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TAP BAI KIEM TRA

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<span class='text_page_counter'>(1)</span>Hä vµ tªn:...................................................... Bµi kiÓm tra 45’ Líp: 6………………… M«n: H×nh häc 6 §iÓm. Lêi nhËn xÐt.. §Ò bµi. 1. (4đ) Vẽ theo lời diễn đạt sau: a, Gãc aOb cã sè ®o b»ng 700 b, Gãc mOn vµ mOk kÒ bï c, Đờng tròn tâm I bán kính 3cm và đờng kính CD d, Tam gi¸c ABC, cã AB = 3cm, AC = 5cm, BC = 6cm. 2. (6®) Trên cùng một nửa mặt phẳng bờ chứa tia Ox, vẽ tia Oa, Oy sao cho gãc xOa = 650 vµ xOy = 1300 . a, Tia Oa có nằm giữa hai tia Ox và Oy không ? Vì sao ? b, TÝnh sè ®o gãc aOy? c, Tia Oa có là tia phân giác của góc xOy không ? Vì sao ? d, Vẽ tia đối Oz cña tia Oy. Tính số đo góc aOz? 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Hä vµ tªn:……………………………………… Líp:…………… Mã đề II. ĐỀ KIỂM TRA VẬT LÍ 8 (Thời gian 45 phút). Câu 1(4đ) : a/Viết công thức tính công suất, nêu rõ các đại lượng có trong công thức ? b/Áp dụng giải bài toán sau: Đầu tàu hỏa kéo toa xe với một công A= 3000J hết thời gian 5 giây.Tính công suất của đầu tàu? Câu 2(2đ): Cơ năng của một vật phụ thuộc vào những yếu tố nào?.

<span class='text_page_counter'>(2)</span> Câu 3(4đ): Đưa một vật có trọng lượng P = 400N lên cao theo phương thẳng đứng bằng một hệ Palăng gồm một ròng rọc cố định và một ròng rọc động người công nhân đã kéo đầu dây đi một đoạn là 10m. (Bỏ qua ma sát). a/ Tính lực kéo và độ cao đưa vật lên. b/ Tính công nâng vật lên. 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Hä vµ tªn:……………………..…………. ĐỀ KIỂM TRA VẬT LÍ 8. Líp :………………. (Thời gian 45 phút) Mã đề I. Câu 1(4đ) : a/Viết công thức tính công cơ học, nêu rõ các đại lượng có trong công thức ? b/Áp dụng giải bài toán sau: Đầu tàu hỏa kéo toa xe với lực F = 5000N làm xe đi được quảng đường 2000m.Tính công của lực kéo đầu tàu? Câu 2(2đ): Cơ năng của một vật phụ thuộc vào những yếu tố nào?.

<span class='text_page_counter'>(3)</span> Câu 3 (4đ):Đưa một vật có trọng lượng P = 240N lên cao theo phương thẳng đứng bằng một hệ Palăng gồm một ròng rọc cố định và một ròng rọc động người công nhân đã kéo đầu dây đi một đoạn là 8m. (Bỏ qua ma sát). a/ Tính lực kéo và độ cao đưa vật lên. b/ Tính công nâng vật lên.. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. 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<span class='text_page_counter'>(4)</span> Hä vµ tªn:...................................................... Líp: 6……... §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 15’ M«n: Sè häc 6. §Ò bµi 1 Câu 1: Tìm x, y a,. x 10 = 6 15. Z, biÕt: 15. 30. b, − 21 = y Câu 2: Rút gọn các phân số sau: 32 a) 40. 27 b)  180. x. 3. c, 5 = y  36 c) 84. 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Hä vµ tªn:...................................................... Líp: 6……... §iÓm. Lêi nhËn xÐt.. §Ò bµi 2 Câu 1: Tìm x, y a,. 4 −10 = x 15. Z, biÕt:. 8. y. b, − 3 =12 Câu 2: Rút gọn các phân số sau:. 2. y. c, x = 5. Bµi kiÓm tra 15’ M«n: Sè häc 6.

<span class='text_page_counter'>(5)</span> a). 32 − 60. b). − 45 75. 72. c) 120 Bµi lµm.. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. 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<span class='text_page_counter'>(6)</span> 1. Thế nào là 2 tia đối nhau? - Vẽ tia đối Ax của tia Ay. 2. Cho N thuéc ®o¹n th¼ng AB, biÕt AN = 3cm, AB = 7cm. TÝnh BN = ? 3. Cho 3 đoạn thẳng AB, BC, CA trong đó AB = 2 cm; BC = 3 cm; CA = 4 cm. Hỏi B có n»m gi÷a 2 ®iÓm A vµ C kh«ng ? V× sao ? 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Hä vµ tªn:...................................................... Líp: 8......... Bµi kiÓm tra 45’ M«n: VËt lý 8.

<span class='text_page_counter'>(7)</span> §iÓm.. Lêi nhËn xÐt.. §Ò bµi. Câu 1. Một ngời đi bộ trên quảng đờng đầu dài 3km mất 30 phút. ở quảng đờng sau dài 2km ngời đó đi hết 0,5 giờ. Tính vận tốc của ngời đó trên quảng đờng đầu và vận tốc trung bình của ngời đó trên cả hai quảng đờng? C©u 2. a, BiÓu diÔn träng lùc cña mét vËt cã khèi lîng 15kg (tØ xÝch tïy chän) b, DiÔn t¶ b»ng lêi c¸c yÕu tè cña c¸c lùc ë h×nh vÏ díi ®©y: F. 350 N. A. 150 N. 50. F. B. a,. b,. Câu 3. Đặt một bao gạo 50kg lên một cái ghế có khối lợng 4kg. Diện tích tiếp xúc với mặt đất của cả bốn chân ghế là 0,4dm2. Tính áp suất các chân ghế tác dụng lên mặt đất? Câu 4. Một cái kích dùng dầu có đờng kính pittông nhỏ 2,5 cm và đờng kính pittông lớn 35 cm. phải tác dụng lên pittông nhỏ một lực bằng bao nhiêu để pittông lớn nâng đợc một vật có khối lợng 4 tấn ? Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ................................................. Hä vµ tªn:...................................................... Líp: 8........ §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 15’ M«n: VËt lý 8. §Ò bµi. Câu 1: Có một ô tô đang chạy trên đờng. Trong các câu mô tả sau đây câu nào không đúng? A. Ô tô chuyển động so với mặt đờng. B. Ô tô đứng yên so với ngời lái xe. C. Ô tô chuyển động so với ngời lái xe. D. Ô tô chuyển động so với cây bên đờng. Câu 2: Trong các chuyển động sau, chuyển động nào là đều. A. Chuyễn động của ô tô từ Hà Nội đến Hải phòng với vận tốc 45km/h..

