giao an vat li song ngu

Preparing day:5/9/2017
Teaching day: 9/9/2017
Period 1: Mechanical Motion.
I.
The aims:
1. Objective: New works in this lesson.
- State concept motion, particle
2. Skill: - Pronounce new word
- Read book.
II.
Preparing:
1. Teacher: New word
2. Students: Read book
III.
Procedueres:
1. Organization: greeting and checking attendance
2. Warm-up: State uniform linear motion and writes it’s equation
3. New lesson

Act 1: Learning new words
Teacher’s activities
Read book and find mean of this
words
Motion
Mechanics
Mechanical
Move
Movement
Object
Position
Distance

Consider
Orbit
Trajectory
Space
Reference point
Reference system
Coordinate system
Perpendicular
Time mark
Diameter
Horizontal
Vertical

Students’s activites
Find mean this words in book.

Listen and read that words


Delete that words, ask Ss write again
corresponding with its mean

Ask Ss listen and repeat that words
Delete that words, ask Ss write again
corresponding with its mean
Translating this concepts
Motion is the change of position of that
objects compared with other objects
Translating this concepts
over time.

An object is consider a particle if it size
is too small compared with the length
of the road.
Reference point is consider as standing
still.
Reference system: include horizontal
and vertical axes.

Acts: Learning concepts
Teacher’s activities
Student’s activities
Find mean of this words
Find mean this words in book.
Translating this concepts
Motion is the change of position of that
objects compared with other objects
over time.
An object is consider a particle if it size
is too small compared with the length
of the road.
Reference point is consider as standing
still.
Reference system: include horizontal
and vertical axes


Preparing day:10/9/2017
Teaching day: 16/9/2017
Period 2: VOCABULARY ABOUT BASIC CALCULATION
I.

The aims:
1. Objective:
- Review words in old lesson
- Know to say basic calculations
2.Skill: - Pronounce new word
- Read book.
II.
Preparing:
1. Teacher: New word
2. Students: Read book
III.
Procedueres:
1. Organization: greeting and checking attendance
2. Warm-up: State uniform linear motion and writes it’s equation
3. New lesson
Act 1: Review old words
Teacher’s activities
Ask Ss writing and reading
again this words
Motion
Mechanics
Mechanical
Move
Movement
Object
Position
Distance
Consider
Orbit
Trajectory

Space
Reference point
Reference system
Coordinate system
Perpendicular
Time mark
Diameter

Students’s activites
Find mean this words in book.


Horizontal
Vertical
Act 2: Learn how to say basic calculation in English
Teacher’s activities
Student’s activities
a+b
a-b
a*b
a/b
b
a=b

a plus/ b
Ss remember calculations.
a minus b
ab, a times b
a over b, a is divided by

a equals b
a is equal to b
a>b
a greater than b
a bigger than b
a strictly than b
a< b
a less than b
b
a a to b
x2 x square
x3 x cube
x-1 x inverse

Act 3: Practices
Teacher’s activities
Calculate
and
read
calculations
125+48=
12*3=
12/3
23=
82=
34=
x2+x2-8x=0
x2>=2

Student’s activities
these


Preparing day:10/9/2017
Teaching day: 16/9/2017
:
Period 3: Uniform linear motion
I.

The aims:

1. Objectives:
- Review way to say basic calculations
- Read and draw graph.
- State concepts of uniform linear motion, speed
2.Skills: - Pronounce new word
- Read book.
II.
Preparation:
1. Teacher: New words
2.Students: Read book
III.

