Kiểm tra 45 phút môn: Hình học 10 tiết 14

<span class='text_page_counter'>(1)</span>Trường THPT Chiềng Sinh.. KiÓm tra 45’ M«n: §¹i sè 10.. Hä vµ tªn:. Mã đề: 14H1007. Líp: §Ò bµi: I. PhÇn tr¾c nghiÖm:. Câu 1 (1đ) : Cho tam giác đều ABC cạnh a.   a. §é dµi cña vÐc t¬ AB  AC lµ gi¸ trÞ nµo trong c¸c gi¸ trÞ sau: a 3 (A). a; (B). 2a; (C). ; (D). a 3 ; 2   b. §é dµi cña vÐc t¬ AB  AC lµ gi¸ trÞ nµo trong c¸c gi¸ trÞ sau: a 3 (A). a; (B). 2a; (C). ; (D). a 3 ; 2     C©u 2 (1®): Cho tam gi¸c ABC víi träng t©m G. §Æt CA  a; CB  b .    BiÓu thÞ cña vÐc t¬ AG theo hai vÐc t¬ a, b lµ:      2a  b  2a  b (A). AG  ; (B). AG  ; 3 3      a  2b  2a  b (C). AG  ; (D). AG  ; 3 3 Câu 3 (1đ): Trong hệ trục toạ độ Oxy, cho hình bình hành ABCD có toạ độ các đỉnh A 1;3, B 2;0 , C 2; 1. Toạ độ của đỉnh D là: (A). 2;2 ; (B). 5;2 ; (C). 4; 1 ; (D). 2;5 ; Câu 4 (1đ): Trong hệ trục toạ độ Oxy, cho bốn điểm A 3;1, B 2;2  C 4;0 , D 1; 6  . a, Hái ®iÓm G 2; 1 lµ träng t©m cña tam gi¸c nµo: A, Tam gi¸c ABC. B, Tam gi¸c ABD. C, Tam gi¸c ACD. D, Tam gi¸c BCD. b, Bé ba ®iÓm nµo sau ®©y th¼ng hµng: A, Ba ®iÓm A, B, C. B, Ba ®iÓm A, B, D. C, Ba ®iÓm A, C, D. D, Ba ®iÓm B, C, D. II. PhÇn tù luËn..    C©u 5 (2®): Cho ba vÐc t¬ a 2;1, b 3;2  , c 4; 1.     a, Tìm toạ độ của véc tơ u  2a  3b  4c .    b, T×m hai sè k vµ l sao cho: a  k.b  l.c . Câu 6 (4đ): Trong mặt phẳng toạ độ Oxy, cho hai điểm A(1;4), B(2;2). §­êng th¼ng ®i qua A vµ B c¾t trôc Ox t¹i M vµ c¾t trôc Oy t¹i N. a, Xác định toạ độ của hai điểm M và N. b, TÝnh diÖn tÝch cña tam gi¸c OMN.. Bµi lµm .................................................................................................................................................. .................................................................................................................................................. Lop10.com.

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