<span class='text_page_counter'>(8)</span> B. Chuyễn động của xe máy khi xuống dốc. C. Chuyễn động của kim đồng hồ. D. Chuyễn động của đoàn tàu lúc vào ga. Câu 3: Chọn câu trả lời đúng. Hai lực cân bằng là hai lực : A. Có độ lớn bằng nhau và cùng phơng. B. Cã cïng ph¬ng nhng ngîc chiÒu nhau. C. Có cùng phơng và cùng độ lớn nhng ngợc chiều nhau. Câu 4: Hành khách ngồi trên xe ô tô đang chuyển động bổng thấy mình bị nghiêng ngời sang tr¸i, chøng tá xe: A. §ét ngét gi¶m vËn tèc. B. §ét ngét t¨ng vËn tèc. C. §ét ngét rÏ sang tr¸i. D. §ét ngét rÏ sang ph¶i. Hãy chọn câu nhận xét đúng? Câu 5: Trong các câu nói về lực ma sát sau đây, câu nào là đúng? A. Lực ma sát cùng hớng với hớng chuyển động của vật. B. Khi vật chuyển động nhanh dần lên, lực ma sát lớn hơn lực đẩy. C. Khi vật chuyển động chậm dần, lực ma sát nhỏ hơn lực đẩy. D. Lực ma sát trợt cản trở chuyển động trợt của vật này trên mặt vật kia. Câu 6: Trong các cách sau đây, cách nào là không đúng? A. Muèn t¨ng ¸p suÊt th× gi¶m ¸p lùc, t¨ng diÖn tÝch bÞ Ðp. B. Muèn t¨ng ¸p suÊt th× t¨ng ¸p lùc, gi¶m diÖn tÝch bÞ Ðp. C. Muèn gi¶m ¸p suÊt th× ph¶i gi¶m ¸p lùc, gi÷ nguyªn diÖn tÝch bÞ Ðp. D. Muèn gi¶m ¸p suÊt th× ph¶i t¨ng diÖn tÝch bÞ Ðp.. Câu 7: Cho 3 bình đựng đầy nớc (hình dới). Biết khối lợng nớc ở các bình bằng nhau.. a,. b,. c,. Chọn câu trả lời đúng. áp suất ở đáy bình:. A. H×nh a lín nhÊt B. H×nh b lín nhÊt C. H×nh c lín nhÊt Hä vµ tªn:...................................................... Líp: 6........ §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 45’ M«n: Sè häc 6. §Ò bµi. Câu 1: a, Nêu quy tắc tìm ƯCLN và BCNN b, So sánh hai quy tắc trên. áp dụng tìm ¦CLN( 12,14,20) Câu 2: Thực hiện các phép tính ( tính nhanh nếu có thể) a, 4. 52 – 3. 23 + 33 : 32 b, 28. 76 + 24 . 28 – 28 . 20 c,. 2. 197   4.52  81: 32  . Câu 3: Tìm số tự nhiên x bết a, 2x – 49 = 45 b, 145 – (x + 26) = 97 c, 6x – 39 = 5628 : 28 Câu 4: Tìm số tự nhiên chia hết cho 8, cho 10, cho 15. biêt rằng số dó trong khoảng từ 100 đến 300..

<span class='text_page_counter'>(9)</span> C©u 5: TÝnh tæng: A= 12 + 32 + 52 + 72 +.....+ 992 Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ................................................. §Ò bµi. Cõu 1: Viết các công thức đã học về lũy thừa với số mũ tự nhiên. Câu 2: TÝnh thµnh mét lòy thõa: a, 56.57.5 b, 78: 75 c, 2.4.5.25 d, 814 : 275 Câu 3: Thực hiện các phép tính (tính nhanh nếu có thể) a, 4 . 52 – 3 .23 b, 28 . 76 + 13 .28 + 9. 28 c, {46 - [(16 + 71.4) : 15]} + 24.5 Câu 4: Tìm số tự nhiên x, biết: a, 4x - 24 = 8 b, ( 9x + 2) . 3 = 60 c, 124 - 2.(x + 3) = 3.42 C©u 5: TÝnh tæng: A = 2 + 22 + 23 + 24 +...+2100 Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ...............................................................................................................................................................................................................................................................

<span class='text_page_counter'>(10)</span> .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .................................................... Bµi kiÓm tra 15’ M«n: Sè häc 6. Hä vµ tªn:...................................................... Líp: 6..... §iÓm. Lêi nhËn xÐt.. §Ò bµi. 1. ViÕt tËp hîp A c¸c sè tù nhiªn lín h¬n 10 vµ nhá thua 17. (b»ng 2 c¸ch) 2. TÝnh hîp lý. a, 123 + 57 + 177 b, 4.5.25.7 c, 6.42 + 37.42 + 42. 57 d, 98.75 3. TÝnh: a, 32.3. 37 b, 79:73 5 3 c, 2 .8 d, 546: 275 Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. 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Hä vµ tªn:...................................................... Líp: 8A §iÓm. Lêi nhËn xÐt.. Bµi 1 (2®): Chøng minh r»ng: a. NÕu a > b, th× a > b - 1. Bµi kiÓm tra 45’ M«n: §¹i sè 8. §Ò bµi. (§Ò ch½n) b. NÕu a < b, th× − 2 a + 4 > − 2 b + 4 3. 3.

