Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
Tit 01. DAO ĐNG ĐIU HA
Ngày son:………. Ngy dy: ………
1. Kin thc:
ωϕ ωωϕ
ω
ωϕ ωππ
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (3’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p:42’
&#'&#'%()*+&
,-."# &'&
/0/1'/2,
333
"
,
3
,
3
'/24π*3
/0/1,%ω'/π5π/05167
"
,
ω'/π%/0/1'018,9
,
ω
'/π
%/0/1*:04,
;<=#'/π4π*)5/0/1%4π*/0/41,
&#&#'%8)*+&
,-."# &'&
*,9*9
/9
/
3
"/01333
',933
ωϕ0ωππ)
>;/
/
x A A
v A
ϕ
ω ϕ
= =−
=− =
5
'
/
ϕ
ϕ
=−
=
5ϕπ)
5*
π
π
"*
π
%/01π?'8,
?*%
π
π
π8,9?ω
*,
?'*
π
π5
π
π?
'
4
π
π
5
π
4
π
54/0(85?
π
%*%
4
π
π44,
@.A;B"C(,0'/670$;"A
2
(
)%DEF)GH"I
JK"LA;M=00<;N;O%
"P,!)FQE<0%
,-."# &'&
(,9'/679R
2
(
)
39393
"
,
39
,
3
SR9S2/2)
5(/2
2
(
,
?S/2
2
(
5?'/2/2
2
(
,
?S
/2
2
(
5?*//2
/2
2
(
,
"
,
S'/2,
,
S
*//2
,
CHỦ ĐỀ BÁM SÁT 12CB trang
1
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
&#*JT;=UV,'TUV)N#AUW<=BMT'//X,%YA)C<=BUV
-#L,F;%&AUVZ;=BT;["KE0;D;.AU\;UWA%&A[Q
L.A;B%]^_'/,
%]$$;U\)P;%
,-."# &'&
,'T9T'//X,9
'/,
93
S
,
T
5S
'//
'
'/)
;U\)P;SR
>;)N#=B0M_C0T;`
;
5T,5,T'%'/'///0','/,%
>;/5R'5R2)
J_0'/'/2,
aaa%bcXbd0aeX6af@JgJhX6i )UW!"#$.=-=B)!;"#$%
Tit 02. CON LC L XO. CON LC ĐƠN
Ngày son: ………. Ngy dy: ………
1. Kin thc:
`?T9π
m
k
9 j
'
,
9j
'
T
9 jj
j
'
T
'
,ω
9
/
/
v
A x
ω
= +
π
l
g
9j
'
,
9j
,='?α9j
,
,='?α
/
9jj
j
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (3’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p:42’
&#'&#%()1+&
,-."# &'&
,1/9/09/0,
/9
/
/9
/
k/
3
"4*9
39 39 3v a F= = =
r r ur
ωπ'/π)ωϕ
E/
/
/
x A
v A
ϕ
ω ϕ
= =
= − <
5
/
/
ϕ
ϕ
=
>
5ϕπ)
/'/ππ,
"E4*;Pωϕ
4
%
*
T
T
π π
π
+ =
5
/
':8 /
v A
a A m s
ω π
ω π
= − =
= − = − <
5
a
r
;UW;N;.AH,<)le.Jb&
`,%/0/1%?':8?:0:Xk/5
F
ur
;UW;N;.A<
a
r
&#-mA AT;=UV,
'
#=B0;nW;ATP
'
/0(%;_m<A#_"ImA AT;!
