
l(z olem)
,
2x-3
Lno
ham
so
y
=
;-;.(
C)
I-L
cos2x
+ 5 sin

1) Giei
phuong
trinh
:
DE
THI
THII
EAI
HQC
LAN
II IYAM
2011
M6n :
TOAN
_
KIIoI
A
Thdt
gian
: 180
phrit
(
kh6ng
nC
tndt gtan
phdt
di
)
=-
/

2)
Gieibdt phuo'ng
trinh
:
-E
<
x+Zt
P
-
Jn.u)"
I
x=2+t
az:ll=-3+3t
felR.
I
z=t
J7T \
iT- I
)l
cAu rrr
(
1
di€m)
:
Tinh
,
's*(rr,
-+)*
d
(

J+-*')
c6u IV
(
I
di6m)
: Trong
kh6ng
gian
cho
ldng
tru
dtrr.g
ABC.AB:C,
eo
AB
=.a,AC
=Za,AA,
=2ali
vit
ti
=120"
.
Gqi
M
li.trungditim
cira canh
CC,
.
Hdy
chfrng

minh
MB
L
MAl
vi
tinh
khoing
c6ch
tir
A toi 1.ndt
phing (A.BM
).
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(
I
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Tim ntde
hC
phuo,ng
trinh
sau c6
nghiQm
v6,ix
>
,,
{111 =-
fVx'+3*^ly'+5=m
rr.
PHAN
RrENG(

3
diem)
A.
Theo
chuong
trinh
chuAn
CduVLa:
(
2
di€m)
l)
Trong
mat phing
v6i
h0 trsc
tea dQ
Oxy cho
tam
gi6c
ABC c6
dinh
A rhugc (d):x
-
4y
-2=0;
dudng
thing
BC
songsongv6'i(d);phuongtrinhdudngcaoBH:x*y*3=0.vdtungdi6mcanhabtaM(f;1).ti-mtqadgcac

dinh
A,
B,
C.
2)
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:x
-2.y+Zz+2=1vdhaidi€mA(4;1;3)vh
B(2;-3;-1).Hdy
tim di€m
M thuQc
(P)
sao cho
MAz
+
MB.2 c6
gi6
ni
nh6
nh6t
.
C6.uVil.a(
ldi6rn)
.t
Trongc6c
s0
phuczthoamdnphucrngtrinh:
liz
-Zl=1,
-2

-
il
haytimstiphri'czc6acgumen
bingTr
B.
Theo
chuong
trinh
ning
cao :
4
Cdu VI.b:
(
2di€m):
l)
Trong
mdtphingOxyclio
di6m
C( 2;0)vit
Elip(E)
c6phuongtrinh:
t*
r=
=1.
Timcricdi6m
A,B thuQc
4'
@)
biet
ring

hai
di6rn
A,B
dOi xn'ng
nhau
qua
tmc
irodnh vir tam
gi6c
ABC ddg.
2)
Trong
kh6ng gian
vdi h€
tga dQ
Oxyz, cho
hai
dudng thdng:
r .x-4
y-I
z+5
At
|
;-
=
-;
=
:-
Va
:

J-i-2
-
Viet phuong
trinh
mflt cdu c6
b6n kfnh
nhd
nhAt ti6p
xirc voi chhai
duong
thing
d, vd
d2.
Cdu VII.b:
(1
diCm)
Tim
gi6
tri
nt
d€ hdm
s6
y
=
x2
+(m2
-r)x-m2
+m
x-L
zr)

x+- I
3)
tan
cira
d6
th!
di
qua
di€m
M(l;
5).
d6ng
bi6n trdn cdc
khoing
cria
tflp
x6c dinh vd
ti€m cdn
xi€n
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NOi
du
oAp
Ax vA
BIEU
DIEM
THI
THITE
C LAN

II
-
KIIOI
A -2011
l)Khio
sit
vi
vc a6 tni
hirm
s5
-2x-3
x-2
1. TXD
: R\{z}
2.
Su
biSn thi6n
:
+
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-
TiQm cgn
+D6thi:
Gitii
phu'o'ng
trinh :
lim
y
=a6p
;

hn-l_
!
=-q=
d6 thi
c6
ti6rn
cf.1
dirng
litx:2
x+2-
x-+2-
li+
y
=2
=
dd thi c6
tiQm cf.n ngang
lity
=
2
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y'
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2
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bi6n tr€n
(-

-;
2);(
2; +oo)
'
(*-2)'
v
E? thigiao
vdi
trpc
Oy tai di6m
A(0;312);
D6 thi
giao
v6i
fi'uc Ox t4i di6m
B
(3/2
;0)
D6 thi
nhdn Di6m
I
Q:2)
lA
giao
cria
2
tiQm
c6n
lALrn tAm
d6i xilng.

2)
co: M[",?;),
xs *
2,y'(xo)
=
6+
Phuong
frinh ti6p
ruyt5n A voi
(
C) t4i
M:
t:y
=-:!
"(r-ro;+?&:1
l*o
-2)-
xo
-
z
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giao
didm
A, B cta
(A)
vd
hai tidm
cfln n(rje4)t
Bea
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x\-z
)
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khdc
l(?;2) vit
AIAB vu6ng
t4i
I n€n duorg
h'dn ngo4i ti6p
AIAB
duoTrg
tr-on cd
b6n kinh
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gt,
diQn
tich ducng
trdn
bdng 2x >
R=
Ji
o AB
=2Ji
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f
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-
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Ll
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a
M(t: t) vd
M
(3:
3)
cos2x+ssin(x+
=-z(1).
Ekxd:
0,25
0,25
0,2s
,un[,-
3n

2
z\
(
r\
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6)
l.
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4,25
0,25
4,25
0,25
r
^
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I
cosx=J
ltoat)
l
r=-;+hZ|T
<+l
r
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'

I
cosr
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I
2n
L
2
L"=-
:
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trinh c6 ngiriQm
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lx>
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u
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ra c6
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n6n
(t)
x-5cosx-3=0
2r
3
l2x+9>
0
1 ,-
f
3-V9 +2x
+0
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+
JS
+zx)-
t
-t2
r
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trinh
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c6
A,=81+54=135=9.15,
vd
hai
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hainghi€m
ndy
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vi
nh6 hon
2.
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cria
hdm
s6 kh6ng
rhe d6i
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tra
ring
cd
d6u
tr6n
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rigodi
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1)
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f
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>
0 n6n
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>
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tri
nh6
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ciia
f
(x)
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cho
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suy ra
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hg thric
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n6n
ta c6
:
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2
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e

tufr nnl nndi
e
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i tr€n
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ra
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cria
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Id
:

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ld.
giao
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crla
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va
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n6n
ta c6
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e R)
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o
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ta
y
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I Y: l-Lf
I
a, :
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c6
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z
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ra rttlu
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