<span class='text_page_counter'>(11)</span> Bµi 2: (2®) Gi¶i c¸c bÊt ph¬ng tr×nh vµ biÓu diÔn tËp nghiÖm trªn trôc sè. 1 1  2x 2x  1   3 6 b. 2. a. 2(3x -1) < 2x + 4 Bµi 3 (2®) T×m x sao cho: a. Gi¸ trÞ cña biÓu thøc 3x + 2 lµ sè kh«ng ©m. b. Gi¸ trÞ cña biÓu thøc 3x - 2 nhá h¬n gi¸ trÞ cña biÓu thøc x + 5. Bµi 4: (3®) Gi¶i c¸c ph¬ng tr×nh: a. ½- 4x½ = 3x + 5 b. ½2x + 5½ = - 5x - 11 C©u 5: (1®) Chøng minh r»ng: (a + b)2 4ab Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. Hä vµ tªn:...................................................... Líp: 8A §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 45’ M«n: §¹i sè 8. §Ò bµi. (§Ò lÏ) Bµi 1 (2®): Chøng minh r»ng: a. NÕu a < b, th× a - 2 < b b. NÕu a > b, th× 7- − 2 a > 7 - − 2 b 3 3 Bµi 2: (2®) Gi¶i c¸c bÊt ph¬ng tr×nh vµ biÓu diÔn tËp nghiÖm trªn trôc sè. a. 2(x + 3) > 5x - 7 b. 7 − 2+ x < 2 x − 5 12 3 4 Bµi 3 (2®) T×m x sao cho: a. Gi¸ trÞ cña biÓu thøc 3 - 2x lµ sè d¬ng. b. Gi¸ trÞ cña biÓu thøc 4x + 5 lín h¬n gi¸ trÞ cña biÓu thøc 2x - 3. Bµi 4: (3®) Gi¶i c¸c ph¬ng tr×nh: a. ½- 5x½ = 4x - 13 b. ½2x - 6½ = - 5x + 21 2 C©u 5: (1®) Chøng minh r»ng: (a+ b). 2. 2ab Bµi lµm.. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ...............................................................................................................................................................................................................................................................

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Hä vµ tªn:...................................................... Bµi kiÓm tra Líp: 6A Chủ đề tự chọn - Môn: Số học 6 §iÓm. Lêi nhËn xÐt.. §Ò bµi. Khoanh tròn các đáp án em cho là đúng : 1. NÕu tia Ot n»m gi÷a hai tia Oy vµ Oz th× : A. t¤z + z¤y = t¤z B. y¤t + t¤z = y¤z C. t¤y + y¤z = t¤z D. z¤y + y¤t = z¤t 2. Gãc nµo sau ®©y cã sè ®o lín nhÊt ? A. Gãc tï B. Gãc nhän C. Gãc bÑt. D. Gãc vu«ng. 3. ý nào sau đây là đúng ? A. Hai tia đối nhau không tạo thành góc . B. Hai tia đối nhau tạo thành góc bẹt . C. Hai tia đối nhau tạo thành góc vuông . D. Hai tia đối nhau tạo thành góc tù . 4. ý nào sau đây là đúng ? A. Hai gãc cã tæng sè ®o b»ng 1800 lµ hai gãc kÒ bï . B. Hai gãc cã tæng sè ®o b»ng 900 lµ hai gãc kÒ bï . C. Hai gãc kÒ nhau cã tæng sè ®o b»ng 1800 lµ hai gãc kÒ bï . D. Hai gãc cã chung mét c¹nh lµ hai gãc kÒ nhau . 5. Cho gãc x¤y = 950, Gãc y¤z lµ gãc kÒ bï víi gãc x¤y . Gãc y¤z lµ : A. Gãc nhän B. Gãc tï C. Gãc vu«ng D. Gãc bÑt 6. A là một điểm nằm trên đờng tròn tâm O bán kính R . đờng thẳng AO cắt đờng tròn tại điểm thứ hai là B . Đoạn thẳng AB đợc gọi là : A. B¸n kÝnh B. §êng kÝnh C. Cung D. Cả B và C đều đúng 7. §iÒn vµo chç trèng trong c¸c ph¸t biÓu sau : NÕu tia AE n»m gi÷a hai tia AF vµ AK th× ............................................................................... Hai gãc ............................ (.............................) cã tæng b»ng 900 (1800) Hai góc có một cạnh chung và hai cạnh còn lại là hai tia đối nhau gọi là ................................. ............................................. , chóng cã tæng sè ®o b»ng sè ®o cña gãc ................................... NÕu Oz lµ tia ph©n gi¸c cña gãc xOy th×....................................................................................

<span class='text_page_counter'>(13)</span> ................................................................................................................................................. .. 8. §êng trßn t©m O, b¸n kÝnh R lµ h×nh gåm.......................................................................... ....................................................................................................., đợc ký hiệu là.................... Bài 1: Điền dấu ( )vào các ô tơng ứng mà em cho là đúng hoặc sai : TT Các khẳng định 1 Ph¬ng tr×nh cã d¹ng ax+ b = 0 lµ ph¬ng tr×nh bËc nhÊt mét Èn , x +5 2 ( x − 2)(x +9). = 0 lµ x. S. ± 3. 2. §KX§ cña ph¬ng tr×nh :. 3. Ph¬ng tr×nh. 4 5. Ph¬ng tr×nh : (y– 2)(5y+1) – 3 = 0 lµ mét ph¬ng tr×nh tÝch. Ph¬ng tr×nh : (y – 1)(y –3) = 0 vµ ph¬ng tr×nh y2 – 4y +3 = 0 lµ hai phơng trình tơng đơng. x+ 2 = 0 cã nghiÖm S = 2 x −4. 2 vµ x. §. { −2 }. Bài 2: Khoanh tròn các đáp án em cho là đúng : 1, Ph¬ng tr×nh : (a – 2) x + 4 = 0 lµ ph¬ng tr×nh bËc nhÊt mét Èn nÕu : A. a 2 ; B. Kh«ng cã gi¸ trÞ nµo cña a ; C. a = 2 ; D. a Z 2, TËp hîp nghiÖm cña ph¬ng tr×nh : x2 – 9= 0 lµ : A . S = { −3 } ; B. S = { 0 } ; C. S = { ±3 } ; D. S = { 3 } 3, Phơng trình (ẩn y): y + k = 3 tơng đơng với phơng trình : y = 2 nếu : A. k = 2 ; B. k=0 ; C. k = 1 ; D. k = – 1 Bài 3: Điền dấu ( )vào các ô tơng ứng mà em cho là đúng hoặc sai: TT Các khẳng định 1 1 √ 3 x − ≥ 0 lµ bÊt ph¬ng tr×nh bËc nhÊt mét Èn 3 BÊt ph¬ng bËc nhÊt mét Èn cã thÓ v« nghiÖm , cã thÓ cã mét 2 nghiÖm duytr×nh nhÊt vµ còng cã thÓ cã v« sè nghiÖm . 3 Với x < 0 thì biểu thức I- 3x I + 4x – 7 đợc rút gọn thành x - 7 4. NÕu a > 0 th× 1 < 1. 5. x = - 1 lµ mét nghiÖm cña bÊt ph¬ng tr×nh x2002 + x2001 + 2 > 0. §. S. a 1+a. Bµi 4: §iÒn c¸c dÊu thÝch hîp (< ; >; 1, NÕu a < b th× a+c b+c 2. NÕu a > b vµ c < 0 th× ac bc. ; ; ;. ) vµo c¸c « vu«ng : 3, NÕu a b th× a – m 4, NÕu b a vµ c > 0 th× ac. b-m bc. Hä vµ tªn:...................................................... Bµi kiÓm tra Líp: 8D Chủ đề tự chọn - Môn: Đại số 8 §iÓm. Lêi nhËn xÐt.. §Ò bµi. (§Ò ch½n ).