T;=UV,
;P;nW;ATP
/0o%G;;ATP<;np, ;mA Aq-#=B
)C
,-."# &'&
'
/0(9
/0o93
'
2
'
m
k
5,
'
'
T%
π
2
m
k
5,
T%
π
2
'
m m
k
+
52
'
m m
k
+
'
T T+
'
CHỦ ĐỀ BÁM SÁT 12CB trang
2
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
@=-=B)N;rMmA AT;=UV,//0=BMTo/X,%>smA A
AT;tF)GH"I',)p)A_.;*/
,;N;UWTs%
G;;ATP#"C<%
"JK$;U\)P;<mA A0;D;O=#=umA AmAF)GH"I0;A_L
;N;.AU\%]^_π
'/%
,-."# &'&
,//9T1/X,9
/
',9*/
,9
33
"3
S
,
T
o/
/
/0
=
)5
/ '/
π π π
ω
= =
/
/
v
A x
ω
= +
( )
*/
' 4
/
+ =
,
"4/R,
>;/;P
/
/
x A
v A
ϕ
ω ϕ
= =
=− >
5
/
/
ϕ
ϕ
=
<
5ϕ
π
)
54/
π
,
&#*%:)8+&
,-."# &'&
,1/9l,9:0o
,
3"α
4/
e
,
3`
,
3
π
l
g
0o
"j
'
,
,
,l'?α
5
,
'
o
gl
α
−
04,
`
,
?,,%
,
v
l
5`
,
/0(X
@=-\#"Il%)T; ;Ov;Q;n'%>; ,#<
"W'(,0)qT; ;Ov;U)C0=-;Q;n/%b;"K:0o,
%G;#
"A<=-%
,-."# &'&
:0o,
9v5
'
'
/l = 3
'
v
'
v'
π
l
g
v
v/
π
/0'(l
g
−
5
'
/0'(
l
l
=
−
/'14
5ll?/0'(%1:5l?l.1:?/0'(%1:
5l/01,1,
aaa%bcXbd0aeX6af@JgJhX6i )UW!"#$.w;V$;.A;Bq$;U\0
q)!;"#$%
Tit 03. SNG CƠ
Ngày son: ………. Ngy dy: ………
1. Kin thc:
v
vT
f
λ
= =
;
2
T
π
ω
=
; λ = vT; u
M
= Acosω(t - ∆t)
π
λ
= −
÷
2
t x
A
T
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (2’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p:42’
&#'"#8%()''+&
CHỦ ĐỀ BÁM SÁT 12CB trang
3
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
,-."# &'&
1@67
T
4*/,3
"
'1//,3
(
(o%'/
v
m
f
λ
−
= =
=> d > 0,68mm
"
(
x
x 4//%'/
v
m
f
λ
−
= =
=> d > 0,3mm
&#"#8%o)''+&
,-."# &'&
''/67
4*/,
yR2yRz2
3z3
40'
v
m
f
λ
= =
#z
'011
m
λ
=
"#o%1)'+&
,-."# &'&
o,'//67
/0o,
A2A
@'
3
"y33
/0o
/0//o /0o
'//
v
m cm
f
λ
= = = =
#
'
o,
'
'(,/{#
'
/
5A
@'
//2/2
"+
'
a+
aT'{*,#+
'
+
+
'
ao,/%{
_;|};C,{/0*,
o0*~T{~o0*
5o0*~T%/0o~o0*
5'/01~T%~'/01
5T'!)F
5/UO;_"N$=#'UO;r
&#*J)A_.H,)T;[T;G=#44/,0)UW=#'*41,%@H,"UW)T;[
T;G=#1/,;PT;)A_.)UW"UW=#
,-."# &'&
T
44/,
'*41,
{
T
1/,{
3
{
5{
T
44//01((/67
5{
'*41((/0'8,
@)A_.)C,•"L"UW*,%
>; !;Z;L,;A;^)Cq,$;U\)A_.=n;$;;A2=#";CA3
