thiết kế xây dựng cho chung cư vạn phong

Đề tài: Chung c Vạn Phong
Đề tài: Chung c Vạn Phong
Thiết kế sàn
* Giới thiệu Công ty

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1. Tĩnh tải:
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Hệ số vợt tải
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2. Hoạt tải tác dụng lên sàn
Sinh viên: Vũ Hồng Quang - XD 502
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Đề tài: Chung c Vạn Phong
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L/48JO
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L/P8O
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II - Tĩnh tải nội lực - cốt thép các ô sàn
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a. Tổng tải tác dụng lên ô sàn
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λ
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t
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λ
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M
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M
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2
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Y
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Sinh viªn: Vò Hång Quang - XD 502
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R
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a
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Sinh viªn: Vò Hång Quang - XD 502
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1
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M
M
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3,1
1
1
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1
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M
M
M
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Sinh viªn: Vò Hång Quang - XD 502

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Sinh viªn: Vò Hång Quang - XD 502
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λ
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M
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A
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22
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Sinh viªn: Vò Hång Quang - XD 502
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Xφ;43<<
J/I\7
Ad
hbR
M

A
n
<=== 02,0
5,6.100.90
10766

22
01
2
*+γ*<>BB
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10766
a
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<>;1)g
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4
*<>;9):
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5,6*100
8,0
.
01
===
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Fa
M

⇒/1)gi
dfφ;^p4*<>;9):
Sinh viªn: Vò Hång Quang - XD 502
;
§Ò tµi: Chung c V¹n Phong
WXφ;43<<^p4*<>;9):
F /]9D>?=2>C:)
84*2>C9):*+
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*;J2>C*?>C9):
/&/
3
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h*D<F5D?<*??F9- )
3
:
WX8λ
2
*2>C9Y:
λ
3
*D>?9Y:Z
472,2
5,1
6,3
1
2
==
λ
λ

@#$1)"2\
Sinh viªn: Vò Hång Quang - XD 502
B
φ;43<<
D>?
φ;43<<
φ;43<<
φ;43<<
D)
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2
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3
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`Z%b
).38,93
16
)5,1.(664
16
2
.
2
1
mKg

q
MM
b
gb
====
λ
`/]
2
2
02,0
5,6.100.90
100.38,93
==A
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@#$
2
)(69,0
5,6.98,0.2100
9338
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a
==
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%05,0%01,0
5,6.100
69,0
min
=<== MM
@#$4Xφ;43<<
J/))I4

02,0
5,6.100.90
9338

01
===
hbR
M
A
a
b
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4
*<>?B9):
/]%(4b
Sinh viªn: Vò Hång Quang - XD 502
2<
K 3<<
D B<<
3 ;<<
2>C) D) D) D)
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JE1e'892>C=D>?:Y

JE1eq892>C=D>?):Y
JE14$
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SJ/]14$
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HÖ sè vît t¶i (n) Kg/m
2
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J678
1800.
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15,0.3,0
2
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3
:
L71O
//
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:
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1560
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Sinh viªn: Vò Hång Quang - XD 502
22
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`r\s]
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Sinh viªn: Vò Hång Quang - XD 502
23
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275,20
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424,3
1
2
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2
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3

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2
220
2
110
1650
1
mmb =−−=
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)/(84,103
16
)485,1.(36,753
16
.

2
2
01
mkg
lq
M ===
J/]8
J/](uuuuuuuu
Y*2<D>;F9G):
[4*2>C9):
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<2
*;J2>C*?>C9):
02,0
5,6.100.90
10380
2
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⇒*<>BB
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5,6.98,0.2100
1080
2
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J/]/A418
Sinh viªn: Vò Hång Quang - XD 502
2D
b

lqb
M
b
1
.
2
1
=
Y
§Ò tµi: Chung c V¹n Phong
98,0)02,0.211(5,0
02,0
5,6100.110
10384
2
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==
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x
A
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B. TÝnh b¶n chiÕu tíi vµ b¶n chiÕu ghi:
1. B¶n chiÕu tíi:
-]'892>C=D>?:)
!
3
8
ml
t
24,1

2
3,0
2
22,0
2
22,0
5,1
1
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672,2
24,1
34,3
34,3
2
3,0
2
22,0
6,3
2
1
2
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t
t
t
l
l
l
ml

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* TÝnh néi lùc8
a) TÜnh t¶i8
J648
ς*2>;)Rγ*33<<9G)
3
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3
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Sinh viªn: Vò Hång Quang - XD 502
2F
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2
*2>D
§Ò tµi: Chung c V¹n Phong
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//
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3
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3
:
)/(5,108
16
8,1.772
)/(5,108
16
8,1.772
2
2
mkgM
mkgM
z
g
==
==
* TÝnh thÐp8

