!"#
$%&'()
!"#$#%&'(#
)
%(*%+,-&.
/01$23!.
$*(+ ,-.'.)"
45/4..36&(7
89/:%+*;63<6=2>?(@A
$/012,2
0B,.#.$CD$C3EFD$C-G#%+3%G
HI762
3$&45)
&
!
J!I.#$K2
"#
6-7&8LM.%+,?
8J45 8J89 46&
4$I6&(7)NO
8@8P−94Q$R
S./
CH: T.I=FU$.
%&H3& .
3 $ . =
V
CH:LM<G
V
CH:LM ( (.(
!"
=2>?(?V
CH:L
;<
V
:1(%+W
B,$&K.
XY(..
4?%+
9:1;( !"#
1. Nhắc lại định nghĩa tính đơn
điệu của hàm số. (SGK)
J;<;6$
Q#KZ$.
(&
J;<<6
$Q#K!Z$.
(&
6-7&80N-
8J45 8J89 46&
45 [ * 6 1(/ \&
(7]
T./
9:1;( !"#
2. Tính đơn điệu và dấu của đạo
hàm:
x
O
y
x
O
y
F^P!−@F^!
P
−P!
CH: _"
` *
6&+
SX?()3
`)&#X
42$N
6FK&6&
T)1!"N*
$V
[a$1!"
89G#Jb@$c
4&61(IFE
.
82
6&$N6FK&
[a$
dJ<@/\94Q]
TF^e\!])
$Q
dLef\!]gA
x K
∀ ∈
N
F^e\!];6$Q
dLef\!]hA
x K
∀ ∈
N
F^e\!]<6$Q
6-7&8<4&61(<
8J45 8J89 46&
4.$61(@
45?i2
1(0
42@$N6FK
&
J* U K &
U
=T.861(
I ? i
.
j# 6& $N
6FK&
41K&
U
&>20N.%&;
63<6/
F^!
k
−k!@
4&/
0_J/l^[
Ff^k!
P
−k
Ff^A⇔!^@m!^−@
0/
!−∞−@@∞
FfA−A
F
Q1/
6-7&8?j>$#<*
8J45 8J89 46&
45<>$#
ano^o
!&F$#
-#Q
41%+
9:1;( !"#
2. Tính đơn điệu và dấu của đạo
hàm:
dJ</\94Q]
[7
S.%,&&
4&7
0$N6F%,&&
dTan/\94Q]
57/_"
F^!
k
J9/8B;6
6-7&8@0(1,FM!"
8J45 8J89 46&
0Z.7$3=F$a
$,FM!"
V
L.-E
n
0%&94Q-$a$
,FM
41%+
9A(B&CDE&&:1;(
!"#9
1. Quy tắc: (SGK)
bn/5N.%&
;63<6
C2!"*6
)
6-7&8Fp(7,FM-=(,
8J45 8J89 46&
[*61(
q. ?i
\E]2&6
1(
422$N6FK
&6&
8UK&
2
4& 6 1( I ?
i.
0$N 6F K &
6&
4 1 K &
U
&>2_"
/
@
P
x
y
x
−
=
+
J9/8;6$.
%&
( )
r P−∞ −
( )
Pr− +∞
&>2<
T+$s/!g!?
2!#%&
Ar
P
π
÷
8l/_"
F ^ ! − ! $ %&
Ar
P
π
÷
Z ) $a $ 6 E
+
$%&/45%+$2XEM
'"()*T.61(94Q90
ttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt
B"-7GHIHJ<
!"#K&&L
$%&'()
r
!"#$#%&'
(#)r%(*%+,-&.
/01$23!.
$&45)
&M(B;&>2
!
6-7&8
@ TF^e\!])$Q3?Q%&3u%&m LM
';63<6$Q
$QV
P L,M!"';63<6
k _"';63<6/F^
k P
@
k v P
k
x x x+ − −
6-7&8/0N.%&./P]F^
k! @
@ !
+
−
r]F^
P
! ! PA− −
8#2 8#.
t0$N6F6&
tL1!"6&6
t4226&$N6F6&=
w6<>
t42#21!"6&
6I<?R6?=6>P
txM'6-2*
.3.$N6F6&
6-7&8</\T61(y94Q]T+6z+/!g!\Ah!
h
P
π
]
8#2 8#. 46&
01(m
$6z+E
+
Q&.*
t8?i2'
I<?
&
_"\!]^!t!!.
<?..$<!∈
Ar
P
π
÷
)/{\!]^
P
!
A≥
x∀ ∈
Ar
P
π
÷
f\!]^AU-!^A
=1(\1(
6&]
0Z%,&
$%1*6z+
E+
;6$
Ar
P
π
÷
⇒
\!]g\A]^A3∀!∈
0;
2
π
÷
$%&=S(.(!"';63<6
p(7';63<6-+#
J0
'"()*
8.61(C>$@@\94Q]390
ttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt