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Đề thi học sinh giỏi vòng 2 lớp 9
năm học 2008-2009
Đề thi môn: Toán
(Thời gian làm bài: 150 phút )
Câu 1: (1,5điểm)
2 Cho các số thực dơng x, y thoả mãn: x
100
+ y
100
= x
101
+ y
101
= x
102
+ y
102
Hãy tìm giá trị của biểu thức: A = x
2008
+ y
2008
.
\ Giải hệ phơng trình:
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x y z 6
xy yz zx 1
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5
Đề 6
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.%7/
8.3
# #
"
x x
+ =
$
!$ 670l9:.QA28I*P$-.@J2
m
8+:
J29:.G.-.@TF^.$
>(Q4
679:.
4 # 4x x x x
− + = −
Q
>(#Q&
%.2-C>A
·
! B BABC BC a AB c
= = =
Q
Sa c
T(2=+(%.FSm
n.VX‰AOV.MGC>S.MGCSX'(‰R.MG>_T(
mn.=.E9.%.2-C>$
$ '@.J2V.MGC>mn.VX‰A+8.TF^.$
+8.TF^.A$
13
$ 1Z'*[z6=.E9.%.2-C>\H.FI}'(%92$
+8.J2'*A$
Đề 17
>(Q
#$ 6789:.
4
4
# 4
# 4
x y
y x
+ =
+ =
4$ 3HE2S\ST(-0?.%7/-\^.<.3
a b c c a b b c a
a b b c c a a b b c c a a b b c c a
+ + ≥ + + ≥ + +
+ + + + + + + + +
Š Š Š Š Š Ša b c
= =
>(Q!
#$ ]-@'*A=+(GT(0?M'(+8.ˆT(0?MK4
m0?S.%A-m0?(:'@S(s'((.?2$
4$ CS>ST(=.A\2.P.=$2J2C.=AASˆ'n%-
J2>'(0%0J2ˆR.%AA$>E.H'(0%0
J2T(2I-F.'(I*97T(%J2>$p.%\2CS>S
2T(I-F.'F2I2{
>(#Q
%.qQN.PNS\-IbS2IC>'(1'*A'F2$~
.qQN
=.E9.%.2-C1$~.qQN
.E95c'FGN>'(N1J2
.2-N>1'(.E95c.%'F.qQN$~.qQN
#
.E95c'FGN>'(
NJ2.2-N>'(.E95c.%'F.qQN$~.qQN
4
.E95c'F.2
C'(1'(.E95c%('F.qQN
$\-IJ2-.qQN
SQN
S
QN
#
SQN
4
.Y%b$
§Ò 18
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u 1:
2 TÝnh gi¸ trÞ cña biÓu thøc:
#""#$#""#$#"4$
"
#
++−+++++
+
=A
\ %0?`I
4
dI
#
i!I
iId"'FIT(0?M$UI8J2I0?2
E.%!$
$%'
%\.3
zy
zy
zx
zx
M
−
+
+
−
+
=
S.%A5SSeT(-\EI-.%7/
UI8
zyx
=+
$
p\.3VA.n-.@p^.\H\2%M{
$%+
%9:.k5S
5
d#
d5i5i4d&`
80?J29:.(.W-.@J25'(
2 ~G.-.@TF^.B
14
\ ~G.-.@p^.$
$%,
%2S5
∈
bS2f$3H
( ) ( )
4
+−
+≤−++−++−
+ xx
a
a
a
axxxx
a
a
$%-
%.3-C>1A2r%C'(>1y.2RN$6+8.J2.3
-C>1T(S+8.J2-.2-CN>'(N1TxT_.T(
'(
$
3HUI8x'(J2GC>'(10%0%'F2T(
SSS +=
$
(§Ò 19)
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
Bµi 1: (2 ®iÓm):
2 Chøng minh r»ng:
( )
( ) ( )
44
! −++=++ xxxx
'F5I*PB
\ 6789:.
( ) ( )
=−++
−=+
"
44
xx
xxx
679:.
$##"
=+−−−− xxxx
AB'(2 điểm):
2 \20?M.?TM.E92S\S02%%
cba ++
ˆT(0?M.?{
\ %20?5S.%7/
#4
−−=−+ xxyxyyx
$/.-.@J2\.3
!&
!
#
−−
−
+−
−
=
yy
y
xxx
x
A
{
-0?M29:.
( )
4#
=−++− axax
A8M{
AB+(2,5 điểm):
2 679:.8M5
d
i5i5id`B
\ 679:.
$
+−=++−+−+ xxxxxx
AB,(1 điểm):%5fBf.%7/
≤+
y
x
$
/.-.@p^.J2\.3
x
y
y
x
P !! +=
{
AB-(2,5 điểm):%.qQNI>`b'(C.2W.MQNQC
I*.,'F>S$~9P-.%ACJ2.2-C>y.QN.G)Q)I-
C$GC'*A'F>$
2 ~;.C`5$+8.J2.2-C).Y%b'(5$502%%G.-.@
TF^.$
\ 3HIC.2WS.WC
d)
T*T(=.GT_I*W$
0?%A>J2.2-C>\E.
"
#
=
HK
AH
$
§Ò 20
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u1:
Chøng minh r»ng
++= nA
T(0?9:I
NA ∈
'(
Nn ∈
$
15
$%'
%2.3XQ5M'(XQ52E.%#I
{ }
BB ++∈ kkkx
'F
Zk ∈
$3
HXQ2E.%#'F
Zm
∈∀
$
$%+
2679:.
( )( )
# −=−+−+− xxxx
\6789:.
++=+
−=−
ayxyx
yxyx
!
#
!
QQ
Q2T(.20?'(2f
$%,
%'*C>1%G.E9.qQNBb'(VT(=..M.q
A$6=+(VCSV>SVSV1TxT_.T(2S\SS+$
3H2
\
d\
+
`b
4
$%-
%2S\ST(-0?.Z+:$-.@p^.J2
`
+
b
a
#
$
+
c
b
#
$
+
d
c
#
$
+
a
d
#
§Ò 21
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u 1:
2 Gi¶i ph¬ng tr×nh
#### yx −=−
.M.n9_9-0?m.O$
\ 6789:.
( )( )
=++
=+++
4
4
xyyx
yxxyx
$%'
DE.9:..<L2CQ4B#Sy..s..GA.=T(
=.0?M+:Sy..s%(.GA%(=T(0?M.?$
$%+
2 %5`'(5f$3
≥
−
+
yx
yx
\ %2S\ST(=+(\2GJ2=..2-.%7/2d\d`$3
<+++ abccba
$%,&"M('#NEOEB*
%.qQNI>`b'(C.2W.MQNQCI*.,'F
>S$~9P-ACJ2.2-C>y.QN.G)Q)I-C$2C'*A
'F>$
2 ~;.C`5$+8.J2.2-C).Y%b'(5$502%%G.
-.@TF^.$
\ 3HIC.2WS.WC
d)
T*T(=.GT_I*W$
0?%A>J2.2-C>\E.
"
#
=
HK
AH
$
§Ò 22
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
1-a, T×m tÊt c¶ c¸c sè tù nhiªn cã 3 ch÷ sè
abc
02%%
16
( )
−=
−=
ncba
nabc
'FT(0?MTA:$
\S-0?5SSeM+:.%7/<.3
Qde`5Qe
S%0?M.?9f#$>E.HA0?.ZM02%%.%-'E..n99P
J20?9
Acm0?$3H
%m0?(A.^.#m0??2$
$ %5T(0?.Z.%7/
#
≤≤
x
-.@TF^.'(-.@p^.J2X`5
x−"
dQ#5
+x
$ 2S679:.
x
xx
x
xx
x
=
−−
−
+
++
+
#
#
#
#
\S6789:.
=++
−=−+
=++
4
!
zyx
zxyzxy
zyx
#$ %.2-UC>G2%G.E9.qQ$V=..E9.EJ2.q
y.GC>SC.3.ZR1S[$~;.C1`5BC[`B1[`e$
3H2S
zxyyx =−+
\S
EC
AE
DB
AD
+
I*WI.E9.E1[.2W$
§Ò 23
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u1: 1) Cho hÖ ph¬ng tr×nh
=−
=+
byax
ayx#
Q2S\T(.20?
