Đề cương ôn tập môn Toán kì 1 lớp 7 năm 2018 - THCS Láng Thượng

<span class='text_page_counter'>(1)</span><div class='page_container' data-page=1>

NQi dung 6n tQp

HKI

Ndm

hgc 2018 - 2019

A.

LY

THUYET

NQI

DUNC

O^I

TAP

HgC

rcY I -TU6ru

TOAN

7

I/

Dai s6:

Ciu

1: Thd

nio

td s6 hfru

ti

duong? Sd hfru

ti

am? Gi6

trf

tuyQt

d6i

cria s6 hiru

ti x

dugc x6c dfnh nhu
th6 ndo?

Ciu

2z

Vi6t

c6c c6ng thric: nhdn, chia

hai

lfly

thua

ctng

co

t6.

tty

thira cria:

lf,y

thria, mQt

tich,

mQt
thuong.

Cf,u

3:

Ti

10

thric

ld

gi?

Tinh

chAt co b6n cria

ti

lQ

thirc.

Vitit

c6ng

thric

tinh

chAt cria ddy

ti

sO Uang
nhau.

Cffu 4:

Dinh

nghia cdn

b{c

hai ctra mQt s61,h6ng 6m? Cho

vi

dp.

Cflu 5:

Khi

ndo

thi

hai d4i luqng y vd x

ti

lQ thuan

v6i

nhau?

Tinh

ch6t cria hai dai luqng

ti

lp thuen?
Cffu 6:

Khi

ndo

thi

hai d4i luqng y

vi

x

ti

l0 nghich vcyi nhau?

Tinh

chdt ctra hai dai luqng

ti

lQ nghich?

Ciu

7: DO

thi

hdm s6 y

:

f(x)

li

gi? EO

thi

cria

him

s6 y

:

u

(a*

0) c6 dang nhu th6

nio?

IV

llinh

hoc:

Cffu

1: Ph6t bidu dinh nghia,

dinh

lf

vd hai g6c ddi dinh. Ph6t bidu

dinh

nghia hai duirng

thing

vu6ng
g6c ? Dinh nghia duong trung truc cira doan

thing.

Cia

2z Ph6t bidu

dinh

ly

vd d0u hi€n nhQn bidt hai ducrng

thing

song song ?

Dinh

lf

vd

tinh

chat hai
duong

thing

song song .

Ciu

3: Ph6t bidu tiOn dd

dctit.

Phdt bidu c6c dinh

lf

vd quan hQ gifia tinh vu6ng g6c

vdi

tinh song song.
Dinh

ly

vd ba dudng

thing

song song.

Cffu 4: Phdt bidu dinh ty vd tdng ba g6c cria mQt tam gi6c ? Tinh chat g6c

ngoii

cria tam gi6c.

Cffu 5: Thd ndo ld hai tam gi6c bang nhau. Ph6t bidu ba truirng hqp

bing

nhau cira hai

tam

gi6c vd c6c

hQ

qui

(Ve hinh, ghi

gii

thidt, kdt luQn)

B

-

BAI TAP

V

D4i sd

Dane,l;

Thuc hiAn phdp

tinh(Tinh

hgp

l!

ndu c6 thA):

ut

zz!.2-

rg1

'

I

at

(

p?-.1)

[o.r-1']'

c\

rc!

fl)

+zs?,1

-'--4's --4'7

_{'(- 3 4)\' 4)}

₇

_(.s/

₇

_s

a>(z',+-+l

9-r,

")

fl)

.(e)"

-!,+

e)

1'f-1-1)*1'[-'-,

'

)

"'(."

'1-rl

t-"

"'(5,,

,

_"

_s'[ts

_oJ'

_s'(

r

'fi)

h)

10.^6:0r

.-ly-

3J4s

-Ilq

l\2r?:

4tr

n(zl*E!)

,(

-qL*r!)+z!

rr.ir

rv'1"'"^'1

9

t

J\a'

6' '

"

_12t1,

63.102

^'(" 3'- 2)'\

_.-

6'-

7

)'

'

2

il

o#.r'(L*,2),+

*r

[rs

.z;-Q^,t

Y),1^;-J-ux*ue]

a

*

(-l

,1*sf,

+,2)

,

(3.+-#)'(+-+.;)

Dang 2:

Tim

x, y,z:

Bni

1.' Tim

x

bidt:

a)

l*1

:2x=-5

at(*-l)fr*1)=o

"l

lr+!l-1=

q

4 3

'\

4)\ 2)

'l

sl

2

10

,

Jm(

Ji*.,ffi)=*

,l*"n*r

,S-I=*

s)28.

-223*-16=0

Tuy

ensinh247

</div>
<span class='text_page_counter'>(2)</span><div class='page_container' data-page=2>

NQi dung 6n tQp

HKl

Ndm

hgc 2018 - 2019
h) (x

-

L)'=25

,l

[,r*l)'=1

k)

_l2x

-

1l

₌

_{lx -}2l

'\. 2)

25
Biri

2:

Tim

\

_!,

z

bidt

:

a)

x:

_!:z=5:3:4vix

+y

-z=-12

b)

3x

_=2y

_iJy=szvdx+

y

*z=92

c) 2x-

3y=5zvix+y-

z=95

d)

x:

y:

z=3:4:5vi

2x2+2y2-3*=-100

. r+l v+2 z-l -

)c+y

x-y

e)

*

1!--t--.-=:---:

vdx+y-z=50

_il::----!-

vdx.y=250

340'73'

l.

HgcsinhthOitOpTdEquy€ng6pdugcs5s6chnQpchothuviQn.

Lop7Ac637

hgcsinh,

lopTBc6

37 hgc sinh, 16p 7C c6 40 hgc sinh, 16p

7D

c6 36 hgc sinh.

H6i

m6i

to'p quy6n g6p du-o. c bao nhiOu

quy6n s6ch

ct.

ni6t

rang s6 s6ch quyOn g6p dugc

ti

lQ

voi

sO hgc sinh cria

m5i

top vd

lop

7C

g6p
nhiAu hon lorp

7D

ld8

quyOn s6ch.

2.

Ba dQi

m6y

cly,

cdy tr€n ba c6ch ddng nhu nhau. DQi

thf

nhdt

hoin

thenh cOng vi0c trong

4

ngiy,

dQi hai

hoin

thinh

trong 6

ngiy

vd dQi thua ba hoan thenh trong 8 ngey.

H6i

m6i

dQi c6 bao nhiOu
mdy

ciy,

bidt dgi

thf

nha't c6 nhidu hcrn

dqi

thrl hai

ld

2

mdy

ciy

vi

cOng sudt c:iua cdc mdy

li

nhu
nhau?

3.

Cho bi6t 56 c6ng nh6n hoan thanh mQt c6ng viQc trong

2l

ngity.

H6i phii

tdng thOm bao nhiOu c6ng

- -l r a, , a t \ / Y A' i: _^

nhdn nfra d0 hoan thanh c6ng viQc d6 trong 14

ngiy

(ndng su6t

m6i

c6ng nh6n ld nhu nhau).

4.

Tffi

chu

vi

ctra mqt hinh chfi nhat, bidt

ti

sd hai c4nh kd cfia n6

ld}

: 5

vi

diQn t(ch

bing

40m2.

5.

Ba td hqc sinh trdng

dux,I79

cAy xung quanh tnr&rg. SO cay td 1 ftdng so v6i td Z Uing 6 : 11. So cay t6 1

tdng

so v6i td 3 bing 7 : 1O.H6i m6i td trohg dugc bao ntrieu cAy.

1)

6.

BakhoA,B,

Cchrlag4o,ndunhflpviokhoAthCm

isdg4octran5.Xuat&khoBdi

1

sdgaocita

7 "'

7

n6

thi

khi

d6

sd gao 3 kho bang nhau.

Tinh

xem

hic

ddu &

m5i kho

c6 bao nhi0u tAn gao. Bidt rang
kho B chrla nhidu hon kho

A

li

21 tan.

Dane 4.' Hd.m sd -

Dd

thi

hdm sd:

Bii

L: Cho

him

s6

y

_'5

=!*

a) VC dd

thi

him

sd

b)

Tim

gi6

tri

cria

him

sd tai _{x =}

-1

;

x

=0

c)

Tim

didm trOn dd

thi

c6 tung dQ 11 4. X6c dinh tga dQ didm d6.

Bii

2: Cho

him

s6

y

_'5

_=--2*

a) VE dd thi

him

s6

b) Trong c6c didm sau dAy

thi

didm ndo thuoc d6

thi

him

sd d6:

M

(-5

;2);

N

(0 ; 3); P

tl

_;

_-f

ll

.

5'

Bii

3: Didm B

(2;-1)

thuQc dd

thi

him

_{s6 Y}_{= ax.}

a)Xdc

dinh a

b) Ve dd

thi

him

sd vDa

tim

duo.c
Dans 5: Cdc bdi tud.n ndng cao:

BiiI:

Tim GTLN,

GTNN.'

1)

Tim

gi6

tri

nh6 nhat

cta

bidu thrlc:

A=312x-

1l

-5

B=x2+3ly-

2l+l

2)

Tim

gi6

tri

l6n nhdt cria bidu thrlc:

C=

10

-5lx-21

D=5 -(2x-l)2

Bii

2: So sdnh:

2

Tuy

ensinh247

</div>
<span class='text_page_counter'>(3)</span><div class='page_container' data-page=3>

NQi dung 6n tQp

HKl

Ndm

hgc 2018 - 2019

a) Z,o, vd

32oo

c)

9920

vI

999910

b)32r

yd.Z3r

d)

S=

l+2+22

+23

+...

+

zt0oydztol

Bii

3; Cho

tt

lQ

thitc:

+:

+

CMR:

bd

,

5a

+3b

5c

+3d

_-,,

7o' +3ab

-

'lc2

+3cd

a)

salb=

tr-,

"'

rro2

_-Bb'-

rF

-gP

Bii 4:

Cho b6n s5 a, b, c, d

thoi

mdn di0u kiQn b2

:

ac; c2

:bd.

chrmgminh:

"1^*4*cr=9

b'+c'+d'

b

IU

llinh

hoc

Bii

L: Cho AABC

(3

g6c nhqn).TrOn tia

Ax

song song vdi BC ldy

AD

= BC (AD, BC

cing

thuQc

nta

mit

phing

bd

li

ducrng

thing

AB).

Chung minh:

a) AADC ₌ACBA
b) G6c

BAD

₌g6c BCD
c)

AB

llDC

Bii

2:.

Cho AABC vu6ng t4i

A

c6 g6c

B

:300.

a)

Tinh

sd do g6c C.

b)

VC

tia

phdn gi6c cria g6c

C

cat cqnh

AB tai D.

Trdn canh

CB

l6y

di6m

M

sao cho

CM

:

CA.
Chrmg minh:

AACD:

AMCD.

c)

Qua C vE

dulng

thdng

xy

vu6ng g6c

CA.

Ttr

A

k6 duong th6ng song song vcvi CD c6t

xy o

K.

Chrmg

minh:AK

= CD.

d)

Tinh

sO do g6c

AKC.

Bii

3:.

Cho g5c xOy. TrCn tia Ox ldy hai didm

A

vi

B, trOn tia Oy tay didm C

vi

D

sao cho
OA _{= OC;}

AB

= CD. Chung minh:

a)

BC=AD

b)

Gqi

I

ti

giao cira BC

vi

AD.

Chrrng minh

rang: AAIB

= ACID
c) OI

ti

phAn gi6c cira g6c xOy

d) OI vu6ng g6c

v6i

BD

Bii

4: Cho tam gi6cABC. Gqi

Eld

trung didm

AC

, F ld trung didm

AB.

TrOn tia ddi cira EB lay didm

M

sao
cho

EM

= MB. TrOn tia

ddi

ctra FC ldy didm

N

sao cho FN = FC. Chung minh:

a)

AAME

= ACBE
b)

AM

= BC

vi

AM

//BC

c)AM=AN

d)M,A,Nthinghdng

Bii

5: Cho tam gi6c

ABC

(AB < AC) kB phan gidc

AD. LifyEthuQc AC

sao cho

AB

₌AE; Ldy F thu6c

tia

ddi cira tia

BA

sao _{cho BF = EC. Chung}minh:

a) AABD ₌

AAED

b)DF=DC

c)F,D,Ethfnghlng

d)ADTFC

Bii

6:

Cho tam gi6c ABC. Ggi

M

li

trung didm cira BC ; N

li

trung didm cira AC. Ldy E thuQc tia ddi cira

NM

sao cho

_{NM ='NE.}

Chung minh:

a)

AE

₌

MC

suy ra AE

//

MC

b)

AMEA

₌

AABM

c)

MN

ll

AB

Tuy

ensinh247

</div>

<!--links-->