Procedures:

1.Organization: greeting and checking attendance
2.Warm-up: State concept motion, particle.
3.New lesson
Act 1: review

Teacher’s activities
Review old lesson
Read calculations
4-6x-x2=0
5/x-8=0
x>=2
y3<8

Student’s activities
Read these calculations

Act 2: State concepts speed and linear motion


Teacher’s activities
Find new words in page 12 and their
mean
Average
Speed
Position
Distance
Assume there is a particle, it moves on
linear line. ( ox axis)
At t1 =,it is on A whose coordinate is x1
At t2 ,it is on A whose coordinate is x2
Calculate its average speed
Ask Ss do exercise C1
What is unit of speed
Concept average speed:
An object’s average speed shows how

fast it’s going, it is calculated by
formula
Average speed=distance travelled/time
of motion

Student’s activities

Average speed=distance travelled/time
of motion
C1:
Unit: m/s, km/h

Uniform linear motion is motion whose
trajectory is a straight line and average
Ask Ss read book and concept uniform speed is the same on any distance.
linear motion.
The equation of uniform linear motion
of a particle
Ask Ss write equation of uniform linear X=x0+vt
motion
Act 2: Draw graph of coordinates- time of uniform linear motion
Teacher’s activities
Student’s activities
Draw graph of coordinates- time of
uniform linear motion
Assume a particle moves with equation
X= 2+5t
Step 1: make a table of corresponding
values between x and t
Step 2: Draw

-draw two perpendicular axis
Vertical axis is the ordinate axis
Horizontal one is the time axis
Make points with corresponding x,t in
table (x,t) then connecting those points,
we get a line segment. It is graph of
coordinate- time
Practice draw x=3+5t

Date of plan : 17/9/2017
Date of teaching: 23/9/2017
Period 4: Exercises about uniform linear motion
I.

The aims:

1. Objective:
- Review old words
- Write equation of uniform motion.
- Find out quantities distance, velocity and time.
2.Skill: - Pronounce new words
- Use vocabularies
II.
Preparing:
1. Teacher: New words
2.Students: Read book
III.

Procedures:

1.Organization: greeting and checking attendance
2.Warm-up: State concept motion, particle.
3.New lesson
Act 1: review
Teacher’s activities

Student’s activities


Exercise 9 in page 15
On a straight line, at two point A,B
which are 10km from each other, two
automobiles start at the same time and
move in the same direction. The
automobile starting from A has speed
of 60km/h and the car starting form B
has the speed of 40km/h.
a, By taking the origin of coordinate at
A, the origin of time at the time of
starting, write the formula to calculate
the distance travel and the equation of
motion of two automobiles.
b, draw the graph of coordinate-time of
two above automobiles on the same
coordinate- time system.
c, Based on the graph to find when and
where the automobile A catches up
with automobile B.

Read and understand question
a, By taking
- the origin of coordinate at A,
-the origin of time at the time of
starting
-positive direction from A to B
Distance travelled of A and B
SA= vAt=60t
SB= vBt=40t
The equation of coordinate-time
XA=x0A+ vAt=60t
xB=x0B+ vBt=10+ 40t
b, Draw graph of coordinate-time
make table of coordinate-time

t
xa
x

0
0
10

c, the time A catches up B is 0,5h
at position whose coordinate is 30km
10.
a, S=60
x= 60t
DP=DP-DH=100-60=40

X=40(t-1)+60
b,
Exercise 10: A van starting from city H
moves linearly and uniformly to D city
P with the speed of 60km/h. When
arriving in city D which is 60 km away
from city H. the automobile stops for 1
hour. After that, it continues to move


uniformly to P with the speed of c, Time the automobile reaches P
40km/h. the route from H to P is
considered straight and 100km long.
1+1+1=3 hours
a, Write the formula for calculating the
distance travelled and equation of
motion of the automobile on two
distances H-D and D-P the origin of
time is when the automobile starts from
H
b, Draw the graph of coordinate- time
of the automobile on the entire of road
H-P
c, specify time that the automobile
reaches P

Date of plan : 17/9/2017
Date of teaching: 23/9/2017
Period 5: Uniform variable linear motion
IV.

The aims:

1. Objective:
- Review old words
- State concepts of velocity, acceleration, uniform variable linear
motion.
- How to describe a vector quantity
- Find out quantities distance, velocity and acceleration of uniform
variable linear motion
2.Skill: - Pronounce new words
V.

- Use vocabularies
Preparing:


1. Teacher: New words
2.Students: Read book
VI.

Procedures:

1.Organization: greeting and checking attendance
2.Warm-up: State average speed and the equation of motion of uniform linear
motion.
3.New lesson
Act 1: review
Teacher’s activities
Student’s activities

Read and write their mean
Do as teacher requite .
Distance
Average
Uniform
Linear
Equation
Direction
Positive
Horizontal axis
Vertical axis
Coordinate system
Perpendicular
Graph
Speed
Velocity
consider
Act 2: concept acceleration, instantaneous velocity
Teacher’s activities
Student’s activities
Vector of instantaneous velocity.
Concept: Vector of instantaneous
velocity specified fastness and
direction of motion.
It is a vector whose origin is at the
moving object, the direction is that of
motion and length is directly
proportional to the magnitude of the
instantaneous velocity in a certain

scale.
Uniform variable linear motion: is
motion whose trajectory is a straight
line and magnitude of velocity either
increases steadily or decreases steadily
over time.
Question : How many kind of uniform
variable linear motion.

There are two kind of uniform variable
linear motion. They are uniformly
accelerated
linear
motion
and
uniformly decelerated linear motion.

Acceleration:
Concept: it shows that the velocity
varies how fast over time. It is
calculated by formula
a= change of velocity/ time taken
Velocity equation:
2
Unit: m/s
V=v0+at
Equation of motion:
The equations of uniform variable X=x0+v0t+at2/2
linear motion.

Distance travelled
Ask Ss write and read equations of s=+v0t+at2/2
uniform variable linear motion.
the formula for the relationship
between the acceleration, velocity and
distance travelled.
V2 -V02 =2as

Date of plan : 24/9/2017
Date of teaching: 30/9/2017
Period 6: Exrecise about uniform variable linear motion
I.

The aims:


1. Objective:
- Review old words
- Find out quantities distance, velocity and time.
2.Skill: - Pronounce new words
- Use vocabularies
II.
Preparing:
1. Teacher: New words
2.Students: Read book
III.

Procedures:

1.Organization: greeting and checking attendance

2.Warm-up: State average speed and the equation of motion of uniform linear
motion.
3.New lesson
Act 1: review
Teacher’s activities
Read and write their mean
Variable
Instantaneous
Origin
Magnitude
Proportional
Steadily
Increase
Decrease
Acceleration
Accelerate
Decelerate
Corresponding
Answer the question
What is uniform variable linear motion
State concept of instantaneous velocity

Student’s activities

Act 2: Do exercise
Teacher’s activities
Student’s activities
Exercise 12:A train leaving from the
station
is

moving
accelerando


uniformly. After 1 minute, it reaches
the speed of 40km/h
a, Calculate the acceleration of the train
b, calculate the distance that the train
has travelled in this 1 minute.
c, if it continues to accelerate, how
long will it reaches the speed of 12:
60km/h
V0=0
t=60s =>v=40km/h=100/ m/s
the acceleration of the train
a=v-v0/t=0,185 m/s2
the distance the train travelled in this 1
minute
s=1/2at2= ½.0,185.602 =
the time to the train reaches the speed
of 60km/h
=
Exercise 13: A car is moving linearly,
uniformly with speed 0f 40km/h
suddenly
accelerates
uniformly.
Calculate the acceleration of the car ,
know that after travelling a distance of 13: v0 =40km/h=100/9m/s
1 km, it has reached the speed of s-1km =>v=60km/h

60km/h.

14. v0=40km/h=100/9 m/s
V=0
t= 2 minutes = 120 seconds
a=(0-100/9)/120
Exercise 14: a train running with the s=v0t+0,5at2
speed of 40km/h is braked and moves
straight decreasing uniformly to enter
the station. After two minute, it stopped
at the station.
Calculate the acceleration of the train
Calculate the distance that the train


travelled in the time of braking

Date of plan : 24/9/2017
Date of teaching: 30/9/2017
Period 7: Exrecise about uniform variable linear motion
I.