J/))I\8
51,0)211(5,0
15,0
5,6.100.110
10830
2
=−+=⇒
==
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A
γ
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51,0
5,091,02100
10880
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F
a
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%03,0%01,0
5,6.100
87,0
min
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3
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15,0

5,6.100.110
10850
2
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91,0)211(5,0 =−+= A
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5,691,0.2100
10880
2
cm
x
F
a
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Sinh viªn: Vò Hång Quang - XD 502
2C
§Ò tµi: Chung c V¹n Phong
2. TÝnh b¶n chiÕu phÝ8
-]'92>C=D><:)
!
3
8
26,2
24,1
34,3
34,3
2

3,0
2
22,0
6,3
24,1
2
3,0
2
22,0
3,1
1
2
2
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l
l
l
ml
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t
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
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



==
==
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16
5,1.772
)/(3,108
16
5,1.772
2
2
mkgM
mkgM
g
b
* TÝnh cèt thÐp8
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91,0
)15,0.211(5,0)211(5,0
15,0
5,6.100.110
10880
2
=
−+=−+=
==
A

A
γ
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Sinh viªn: Vò Hång Quang - XD 502
2?
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2
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§Ò tµi: Chung c V¹n Phong
c) TÝnh dÇm chiÕu tíi vµ dÇm chiÕu ghi
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Z%1[8

)/(5,1811,1*22,0*3,0.(2100 mkgg
bt
=+=
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3
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6,2
1
2
=
l
l

⇒L*<>;?3
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V*
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
*2;2>C5;3C*2<<?>C
J/1[())$i"'7#
J,4#v4())$i"4)(A4>4
2#XA48
)/(3,490
2
424,3
.7,639.2
2
365,1
2
22
mkg
gP
ct
=
=
+
=

@'


*

5V
D


2
*32<<9<>D=<>2:=2>2=<>;K?
*?<>K9G):
/1[14$$i"
Sinh viªn: Vò Hång Quang - XD 502
2K
3600
gl
2
/8
300
200200
§Ò tµi: Chung c V¹n Phong
V

*KK3 
579
2
65,1
=
9G):
⇒


*CKB5?<>K*?DB>K9G):
`r\s]8
d()eN4(
!//8D?<<J322<*DD;<9)):
Y)I'Hl$4N()
4
3,2190
2
6,3*5,1006
48
22
+=+=
plgl
M
*3DCB>3
`/]8
J[
2200,0
)430.(22.110
360180

22
01
=
−
==
lbR
M
A
n

251,0211 =−−= A
α
@#$
)(6,6
210
26*22*110*251,0

2
01
cm
R
lbR
Fa
a
===
α
@#$fFφ2F4"'p4*?><)
3
J48*3DCB>3
-)4i"w'%x4.H
]
h*3DCB>3k<>DC 22< 33 3?*33<339:
-1yx4xa
@#$4φ?ST
-1%IH78






==
≤
180
150
2
300
2
h
KT
@#$4[φ?42;<
Sinh viªn: Vò Hång Quang - XD 502
2;
Đề tài: Chung c Vạn Phong
2. Tính bán dầm chiếu tới (220 x 300)
a) Xác định tải trọng8
J/1[1l()
V

*32<<9<>D=<>33:=2>2*2C3>F?9G):
J/1[le'$i"8h$v
3
4"i1
[li"'
3
G
2
*3>?*<>;?3
V

*= V

2
*<>;?3=KK3=2>CF*;3CG)
@#$&1[l8
V*V

5

*2<<?>C
/1[()$i"'7#>#v3
()$i"4)(A4 /42#XA4
8
O*3


3,2190
2
424,3
.7,639.2
2
365,1
22
==
+
@'g^N(e]()eq
* Sơ đồ tính8
d()()euuuuN3(/
3
8

*D>?J<>22J<>2C*D>DF9):
Y)I'Hl$4N()8
Sinh viên: Vũ Hồng Quang - XD 502
2B
3600
300
220 220
V
3
G23V
3
G23
V
3
G;
§Ò tµi: Chung c V¹n Phong
)/(8,3601
4
6,3*3,2190
8
6,3*5,1006
45
22
mkg
plql
M =+=+=
,a'H78
)(2,2359
4
3,2180

2
6,3*5,1006
42
kg
Pql
Q =+=+=
* TÝnh cèt thÐp8
[4*F)
251,0211
22,0
26.22.110
360180

22
01
=−−=
===
A
lbR
M
A
a
α
@#$8
)2
01
(6,6
2100
26.22.110.251,0

cm
R
lbR
Fa
a
n
===
α
@#$4fFφ2F"'p4*?>?9):
J48h*3DCB>39:
J-)4i"w'.Hj]
h*3DCBk-
<
=Q
2
= 
<2
*<>DC=B<=33=3?*2;<2;
-1yx4xa
@#$[4φ?
-1%4IH78





==
≤
180
150

2
300
2
h
M
ct
@#$[4φ?42;<
b. DÇm linon (èng thay: (100 x 300) (2)
* Tæng t¶i gåm t¶i träng b¶n th©n vµ t¶i träng do b¶n thang truyÒn vµo.
5/1[1l

2
*32<<=<>2=<>D=2>2=<>;K?*?<>K9G):
@'?α*<>;K?
5/1[14$i"
)/(5,62136,753*
2
65,1
mkgq
S
==
Sinh viªn: Vò Hång Quang - XD 502
3<
§Ò tµi: Chung c V¹n Phong
* S¬ ®å tÝnh8
@'
0
81,2855,0
3000
1650

=⇒==
αα
tg
* TÝnh cèt thÐp8
Y)I'HA48
[4*D)⇒
<2
*D<JD*3K9):
)/(7,999
8
)424,3(*2,682
8
22
mkg
ql
M ===
15,0
27.10.90
99970

22
01
===
hbR
M
A
n
c)
91,0)211(5,0 =−+= A
γ

@#$
)(94,1
27*91,0*2100
99970
cmFa ==
@#$4=%48
* TÝnh cèt ®ai8
-)4%7eI.H
]8
h≤-
<
 Q

  
<2
Sinh viªn: Vò Hång Quang - XD 502
32
φ23
φ2?
3,424
3000
1,65
28,80
0
§Ò tµi: Chung c V¹n Phong
)(9,1167
2
424,3*2,682
2
kg

ql
Q ===
Q

  
<2
*;C<C
⇒/1)g
-)4%)ax4
22?K>Bk<>?=K>C=2<=3K*232C
@#$4g1)g
4X8z

≥)92;<RG3:
@#$[4φ?42;<
b. DÇm linon cÇu thang 18
@'8
0
8,2855,0
2
1,1
=⇒==
αα
tg
⇒α*3;>;2
<
*<>;K?
+ TÝnh t¶i träng8
J/1[1l


2
*32<<=<>2=<>D=2>2=<>;K?*?<>K9G):
J/1[14
V
2
*KCD>D?
/&18
3,8897,606,828 =+=q
- TÝnh cèt thÐp8
Y)I'HA48
[4*D9):
⇒
<2
*D<JD *3K9):
Sinh viªn: Vò Hång Quang - XD 502
33
220 m
2,0 m
1,1 m
3;>;2
<
§Ò tµi: Chung c V¹n Phong
)(01,0
27.95,0.2100
53800
95,0)211(5,0
08,0
27.10.90
53800

)/(538
8
)2,2.(3,889
8
2
22
01
22
cmFa
A
hbR
M
A
mkg
ql
M
n
==
=−+=⇒
===
===
γ
@#$[8φ23^p4*29)
3
:
* TÝnh cèt ®ai8
)(23,978
2
2,2
.3,889

2
kg
ql
Q ===
-)48
h*BKB>3Dk<>DC=B<=2<=3K*;C<C9:
⇒/1)g
-)41ya
h≤
2
 Q

 J
<2
*<>?=K>C=2<=3K*232C9:
⇒@#$1)g
@#$4Xφ?42C<
c. TÝnh dÇm D
1

* S¬ ®å tÝnh to¸n8
@'8

*D?<<J2C<J33<G3533<G3*DFC<9)):
Sinh viªn: Vò Hång Quang - XD 502
3D



*D>?) *D>?)

<>C <>C

3

3

3
Đề tài: Chung c Vạn Phong
*D?<<J2C<J2C<*DD<<9)):


*D<<
@8

*
3
J
22
1
2
Sdbdc
+
b. Xác định tải trọng8
/4H$()N1A4)7]% d()1
[li1$i""[_1l()

* Hoạt tải:
L71$i=()_]v341$i=
)/(5853.
2

195
2
195
mkgP =






+=
* Tĩnh tải8
*


2
5
<
@'
<
*9

J

:=2=32<<=2>2
*<>39<>D?J<><;:=2=32<<=2>2*23B>F



2

*D<F=D*B23
*B23523B>F*2<F2>F9G):
V*O5
<
*C;C52<F2>F*2?3?>F
Sinh viên: Vũ Hồng Quang - XD 502
3F

2

2
d()4=

O


§Ò tµi: Chung c V¹n Phong
c. X¸c ®Þnh néi lùc8
Z%bI\s{"i%7
h
S
*<>F V

 

*<>F 2?3?>F D>FC*33FF>F
h
E/
*J<>? V 


 

*J<>? 2?3?>F D>FC*JDD?C>;
h
E
*h

*<>CV *<>C 2<3?>F D>D*3?;D>C
@'b4))I]I.8
Y*β V 
3
Sinh viªn: Vò Hång Quang - XD 502
3C
0,5l 0,5l
0,425l
b
k.l
b
1b
Y
h
∆
h
EO
h


E
h
E/

*<>?