Bài tập trắc nghiệm hàm số mũ logarit 20162017

2-GT t2
2016

chofdm.6

a'
C'

.v

-logro

x

po thi hdm

*naffir[u-r,,
ngang.
dinh]

s5 da cho kh6ng c6 ti6m
c6n
Hdm sd da cho dong bi6n
,,€n tap x.,c

,

I

0

Dg thihdm

.!

l:

s6 da cho nhfln rruc Ox

l',H;::;:l

ldm ti€m , ^

(tr\

\l

IJ i

B.

A')--lri -tlJ

s6 da cho c6

logu a

y = Q_,
,;

=log,,l

B.r=-log,x

*ur r,e- cfn dung rd trpc
e;.

b
x.

tog" .i,

HT,::T,'I:Tff',1:i.::H,#
a < 1
x6c dinh

.oui'o'o*'

b

D.

cr=,,Jll

' {'.

Iog,a>log.

{-tiu 7:

( :irr

cho ham s6

-v

=

i

l

I], Inx>0<+x>l

;'-€ ' Hoi khing dinh ndo duoi

,ti.".'#"".
iii, .i, ,**,

$:

A'J' :

b*o
logra
d6y ld khang dlnh dring?

hAm s6 da
rQr ti6m c6n ngung ua kh6ng
"ho::
c6
ti6m cfn dimg.
thi hdm so dd cho urong .J
thi hdm s6 da cho tf,r ,g .O
vd
mQr tiem c4n dung.
rhi hdm s6 da cho ..o. *Qt tiOr,,
^co

A. D6 thi

B. Di
C. D6
D. Do

B"

log., e <

.an

,euf! ,u *Ot

ti€m c6n drnr.

*,?lHt;"JilrlllB:'.:g;;i;;'';a' 'JffiT;;Tf;

hdm so duoc ridt

xo

s.y -- *fi
C,y=,u
D. 1t:Y'
ci* 9: , Euong cong o hinh b6n ii d6 rhi cua

s6 trong b6n hdm s6 ducrc
li€t k6
Tj,l:*
o J"oi aiv]uu,
ao rd hdm s6 nao?

o b6n phucrng 6n A, B, c,

A.y = 16
x.
B.Y =7ogs

C.y:

'

D,V:

log.,-,

x

1

(6)'

Clliu l{}:

Chox)0,vi6tbi6urhuc

5

I

A, X'

dudi dang cria mQt stl vdi sfi
mu hiru ti. Chon drip rin dring.
9

B. xi

C.

!!
Ciu I l:

Cho

a

tdsii thpc duong. Rrit gon
bi6u thuc

xi
/z

a3 ba

__l
4

*3,

a-b

H6i

A- n
!
xe

3b4,)
'rr"rl

l,'u
, =" !," tl,V'r-o
3 r
I )\
ot6tl aib-l *o-if

\)
{'. a+b

D.

_!1t\

ta

.7-

,\r. a2 -bz

I < log,

,-,
D'
]=-3lnx

(Iiu 6: chqnkhingdinhsairrongc6ckh5ngdrnhsau: [:i

.:." logx<0c>0
7 = r( \ {0}

d6 sau, mQnh da nao o,ingz

D. tog, (*.y ) =log"

g::ffi*;nsans

6.^ lnag.0( l;i * 5: HAm s6 ndo sau
d6y d6ng ulan oer-iap
/,

B. Hdm sti da cho co t4p x6c
dinl ta

o. po tiri him

*1 vit x,.1, rd hai s6 duong ;;:;:'-rnh

:'-:::tvbu'r.l_',j*::;r
D'
,l- lwj
c. log, (, u y) = iogn x + log, y
(."f,u -1: phat Ui6u nio sau
d6y sai khi n6i vC ham s6

A.

- 2017

ducy.

c ktit qu6

;

l

li. b -a

e


16 toan -

THPT TrAn
_3

_l

l?: Tim di6u kiQn cira a.biCt (2*a)i .12- olt
A.08.1C'lirr

Ciu l3:

Cho

log.r=j ,u log b= j *'do.

A,3

ab'

log.

.tr

B. t2

l'1r

Clu

Cho

m>0,

m

*! ,

I

bgo,,3mz = a

,

a>2

C.

lop.2 = I

nhAn gi6

D. a>)
tri bing?

c.6

D.4

Tinh log. m theo a ya

b.

D

A_2a-b

o-b

B.

('iu IS:

^
L_

1-a

b-a

t'.8a-4

i,lR.l
2+e

i'.

2-a

l7:

TAp x6c dinh cria hdm s6

A. R\ {ln3}

C.

2+xi

l

i),

2(1-a)

(1;+oc) \

D. (0; +oc) \ { ln 3}

{ln3}

lir:

B. (0;+"c)

'* I
" = ln(x
+i)

I9l

D4o hdm cua hdm s6 ,,

l{}:

TAp x6c dinh cua

ln-(x+J)

him s6

A. D=[-3;5]

r].

-}.

C. [0:+rc) \ {2}

D. (l,+cc) \ {2}

^ l-h(x+l)

D.

ld,

ln(x+l)-1
D
D._-_-

I

,n1**,t

Cf,u

I

2(t - a)

fa'

B. (-co;l)

T4p xdc dinh cua hAm s6 .r'= iog__r

In(x+ l) -

^^

= ? ;* fn [:1]
\t-x,/

y

l),8a+4

l

Cin lll:
A. (l:+co)
CAu

2-a

Ndu a=log5 thi log925 6;n*,

q.. 4a
It. 4a +8
-8
Citr 16: Cho a = Iog,r 3 . Khi d6 logr, 15 bing:

Ciiu

Za-b

D

1-a

ln- (x + l)

= logj

r=R\{s}

_1

ln(x + 1)

[#),,
_3

C. D =(_-"o;

f

t,

{5; +"o)

D.

r=(-3;s)

Ciu 2l : Hdm s6 v = (n' - 3)-' c6 r4p x6c dinh ld:
.'{. D

Ciu

,{.

=(*,-€).(.6;*)

"

22:

Gi6 tri lon nhAt cira him s6

1

Cho a=log3 ; 6

CAU 2.1:

3fi-q\
A,.2{:

Ciu

"
(liiu

25:

8

ln

tr6n do4n

'

C.

,=a
jt\

B. 'y'=

3(t +b)

a+b

l-2xln2

A

C.y'=

(2x-5)ln3

Tinh d+o him cia hdm s6 -y =

lzx-sltn:

log€ (x,3"
r 2.2r-l

+

l)

2'

B.

'

(--co:

ii

2'I

I). 4+81n2

$.

3(r

-p)
a-b

D.

2xln2-1
4'

I

/12.,

-1r"3

.

(xln3+1).32'

C.v'=+
' (*3" +t)tnJz

27t Tdp nghiQm cria b6t phuong trinh logro(x-4)+1>0
1?

r{.5}

ta:

-v,

2\'
Tinh d4o hdm cria hdm s6 y = logs
lZx -Sl

3 +'+x.'5
B.v'=
' (*.3'. +t)tnJza. r+:!t
'

[t;e]

D. D =n

.

o l-2x1n2

r2t

CAu

x

D.-

(2x-5)ln3

26:

! : x' -

D=f ,/-l:l
(l

fr. e2 -g
{1.4-81n2
:1og5 . Khi do 1og,, 8 bing:

Tinh dao hdm cua him s6

A,:l-xln4
2"

{..

{-.6;.6}

3(r -b)
-lt';;'

a+b

( iu

B. D =,t

c.

D. v,=

'

ta:

t?r+*l
'2

HQi An, 05112/2016

D t+;ilt
' 2"

(xln-81 +

(x.3"

2)'3"
.

+ 1) ln 2


6n t$p chuong 2 -GT

2lt:

Clirr

Phucrng

lq:

iu

trinh 41.' +4r-' = 10 co:
B. Hai nghi€m Am

T4p nghrem cua

bit phuong tri"h [ 1] .

C. Hai nghiQm trrii d6u

ll
\.5, 12,)

A. [1;+.o)

(liu l{}:

Nim hgc 2016 -2017

dumg

A. Hai nghi€m
c

12

B.

"

I

,u,

D. .x

C. (--cc;-1]

[-l;+co)

Sii nghiQm cuaphuongtrinh logr(9 -2')=l0ro8(r-tr) ld'

c.

8.2

AO

3l:

("iiu

D. V6 nghiQm

+.o;

Gi6 tr"i lon nh6t. nho nhAt cua hiim s6 y = xe-' tr0n [0,

A

Hirm s6 khOng c6 gi6 tri 1on nhAt, gi6 hi nho nhdt cua him sri

r

o;-e

C

-:0
e

D.3

1

bing

IAn

luqt ld

:

f
e

1

uing

D. Giatri lon nh6r cuahirm sti

I

. narn so

ttong

co girl tri nho nhdt.

e

32:

C-irr

Tap nghi€m cira b6t phuang trinh sau 21og.(4x-3)+log, (2x+3)

j

('iu ,13:

1

" I*,:l

3
A.(-;+-)

c. (::3'l
'4

trini

T4p nghidm cua b6t phuong

( 3 li:

D.

v6 nghigm

(*' -Sr-O)> -3 li:

1og,
2

t.l-2;tl
3-l:

Ciu

,r.

.\.

GiA tri nho nhat cua hirm

ln10

('iu.15:

+x

..i''[f]

\,6,/

36:

(liu 3tlr Gqi

D.

ln40

-.6

r).

.6

fa,

rrinh (2 *

.6)' .

(z

n. [-+;-:)u(o;t]

-+6)'

ru,

Cho b6t phuong trinh

l"*-1
A.(*)e]"'
' '- Ilr*tlCiu .10: T4p x6c dinh

D=(3;+*)

f

a

: log"

lx +

1l

+ 1og,,, (x

i.i,irg linf-, itung

Daohirmcuahims6

y

-

D=(--*;*)

n.-6

ta

fx+-r
c.(*)<+lx-2,0
|.lr*),> r+2
:

C.

D=(*;3)

4l3x

+2

D.

D=R\i3|

y= llgS +n*++ n

!lr.'=---L'

Id:

?

sri y =(*' -Ox +e)f

B.

x,

+2) > 0 (*).

[x+2>o
B.(*)ei
' [lr*licx+2

cua hdm

khi d6 tich cua x, vd

c.l

a
.1.

o. (a;+rc)

C. (--o;-a]

ts.6

Hoi khang dinh ndo duoi d6y

Ctu41:

ld:

)x, Iit hainghiQm cria phuong trinh 22'*3 -33.2' * 4 :0,

A.l24

39:

(x' + 3x) < 2

n. (-+;+o)
xr

ta:

2_l

T4p nghiQm cua bAt phucrng

a (*;-a)

(-2;-1)w(6;7)

t:. (--co;-3)t,(0;+*)

n. [0,1.l

(

r].

c. h2o

C.

Tap nghiQm crla b6t phuorg trinh log,

[-2;-1)

_2) tren do4n
[:lO]

J

au -t /:

A.

h (.t'

B"6

I

CiArr

:

Cho hirm sO y = 61r1r.,x). KhiaO

r. (0;t]
t

so ,

-24

B.

-3

Ciu

c.

*. [-2;-i)r-,(6;z]

{ r.'=-L

z{Q*-z)'

:{(:**2)'

HQi An, 05l1212016

x! t''1--:

t'l3x

+2


t6 to6n - Trulng THPT
i iu -ll:
a

.r
Tinlr dao hirm cua hirm so -9"
=

totl-l
.

B.y'=- sinx+2(cosx-1)ln3

J

,

sinx-4(cosx-l)ln3
J

Cho so thuc

ciiu
.r.
Ciu

.{4:

10

t4. 12

TapnghiQm cuaphucrngfrinh 21ogl

-

{.,6,a}

(lAu

46:

tl

I+4

( t-t
tl. I 0:t

I

Clu 47:

t
loglx
Goi

x,

P""9

Ciu'{8:

ld:

{-2:8}

Chophuongtrinh igg,2

!).

{.tr;6}

ri

f1,e'l
\3 )

h:

t " (o;e]

l

3_l

o=lt6

t). 13

;x, ld hainghiQm cuaphuongtrinh 32'*4.3"r +27 -0.klidri

l')

f,oa,

(.11

x-14logox+3=0

{;,}

T4p nghiQm cuabAtphuongtrinh

[1".l

D.a=16

C.a=64.

256

si6t 64' +64-' = 1 19. Kri do 23' +2-3' bing',

45:

r 4x

J

a, bidr lOg, a.lOg.o a =32.

a= 1 .B.a=76.

A.a=256troac

sinx-2(cosx-l)ln3

D,y' =

*

-

( ritr {.1:

!

Tp HQi An

.q \

L'.i

.

-

sinx- 4(cosx-l)ln3

-.'
,

,.

TrAn Qriy C6p

c.3

\+x2

lirl

u.6

x-mlognx+m+J:S.TimtAtcac6.916tr[ cuazd6phusngtrin]dachoc6hai

2

nghiQm phAn

bi6t

xr

,r,

sao

* x, > 2
g. m>2

cho

t. m> -l

-tr,

Ciu4tir Timm phuongtrinh 4'-2m.2'+2m=0
It.

m

D m>0

C. m>0

=3

cohainghiQmphAnbiQt x.x2saocho x,+x" =3
L\. m=-2
tl . m=-1

5(l: Tim c6c gi6 tri cua zr d6 phuong ,rlnt.,, J3' +l + S= m co 2 nghiQm phAn biQt:
g2A
D. ..6".6

c.m > 2Ji
L.z.,fzCftrr

Clirr 5l

:

Tim tdt cit

citc gi6

tri thirc cira tham s6

z

sao cho phuong

trinh

1og,

{-r'

-3x -

rn + 10)

biOt, tr6i dAu.

B.m<4.

A.m <2.

Ciu

52:

GiA su cri sau m6t n6m diQn tich nmg cua nuoc ta
cta nuoc ta sE li bao nhi6u phAn diQn tich hiQn nay?

r

r

--\a

C,m>2.
giim x phAn trin:

=

3

c6 hai nghiQm thgc phAn

D. m>4.
diQn

tich hien co. Hoi sau 4 nim diQn tich nmg

;4

D. 1-4'
B.r-[1]
c.100%
a..lr--i(r00,
100
I r00,
Ci u 53: MQt ugudi gui I 5 triQu ddng vlo ngAn hang theo Fti :h"" 16i k6g d$h k ' k} hen mQt qqf, vdi I6i sudt 1,65% mQt quf.
l

H6i sau bao hu ngudi d6 .6 d.rr.. it ntr-At ZO triQu ddng (ci v5n 6n ldi) tt si5 viin ban tliu? (Gin st ldi su6t kh6ng d6i)
Siist the thirc l6i t
tt eo dlnh lci h n6u d6n ki h4n nguoi gui khdng rut lii ra thi tiAn Ei tlugc tinh viro v6n cria ki k6 ti6p.
"p
D' D6p 6n kh6c'
C. 4 n6m 3
B, 4 nim I
A. 4 n[m 2
C6u 54: dog a.uuy ngin h4n ngin lring iOO trieu d6ng,.l6i stdt 7zYoln5rm. Ong mui5n hoin ng cho ngin hang theo cich: Sau
ilung mQt th6ng k6 tu ngay vay, 6ng bit dAu hodn ng; hai lan noin ng li€n titip c6ch ntqu {u+g mQt thring, st5 ti6n hoan no d m6i
ngdn hang
lan la nhu nhau vd trn hiit tiAn ng sau dring 3 th6ng k€ tir ngdy vay. H6i theo cich d6, s6 ti6n ,?, md 6ng A sE phii
gian
A
hoan
ng.
6ng

thay
tt6i
trong
thcri
hang
khdng
tong m6i lin hoan ng li bao nhi6u? Bitit ring, l6i sudt ngdn
100 x 1.03
g.,,

quf

qulf

quf

ti

A. n1

: --- -J-

r20
C.m=+

(r, l2)r

(1,r2)'-l

(tri6u dong)

=

(trieudong)

D.

ilf-!
(1.01)' - I

(tri6u d6ng)

m -1oo'(1,01)3
3

=-#
HQi An,0511212016

(triQu d6ng)