]-@\8T*A8Q5B'F2$
DE.9:..<L2VQB#Sy..s%('(.s..G
-CQ2B'(>QB\02%%2S\T(-0?M.?$
$%'%.q.PN=.E9.2-C>S.E95c'F-G>SCSC>Tx
T_..G1S[Sz$Du1'*A'F[zQ
∈
[z$
3H
HCAHBA
‹
‹
=
$
$%+3HzQ`4
d"iT*2E.%'FM+:$
.^.7-;90?MQ5B.%7/5
#
`
#
d
d$
$%,%2S\S
−≥
'(2
#
d\
#
d
#
`!$
-.@TF^.J2\.3C`2
d\
d
$
§Ò 24
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u 1: a) Cho a, b > 0, c
≠
$3H
cbcaba
cba
+++=+⇔=++
\6789:.
+=−+−
=+
xyyx
yx
17
$%'2%9
"T(0?M.?02%%9dT(0?M.?$3H
9d2E.%!'(9
dI*97T(0?M.?$
\679:.M5
#
`
#
d5d&
$%+2.^.7-0?M\^.<.3
Q
i5g#
#
i4
ddc'F0?M+:5$
\%5SSeT(-0?.ZI*P'(5dde`$-.@TF^.J2X`
5dede5$
$%,%'*C>1.PN$6)STxT_.T(.J2C>S>'(zT(
.J2$wCI}.<0%0%'F)zy.1.G6$3z6T(
.E9.EJ2.q.PN=.E9.%'*$
Đề 25
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Bài 1 (2 điểm):
a) Chứng minh rằng nếu b là số nguyên tố lớn hơn 3 và 10b+1 cũng là số nguyên tố thì
5b+1 chia hết cho 6.
b) Tìm nghiệm nguyên của phơng trình x
2
+x+13=y
2
.
Bài 2 (1 điểm):
Cho xyz = 1, chứng minh rằng :
=
++
+
++
+
++ xzzyzyxyx
$
AB+(3 im):bc.\.3
x
x
x
xx
x
x
$
+
+
+
AB,(2 im):-.@TF^.J2\.3
44
# xxxxA ++=
'F
x
$
AB-(2 im): %'*C>1AG:'@$MG>'(1TxT_.T^V
'(02%%VddV`$-%G.<CVSCTxT_.y.r%1>.GtS)$
3-%G.<>tS)S)1Tn9.(\2GJ2=..2-'*$
Đề 26
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Câu 1: a) Chứng minh rằng với mọi số tự nhiên
n
.0?
#
+
n
2E.%#
d
I*2E.%#
d
$
\.^.7-0?M5S\E.5ff.%7/5
#
d `
#
d 5
$%'679:.
axxxx =+ 444#
Q2T(.20?$
$%+wXH%(.q.PN\-IbI}2.E9.EXCSX>'FCS>
T(-.E9$6T(P'*AG.wCEI>$
2 3HXy.C.G.J2CB
\ C.Y%b'(XN`+$
$%,%2S\ST(-0?.ZI*P.%7/2d\d`$-.@TF^.J2\
.3
( )
++= cbcabP
$
Đề 27
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Câu 1: a) Chứng minh rằng với mọi số tự nhiên
n
.0?
#
+
n
2E.%#
d
II*2E.%#
d
$
\.^.7-0?M5S\E.5ff.%7/5
#
d `
#
d 5
$%'679:.
axxxx =+ 444#
Q2T(.20?$
$%+wXH%(.q.PN\-IbI}2.E9.EXCSX>'FCS>
T(-.E9$6T(P'*AG.wCEI>$
18
3HXy.C.G.J2CB
+ C.Y%b'(XN`+$
$%,%2S\ST(-0?.ZI*P.%7/2d\d`$-.@TF^.J2\
.3
( )
++= cbcabP
$
Đề 28
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Câu 1: a) Giải phơng trình:
( )
( )
4$4
#
#
=
+
+
+
y
yy
x
x
$
\6789:.
+=
=+
&!&
xxy
yxyyx
$%'
2 M.<&5i#d!`S/.-A.%G=MHm22
.<5`i'(5`"$
\ 0?.ZMS\E.HI\p\2m0?.n,\M97J2A._0?
FA-.@\H
#
n
$
$%+%-0?.Z5fS
y
.%7/5
#
d
#
`5$-.@TF^.J2\.3
X`5
d
$
$%,%.2-t1%G.E9.q.PN$)}.<C>.E95c'FQN
.GV'(0%0%'F1QC.=t1S>.=t$)}IVJ2.qQN$
62%J2t'FC>T(V
$3H
2 CV
$`>V
$1B
\ CV
`>V$
Đề 29
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Câu 1:
2 Rút gọn biểu thức:
( ) ( )
bbaa
bbaaba
ba
bab
A
+
++
+
=
#
#
'F2fS\f'(
ba
$
\ -.@J2\.3
( )
##
+
=
xx
x
y
'F
# +=x
$
$%'
2 %\.3
( ) ( ) ( )
# xzzyyxB +++=
$
-0?M5SSe
B
$
\ %
x
'(T(0?M+:$3H
( ) ( )
n
nn
xx ++
$
$%+
2 679:.
( )
#
=+ xxxx
$
\ 67\^.9:.
#!4#4 ++>+ xxxx
$
$%,
2 %.2-C>'*.GCSVT(.J2C$~.<L2C'*
A'F>Vy.>.G1..O0?
DB
DC
$
19
\ %.2-C>P.GC$MG>Ir%+('U92T^=.V$V=.
.<+L2Vy.C'(C>.Y%.3.Z.G'(X$3H
CN
CM
BP
BM
I*WIV'(+.2W$
$%-
3H'F5SI-2'(I-.
( )
=
+
y
y
x
x
yx
yx
xy
yx
$
Đề 30
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Câu 1: (2,0 điểm)
2 Rút gọn biểu thức:
+
+
+
+
=
aa
a
aa
P
'F2f'(2
$
\ 679:.
=
+
++
+
x
x
x
x
$
AB'(3,0 im)
2 ?%2GA'*J2=..2-'*T(8J29:.\n2
Qi5
iQi5d`$/5-@-.@J20?%2%3'F
GUJ2.2-T(
"
$
\ Du-.<5`!B5`4B`B` .M,=.8.s.%G=$3
H.%mn.FG\R-.<.MI*A
M(%.=.<#5d"` $Q~VQ5S_T(ME
5S,T(0?M$
AB+(2,0 im)
%.3-C>1A-G?+8C1y.>.G['(C>y.1.Gz$3
HUI8x'(J.3-C>1=.E9_.qT([C$[1dzC$z>
`[z
$
AB,(2,5 im)
%.2-C>PRCSC>`
#
>S2%C[$~.q.PN=.E9
.2-C>.E95c'FC.Gz$
2 3H>zT(.E9.EJ2.q%G.E9.2-[z$
\ 6VT(2%J2>z'F.qQN$3H>VNT(.3-=
.E9$
AB-(0,5 im)
VJ2;.9<_y'F=..%2(52%;.y$3
H.K.G=..2-US'FG\H%;
#
Q:'@+(SA\2O,
($
Đề 31
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Phần 1 (Mỗi câu 5 điểm): HS chỉ cần trình bày vắn tắt cách giải và ghi đáp số.
$ Tìm số lớn nhất trong hai số
B
####
+
+
+
+
$ %.2C>1Q>1CS2r%y.2.GNS^X.MC>02%
%XN>$>E.>`#S1C` $/.NX$
20
#$ 6789:.
=
=
#
&
y
x
xy
4$ ]r.0?M+:2'(-0?.Z5SSe.%7/
$ 5d2`
$ 2d`5
$ 5d`e
-.@TF^.A._J2.W5dde$
PQ'&R$%!5() *L"EBN;L
$ -CS>SS1T^.M-GX‰S‰bSbSXJ2.3-X‰b02%%
C>1T(\('(CS>1SXbS‰KL$3HX‰bT(
\($
$ 2%•Q5`5
d!5dS
Zc
∈
$3H•Qd•QT(0?MT}$
\%Q5`5
#
d95
dL5dB
Zrqp ∈SS
$3HE7QSQUT}.
9:.Q5`I*.A\28M$
#$%mn.C>1$…^]
∈
C>SŽ
∈
>B
1C]
`"S
]>Ž
`4S
Ž1
`#$+8
..2-1]Ž$
4$)‚8
x
T(0?MTF^.I*'_.L-5$.W
"44&$$$# ++++++
"$ -1S[SzT^.M-GJ2.2-C>02%%
AEFCEDCDEBDFBFDAFE ∠=∠∠=∠∠=∠ BB
2$ 3
BACBDF ∠=∠
\$ >E.C>`"S>`&SC` $>1$
!$ 3H'F0?M+:0?
( )
n
nnn
4" −−+−
T*2E.
%$
$ %-0?.Z2S\SS+.%7/
=++
=++
cabcab
cba
/.-.@J2\.3
cacbcbaba
M
++
+
++
+
++
=
&$3-TKC>1A.^.C>`1S$…^G>T(-S+Z2%(.2-
'*P[>$3H.2-[C1ˆ'*P$
§Ò 32
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u 1: (1,5 ®iÓm) Cho biÓu thøc
4#
Q
+−
−−
=
xx
xx
xP
2 .^.7--.@J25XQ55-@$bc.XQ5$
\ 3HE5f.XQ5$XQ5g$
$%'(1,5 điểm)-.@MJ25'(.%<.3
5
#
d5` $
$%+(2 điểm)6789:.
=+
−=+−
#!
yx
yxxyx
21
$%,(3 điểm)~.q.PN=.E9.2-C>.E95c'F-G>SCSC>
.:3.G-1S[Sz$~.q.PN
€
H.%ACJ2.2-C>.E9
5c'FG>'(9xIr%+(J2-GC>SC.:3.G-XSVS$
2 3H>X`1$
\ M.<V.2T^-t'()02%%)€€C>S>t€€C$3
H>t[T(\($
6QT(.qL2\2tS)SX$3HQ.E95c'F-
.<>S>tS)$
$%-(2 điểm)%2S\Sf$3H
bacacbcbaaccbba ++
+
++
+
++
≥
+
+
+
+
+
#
#
#
§Ò 33
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u 1: (2,5 ®Óm)
2 Gi¶i hÖ ph¬ng tr×nh:
( )
( )
=−
=−−
xxyz
xxyxz
\ 679:.
4
4
+
−
=
+
x
xx
x
x
$%'(2,5 điểm)
2 670l
B
44
+−
−
=
++
=
xx
x
B
xx
A
$]-@
Zx ∈
#
BA
C
+
=
n-.@
M$
\ 62'(\T(28J29:.\n2
=−− xx
$3H
Q
++
+++=
nnnn
babanP
T(m0?M'(2E.%"'F0?M
+:$
$%+: (2,0 điểm)%.2-C>S2%Q
ABH ∈
$6VSQ
ABNM ∈S
TxT_.T(9P--ACSA>$P.q%G.E9.2-V.,
.P.q=.E9.2-C>$3H
$BMAN
S
ABC
=
∆
$Q
ABC
S
∆
T(I‚8
+8..2-C>$
$%,(2,0 điểm)%.2-C>S-2%>1S[B..ECV$‰2C
I}-.<0%0%'F['(>1y.>1'([.3.Z.GX'(‰$6)T(2%
J2CV'(X‰$3CX1).3-=.E9$
$%- (1 điểm) >E.H20?.Z,+^'(.%7/<.3
( )
( )
44#
##
=++++++ yxyxyx
$
/.-.@TF^.J2\.3
yx
Q
+=
$
§Ò 34
®Ò kh¶o s¸t chÊt lîng HSG líp 9 M«n: To¸n
C©u 1. (2 ®iÓm) Cho
aaa
aaa
aaa
aaa
P
4
4
4
4
−+
−−
−
−−
−+
=
2 UI8J22\.3XA•2'(c.X$
\ 2
"<P
$
22
$%'(1,5 im)%2.3Q`
"
i"
#
d4'FM+:$3HQ
2E.%'F-.@M+:J2$
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Đề 35
đề khảo sát chất lợng HSG lớp 9 Môn: Toán
Bài 1: (2 điểm)
a) Chứng minh rằng nếu p là số nguyên tố lớn hơn 3 thì ( p 1)( p + 1) chia hết cho 24.
b) Tìm nghiệm nguyên dơng của phơng trình: xy 2x 3y + 1 = 0.
Bài 2: (2 điểm) Cho các số a, b, c khác không và đôi một khác nhau, thoả mãn điều kiện
a
3
+b
3
+c
3
= 3abc. Tính:
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Đề 36
ST Toỏn
Bài 1.
Giải hệ phơng trình
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=+
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xy
yx
65
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d!5d`'(5
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24