The aims:

1. Objective:
- Review old words
- Write the equation of motion.
2.Skill: - Pronounce new words
- Use vocabularies
II.

Preparing:
1. Teacher: New words
2.Students: Read book
III.

Procedures:

1.Organization: greeting and checking attendance
2.Warm-up: State average speed and the equation of motion of uniform linear
motion.
3.New lesson
Act 1: do exercises
Teacher’actives
Student’actives
Question 7: The two cars are traveling
in the opposite direction through two
points A, B separated by 130m, people
traveling from A moving slowly with a
head speed of 5m / s and acceleration
of 0.2m / s2, people going from B shift
Accelerate gradually with a top speed


of 1.5 m / s and an acceleration of 0.2
m / s2. Select the origin at A, positive
from A to B.
a) Write the equation of the two
vehicles.
b) Calculate the distance between two
vehicles after the two vehicles get t1 =

15s; t2 = 25s.
c) How long does it take to get two
vehicles? Calculate the distance each
car was going to meet.
answer question 7
a) equation
1
x1 = v0 t1 + at12 = 5t − 0,1t 2
2
x2 = v0 t1 +

1 2
at1 = 130 − 1,5t − 0,1t 2
2

b) t1: d1 = x2-x1 = 32.5m never

met;
t2: d2 = x2-x1 = -32.5m met;
Question 8: A car is moving at a speed c) d = 0 if t = 20s; s1 = 60m; s2 =
of 4m / s, the driver accelerated 70m
suddenly with an acceleration of 0.5m /
s2. After 10s since the acceleration,
driver brakes to slow the car moving
slowly after 6 seconds to stop.
a) Write the equation for the
coordinates and velocity equation of
the vehicle in each CCT
b) Graph the acceleration and velocity
of the vehicle in each phase of motion.

Solution 8
-choose the origin is the position of the
car starts to accelerate,
-the time mark is the time the car starts
to accelerate,


-positive direction is direction of
motion :
Stage 1: t01 = 0; x01 = 0; v01 = 4m / s,
a1 = 0.5m / s2.
Equation coordinates:; equation of
velocity: with (0Stage 2: t02 = 10s; x02 = 4.10 + 25 =
65m; v02 = 4 + 5 = 9m / s; a2 = -v02 /
t2 = -9 / 6 = - 1.5m / s2;
Equation coordinates:;
Equation of velocity: with (10 16s)
b) Acceleration graph: phase (1):
a1 = 0.5m / s2 (0Stage 2: a2 = -1.5m / s2: (10Speed chart:
stage 1: v1 = 4 + 0.5t (m / s) (010s);
Stage 2: v2 = 24-1.5t m / s (10
Date of plan : 30/9/2017
Date of teaching: 6/10/2017
Period 8: FREE FALL
I.

The aims:

1. Objective:
- Review old words
- Write the equation of motion.
2.Skill: - Pronounce new words
- Use vocabularies
II.
Preparing:
1. Teacher: New words
2.Students: Read book


III.

Procedures:

1.Organization: greeting and checking attendance
2.Warm-up: State average speed and the equation of motion of uniform linear
motion.
3.New lesson
Act 1: review
Teacher’actives
New words:
The fall:
Drop
Sheet
Conclusion
Tube

Mass
Ignore
Resistance
Consider
Apply
However
Tower
initial velocity
impact
affect

Student’actives
Find mean of new words

1. Concept

ask Ss state concept of the fall in the The fall of objects in the air: Drop an
air and free fall
object from a certain height , it moves
without initial velocity and it moves
downwards. It is affect of the air.
2. Free fall:
-the fall of objects in vacuum
-free fall is the fall only under the
impact of gravity.
II. Studying the free fall of objects.
State characteristics of free fall:
Find out characteristics of a free fall
Direction, acceleration.
motion

Direction of a free fall is vertical
Dimension: is from top to bottom


A free fall motion is uniformly
accelerated
linear
motion
with
acceleration of gravity of g.
Ask Ss write equation of motion and g. is called acceleration of free fall
velocity of free fall.
the distance of free fall: h=1/2gt2

State which affects
acceleration of free fall.

impact

formula calculated velocity of free fall
to
v=gt
three are many ways to measure g.
objects fall freely with the same of
acceleration.
G depens on its position in the earth.

