Đáp án đề thi học kỳ 2 môn cơ sở dữ liệu pdf

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TruO'ng D~i HQc cAn ThO' Dap an d~ thi hQc ky 2 Dam hQc 2005-2006
Khoa Cong Ngh~ Thong Tin & TT Mon thi: CO' sit dfi' li~u (CD033) - LAn 02
L(rp: CD Tin hQc K30.
ThOi gian lam bai: 90 photo
NQIDUNG
£.A!!l (1.5 di~m): cho t~p ph\l thuQc ham sau:
F = { AB7 C, B7 DE, CD7 EK, CE7GH, G7 AC }
a. (0.75d) Su d\lng cac tinh chAt cua ph\l thuQc ham de ch(mg minh: AB 7 G.
Tac6: AB 7 C
B 7 DE => B 7 E => AB 7 E
=> AB 7 CE (I)
CE7GH :::> CE 7 G (2)
Tir (1) & (2) => AB7G (dpcm)
b. (0.75d) Kiem tra ph\l thuQc ham sau: BG7 H c6 thuQc F+ hay khong?
Ta c6: BG7 H E F+ <;:> HE (BG)+
M~t khac: (BG)+ = BGDEACKH => H E (BG)+
V~y BG7 H E F+.
~.l (1.0 di~m): tim t~p ph\l thuQc ham t6i thi~u cua t~p ph\l thuQc ham:
F= {A7 BCD, DE7 EFG, D7 EG}
Bwc 1 (0.25d): tach cac thuQc tinh it v~ phii cua cac pth d~ v~ phii chi con mQt thu9c tinh
H= {A7 B,A7 C,A7 D,DE7 E,DE7 F,DE7 G,D7 E,D7 G}
Bwc 2 (0.5d): Lo~i bo cac thuQc tinh thira
-XetA7 B:J= {A7 C,A7 D,DE7 E,DE7 F,DE7 G,D7 E,D7 G}
Ta c6: (A)+J = ACDEGF khong chuaH nen gitI A7 B.
-XetA7 C:J= {A7 B,A7 0, DE7 E,DE7 F,DE7 G,D7 E,D7 G}
Ta c6: (A)+J = ABDEGF khong chua C nen gitI A7 C.
-XetA7 D: J= {A7 B, A7 C,DE7 E, DE7 F,DE7 G, D7 E, D7 G}
Ta c6: (A)+J = ABC khong chua 0 nen gitI A 7 0
-XetDE7 E:J= {A7 B,A7 C,A7 D,DE7 F,DE7 G,D7 E,D7 G}
Ta c6: (DE)+J = DEFG chua E nen lo~i bo DE7 E trong H.

-XetDE7 F: J= {A7 B, A7 C, A~ 0, DE~ G, 07 E, D~ G}
Ta c6: (DE)+J = DEG khong chua F nen gitI DE~ F.
- Xet DE7 G: J = {A7 B, A~ C, A~ D, DE7 F, D7 E, D7 G}
Ta c6: (DE)+J = DEFG chua G nen lo~i bo DE7 G trong H.
-XetD7 E: J= {A7 B,A7 C, A7 0, DE7 F, 07 G}
Ta c6: (D)+J = DG khong chua E nen gitI D~ E.
-XetD7 G: J= {A7 B, A7 C, A~ D, DE7 F, 07 E}
Ta c6: (D)+J = DE khong chua G nen gitI 07 G.
V~yH= {A7 B,A7 C,A7 D,DE7 F, D~ E,D7 G}
Bwc 3(0.25d): Lo~i bo cac thuQc tinh thira it v~ trai
Ta chi xet cac pth ma v~ trai c6 nhi~u bon 1 thuQc tinh. Do d6, v&i H ta chi xet pth sau: DE~ F
- Thu lo~i b6 0:
J = { A ~ B, A 7 C, A 7 0, E7 F, D~ E, D~ G}
Ta tinh (E)+J = EF
Ta tinh (E)+H = E => (E)+J * (E)+H nen gitI D l~i
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- Thir 1o~i b6 E:
J= {A~ B,A~ C,A~ D,D~ F, D~ E,D~ G}
Ta tinh (D)+J = DFEG
Ta tinh (D)+H = DEGF =:) (D)+J = (D)+H Den 1o~i b6 E
V~y t~p pth t5i thi~u 1a: H = {A~ B, A~ C, A~ D, D~ F, D~ E, D~ G}
~~ (1.5 di~m): cho quaD h~ R(A, B, C, D, E, F, G) v6'i A 1a kh6a cua R. T~p ph\! thuQc ham
tren R 1a F= {A~ BC, A~ DE, E~ FG}. Yeti cau:
- (O.5d) Viet cac ph\! thuQc ham truy6n
E~F,E~G
- (I.Od)Tach R thanh cac quaD h~ m6'i th6a d~ng chuAn 3. Cho biet kh6a cua timg quaD h~
tach duqc.
RI(A, B, C, D, E) v6'i kh6a chinh cua quaD h~ RI 1a A