"XKA<=#/0167;P;P<=#";CA3
,-."# &'&
{
*,
yR23
"',3
XKAL,)C$;U\)A_.!;;A*,;P=n;$;ZL,
=#2)5=n;$;ZL,=#2);P!;;A',
"{5{%*%/01,
aaa%bcXbd0aeX6af@JgJhX6i )UW!"#$.€)!;"#$%
Tit 04. SNG DNG. SNG ÂM
Ngày son: ………. Ngy dy:. ………
1. Kin thc:
2
l k
λ
=
;
(2 1)
4
l k
λ
= +
v
vT
f
λ
= =
;
2
T
π
ω
=
; λ = vT;
1
1
10
dB B=
;
0
( ) 10lg
I
L dB
I
=
;
I
0
= 10
-12
W/m
2
CHỦ ĐỀ BÁM SÁT 12CB trang
4
2
λ
A
P
N
N N N
N
B B B B
4
λ
A
B
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (2’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p:(43’)
&#'"#:%8)'*+&
,-."# &'&
l'0/1,
/0167
yX'0yX0yX4
'
3
3
4
3
"
/0167
&T
3
]$=AU) l 3λ/4 5λ = '0*,50',
)CH_;C,'u;P l 5λ’/4 5λ = /0o*,5
'
0167
5Bn
'
z
'0167
)CH_;C,u;P λ
2
= 4l/7 = /0(,5
40167
5Bn
z
'08167
)CH_;C,4u;P λ
3
= 4l/9 = /0*8,5
4
*0167
5Bn
4
z
0167
"]$=AU) lT λ 5λ lTT'004•
5
T
λ
T
Tl 9z
T
Tl
5
T
T679z
T
T67%
&#"#:%:)'*+&
,-."# &'&
λ/2 = '0,
3
)C=B;|,"l=> l =λ/2 => λ=2l = 0*,
5 λ.f = '/,
@VH_&A&-;•#A-#,;!;H,
;;U;P;‚%b;H,;mA!;^_
)C&""l€0&=#,u#_!,u
€%
P,"UWλ<)A_.)CH_%b;&/,0'/67%
"P,)A_.)CH_%
,-."# &'&
&*&/,0'/67
λ3"3
AB =Tλ/2 = *λ/2 / => λ= '/,
" λ5 λ.f = //,
&#*@VH_A.AF;0A&W1670&'o,0)A_.)CH_=#
1/,%)CH_";CA"l%
,-."# &'&
167&'o,
1/,&3
λ1/1,
AB =Tλ/2 = T 'o => có 18 bụng sóng
@H_&;AF;&1/,0)A_.)CH_',0)A)CH_'//67%YL,@
!;,E401,=#u;_"l;M,^_TL€%
,-."# &'&
&1/,',
'//67401,
X;_&;M,^_3
λ'//'//',
=Tzλ/2 = Tz/01 4018%/015Tz8
J_E@=#u;Mo
&#(E,L,I,!;ApH,XApL,,T; X0,MUOH,=#]
:/&%&K
Uƒ;N<H,=#a
/
/0'j,
%bUO<H,E=#";CA3
,-."# &'&
]
:/&a
/
/0'j,
a
3
= = = =
9 2
0 0 0
( ) 10lg 90 => lg 9 => 10 => = 0,1W/m
A A A
A
I I I
L dB I
I I I
Ngêi ta dïng bóa gâ m¹nh vµo ®êng ray xe lưa c¸ch n¬i ®ã 1090 m, mét ngêi ¸p tai vµo ®êng ray nghe thÊy tiÕng
gâ trun qua ®êng ray vµ sau 3 s míi nghe thÊy tiÕng gâ trun trong kh«ng khÝ. X¸c ®Þnh vËn tèc trun ©m trong thÐp
(®êng ray) bݪt trong kh«ng khÝ v = 340m/s.
,-."# &'&
d = 1090m t = 3s
v
k
=340m/s v
t
= ?
T
k
= 1090/340 = 3,2s
=>
40?4/05v
t
= d/
'/://01*1/,
aaa%bcXbd0aeX6af@JgJhX6i„$.,E;…]bK$% )UW!"#$.,E;…]b
K$)!;"#$%
CHỦ ĐỀ BÁM SÁT 12CB trang
5
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
()%
Tit 05. Ngày son: …………… Ngy dy: ……………
1. Kin thc:
?<BnS
π
π
?b ,T;!†
]
S]%
?‡AT;!†
b
'Sb%
?w)ˆ†
b]
††… −+
?YF;=A„,a‰†‰
…
…‰
]
†
]
‰
b
†
b
?6n[A^R‰
…
‰…†%
?R‰
]
?‰
b
‰
…
†
]
?†
b
…%
?b[A^‰%a%R…%a
?@E; _);Uˆa
,
T;†
]
†
b
0R/0S
]b'0†
,
…0R'0‰a
,
…%a
,
?6n)ˆ,-'…'…
'
'…
0,-K$……
'
…
?6ln,-bb
'
b
0,-K$'b'b
'
'b
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (10’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p: (35’)
&#'"#'4%()/+&
,-."# &'&
b'1///2`
A
'/ t V
ω
'// rad s
ω π
=
3
"
'/// rad s
ω π
=
3
†
b
'Sb1/Ω9 a‰†
b
0*50*
'//ππ
"†
b
'Sb1Ω9 a‰†
b
*5*
'///ππ
&#"#'4%o)/+&
,-."# &'&
…4/
4Ω
b'4///2`
A
'/ t V
ω
3
"‰
…
3‰
b
3
†
b
'Sb4/Ω9 †
b]
††… −+
(/Ω
a‰†
b
9ϕ'
4
5ϕ?π(
5
'//ππ(
"‰
…
a…(/
4
J9‰
b
a†
b
(/J
"#'4%:)'+&
,-."# &'&
…*/
Ω
]/0*26
o/'// u t V
π
=
3
"‰
…
3‰
]
3
†
]
S]*/Ω9 †
b]
††… −+
*/
Ω9
a‰†
'9ϕ'5ϕπ*
5
'//π?π*
"‰
…
a…*/J9‰
]
a†
]
*/J
&#*"#'4%'/)'+&
,-."# &'&
…4/Š
'/'// u t V
π
=
‰
]
(/J
†
]
3
"3
5 (/ (/
R L R L R
U U U U U U U V= + = − = => =
5a‰
…
…(/4/‹
†
]
‰
]
a(/4/Š
"ϕ'5ϕπ*5
'//π?π*
CHỦ ĐỀ BÁM SÁT 12CB trang
6
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
Tit 06. Ngày son: ……………Ngy dy: ……………
&#'"#'*%')+&
,-."# &'&
…4/Š]/0'26
b'*///2`
'/ '// u t V
π
=
3
"‰
‡
3
†
b
'Sb*/Ω9 †
]
S]'/Ω9
†
CL
ZZR −+
4/
Ω
a‰†
9ϕ†
]
?†
b
…?'5ϕ?π*)
5*'//ππ*
"‰
‡
a%
C
ZR +
'//
J
&#"#'*%)+&
,-."# &'&
…*/Š]/0426
b'8///2`
'(/'// u t V
π
=
3
"‰
]
3
†
b
'Sb8/Ω9 †
]
S]4/Ω9
†
CLL
ZZR −+
*/
Ω
a‰†9ϕ†
]
?†
b
…?'5ϕ?π*)
5
'//ππ*
"‰
]
a%
LL
ZR +
'//J
"#'*%4)+&
,-."# &'&
…4/Š
*/ '// u t V
π
=
]/0426
b'8///2`
3
"‰
]
3
†
b'
'Sb
'
'/Ω9 †
b
'Sb
8/Ω9
'
CLCL
ZZRZZR −+=−+
5†
]
*/Ω
"†
4/4/ +
4/
Ω9a*
9
JW†
b'
o'//π?π*
JW†
b
o'//ππ*
‰
‡
a%
L
ZR +
//
J
&#*"#'*%1)+&
,-."# &'&
*/ '// u t V
π
=
* '//
(
i t A
π
π
=
]/0(26
…3b3
†
]
S](/Ω9 †
‰a(/Ω9
R…†5…†R4/
4
Ω#
4
4
L C
Z Z
R
ϕ
−
= = −
5†
b
4/Ω95b
π
4
'/
4−
`
Tit 07. Ngày son: ……………. Ngy dy: ……………
&#'"#'*%8)4+&
,-."# &'&
…*/Š]/0126
/ '// u t V
π
=
a*0*b3R3
"a
,
3b3
†
]
1/Ω9†‰a/*0*1/Ω9
†
L C
R Z Z= + −
5
† 1/ */ 4/
L C
Z Z R− − = − =
5
4/
L C
Z Z− = ±
5
1/ 4/
C
Z− = ±
5
Ω
Ω
=
/
o/
C
Z
5
=
=
FC
FC
π
π
///
'
o///
'
JW†
b
o/Ωϕ?4*5ϕ/0(*)
JW†
b
/Ωϕ4*5ϕ/0(*)
"bUO;nAl=W;^T;†
]
†
b
1/Ω%
>;
FC
π
1///
'
=
# I
max
= U/R = 220/40 = 5,5A
CHỦ ĐỀ BÁM SÁT 12CB trang
7
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
&#"#'*%:)4+&
,-."# &'&
…*/Š
o/'// u t V
π
=
‰
…]
1/J‰
b
8/J
]3b3
"3
1/
%*/
RL R L
R L C
U U U
U U U U
= + =
= + − =
5‰
]
4/J
*/
R RL L
U U U V= − =
9
a‰
…
…*/*/'5†
]
‰
]
a4/Ω5
HL
π
40/
=
†
b
‰
b
a8/'8/Ω5
FC
π
8///
'
=
"
4/ 8/
'5
*/ *
L C
Z Z
rad
R
π
ϕ ϕ
− −
= = = − = −
5
'//ππ*
"#'*%')*+&
,-."# &'&
‰4801J‰
…]
1/J
‰
b
'801Ja/0'
…3†
]
3†
b
3
"z44/67
aa
,
]3b3
†
b
‰
b
a'801/0''81Ω
†
…]
‰
…]
a1//0'1//Ω
†‰a4801/0'481Ω
1//
481
RL L
L C
Z R Z
Z R Z Z
= + =
= + − =
5†
]
*//Ω5…4//Ω
"†
]
ω]*//Ω†
b
C
ω
'
'81Ω5
'81
*//
==
ω
LC
Z
Z
C
L
@•T;!†
]z
ωz]†z
b
'
xC
ω
5
x
x '
x
L
C
Z
LC
Z
ω
= =
5
'81
*//
x
=
ω
ω
*//
% %44/
'81
ω π
=> =
5ω'///π)
5]†
]
ω*//'///π*'/π6
5b'ω†
b
''///π%'81`
Tit 8. Ngày son: ……………. Ngy dy:. ……………
&#'"#'1%1)1+&
,-."# &'&
1/ '// u t V
π
=
‰
]
4/J‰
b
(/J
R3
"P/j
…3]3b3
‰
CLR
UUU −+
5‰
…
*/J5R‰
…
‰/0o
"P/*/a5a/01
5…‰
…
ao/Ω9
5†
]
‰
]
a(/Ω95](/'//π6
5†
b
‰
b
a'/Ω95b''//π%'/`
&#"#'1%8)1+&
,-."# &'&
]/0(26
b''*///2`
'(/'// u t V
π
=
Po/j
3
†
]
(/Ω9†
b
'*/Ω9
ϕ
−=
−
U
UU
CL
5ϕ
*
π
)5ϕ
m•T;!P‰aϕ5aP‰ϕ'
5
'//ππ*
CHỦ ĐỀ BÁM SÁT 12CB trang
8
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
b;,E;n_;.Ap,…0]0b,-K$%
&K…'//
4
Ω
]
'
π
60b1/
π
Œ`
'//
π
%
G; ,T;!0AT;0w)ˆ<,E;%
" JK"LA;MAZ;AE,E;%
c) G;n!$;nAlZ;A,•$;Žn%
,-."# &'&
…'//
4
Ω
]
'
π
60
b1/
π
Œ`
'//
π
†
]
3†
b
3†3
"A3
‰
…
3 ‰
]
3‰
b
3
†
]
S%]'//
Ω
0†
b
'S%b//
Ω
0
†
+ −
L C
R Z Z
//
Ω
%
"‰
/
a
/
%†//
J0R†
]
?†
b
…?'
4
5R?
π
()
J_0A//
'//
π
?
π
(J%
‰
…
…%a'%'//
4
'//
4
J0
‰
]
a%†
]
'//J0‰
b
a%†
b
//J0
Tit 9. Ngày son: ……………. Ngy dy: ……………
&#'YE,E;_;.A&p,A ,n)ˆ;AT;[!TL0 ,T;!8/
Ω
0,-K$W
lnAT;!1/
Ω
0Bn),E;"LA;M1
'//
π
a) G;n!$;nAlZ;AA ,#Z;AE,E;%"G;]0b%
,-."# &'&
†
]
8/Š†
b
1/
Ω
1
'//
π
A3
"]30b3
aa
/
%€"LA;MUV
a10S'//
π
)
;N=„,a‰
]
†
]
5‰
]
a†
]
41/J
†
b]
††… −+
5†
b]
†† −
/
Ω
%
;N=„,a‰
&
†5‰
&
a†'//J
"†
]
S%]5]†
]
S8/'//π/046
†
b
'S%b5b'S†
b
''//π.1/(40((%'/
?(
µ`
&#b;E,E;&p,…0]0b,-K$%&K…'//
Ω
0]/04'o60b1/
π
µ`0A
&
//
'//
π
J
JK"LA;MUOBnmA,E;%
"JK"LA;M;nAn;KA
•
A
…
#A
•&
A
]0b
G;[A^#;n[A^<E,E;&%
,-."# &'&
…'//
Ω
0]/04'o60
b1/
π
µ`0A
&
//
'//
π
J
3
"A
•
3A
•&
3
P 3R3
†
]
S%]'//
Ω
0†
b
'S%b//
Ω
0
†
+ −
L C
R Z Z
'//
Ω
%5a
/
‰
/
†//
'//
R†
]
?†
b
…?'5R?
π
*)A)L$;
π
*W
J_0'//
π
π
*%
"‰
/•
…%a
/
//J5A
•
//'//
π
π
*J%PA
•
#q$;
‡†
]
k†
b
CA
•&
)L$;
π
W0‰
/•&
a
/
%†
•&
//J0
5A
•&
//'//
π
π
*?
π
5A
•&
//'//
π
?
π
*J%
P…a
'//%
//j0R…†'//'//
b;E,E;p,]n)ˆ)#b,-K$%&Kn!$Z;AE,E;=#A*//'//
π
J0n!$;nAlZ;AA ,=#//
1
J0BnmA,E;=#0G;)0]0b%&K;n[
A^<,E;=#
,-."# &'&
A*//'//
π
J
‰
)]
//
1
J
a
)3]3b3
†‰a*//%
'//
Ω
0
R)†5)†%R'//
%
'//
Ω
%
†
]0)
+
L
r Z
‰
]0)
a//
1
'//
1
Ω
0
5†
]
0
−
L r
Z r
//
Ω
05]/0(4(6
5†
+ −
L C
r Z Z
'//
Ω
%5
] b
† † '//− = Ω
5
b
b
† 4//
† '//
= Ω
= Ω
5
b '/0( `
b 4'0o `
= µ
= µ
CHỦ ĐỀ BÁM SÁT 12CB trang
9