Date of plan : 30/9/2017
Date of teaching: 9/10/2017
Period 9: EXERCISE ABOUT FREE FALL

I.

The aims:

1. Objective:
- Review old words
- Write the equation of motion.
- Do exercises about free fall
2.Skill: - Pronounce new words
- Use vocabularies
II.
Preparing:
1. Teacher: New words
2.Students: Read book
III.

Procedures:


1.Organization: greeting and checking attendance
2.Warm-up: State average speed and the equation of motion of uniform linear
motion.
3.
Teacher’s actives
Check old words. Answer teacher.
What factors affect the fast and slow
fall of different objects in air
What is a free fall. State characteristics
of a free fall.
Write formulas to calculating the

acceleration and distance of a free fall
object

Student’ actives
-the fall of objects in vacuum
-free fall is the fall only under the
impact of gravity.
II. Studying the free fall of objects.
Find out characteristics of a free fall
motion
Direction of a free fall is vertical
Dimension: is from top to bottom
A free fall motion is uniformly
accelerated
linear
motion
with
acceleration of gravity of g.
g. is called acceleration of free fall

Ex 7: which motion of the following
objects is considered a free fall motion. the distance of free fall: h=1/2gt2
If it is dropped
A. A falling leaf
B. A thread
formula calculated velocity of free fall
C. A handkerchief
v=gt
D. A piece of chalk
Ex 8: Which motion of the following

objects can being considered a free fall
A. The motion of gravel being
thrown horizontal
B. The motion of gravel being
thrown up
C. The motion of gravel being
thrown diagonally
D. The motion of gravel being
dropped
7.
The correct answer is D. the gravity of
the chalk is greater than resistance of


Ex 9: drop a stone from a height of h to air thus we can ignore impact of air.
the ground. This stone has fallen for 1
second. If we drop the stone from the
height of 4h to the ground, how long
has it fallen?
8.
The correct answer is D. the free fall
without initial velocity
Ex 10: a heavy object falls from height
of 20m to the ground. Calculated the
time of fall and velocity of the object
when it reaches the ground. Take g=
10m/s2

9.
=1second

=2second

10.
=2second
V=gt=10.2=20m/s

Date of preparing: 7/10/2017
Date of teaching: 13/10/2017
Period 10: UNIFORM CIRCULAR MOTION
I.
The aims:
1. Objective:

- definition circular motion and uniform circular motion
- state characteristics of vector of velocity of a uniform circular motion


- definition linear speed, angular speed, period, frequency and centripetal
aceeleration
2.Skill: - Pronounce new words
- Use vocabularies
II.
Preparing:
1. Teacher: New words
2.Students: Read book
III.

Procedures:

1.Organization: greeting and checking attendance

2.Warm-up: State definition of uniform circular motion.
Act 1: definition uniform circular motion
Teacher’s actives
Circular motion: is motion whose orbit
is circle

Student’s actives
V=distance travelled/ time taken

Ask Ss repeat formula for calculated
average speed
On a circular motion, distance travelled
is equal to length of arc travelled.
Average speed = the arc length
travelled/ time taken
Read book and definition uniform
circular motion

Uniform circular motion is motion
whose orbit is circular and average
speed on all arc is the same.
Act 2: State characteristics of vector of velocity, period, frequency

Teacher’s actives
Circular motion, magnitude of
instantaneous velocity is called linear
speed
Vector of velocity is always tangent
with its orbit and perpendicular with
radius

Student’s actives
V=distance travelled/ time taken


Request to comment the angular speed
of the uniform circular motion .

Name the angular speed unit.
Definition of period.
Request response C4.