<span class='text_page_counter'>(14)</span> Bµi 1: §iÒn dÊu ( TT 1 2 3. ) vào các ô tơng ứng mà em cho là đúng hoặc sai : Các khẳng định. §. S. Ph¬ng tr×nh : − 1 − √ 2 x lµ ph¬ng tr×nh bËc nhÊt mét Èn . 3 Ph¬ng tr×nh : (x- 1)(3x + 4) – 2 = 0 lµ mét ph¬ng tr×nh tÝch Phơng trình : (x-1)(x-3) = 0 và phơng trình x2 – 4x + 3 = 0 là hai phơng trình tơng đơng. 4. §KX§ cña Ph¬ng tr×nh :. 5. Ph¬ng tr×nh. x −3 2 ( x − 2)(x +1). = 0 lµ x. x +1 = 0 cã nghiÖm S = x 2 −1. 2 vµ x. ± 1. { −1 }. Bài 2: Khoanh tròn các đáp án em cho là đúng : 1, TËp hîp nghiÖm cña ph¬ng tr×nh : x2 –1 = 0 lµ : A . S = {1} ; B. S = { ±1 } ; C. S = { −1 } ; D. S = { 0 } 2, Phơng trình (ẩn x): x + m = 3 tơng đơng với phơng trình : x = 2 m nếu : A. m = 1 ; B . m = 0 ; C. m = 2 ; D. m = -1 3, Ph¬ng tr×nh : (k –2) x + 4 = 0 lµ ph¬ng tr×nh bËc nhÊt mét Èn nÕu : A. k = 2 ; B. k 2 C. Víi mäi k R ; D. Kh«ng cã gi¸ trÞ nµo . Bài 3: Điền dấu ( ) vào các ô tơng ứng mà em cho là đúng hoặc sai: TT Các khẳng định 1 x −3>0 lµ bÊt ph¬ng tr×nh bËc nhÊt mét Èn . 1. §. S. 2. 2 3. I3-xI= x - 3 nÕu x >3 Với x < 0 thì biểu thức I- 2x I + 5x - 4 đợc rút gọn thành 3x+ 4. 4. NÕu a < 0 th× 1 < 1. 5. x = - 1 lµ mét nghiÖm cña bÊt ph¬ng tr×nh x2010 + x2011 - 1 < 0. a 1+a. Bµi 4: §iÒn c¸c dÊu thÝch hîp (< ; >; 1, NÕu a > b th× a+c b+c ; 2. NÕu a < b vµ c < 0 th× ac bc ;. ;. ) vµo c¸c « vu«ng : 3, NÕu a b th× a–m 4, NÕu b a vµ c > 0 th× ac. Hä vµ tªn:...................................................... Líp: 8A §iÓm. Lêi nhËn xÐt.. b-m bc. Bµi kiÓm tra 15’ M«n: §¹i sè 8. §Ò bµi. Bài 1.(4đ) Các khẳng định sau khẳng định nào đúng, khẳng định nào sai? Cho a > b ta cã : 3 3 a, a> b 5 5 b, 4 − 2 a<4 −2 b c, 7a – 3 < 7b – 3 d, a2 < b2 Bµi 2. (6®) Gi¶i c¸c bÊt ph¬ng tr×nh sau vµ biÓu diÔn tËp nghiÖm trªn trôc sè : 1 1− 2 x 2 x −1 a, 4x + 3 5x +7 b, + > 2 3 6 Bµi lµm..

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Hä vµ tªn:...................................................... Líp: 8D §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 15’ M«n: §¹i sè 8. §Ò bµi. Bài 1.(4đ) Các khẳng định sau khẳng định nào đúng, khẳng định nào sai? Cho a < b ta cã : 1 1 a, a> b 3 3 b, 7 −2 a<7 − 2b c, 3a – 5 < 3b – 5 d, a2 > b2 Bµi 2. (6®) Gi¶i c¸c bÊt ph¬ng tr×nh sau vµ biÓu diÔn tËp nghiÖm trªn trôc sè : a, 5x - 4 4x + 3 b, 1 + 1− 2 x > 3 x +1 5 10 2 Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ...............................................................................................................................................................................................................................................................

<span class='text_page_counter'>(16)</span> .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn:...................................................... Líp: 6A §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 45’ M«n: H×nh häc 6. §Ò bµi. 1. T×m: a, 3 cña 8,2 b, 2 cña − 14 c, 2 3 cña 3 3 d, 25% 5 7 15 8 5 cña 12,8 2. T×m mét sè biÕt: a, 3 cña nã b»ng 39 b, 2 3 cña nã b»ng - 8 c, 35% cña nã b»ng 27,5 4. d, Mét n÷a cña nã b»ng. 5. 1 . 2. Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. 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Hä vµ tªn:...................................................... Líp: 8A §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 45’ M«n: H×nh häc 8. §Ò bµi. 1. Cho tam gi¸c ABC cã AB = 15cm, AC = 12cm, BC = 20cm. Trªn c¹nh AB, AC lÊy 2 ®iÓm M, N sao cho AM = 5cm, CN = 8cm a, Chøng minh: MN // BC. b, Tính độ dài đoạn thẳng MN. 2. Cho tam giác ABC vuông tại A, đờng cao AI. Biết AI = 12cm, AC = 15cm a, c/m Δ AIB đồng dạng Δ CIA..

<span class='text_page_counter'>(17)</span> b, Tính độ dài BI, IC, AB c, Trªn c¹nh AC lÊy ®iÓm E sao cho CE = 5cm, trªn c¹nh BC lÊy ®iÓm F sao cho CF = 4cm. c/m Δ CEF vu«ng. 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Bµi kiÓm tra 45’ M«n: Sè häc 6. Hä vµ tªn:...................................................... Líp: 6A §iÓm. Lêi nhËn xÐt.. §Ò bµi. 1. TÝnh gi¸ trÞ biÓu thøc: a, 3 + −6 : 3 + 2 5 7 14 5 2. T×m x, biÕt: a, 1 x − 5 = 2 4. 7. 5. b,. 7 9 5 7 3 . + . + 8 14 14 8 8. b, (3 1 −2 x). 4 =2 1. 4 5 3 7 km, chiÒu dµi b»ng 8. c, c,. 1 5 1 5 −( +2 ) 3 7 3 1 5 5 2 x − =3 3 4 6. 3 3. H×nh chö nhËt cã chu vi b»ng km. TÝnh diÖn tÝch h×nh chö 7 nhật đó. 4. H·y viÕt ph©n sè 1 b»ng tæng cña 3 ph©n sè cã tö sè b»ng 1 vµ mÉu sè kh¸c nhau. 3 Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ...............................................................................................................................................................................................................................................................

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<span class='text_page_counter'>(19)</span> x. 1 1  3 x 3 x 3. a) 2x - 4 = 0 <=> (x - 2)(x2 + 1) = 0 b) 3x + 9 = 0 <=> C©u 2 (3®) Gi¶i ph¬ng tr×nh. a, x(5 + x) - 5x2 = 7x - 4(x2 + 3) 3x  2 3  2( x  7)  5 4 b, 6. c, (x + 3)(1 - 4x) + (x2 + 6x+ 9) = 0. C©u 3 (4®) Một ngời đi xe máy từ A đến B với vận tốc 45km/h, đến B ngời đó làm việc trong 1,5 giờ rồi quay về A với vận tốc 36km/h, biết thời gian tổng cộng hết 6h30ph. Tính quãng đờng AB? C©u 4 (1®) T×m gi¸ trÞ lín nhÊt cña biÓu thøc: A = (x + 2) - ( 2x - 1) . 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Bµi tËp tÕt 1. Cho h×nh b×nh hµnh MNPQ, tõ N h¹ NH MQ, NK NH, từ K kẻ đờng vuông góc với HK cắt NP tại I. a, c/m GNIK lµ h×nh b×nh hµnh, NQ = HI. b, BiÕt NQ = 10cm, HK = 8cm. TÝnh NG =?. PQ. Gäi G lµ trùc t©m cña. 2. H×nh b×nh hµnh ABCD cã gãc A = 1200 vµ ph©n gi¸c cña gãc D ®i qua trung ®iÓm I cña c¹nh AB, a, c/m: 1. AD = AI 2. Độ dài DI gấp đôi khoảng cách từ A đến CD 3. CA AD b, Ph©n gi¸c cña gãc A c¾t BD ë E. C/m : 1 = 1 + 1 AE. AB AD. 3. Cho h×nh b×nh hµnh ABCD cã BC = 2AB, M lµ trung ®iÓm cña AD. H¹ CE C/m : gãc EMB b»ng 3 lÇn gãc AEM.. AB,. 4. Cho tø gi¸c ABCD, E vµ G lÇn lît lµ trung ®iÓm cña AD vµ BC. LÊy F vµ H lÇn lît trªn AB vµ Cd. BiÕt r»ng EFGH lµ h×nh b×nh hµnh, F kh«ng trïng víi trung ®iÓm cña AB . C/m r»ng: a, Tø gi¸c ABCD lµ h×nh thang b, Diªn tÝch cña EFGH b»ng mét nöa diÖn tÝch cña ABCD. 5. a) Chøng minh r»ng: A= (n2 + n -1)2 - 1 chia hÕt cho 24 víi mäi sè nguyªn n..

<span class='text_page_counter'>(20)</span> b, T×m nghiÖm nguyªn d¬ng cña ph¬ng tr×nh sau: xy-2x-3y+1=0 6. Cho biÓu thøc: 1 1 1 1 1 P 2  2  2  2  2 a  a a  3a  2 a  5a  6 a  7a  12 a  9a  20 a. Tìm điều kiện để P xác định và rút gọn P. b. TÝnh gi¸ trÞ cña P biÕt a4-3a3 +2a2 + 2a-4 = 0 7. T×m c¸c sè x,y, z tho¶ m·n: 2 2 2   x  y  z xy  xz  yz  2009  y 2009  z 2009 32010  x. 8. TÝnh tæng: S =. 1 1.3. 9. Gi¶i ph¬ng tr×nh:. +. 1 3.5. +. 1 5.7. +…+. 1 2007 .2009. 59 − x 57 − x 55 − x 53 − x 51 − x + + + + =− 5 41 43 45 47 49. Hä vµ tªn:...................................................... Líp: ............................ §iÓm. Lêi nhËn xÐt.. Bµi kiÓm tra 15’ M«n: Sè häc 6. §Ò ra:. Câu 1:  9 15 3  12 5 60 ; ; ; ; ; Cho các phân số sau đây: 33 9  11 19 3  95 .. Tìm các cặp phân số bằng nhau, vµ gi¶i thÝch t¹i sao ? Câu 2: Rút gọn các phân số sau:  63 a) 81. Bµi 3: T×m x, y, biÕt:. 27 b)  180.  36 c) 84. 12 3 y 72 = = 5 x 20 30. Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ...............................................................................................................................................................................................................................................................

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Hä vµ tªn:...................................................... Bµi kiÓm tra 45’ Líp: ............................ M«n: Sè häc 6 §iÓm. Lêi nhËn xÐt.. §Ò ra: C©u1 : Thùc hiÖn phÐp tÝnh a, (7 - 10) + 139 b, 235 - 476 -100 + 670 c , 73.(- 5) - 5.27 + (-79) C©u 2 : T×m sè nguyªn x biÕt : a , 15 - 3x = 39 b , 2x - (-7) = 15 2x  5. c, - 13 = 0 C©u 3 : TÝnh tæng c¸c sè nguyªn x tho¶ m·n . a, - 20 < x < 18 x. b, <5 C©u 4 : T×m x  Z, biÕt : a, 24 chia hÕt cho x. b, x chia hÕt cho 48 vµ - 200 < x < 250 C©u 5 : TÝnh tæng . S = 1 + 2 + 3 - 4 - 5 - 6 + 7 + 8 + 9 +…+ 55 + 56 + 57 - 58 - 59 – 60.. Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn:...................................................... Líp: ............................ §iÓm.. bµi kiÓm tra 45’ M«n: §¹i sè 8 Lêi nhËn xÐt.. §Ò ra..

<span class='text_page_counter'>(22)</span> 1. Phát biểu quy tắc nhân đa thức với đơn thức. ¸p dông : a, TÝnh nh©n : - 7x(4x2 - 3x + 7) b, Rót gän biÓu thøc : 3x(x - 4) - x(3x + 5) 2. Ph©n tÝch c¸c ®a thøc sau thµnh nh©n tö. a, x2 – 2x + 2y - xy b, z2 – 2xy + x2 + y2 c, x3 + x2 - 4 3. Rót gän, råi tÝnh gi¸ trÞ cña biÓu thøc. ( x 2  1)( x  3)  ( x  3)( x 2  1) víi x = - 3. 4. Tìm x, biÕt. a, 3x3 – 27x = 0 b, (x - 3)2 - (x-2)(x + 2) = 25 5. Tìm a để : 2x2 + ax + 1 chia cho x - 3 có số d là 4. Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn:...................................................... Líp: ............................ §iÓm.. bµi kiÓm tra 15’ M«n: Sè häc 6 Lêi nhËn xÐt.. §Ò ra. 1. Cho c¸c sè sau: 1235, 240, 387, 346, 359, 1260 a. ViÕt c¸c sè chia hÕt cho 2. b. ViÕt c¸c sè chia hÕt cho 2 vµ 3. c. ViÕt c¸c sè chia hÕt cho 2 vµ 5. d. ViÕt c¸c sè chia hÕt cho 2 vµ 3 vµ 9 2. Ph©n tÝch c¸c sè sau ra thõa sè nguyªn tè. 150 ; 960 ; 3240 3. T×m c¸c sè x, biÕt. 24 ⋮ x, 32 ⋮ x, 40 ⋮ x Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ...............................................................................................................................................................................................................................................................

<span class='text_page_counter'>(23)</span> .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn:...................................................... Líp: ................ §iÓm.. bµi kiÓm tra 15’ M«n: H×nh häc 8 Lêi nhËn xÐt.. §Ò ra. 1. Hãy điền vào chổ ....... để đợc câu trả lời đúng. a, Tứ giác có 2 cạnh đối song song và có 2 đờng chéo bằng nhau lµ .................................. b, H×nh b×nh hµnh cã 1 gãc vu«ng lµ .......................................... c, H×nh thang cã 2 c¹nh bªn song song lµ ......................................... d, Hình chữ nhật có có 1 đờng chéo là phân giác của 1 góc là .................................... e, Hình bình hành có 2 đờng chéo vuông góc là .................................. 2. Cho tam gi¸c ABC vu«ng t¹i A, cã AB = 12cm, AC = 16cm, M lµ trung ®iÓm cña AC, N là trung điểm của AB, lấy P là điểm đối xứng của M qua N. a, Chøng minh : Tø gi¸c AMBP lµ h×nh thoi. b, Tính độ dài cạnh của hình thoi ? Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn:....................................................... bµi kiÓm tra 45’.

<span class='text_page_counter'>(24)</span> Líp: §iÓm.. 8A. M«n: H×nh Häc 8 Lêi nhËn xÐt.. §Ò ra. 1. a, Cho Δ ABC và một đờng thẳng d tùy ý. Vẽ Δ A’B’C’ đối xứng với Δ ABC qua đờng thẳng d. b, Phát biểu định nghĩa hình bình hành, Nêu các dấu hiệu nhận biết hình bình hành. 2. Cho hình vuông có đờng chéo bằng 8cm. Tính cạnh của hình vuông đó. 3. Cho Δ ABC c©n t¹i A, M lµ trung ®iÓm cña BC, I lµ trung ®iÓm cña AC, N lµ ®iÓm đối xứng với M qua I. a, Tø gi¸c AMCN lµ h×nh g×, V× sao ? b, Tø gi¸c ABMN lµ h×nh g×, V× sao ? c, Tìm điều kiện của Δ ABC để tứ giác AMCN là hình vuông. d, Cho AM cố định, khi BC di chuyển. Thì điểm I sẽ chuyễn động trên đờng thẳng nào ? Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn:...................................................... Líp: 6A §iÓm. Lêi nhËn xÐt.. §Ò ra. 1. T×m x, biÕt: a. 135 - 5.(x - 7) = 95 b. 153 - 2.(x + 5) = 5.32 c. 3.(x - 4) + 5.(x +7) = 47 2. Thùc hiÖn phÐp tÝnh (tÝnh hîp lÝ - nÕu cã): a. 57 : 54 + 22.23 - 1224 : 12 b. 3468 :  135 - ( 93 + 25 ) - 165 c. 78.31 + 78.24 + 78.17 + 22.72 3. T×m sè tù nhiªn x , biÕt :. bµi kiÓm tra 45’ M«n: Sè häc 6.

<span class='text_page_counter'>(25)</span> a. 120 ⋮ x ; 105 ⋮ x ; 90 ⋮ x vµ x > 8 b. x ⋮ 15 ; x ⋮ 24 ; x ⋮ 36 vµ 250  x  450 4. Lớp 6C có 24 em nam và 16 em nữ. Hỏi có thể chia lớp đó nhiều nhất thành mấy tổ để số nam cũng nh số nữ đợc chia đều vào các tổ. khi đó mỗi tổ có bao nhiêu em ? Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn:...................................................... Líp: 6A §iÓm.. Bµi kiÓm tra 15’ M«n: H×nh häc 6 Lêi nhËn xÐt.. §Ò ra. Hãy khoanh tròn vào chữ cái đứng trớc câu, mà em cho là đúng: 1. Cho 4 điểm A, B, C, D trong đó không có 3 điểm nào thẳng hàng. Tổng số đờng thẳng đi qua 2 ®iÓm lµ: A. 2 B. 4 C. 12 D. 6 2. NÕu ®iÓm M n»m gi÷a 2 ®iÓm A vµ B, th×: A. Tia AM trïng víi tia AB B. Ti AB và tia BA là 2 tia đối nhau. C. Tia BM trïng víi tia MA D. Tia MA và tia MB là tia đối nhau 3. Cho 5 điểm A, B, C, D, E cùng nằm trên 1 đờng thẳng. Trên hình vẽ có tất cả là: A. 4 ®o¹n th¼ng B. 6 ®o¹n th¼ng C. 7 ®o¹n th¼ng D. 10 ®o¹n th¼ng 4. Cho 3 đểm A, B, C thẳng hàng, biết AB = 3cm, AC = 2cm, BC = 5cm. Thì : A. B n»m gi÷a A vµ C. B. A n»m gi÷a B vµ C. C. C n»m gi÷a A vµ B. D. B n»m cïng phÝa víi A. 5. Trên tia Ox vẽ 3 điểm M, N, P sao cho OM = 4cm, ON = 5cm, MP = 5cm. Khi đó : A. OP = 6cm B. MN = 2cm C. PO = 10cm D. NP = 4cm 6. Trªn tia Oy LÊy 3 ®iÓm A, B, C sao cho OA = 2cm, OB = 5cm, OC = 8cm. Th× :.

<span class='text_page_counter'>(26)</span> A. A lµ trung ®iÓm cña OB C. B lµ trung ®iÓm cña OC. B. D.. B lµ trung ®iÓm cña AC B lµ trung ®iÓm cña OA. Hä vµ tªn:...................................................... Bµi kiÓm tra 45’ Líp: 6........ M«n: H×nh häc 6 §iÓm. Lêi nhËn xÐt.. §Ò ra. 1. Hãy điền vào chổ ....... để đợc câu trả lời đúng. a, §o¹n th¼ng CD lµ h×nh.................................................................................................. ................................................................................................................................................. b, NÕu AI + IB = AB th×.................................................................................................... c, Hai tia chung gèc Ox, Oy vµ t¹o thµnh ................................................ §îc gäi lµ 2 tia.............................................................. d, Trªn tia Ox nÕu OA > OB th× ....................................................................................... e, NÕu M lµ trung ®iÓm cña ®o¹n th¼ng CD th× ............................................................... ................................................................................................................................................ 2. Cho điểm I nằm trên đờng thẳng xy, trên tia Ix vẽ 2 điểm A, B sao cho IA = 2cm, IB = 5cm, trªn tia Iy vÏ 2 ®iÓm C sao cho IC = 1cm, a, Viết tên các cặp tia đối nhau gốc I. b, Tính độ dài đoạn thẳng AB. c, Chøng tá r»ng A lµ trung ®iÓm cña ®o¹n th¼ng BC. 3. Cho 1 sợi dây ngắn hơn 1 thanh gỗ. Làm thế nào để chia thanh gỗ ra 2 phần bằng nhau ( vẽ hình để minh họa cách chia ). Bµi lµm. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................. ............................................................................................................................................................................................................................................................... Hä vµ tªn :........................................................... líp :................. §iÓm Lêi phª cña thÇy ,c« gi¸o. Bµi kiÓm tra häc kú i M«n : VËt lý 8. §Ò ra. 1. T¹i sao các vật như kim khâu, mũi khoan, mũi đột người ta thường làm đầu nhọn? 2. Một người đi xe đạp xuống một cái dốc dài 100m hết 20s. Xuống hết dốc, xe lăn tiếp một đoạn 60m hết 30s rồi mới dừng hẳn. Tính vận tốc của người và xe trên mỗi đoạn đường và trên cả quãng đường? 3. H·y biÓu diÔn c¸c lùc sau: ( tØ xÝch tïy chän ).

<span class='text_page_counter'>(27)</span> a, Träng lùc cña vËt nÆng 60 kg, b, Lùc kÐo cña ®Çu tµu lµ 750 000N. 4. Một vật làm bằng kim loại, nếu bỏ vào bình chứa có vạch chia thể tích thì làm cho nước trong bình dâng lên thêm 100cm 3. Nếu treo vật vào một lực kế thì lực kế chỉ 7,8N. Cho biÕt TLR của nước 10.000N/m3. a, Tính lực đẩy Acsimet tác dụng lên vật. b, Xác định khối lượng riêng của chất làm nên vật. Bµi lµm. …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… ……………………………………………………………………………………………………………………………………………………. Hä vµ tªn :........................................................... líp :................. §iÓm Lêi phª cña thÇy ,c« gi¸o. Bµi kiÓm tra häc kú i M«n : VËt lý 8. §Ò ra. 1. Tại sao khi trời mưa, đường mềm lầy lội, người ta thường dùng một tấm ván đặt trên đường để người hoặc xe đi? 2. Một vật chuyển động ừ A đến B cách nhau 180m. Trong. 1 3. đoạn đường đầu vật đi. với vận tốc V1 = 5m/s, trong đoạn đường còn lại chuyển động với vận tốc V2 = 3m/s a, Sau bao lâu vật đến B. b, Tính vận tốc trung của vật. 3. H·y biÓu diÔn c¸c lùc sau: a, Lùc kÐo vËt nÆng 45 kg tõ díi lªn. b, Lùc cña ngêi kÐo xe bß lµ 600N. 4. Một vật có trọng lượng riêng là 26000 N/m 3 dạng hình cầu, nhúng ngập vào trong nước thì nặng 150N. Hỏi: a, Vật chịu tác dụng của những lực nào? Hãy biểu diễn các lực tác dụng lên vật đó. b, Ngoài không khí vật đó nặng bao nhiêu? Cho biết trọng lượng riêng của nước là 10000 N/m3. Bµi lµm..

<span class='text_page_counter'>(28)</span> …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… ……………………………………………………………………………………………………………………………………………………. Hä vµ tªn :........................................................... líp :................. §iÓm Lêi phª cña thÇy ,c« gi¸o. §Ò ra. C©u 1. Rót gän c¸c ph©n thøc sau. a.. x2 − x 3 x −3. 3. b.. 2. 4 x − 16 x +16 x 2 x −4. C©u 2. Thùc hiÖn phÐp tÝnh. a.. x 9 −6 x + x −3 x 2 −3 x. b.. 6 x −3 4 x 2 −1 : x 3 x2. Bµi kiÓm tra 45’ M«n : §¹i sè.

<span class='text_page_counter'>(29)</span> C©u 3. Cho biÓu thøc: A=. x x 2 +1 + 2 x − 2 2 −2 x2. a. Víi gi¸ trÞ nµo cña x th× biÓu thøc A cã nghÜa. b. Rót gän A, c. Tìm giá trị của x để A = - 1 4. C©u 4. Cho 2 sè x, y tháa m·n x + y = 1. Chøng minh r»ng: x2 + y2 1 2 Bµi lµm. …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… …………………………………………………………………………………………………………………………………………………… ………………………………………………………………………………………………………………………………………………. Hä vµ tªn :.......................................... Líp :.................... §iÓm Lêi phª cña thÇy , c« gi¸o. Bài 1: Chọn đáp án đúng : a, Ph©n thøc : − 5 x rót gän thµnh :. Bµi kiÓm tra 15’ M«n : §¹i sè. §Ò bµi :. 5−5x. x 1−x −x D, x−1. B. 1. A,. b, Ph©n thøc : A,. 1 2. c, Ph©n thøc : A , −4 x. 5. 2(x −5) 2 x (5 − x). C,. x x −1. rót gän thµnh:. −1 x 3 2 4 x − 16 x +16 x rót gän thµnh : x2 − 4 4 x (x −2) B, x +2 B,. C,. x −5 x (5 − x ). C,4 x. D ,− x. D,. 4 x(x +2) x −2.

<span class='text_page_counter'>(30)</span> d, Ph©n thøc : A,. 1− x2 x ( x −1). −1 2. rót gän thµnh:. B,. −2 x. C,. 1+ x −x. D,. 1+ x x. Bài 2: Đặt các số thứ tự 1 , 2 , 3 … chỉ các đa thức ở cột A vào vị trí (…) cột B để có kết quả đúng là mẫu thức chung của 2 đa thức đó ở cột A. Cét A 1,. Cét B. 12 2 vµ 2 3 2 x −6 x x − 36. …..(x+3)2. 2,. 0,5 19 vµ 2x+8 x +4 x. …..x2(x–6)(x+6). 3,. 1 x vµ 2 x +3 x + 6 x+9. …..2x(x+4). 4,. 3 x vµ 2 2 x − xy y +2 xy. …..xy(2x–y)(2x+y). 2. 2. Bài 3: Điền vào chổ ............. để đợc đáp án đúng. x+1 3 x −5 . .. . .. .. . .. a, − = b, − 2+3 x + 4 x +3 =.. .. . .. .. .. . 6−7 y. 6 −7 y . .. . .. .. . .. .. Bài 4: Hãy đánh dấu (. 4−5 y 5 y−4. .. .. . .. .. .. . .. ) vào các ô tơng ứng mà em cho là đúng hoặc sai : Các khẳng định. §. S. a, x+ y là phân thức đối của phân thức x+ y x−y y −x b, 2 x +1 là phân thức đối của phân thức 1+ 2 x 3 x+ y 3 x+ y 1 −1 c, là phân thức nghịch đảo của phân thức x−y y−x 2 y +1 1 d, Ph©n thøc : 2 =0 nÕu x 2 vµ y= − 2 x −4 Bµi kiÓm tra15’ M«n : §¹i sè. Hä vµ tªn :...................................... Líp : ..................... §iÓm Lêi phª cña thÇy , c« gi¸o. §Ò bµi :. Bài 1: Chọn đáp án đúng : a, Ph©n thøc : A,. 1− x2 x (x −1). −2 x. rót gän thµnh: B,. b, Ph©n thøc : − 5 x. 5−5x. 1+ x x. rót gän thµnh :. C.,. 1+ x −x. D,. −1 2.

<span class='text_page_counter'>(31)</span> A. 1. B,. 5. c, Ph©n thøc : A,. 2(x −5) 2 x (5 − x). x−5 x (5 − x ). x x −1. C,. −x x −1. D,. x 1− x. rót gän thµnh: B,. 1 2. D,. C, -x. −1 x. 3 x2 +16 x d, Ph©n thøc : 4 x − 16 rót gän thµnh : 2. x −4. 4 x (x −2) A, x+2. B ,4 x. C,. 4 x (x +2) x−2. D ,− 4 x. Bài 2: Đặt các số thứ tự 1 , 2 , 3 … chỉ các đa thức ở cột A vào vị trí (…) ở cột B để có kết quả đúng là mẫu thức chung của 2 đa thức đó ở cột A. Cét A. Cét B. 3. 1,. x 2x vµ 10 −5 x 5. …(x–1)(x+1)2. 2,. x +1 1 vµ 2 x −3 x +3 x +9. …(x2+1)(x2–1). 3,. 2x x vµ 2 2 x −1 x +2 x +1. …5(2–x). 4,. 2x x vµ 2 2 x +1 x −1. …(x–3)(x2+3x +9). Bài 3: Điền vào chổ ............. để đợc đáp án đúng. a, − y +2 + − y −5 =.. .. . .. .. . b, 3+ 4 x − 6 x+ 4 =. .. .. . .. .. . 3 −8 y 3 − 8 y. .. .. . .. .. . .. Bài 4: Hãy đánh dấu (. 5 y −1. ) vào các ô tơng ứng mà em cho là đúng hoặc sai :. Các khẳng định là phân thức đối của phân thức a+ b. a+ b a− b b− a b, 2 x +5 là phân thức đối của phân thức 5+ 2 x 6 x+ y 6 x+ y 1 c, là phân thức nghịch đảo của phân thức −1 a− b b− a 3 y +5 5 d, Ph©n thøc : 2 =0 nÕu x 3 vµ y=− 3 x −9. a,. 1 −5 y . .. .. . .. .. .. §. S.

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