R2(E, F, G) vm kh6a chinh cua quaD h~ R2 1a E
A A
CAU 4 (6.0 diem):
-~ Viet bi~u thuc d~i s5 quaD h~ cho biet s5 hoa dan, hQ ten, dia chi va s5 di~n tho~i cua nhiing
khach hang c6 h6a dan xufit trong thcing 06 Dam 2006.
(I.Od)
E = (MONTH(NG_XHD)=6 AND YEAR(NG_XHD)=2006)
KHACHHANG*HOADON(E) [SOHD,HOTEN, DCHI, SODT]
b. Hay viet bi~u thuc d~i s5 quaD h~ va ve cay bi~u thuc t5i Uti tuang (rug v6'i cau a.
(O.75d)
E = (MONTH(NG_XHD)=6 AND YEAR(NG_XHD)=2006)
(KHACHHANG[MAKH, HOTEN, DCHI, SODT] *
HOADON(E) [SOHD,MAKH))[SOHD, HOTEN, DCHI, SODT]
(O.75d)
[SOHD,HOTEN, DCHI, SODT]
(E) [SOHD , DCHI, SODT]
(=~~~ KHACHHANG
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c. Vi~t cau l~nh SQL:
- Cho bi~t hQ ten va s5 di~n tho~i cua cac khach hang co dja chi 6' duCmg 'TrAn Hung
D~o'.
(0.75d)
SELECT HOTEN, SODT
FROM KHACHHANG
WHERE DCHI LIKE '%Tran Hung Dao%'

- Cho bi~t s5 m~t hang hi~n co trong h~ th5ng mua ban hang.
(.I.Od)
SELECT COUNT(*) AS SO_MHANG
FROM HANGHOA
- Cho bi~t hQ ten, dja chi, s5 di~n tho~i cua nhti"ng khach hang da d~t mua hang hoa trong
nam 2005.
(0.75d)
SELECT HOTEN, DCHI, SODT
FROM KHACHHANG KH, PffiEU- DA THANG PDH
WHERE KH.MAKH=PDH.MAKH AND YEAR(NGA YDH)=2005
- Cho bi~t s5 hoa don va t6ng trj gia hoa don da xuAt cho khach hang 'Nguy~n Quynh'.
(.I.Od)
SELECT SORB, SUM(SOLG*DONGIA_BAN) AS TG_TGB
FROM HOADON HD, CHITIET_HD CTHD, KHACHHANG KH
WHERE CTHD.SOHD=HD.SOHD AND HD.MAHH=KH.MAHH AND
HOTEN='Nguyen Quynh'
GROUP BY SOHD
H~t CAn thO', ngay .12 thang 08 nam 2006
GV ra d~
-~~~:::====~=-
Phan Tin Tai
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