Uniform circular motion is motion
whose orbit is circular and average
speed on all arc is the same.
Angular speed: when the object moves
an arc, the radius rotates an ange
Angular speed shows how fast the
radius rotates. On a uniform circular
the angular velocity of circular motion
is a constant quantity.
The angular speed unit is rad / s.
Period.
The period T of circular motion is the
time for the object to go round.
Relation between angular speed and
period T =
2π
ω

Request if unit period. Frequency
definition. Request response C5.
Request if unit of frequency.
A request is made for the relationship
between cycle and frequency.
Request response C6.

its unit is seconds (s).
Frequency.
The frequency f of circular motion is
the number of loops that the object
travels in a second.
Relationship between period and
frequency: f =1/T
Unit frequency is per second (1 / s) or
Hz (Hz). d) Contact between linear
speed and angular speed. v = rω

Act 3: Centripetal acceleration
Write formular for calculated
acceleration

Centripetal acceleration.
1. The direction of the acceleration


Read book and show characteristics of
acceleration of uniform circular
motion.

vector in circular motion.
In circular motions, but the speed
with constant magnitude, but the
direction is always changing, so this
motion has accelerated. Acceleration in
circular motion are always directed at
the center of the orbit is called the
centripetal acceleration.
2. The magnitude of the centripetal
acceleration

Date of preparing: 7/10/2017
Date of teaching: 13/10/2017
Period 11: EXERCISES ABOUT UNIFORM CIRCULAR MOTION
IV.
The aims:
2. Objective:

- definition circular motion and uniform circular motion
- state characteristics of vector of velocity of a uniform circular motion
- definition linear speed, angular speed, period, frequency and centripetal
aceeleration
2.Skill: - Pronounce new words
- Use vocabularies
V.
Preparing:
1. Teacher: New words
2.Students: Read book
VI.

Procedures:

1.Organization: greeting and checking attendance
2.Warm-up: State definition of uniform circular motion.
Act 1: review
Teacher’s activities
Repeat these words

Student’ activities


Linear speed
Arc
Angular speed
Revolution
Period
Frequency
Centripetal
Tangent
Act 2: exercises
Teacher’s actives
Example: a person sitting on a
bicycle and another person
standing by the roadside what
motion of the valve .
Question 6: A fan rotates with a
frequency of 300 verolution per
minute. Propeller length is 0.8 m.
Calculates the linear and angular
velocity of a point at the top of

the propeller

Student’s actives

Câu 6:
(m/s).

ω = 5π ( rad / s )

Question 7: The outer perimeter
of a car wheel has a radius of 25
cm. Calculates the angular
velocity and acceleration of a
point on the outer ring of a wheel
when the car is running at a speed Câu 7:
r = 25cm = 0,25m.
of 36 km / h.
Question 8: An artificial satellite
at a height of 250 km flying
around the earth in a circular
orbit. The rotation of the satellite
is 88 minutes. For the radius of
the earth is 6400 km.
a) Calculate angular velocity
b) The radial acceleration of the

v 10
ω= =
= 40 ( rad / s )
r 0, 25

aht =

2

2

v = 36 km/h = 10 m/s.;
;

v
10
=
= 400 m / s 2
r 0, 25

(

π

; v = 4 (m/s) = 12,56

)


satellite.
Câu 8:
Question 9: See Earth is a sphere
with a radius R = 6400 km
spinning around the polar axis.

Calculates the velocity and radial
acceleration at a location of
latitude 30 °.

ω=

2π 2.3,14
=
= 1,19.10−3 ( rad / s )
T
88.60

(

aht = ω 2 ( R + h ) = 1,19.10

)

−3 2

;

(

.6650.103 = 9, 42 m / s 2

)

Câu 9: T = 24.3600 = 86400s.
r = R cos ϕ

v = ωr =

( ϕ = 30 )
o

;

Tốc

2π
.R cos ϕ = 403 ( m / s )
T

(

độ

.

aht = ω 2 r = ω 2 R cos ϕ = 0, 029 m / s 2

)

Date of preparing: 14/10/2017
Date of teaching: 21/10/2017
Period 13: EXRCISE ABOUT RELATIVITY OF MOTION.
THE FORMULA FOR ADDING VELOCITIES
I.

The aims:

dài: