~Bo tr^kien
tlsiic Vat li L mil l,<^n kenh
VTVZ
t$p 2 - Chu VMn
Bien
Cty
T.
lOOVS
T
100
7(R + R o r + ( Z L - Z c ) '
=> Chon B.
^,
,
i, va i2.
V i d u 5: D a t dien ap u = 200cosl007it (V) vao doan macii noi tie'p g o m dien t r o
R = 100 Q, t u dien co dien d u n g C = 15,9 |.iF va cuon day tliuan cam c6 d o tu
!C : vm ):y.i<\.> iJ'^:
A. (pi = 71/6 va (p2 = - 7 T / 3 .
do d o n g dien t r o n g mach som pha so v 6 i hieu dien the'gii>a hai d a u mgch.
B. L i = 1/71 ( H ) va i = V2 cos(100Kt + 7r/4) ( A ) .
,^
-
= Ul
c o s cp =
''"'^ ' A
; / -*f*;
^- '
C. L i = 3/71 ( H ) va i = cos(l OOTrt - 7r/4) ( A ) .
C. L i = l / 7 t ( H ) v a i = V2cos(1007it-7T/4)(A).
Huang
„
P =
2
(p=>100
CDS
100-.2
=
t....
dan
.
R
- cos
(p :
•-
'••'MA-'
7T
„
.73 =
cos(p2 _
COS(P|
.3 = - ^ =
COS^
(P2
COS
COS^
(P|
cos(p|
-sin(pi
' (pj =
COS(pi
(P2
^
r-
^
4 =^i = V 2 c o s
=>L = - H => Chon B.
1007rt + - -
(A)
'
,
. ^ « p ,(,ji
tan so 50 H z . Ban dau d o lech pha giira dien ap giCra hai dau mach va d o n g
dien la 60" t h i cong suat tieu t h u trong mach la 50 W . Thay d o i C de dien ap
giira hai d a u mach c u n g pha v a i i thi mach tieu thu cong sua't la
U'»i(b./t
2
P = UI cos CP = — c o s ^ ^ > = ^ ^ =
R
P|
C. 5 0 W .
Hitoitg dan
'
'
•
D. 120W.
•,,U.l>l' -
ri J i}i f T O ^ ri'>i>m 'fia'".,
song v o i t u d i e n C i thi d o n g dien trong mach la i2 va cong suat tieu t h u la
P2. Biet P I = 3P2 va ii v u o n g pha v o i i : . Xac d j n h goc lech pha cpi va (p2 giua
^ P2 = P,
cos (pj >•• • <.•'•
cos"
= 200 (W)
,,,,
U
P = U I cos(p = — cos^ (p
_ c o s ^ , _ -siiif/?!
Chon B.
IP|
. «
COS c/>|
cos ^,
P,
p2
• o = —
G2 = C i + C ' = 5C, : ^ Z c 2 =
1
1 ' , i * ^'
B. ( p i = - 7 t / 6 v a ( p 2 = Tr/3.
'•901 •
=
. ^„|
dan
cos^ (pi
^..2
C O S (p2
,5 ] "
COS(p2
1
tos(p,
V3
—
n
>^1 =
=> Chon B.
V i d u 9: Cho mach xoay chieu g o m cugn day k h o n g t h u a n cam co d o t u cam L,
dien tro r mac n o i tie'p v o i t u dien ccS dien d u n g C thay d o i . D i e n ap 6 2 dau
doan mach u = U V2 cosl007rt V. K h i C = C i thi cong suat mach co gia trj la
240 W va i = I V 2 sin(1007rt + 7t/3) A . K h i C = C2 t h i cong sua't cua mach cue
cos" (p
vai dicu kicn (p^±(p.,=a
hi tiiili duvc cik dqi limn<^ khdc.
cos- ^1
dai. Xac d i n h cong sua't cue dai do?
A.300W.
V i d u 7: D a t dien ap xoay chieu o n d j n h vao hai dau doan mach g o m cugn day
B. 3 2 0 W .
'
C. 960 W .
mcich la i) va cong sua't tieu t h u cua mach la P,. K h i C = C2 > C i t h i d o n g
di^n t r o n g mgch la i j va cong sua't tieu thy la P2 • ^^'^^ ^2
3 P i va i , v u o n g
D. 480W.
Huaitgdan
noi tie'p v o i t u dien c6 dien d u n g C thay d o i . K h i C = C i d o n g dien trong
60
' ' ! ' ( ' . •
D . (pi = -7r/4 va (p2 = 7t/4.
Huang
yj3
if;tb , D ' j ^ i •
2
Chiiy:
Kcl hap
}(••
noi tie'p v o i tu dien co dien d u n g C i . K h i d o d o n g dien t r o n g mach la i i va
C. (pi = 7i/4 va (p2 = - 7 i / 4 .
va t u d i e n co dien d u n g C thay d o i dugc. D i e n ap d a t vao hai dau mach c6
B. 2 0 0 W .
I • y-i"
V i d u 8: Dat dion ap xoay chieu on d j n h vao hai dau doan mach g o m cugn day
dien ap hai dau doan mach v o i ii va i2.
V i d\ 6: Doan mach xoay chieu g o m dien tro thuan R, cugn day t h u a n cam L
A. l O O W .
= V3
71
=> Chon C.
A. tpi = 7 t / 6 va (p2 = - 7 i / 3 .
tan cp =
ui u
cong sua't tieu t h u cua mach la Pi. Lay mc)t tu dien khac C = 4Ci mac song
cos"(p=>(n = —
R
too
P = I - R ^ 1 0 0 = I-'.100=?>I= l A
M -
-''^ '
' ' 'p'
.'iK/I
C o > C i = > Z c 2 < Z c i =>(p2 - 'PI = T = = ^ ^ 2 = 9 l +
^
Vtft
r.
Huang dan
.Vv
Gia t r j L i cua cuon cam va bieu thuc c u o n g d o d o n g dien qua mach dirge
xac d i n h
'^^'•^
.A I g n s j b ti^- B. (pi =-7r/6 va (p2 = 7i/3.
C. (pi = -7t/3 va (p2 = n/6. •fi^iikf.U> v.
cam L thay d o i d u g c . Biet cong suat tieu thu cua mach la 100 W va cuong
'' '
MTV D vvniihang
pha v o i i2 • Xac d j n h goc l§ch pha cpi va
V'^ +(Zi.-Zc)
A. L I = 3/7r ( H ) va i = N/2 cos(1007tt + 7i/4) ( A ) .
Timn
P = _ c o s 2
=>240 = P,,„g ha<.ng
•Pc6„gha(,nK=320(W)=>ChonB.
2
.. .final} i=fy.^
^
^
iJi'if
61
Cty
B S trp kiSn
thitc
V^t It LTDtl
tren
kenh
VTV2.
t^p 2 - Chu Vitn
Blen
Huang
V i d u 10: T r o n g m o t mach dien xoay chieu g o m m o t d i e n t r o t h u a n mac noi
tiep v o i m o t tu dien. D i e n ap hieu d u n g dat vao doan mach la 150 V, d o n g
dien chay t r o n g mach c6 gia t r i hieu d u n g 2 A . D i ^ n ap h i ^ u d u n g g i i i a hai
ban tu d i e n la 90 V. Cong suat tieu t h u ciia doan mach la
A. 200W.
B. 1 8 0 W .
C. 2 4 0 W .
= U K + U c =>150
=UR+90^
^ HV7:)
D . 270 W .
Huang dan
U
'
doan mach g o m tu C n o i tiep v o i cuon day t h i dien ap hieu d u n g tren t u la
100 V S V va tren cuon day la 200 V. D i e n t r a t h u a n ciia cuon day la 50Q.
C o n g suat tieu t h u d i e n ciia doan mach la:
' ''
"
C. 120 W .
Huang
tancp =
DVVH
Khang
Vipt
dan
= 200(Q) ;
U
= tan - => Uj =
6
Uc = U , = H ( V )
U ' = U?+(U| -Ue)^ = 1 0 0 '
V i d u 11: Dat m o t d i e n ap u = 100 V2 coslOOnt (V), (t d o bang giay) vao hai dau
'
coC
MTV
U,=100(V)
H
UR =120(V)
B. 100 W .
=
,
P = I^R = I . U K = 240 ( W ) =^ Chon C.
A. 150 W . = ' ;;
Zr
Tisnn
I =
Zc
2V3
1
P = l'r =
•t)
^ r = ^ = 200^/3 (Q)
1
= -V(A)
.200V3 * 28,9(W) => Clion B.
V i d u 14: M o t mach d i e n xoay chieu noi tiep g o m tu dien c6 d i ^ n d u n g C, dien
D . 200 W .
tro t h u a n R va cuon cam t h u a n c6 cam khang 80 Q. D o Ion he so cong suat
dan
ciia doan mach RC bang he so cong suat ciia ca m a c h va b a n g 0,6. D i e n t r o
t h u a n R CO gia t r j
B.30(Q).
A . 50 (Q).
=> 100^ = 200^ + 3.100^ - 200V3.UL
U, =100V3
[ U , =100
,
=>P = I r = — ^ = 200{W)=>ChonB.
r
"
^''
d a u doan mach RLC no! tiep cuon day thuan cam c6 L = 0,l/7t H t h i tli
d i e n ap hieu d u n g tren t u va tren cuon day bang nhau va bang 1/4 d i e n > ^
hieu d u n g tren R. C o n g suat tieu t h u tren mach la
B. 1 8 0 W .
-
R
COSCPKC =
: = 0,6
Zc =0,5ZL =40(Q)
R = 30(Q)=:>Chon B.
= 0,6
=U,
D. 120W.
• Z'^^^i^J
a hai dau t u d i e n 120 V. H e so cong suat ciia mach la
A. 0,125.
B. 0,87.
C. 0,5.
Huang dan
U2=U^+(UL--UC)'_
Mach cong hUdng => I = —
p = I^R = — = 360(W) => Chon A.
R
•
' *
^
'
C = 0,1/K (mF). Dat vao doan mach dien ap xoay chieu u = 100 V2 cosSOnt (V)
thi thay d i e n ap g i i i a hai dau cuon day sam pha h o n d o n g d i e n t r o n g mach
la 7t/6, d o n g t h a i d i e n ap hieu d u n g tren cuon day gap d o i tren t u dien.
Cong suat tieu t h u ciia doan mach la
B.28,9W.
C. 240 W .
^c=^la=^l+^i
coscp =
/f
d u 13: M o t doan mach g o m cuon day no'i tiep v o i t u d i e n c6 d i e n d u n g
A.200W.
( r i ' r i ' j i b i<:
V i d u 15: Mcich dien xoay chieu gom cuon day mac noi tiep v a i t u d i e n . Cac
R = 4Z| =4coL = 40(Q)
M
dan
dien ap hieu d u n g 6 hai dau doan mach 120 V, a hai dau cuon day 120 V va
C. 1440W.
Huong dan
R
coscp =
^ R 2 + ( Z L - Z C )
d u 12: Dat m o t hieu dien the xoay chieu u = 120>/2 cos(1007rt - n/6) V v i .
A.360W.
Huang
if!>
D . 100 (Q).
C.67(Q).'
D.57,7W.
U
U
'I'lOr i . : '1 , t j - ,JS +
jl202=u|+(UL-120f
ll202=U|+u2
;
= 0,87^
'
D . 0,75. '
Chon B.
'
M i , , ,
. .viLi'
|UL=60.1:?
U K = 6OV3
«'lU f!;,Ue
,<,.-i:„,,
. „
,
,r,,j.-.
^--.^^•5!•M,.=•'I •viuVVv'^(;'')!\
V i d u 16: M o t d o a n mach dien xoay chieu RLC k h o n g p h a n n h a n h , cuon day
c6 d i e n t r o t h u a n . D i e n ap hieu d u n g g i i i a hai dau doan mach, tren d i e n tro
R, tren cuon day va tren tu Ian l u g t la 75 (V), 25 (V), 25 (V) va 75 (V). H e so
cong suat ciia toan mach la
A . 1/7.
B. 0,6.
'
C. 7/25.
W'tKH
D . 1/25.
i-
63
B o t r pk i c n thiic
V^t l i LTDH
t r e n kenh
VTV2.
t a p 2 - Chu
Huong
U- = (UK +
+ ( U , - U^.f =
Vdn
CtyTNHHMlTVDVVtlKhang
Bicn
dan
A. 5 a.
B. 10 n hoac 200 Q.
C. 15 Q hoac lOO Q.
D . 40 0 hoac 160 O.
•;,d ii hh V/ Oi.«,) >; «!•(•' r'^•.f
Z, =coL = 2 0 ( n ) ; Z e = — = 100(Q)
wC
7 3 - = 2 5 ^ + 25-+ 2 . 2 5 . U , - 2 U , .75 + 75f U , =20(V)
Up + U
[ U , - 15{V)
,,i
^ \
•
U
'
•
•
( ^iJ
,1
P = 1'^R =
"
*•
»
,
,
-R =
R = 40(D)
- 200R + 6400 = 0 :
200r2R
R^ +(20-100)^
400 =
R^+(Z,-Zc)^
R = 160(Q)
V i d u 17: D o a n mach dien xoay chieu mac no'i tiep g o m tu ctien, dien t r a t h u a n
Chon D.
^
>iH
va cuon cam t h u a n . D i e n ap hieu d u n g 6 hai dau doan mach va tren cuon
V i d u 20: D a t vao hai dau doan mach m o t dien ap xoay chieu co gia t r i hieu
cam Ian k t o t la 360 V va 212 V. He so cong sua't cua toan mach coscp = 0,6.
d u n g 200 V . D o a n mach g o m cuon day co dien t r o t h u a n R co cam khang
D i e n ap hieu d u n g tren tu la
A. 500(V).
! , , . , , . , , A , , r.:
^
.r^:' m
cos(p = ^
B. 200 (V).
-O'
.
^
C. 320 (V).
"
'
^
= 0,6=^U|, =0,6U = 2 I 6 ( V )
-
"
S
,
D. 400 (V).
,
,
,,5,^
„
140 Q. mac n o i tiep v o i tu dien co d u n g k h a n g 200 Q. Biet cong sua't tieu t h u
tren mach la 320 W . H e so'cong sua't ciia mach la
B. 0,6 hoac 0,8.
A. 0,4.
Huang
ill
>,n,'r*^nit\ (bi
U - = Uf, + ( U | - U^.)^ => 360- = 216- + ( 2 1 2 - U(.)- ^
Z, =a)L = 140(Q);Zc =
P = 1^R = - ^ R =
V i d u 18: Doan mach dien xoay chieu mac no! tiep g o m tu dien, dien t r o thuan
mach va tren tu Ian l u o t la 300 V va 140 V. D o n g dien trong mach tre pha so
voi dien ap hai dau doan mach va he so cong sua't cua mach coscp = 0,8.
C. 3,2 ( A ) .
D. 4 (A).
Humtgdan
U- = Uf^ + ( U | - U e ) " ^ 300- =240- + { U , -140)- =>U|
= 4 ( A ) ^ Chon A.
R
"''t'.
=320(V)
^'5'"
.
.
= 0,8
•ChonB.
!r:,M
V i d u 21: D a t vao h a i dau doan mach m o t dien ap xoay chieu 100 V - 50 H z .
I/TI ( H ) va tu dien co d u n g k h a n g Zc. Biet cong sua't tieu t h u tren mach la
100 W va k h o n g thay d o i neu mac vao hai dau L m o t ampe-ke co dien t r o
k h o n g d a n g ke. Gia t r j R va Zc Ian luc^t la
A.40i^va30Q.
B. 5 0 Q v a 5 0 Q .
u = 400cos(1007rt) ( V ) . M a c h AB g o m cuon day co dien t r o t h u a n R co d o t u
cam 0,2/7: ( H ) mac noi tiep v o i tu dien co dien d u n g 100/K (HF). N e u cong
: ..
U^R
100^ R
p
R'^ + Z,c
rZc=50(Q)
R = 50(Q)
C. 3 0 Q v a 3 0 a
R^+Z^.
D . 20 Q va 50 Q.
dan
100-R
'""""R^ + (Z,,-ZC)^
.
V i d u 19: Dat vao hai dau ctoan mach A B m o t dien ap xoay chieu:
sua't tieu t h u R la 400 W t h i R bang
- 125R + 3600 = 0
= 0,6
Huong
•
R ^ + ( Z , - Z J -
•
+ (140 - 200)^
Chil y: NCni hict cCm;^ siid't tiC'u thu trcii toan mach de tinh dien tnr Iioac cos(p ta
dim vao con;^ thu'c: P = l~R =
R^ +(140-200)^
D o a n mach mac n o i tiep g o m dien t r o t h u a n R, cuon cam co d o t y cam L =
Z, >Z^-=>U| >Uc;coscp = - ^ = 0,8 =i.U|, = 0 , 8 U = 240(V)
^
Zi
D . 0,75.
;7t iJfi? v/.ni I f i u a ^/.no'j t'>::ci
2001R
=> 320 =
R^+(Z,-Ze)^
R = 45(Q)=> coscp =
C u o n g do hieu d u n g d o n g qua mach la
B. 2 ( A ) .
dan
R
R
R = 80(Q)=> coscp = — =
Z
yJR^ +(140-200)
va cuon cam t h u a n co cam k h a n g 80 Q. Dien ap hieu d u n g a hai d a u doan
A. 1 (A).
C. 0,45 hoac 0,65.
^ = 200(Q)
coC
U-R
=500(V)
Chon A.
64
i,v.:io!:
Huong dan
+ Uf ) + Uf, + 2U„U, - 2U, Ue + U^^
Vift
= 100
R2+(100-ZJ^
= 100
U ^Jl'nwtl
Mach dien liic dau
> Chon B.
M a c h dien .sau
65
Bo tip hien thiic
Vpl li LTDH
Cty
VTV2, t^p 2 - Chu Van
tren hSnh
V i du 22: Dat vao hai dau doan mach AB mot dien ap xoay chieu 100 V - 50
Hz. Mach AB gom cuon day c6 dien tro thuan 20 Q c6 cam khang 60 Q mSc
noi tie'p voi tu dien c6 dung khang 20 Q roi mac noi tiep voi dien tro R. Ne'u
cong suat tieu thu R la 40 W tiVi R bang
A. 5 Q .
B. 10Qhoac200Q.
'
;i;:,-OfJL.
C. 15^2 hoac 1 0 0 Q.
• i^'iU
T2T,
PR
U^O
r.^; : .
D. 20Q.
• Huong dan
,\)--->\s
U^R
=r R = — R =
=> 40 =
(R + r)2+(Z, - Z c f
R2 -210R + 2000 = 0=>
J- s ..,
5
(R +20)2+(60-20)2
R = 10(Q)
,:,vyb
=> Chon B.
R = 200(Q)
. . ^ = - ^ = 0,5(A)
^'^ U j
120
-<x>2 ^ — = * / ( R d + r)^ +(1007rL)2 = —
tie'p, dien ap giua hai dau doan mach u = 50 \/2 coslOOnt ( V ) . Dien ap hieu
V . Bie't cong suat tieu thu trong mach la 20 W. Gia tri R bang
,
= U | + ( U L - UC)^
p = I2R = 2K-.R
C. 15Q.
Huong dan
^
D. 2 0 Q .
- ,X
tieu thu cua doan mach la
A.240>y'3W.
Cdchl:
C. 240 W.
u = 120sin 1007rt + - j = 120cos lOOnt-V
D. 120>/3 W.
•
3;
6,
(V)
i = 4cos 100TUt + - ( A )
6)
3
UR
= 40(V)
\
Cdch 2: Goi i* la so phuc lien hop cua i thi cong suat phuc: P = - i u
= 120 - 207,85i => P = 120(W) ^ Chon B.
4Z-
V i du 24: Mot mach dien xoay chieu gom dien tro R noi tiilp voi cuon day c6
6J
dien tro 1 0 Q. Dat vao hai dau doan mach dien ap u = 40 ^/6 coslOOTtt ( V ) , (t
(Phan thuc cua cong suat phuc la cong suat tieu thu con phan ao la cong
do bang giay) thi cuong do dong dien cham pha hon dien ap giua hai dau
suat phan khang).
doan mach la Tt/6 va cong suat toa nhiet tren R la 50 W. Cuang do hieu
Thao tac ba'm may tinh: sau khi nhap -
'-i";*')
dung trong mach la:
A. 1 A hoac 5 A.
\'d
B. 5 A hoac 3 A.
V.
sau do ba'm 0 dugcketqua 120-207,851.
' I = 1(A)'
I = 5(A)
mac no'i tie'p voi mot
UAD = 100 V2 cos(100nt + nil) ( V ) ; um = 100 76 cos(1007it + 2TI/3) ( V )
va i = V2 cos(100r!:t + 7T/3) (A). Cong sua't tieu thu cua doan mach AB la
A. 173,2 W.
C . 0,639H.
D . 0,636H.
Htiatig dan
Khi den sang binh thirang thi cuong do dong dien chay qua va dien tro
thuan cua den:
?in-: i i
iiK
220 V - 50 Hz, thi den sang binh thuong. Do t u cam cuon day la:
B. 1,15H.
,, • :
thoi tren cac doan mach va dong dien qua chung Ian lugt c6 bieu thuc:
Chon A.
bong den 120 V - 60 W. Noi hai dau mach dien voi nguon dien xoay chieu
~r::::Z
7:
120Z--
Vi du 27: Doan mach AB g5m hai doan A D va DB ghep noi tie'p. Dien ap tiic
Huong diin
V i du 25: Mach dien gom cuon day c6 dien tro thuan 10
A . 1,19 H .
ba'm IshiftlfUfzll^
' •
C. 2 A hoac 5 A. D. 2 A hoac 4 A.
UIcoscp = PR + I^r ^ 40V3.1.— = 50 + I^.IO
66
B.120W.
•
20 = — =^ R = 80(Q) =^ Chon A.
R
V /
.
R2
'
P = UIcoscp = 60N/2.2>/2 C O S — = 120(W) =:> Chon B.
\
^ 50^ = U ^ + (30 - 60)^
Chon B.
thi dong dien trong mach c6 bieu thuc i = 4cos(100TTt + nib) (A). Cong sua't
dung 6 hai dau cuon cam va hai dau tii dien Ian lugt la U L = 30 V va Uc = 60
B. lOQ.
L «1,15(H)
Huang dan
V i du 23: Mot mach gom co dien tro R, cuon cam thuan L va tu dien C mac noi
A. 80Q.
yj^
Khang
Vi du 26: Dat dien ap u = 120sin(1007Tt + TT/3) ( V ) vao hai dau mot doan mach
lOO^R
J
TISnn MTV own
Bien
B. 242 W.
- )i ,
C. 186,6 W.
D. 250 W. '
Huong dan
E^ien ap tong: u = L I ^ D + " D B
Cong sua't phuc:
,'•'1
1
u = ^^72Z-1
flO072Z- + 100V6Z—1 = 173,2 + 2001
2
3; I
2
3,J
^
=>P = 173,2(W)=>ChoiiA.
• "
1 = -1
2
, /
. . . . . . . . . . u:, , '.. xHtK^:
- : v : a.
67
Cty
Bd
trp
hien
thiic
V$t
IIL
TO I I trcn
k&nh
VTV2.
t^p
2 - Chu
Via
M a c h no'i tiep chua tu cho d o n g xoay
^
chieu d i qua n h u n g k h o n g cho d o n g
,
|
i
|
voi
'
<^^^^
50W.
''
-
Nguon 1 chieu : I , =—;R
= IfR =
Nguon xoay chieu : I , =
,
U
C. 120W.
•\r':)'}')n{.:\j\\
,
U^R
U
Nguon xoay chieu (RL): L =
• • • >(
;P; = \iR = —
- ; Z , = wL
D . lOOW.
U
= — ^ 50 (Q)
U
Nguon 1 chieu (RL) •.1^= — ^^
qua. N h u n g L chi can t r o d o n g xoay chieu con k h o n g c6 tac d u n g can tro
'
B, 200W.
Huangdan
M a c h noi hep RL v u a cho d o n g xoay chieu d i vua cho d o n g m o t chieu di
d o n g m o t chieu.
tu dien ccS dien d u n g C = 87|aF vao mach dien xoay chieu noi tren. Cong
suat tieu thu tren mach la:
•
m o t chieu d i qua.
*
• ^'!v^^V'\•J-
P3=1^R =
m o t hieu dien the m o t chieu 12 (V) thi c u o n g do d o n g dien qua cuon day la
100
•=>1 =
- Z L =50%/3(Q)
+Z
Nguon xoay chieu (RLC): Zc =
V i d u 1 : ( D H - 2012) K h i dat vao hai dau m o t cuon day c6 do t u cam 0,4/7i (H)
(oC
= 36,6(Q)
U^R
100^50
R2+(Z|-ZC)^
50^+(50V3-36,6)
aOO(W)=^ChonD.
0,4 ( A ) . Sau do, thay hieu dien the nay bang m o t dien ap xoay chieu c6 tan
Vi dii 4: (DH-2009) K h i dat dien ap k h o n g d o i 30V vao hai dau doan m?ch g o m
so 50 (Hz) va gia t r i h i ^ u d u n g 12 (V) thi c u o n g d o d o p g d i e n hieu d u n g qua
dien t r o thuan mSc noi tiep v o i cuon cam thuan c6 do t u cam 0,25/Tt (H) t h i
cuon day bang
:
d o n g dien t r o n g doan mach la d o n g dien m o t chieu c6 c u o n g d p 1 A . Neu
A. 0,30 A .
B. 0,40 A .
.i^
.
v
. i ; :
;
" u
C. 0,24 A . ' - • ' D . 0,17 A .
Huangdan
dat vao hai d a u doan mach nay dien ap u = 150 V2 cosl207rt (V) t h i bieu
'
thuc ciia c u o n g do d o n g dien trong doan mach la
•
.
,v«t nail ' j u d q
" u
N g u o n l c h i e u : ! , = — = > R = — = 30(Q)
'
'
A. i = 5N/2cos(120Tit-7t/4)(A).
B. i = 5cos(1207tt + 7i/4) ( A ) .
C. 1 = 5^/2 cos(1207it + 7t/4) ( A ) .
D . i = 5cos(1207rt- 71/4) ( A ) .
i'
Huong dan
Nguon xoay cliieu :
Vi
:UV-
,
h = •I
R-+Zf
=
12
,
^ = 0,24(A)z=>ClionC.
V30-+40-
Mac vao nguon 1 chieu : R = y = 30 ( f i )
d u 2: Dat vao hai dau cuon day co do t u cam L = 0,35/7i ( H ) m o t dien ap
Z L =coL = 30(Q)
k h o n g d o i 12 V t h i cong suat toa nhiet tren cuon day la 28,8 (W). N e u dat
Mfic vao nguon xoay Chieu : Z =
vao hai dau cuon day do dien ap xoay chieu c6 tan so 50 H z va gia t r i hieu
•' d u n g la 25 V thi cong suat toa nhiet tren cuon day bang bao nhieu?
• A . 14,4 (W).
B.5,0(W).
C.2,5(W).
Nguon 1 chieu : Pi = — => R = — = 5(Q)
•
:.
• V -Silt •
Nguon xoay chieu:
'
'Z| =a)L = 35(Q)
P, =
U^R
=
R-+Zl
5^+35^
= 2 , 5 ( W ) =^ Chon C.
du 3: Dat vao hai dau ong day m o t dien ap m o t chieu 12V thi c u o n g do
d o n g d i e n t r o n g o n g day la 0,24A. Dat vao hai dau ong day m p t dien ap
xoay chieu c6 tan so 50 H z va gia t r i hieu d u n g 100 V thi c u o n g do d o n g
R
'
•••SI/
= 30V2 ( Q )
!(, =
= 5(A)
= !=:>« = — > 0 : u sdm pha hdn i la —
4
i = 5cos 1207rt - - ( A ) => Chon D.
4
V i d u 5: Dat dien ap xoay chieu c6 gia trj cue dai Uo vao hai dau m o t dien tro
thuan R t h i cong suat tieu t h u la P. K h i dat vao hai dau dien t r a do m o t hieu
.
S
+ zl
tancp =
D . 28,8 (W).
Huattg dan
Vi
r j p i -
UWJrKnang
dien hieu d u n g trong ong day la l A . Mac mach dien g o m ong day noi hep
2) Mach R L mic vao nguon mgt chieu roi mic vao nguon xoay chieu
*
TimnniV
BlSn
I
dien the k h o n g doi c6 gia t r i Ug t h i cong suat tieu t h y tren R la ^
A. P.
B.2P.
C.PV2.
^ Huang dan
Nguon xoay chieu .• P = I R =
R
D.4P.
_
'i,; ;
2R
69
B d t r a kle'n
thurc
V^it If LTDlt
t r e n kenh
VTV2.
t^p
2 - Chu
VSn
Cty
Bicn
J ,2
DVVHKhang
VIft
m o t n g u o n d i e n tong h o p c6 bieu thirc u = [100cos(100Trt + 7r/4) + 100] V.
=*P' = 2P =>ChonB.
T i n h cong .suat toa nhiet tren dien t r o
Chu y:
A. SOW.
B. 2 0 0 W .
mach noi tiep chi'm tu thi chi ddng dien xoay diicii di qua: I^^. =
,
^
.
mach not tiep khong chi'ra tu thi cd dong dien xoay chieu va dong mot chieu deu di
^
1,^,= — . Do do, dong liicu dun<^ qua mach:
= ,
'
D. ISOW.
dan
D o n g 1 chieu i
p = rR = 2) Khi mac dong thai nguon mot cliicu vi) xoay chieu (u = a + b^/2 cos(wt + cp)) vijo
C.25W.
Huong
1) Khi mac dong thai nguon mot chicu va xoay cliicu f u = a + bV2 cos((ot + (p)) vao
= —j=
NTV
Vi d u 8: Dat vao 2 dau mach dien c6 2 phan tir C va R v o i d i e n t r o R = Zc = lOOQ
Nguon mot chieu ; P' = I^K = —^
qua:
TlStlH
Zl
= 25(W)=i-ChonC.
BAI TOAN LIEN QUAN DEN GIAN DO VECra
Da so hoc sinh t h u o n g d u n g p h u o n g phap dai so'de giai cac bai toan dien
con p h u o n g phap gian do vecto t h i hoc sinh rat ngai d i i n g . D i e u d o la rat
V i du 6: M a c h g o m d i e n t r o R = 100 Q mac noi tiep v o i cuon day thuan cam
dang tiec v i p h u o n g phap gian do vecto d u n g giai cac bai toan rat hay va
L = l / 7 i ( H ) . D i e n ap dat vao hai dau doan mach co d a n g u = 400cos2507rt (V).
ngan gon dac biet la cac bai toan lien quan den nhieu d i e n ap hieu d u n g ,
lien quan den nhieu d o lech pha. Co nhieu bai toan k h i giai bang p h u o n g
•'' C u o n g d o d o n g d i e n hieu d y n g qua mach c6 gia trj bang
^•^A-
B. 3,26 A.
•"'^
' ^^^^^^^^^^^
C.(2H-V2)A.
D . Vs
A.
Ap d u n g cong thuc ha bac viet lai: u = 400cos- (507ct)= 200 + 200cos(]007rt)(V)
U 1c
Dong 1 chieu: I , ^ =
200,
do vec to t h i to ra ra't hieu qua.
T r o n g cac tai lieu hien co, cac tac gia hay de cap den hai p h u o n g phap,
p h u o n g p h a p vec to buoc (vec to chung go'c) va p h u o n g p h a p vec to t r u g t
(vec to n o i d u o i ) . H a i p h u o n g phap d o la ket qua cua vl§c v a n d u n g hai q u y
= 2(A)
/ R ^ + Z , \-
tac cong vec to t r o n g h i n h hoc: q u y tac h i n h b i n h hanh va q u y tac t a m giac.
100^/2
Dong xoay chieu : 1^^ = •
VlOO- +100-
•JR^ + Zl
=> I =
phap dai so rat dai d o n g va phuc tap con k h i giai bang p h u o n g p h a p gian
i
I'
• = ](A)
Theo c h i i n g t o i , m o t t r o n g n h u n g v a n de t r o n g t a m ciia viec giai bai toan
bang gian d o vec to la cong cac vec to.
(» j imdv/j
v , .. -
1) Cac q u y t3c cpng vec t o
+ Ixc = N/5 (A) => Chon D.
V i du 7: Dat m o t d i e n ap c6 bieu thiVt u = 200N/2 cos2(1007rt) (V) vao hai dau
d o a n mach AB g o m d i e n t r o R = lOOQ va cuon cam t h u a n c6 d o t y cam
T r o n g toan hoc de cong hai vec to a va b , SGK h i n h hoc, g i o i thieu hai quy
tac: quy tac t a m giac va quy tac h i n h b i n h hanh.
0,25/7t ( H ) mac n o i tiep. Cong suat toa nhiet tren d i e n t r o la
, A.280W.
B. SOW.
C. 3 2 0 W .
D . SOW.
Humgdan
^ Ap d u n g cong t h i i c ha bac vie't l a i : u = lOO-Jl + 100N/2cos2007tt ( V )
Z L = 2007t.L - 50 ( Q ) ; P = I^^R + I^^R =
[ R
P =
10012
100^100
100
1002+502
R +-
U^R
= 2 8 0 ( W ) r > C h o n A.
Hinh a
71
Bo trg hicn
thiic
V^t li LTDII
tren kenh
VTV2.
Cty T/SHff MTV DVt^H KHang
t$p 2- Chu VSn Bl€n
Vlft
a) Quy tac tarn gidc
N o i d u n g cua q u y tac tarn giac la: Tir d i e m A t u y y ta ve vec t o A B = a, roi
t u d i e m B ta ve vec t a B C = b . K h i do vec t o A C d u o c goi la tong cua hai
vec t o a v a b (Xem h i n h a).
b) Quy tac hinh binh hanh
d'> vi^ox }>noh A > if!-i . n y . n > n f - f ( , J >••'•('( , .r r . p r . f
N o i d u n g ciia q u y tac h i n h b i n h hanh la: T u d i e m O t u y y ta ve hai vec to
o
O B = a va O D = b , sau do d u n g diem C sao cho O B C D la h i n h b i n h hanh thi
vec t o O C la tong ciia hai vec t o a va b (Xem h i n h b) . Ta thay k h i d u n g
q u y tac h i n h b i n h hanh cac vec t o deu c6 chung m o t goc O nen goi la cac
vec t o b u o c .
.,
Goc h o p b o i hai vec t o a va b la goc B O D (nho h o n 180°).
V a n d u n g q u y tac h i n h b i n h hanh de cong cac vec t o t r o n g bai toan dien
i xoay chieu ta c6 p h u o n g phap vec t o buoc, con neu van d u n g q u y tac tarn
giac t h i ta c6 p h u o n g phap vec t o t r u g t ("cac vec t o n o i d u o i nhau")..
2) C a so vat l i ciia phirong phap gian do vec to
' ""^
*Chgn ngang la true dong dien, diem O lam
goc.
*Ve ISii luol cac vec-to" bieu dien cac di^n ap,
cung chung goc O theo nguyen tac:
ji: ' ik
+ L - len.
+ C - xuSng.
+ R - ngang.
Do dai cac vec-to' ti le vol cac gia tri liieu
dung tuolig ling.
*Chi t6ng hffp cac vec-to" dien ap c6 lien quan
den du kien cua bai toan.
^
-.,
•Bieu dien cac so Ueu len gian do.
•Dua vao cac he tliijc lutmg trong tam giac de
tim cac dien ap hoac goc chuabiet.
Mot so'diem can heu y:
; ,5> , •
Cac dien ap tren cac phan tu* d u g c bieu dien b o i cac vec to ma chieu dai t i le
v o i dien ap hieu d u n g ciia no.
D o lech pha g i i i a cac dien ap la goc h o p boi gii>a cac vec t o t u o n g l i n g bieu
Xet mach d i e n . D a t vao 2 d a u doan A B m o t dien ap xoay chieu. Tai m o t thoi
d i i n chiing. D o lech pha gii>a dien ap va c u o n g do d o n g dien la goc h o p boi
^ d i e m bat k i , c u o n g d o d o n g dien 6 m o i cho tren mach dien la n h u nhau.
vec t o bieu dien no v o i true I . Vec t o " n a m t r e n " ( h u o n g len tren) se nhanh
N e u c u o n g d o d o n g dien d o c6 bieu thiic la: i = IQ coswt ( A ) t h i bieu thuc
^^y; dien ap g i i i a hai d i e m A M , M N va N B Ian l u g t lac , ( ^ j
u^^l = U L V 2 cosf Q t + - 1 ( V )
2
UMN
, ; i
^.i^.uuA - n .
pha h o n vec t o " n a m d u o i " ( h u o n g xuong d u o i ) .
Viec giai cac bai toan la nham xac d j n h do Ion cac canh va cac goc ciia cac tam
giac hoac t i i giac, nha cac he thiic l u g n g trong tam giac v u o n g , cac he thuc
l u g n g giac, cac d j n h l i ham so sin, ham so cos va cac cong thiic toan hgc.
• , , M . A ' y ] t i f f J ^rit..
=UKV2coswt(V)
" N B = Uc\/2cos
( D t - -
(V)
+
D o do, dien ap hai. dau; A , B la: u^g = u
+ U^N +"NB•
+
Cac dai l u o n g bien thien dieu hoa ciing tan so' nen c h i i n g c6 the bieu dien
b a n g cac vec t o Frexnel: U ^ B = U L + U R + U C (trong do do I o n ciia cac vec to
bieu t h i dien ap hieu d u n g ciia no).
+
—•—
D e thuc h i e n cong cac vec to tren ta phai van d u n g m o t t r o n g h a i quy tac
cong vec to.
Ve. gian do vec ta theo phuong phap vec to buoc gom cac hu&c nhu sau:
a'- •
•
T
•:.d
3) V e gian do vec to bang each van dung quy tac h i n h binh h a n h - Phuong
phap vec to bupc (vec to chung goc)
— •
T r o n g toan hgc m o t tam giac se giai dugc neu biet t r u o c 3 (hai canh m o t goc
hoac hai goc m o t canh hoac ba canh) trong so 6 yeu to' (ba goc t r o n g va ba
canh).
73
Cty
Bo trg kien
t h ^ c Viit
l i L mil
l i c n henh
VTV2.
t^p
2 - Chu
T/VHH nrv
T i m tren g i a n d o vecto tam giac biet triioc ba y e u to (hai c a n h mot goc,
Khang
Vipt
hai
goc mot c a n h ) , sau dcS giai tam giac do de tim cac y e u to c h u a biet, c u tiep
u,
tuc n h u v a y c h o cac tam giac con lai.
D o dai c a n h c u a tam giac tren g i a n do bieu thi d i e n ap h i e u d u n g , d o Ion
400,/
/•I
/
goc bieu thj d o lech p h a .
M o t so he thii'c l u o n g trong tam giac v u o n g :
i
a' -~ b' + c
1
1
h-
DVVn
VSn B i e n
b-
• H
O
,
o
I
306'^
1
I
11,
Chii y: Khi sit dung gian do vec ta ta tinli duyc dien ap hieu dung va do lech pha.
T
c-
u,
/>- = a.b'
R
Tie do CO th(;'tinh dwgc dong dien, cong sud't:
P = l-'R
M o t so he thi'rc h r o n g trong t a m giac t h u o n g :
V i d u 2: Tren doan mach xoay chieu k h o n g phan nhanh c6 b o n d i e m theo
d i i n g t h i i t u A , M , N va B. G i i i a hai d i e m A va M chi c6 cuon cam thuan,
a'
= b' + c
giOa hai d i e m M va N chi c6 dien tro thuan, giCia 2 d i e m N va B chi c6 tu
- 26ccos A
a
b
c
^ sin A
sill B
sin C
Phu'ong phdp vec ta bugc chi hicu qua v6i cac bai
todn CO R nhm giua dong thai lien qua den dien
dien. D i e n ap hieu d u n g giCta hai d i e m A va M la 150 (V) va dien ap hieu
d u n g g i u a hai d i e m N va B la 200/3 (V). D i e n ap tiVc t h a i tren d o ^ n A N va
tren doan M B lech pha nhau 90". D i e n ap hieu d u n g tren R la '
R
C
dpbatclieo O ^ N ' ^ M B V i d u 1 : Tren doan mach xoay chieu k h o n g phan nhanh c6 bon d i e m theo
d u n g t h u t u A , M , N va B. Giua hai d i e m A va M chi c6 cuon cam thuan,
giua hai d i e m M va N chi c6 dien tro thuan, giOa hai d i e m N va B chi c6 tu
A . lOO(V).
'
200
L
D . 180 (V)
He thiic ktcing : -
=h =
be
1
b"
R
-KJ
,B
300.400
h
r
150
/
be
'b^+c^
7300^+400^
74
A/f
UR + U , , U^n = OR + U c .
1
= 2 4 0 ( V ) = > C h o n A.
i
.150 = 1 0 0 ( V ) = > C h o n A.
UT
V i lien quan den U ^ N -L ^ M B " ^ n ta tong h g p theo q u y tac h i n h b i n h hanh
=
•
HethiJtcIildng:h^ =b'.c'
Huong dan
cac vec ta dien ap do: 0
*
cac vec t o dien ap do: U ^ N = UR + U| , 0^415 = OR + U c .
doan M B lech pha nhau 90°. D i e n ap h i ^ u d u n g tren R la
C. 500 (V)
'
D. 180(V).
V i lien quan den 0^^^ 1 U^^u nen ta tong hap theo q u y tac h i n h b i n h hanh
d u n g hai d i e m M va B la 300 (V). D i e n ap tuc t h o i tren doan A N va tren
B. 120(V)
C.90(V).
Huong dan
dien. Dien ap hieu d u n g giua hai d i e m A va N la 400 (V) va dien ap h i f u
A.240(V)
B. 120(V).
O
Uc
o
150'
?
\ 2 0 0 / 3 ,
200/3
!
I
1
7
\
\
A
1
1
= a J b '
75
B6
lis> hicn
lliiic
yjt
li LIOll
litin
Chu y: Neii cho bict
«
^
coC
tanip,^,
VTV2.
t^p
2 — Chu
V^n
Bien
cty Timn MTV p vvn m^ng vi^t
= L/C tht sm/ ra:
R 2 = , , L . — = Z,Zc
»
hcitli
^
R
tancpRc = -1 «
= - l
R
0^,
•
-
• ;
_L
Y i d v 5: T r e n d o a n m a c h x o a y c h i e u k h o n g p h a n n h a n h c 6 b o n d i e m t h e o
Vi c
d u n g t h u t u A , B, C v a D . G i u a h a i d i e m A v a B c h i co t u d i e n , g i u a h a i
d
d i e m B v a C c h i c 6 d i e n t r o t h u a n , giCra 2 d i e m C v a D c h i c 6 c u o n
t :•./
t h u a n c a m . D i e n a p h i e u d u n g g i i r a h a i d i e m A v a D l a 100
0^^
V i d u 3: M a c h d i e n x o a y c h i e u n o i t i e p A B t h e o d u n g t h u t u g o m c u o n Cam
t h u a n L, d i e n
t r o t h u a n R va
URC = 0,75UKL v a
A . 0,8.
tu dien
C.
Cho
biet dien
ap
hieu
dung
R- = — = ZLZC
do hieu d u n g chay qua m a c h la 1 (A). D i e n ap tire t h o i tren d o a n A C va tren
ctoan B D l e c h p h a n h a u 6 0 " n h u n g g i a t r i h i e u d u n g t h i b a n g n h a u . D u n g
A.40Q.
B.lOOa
dan
•'
C.^>/3:Q,
Huong,
<^
, !>, i j i V H '-ntiCi j r ' i s h '^^ncvv
s i n a = 0,6
'' •
ac d e u n e n
R
\}Q = 0,75a sin a = 0,45a => COS (p = —
,r[ & u i O . , S fr/ lA ,,M
'''''
: 0,864 = > C h o n B .
t u d i e n C.
Cho
biet dien
ap
hieu
dung
= L/C. T i n h h e s o ' c o n g s u a t c i i a d o a n m a c h A B .
A . V2/7.
C. 43J7
B. ^/3/5.
Huong
= C
,2
= Z,Zc =>UR
.
D.
I
• = 1 0 0 ( Q ) !> C h o n B .
d i e m M v a B l a 40 ^/3
^
doan
AN
va
tren
doan
MB
lech
pha
n h a u 90", d i e n a p t u c
tren
pha
u,,
= J-r^ChonC.
ha
phwcmg
phdp vec to huge thi khong
+ ( U L - U c )^• tan cp =
U]3
-
m"-^
theo
(V).
NB
nhau
va
hieu
C
N
M
UT
1,0,
o
— ^ .
AN
lech
30"
do
R
va
dung
>
0.
,<-''M"
v
-»
UR
?
:Ul!+r .
t r o n g m a c h la N/3 ( A ) .
ve cdc dien dp bat cheo de tinh cdc dien dp thdnh phan
=
doan
cuong
Vuf,+(U,-Ucr
y: Ne'u dung
Uc
D i e n ap t u c t h o i tren
U L = a>/3 cos a = 1,5a
Z
Uc
d u n g t h u t u A , M , N v a B. G i u a h a i d i e m A v a M c h i co c u o n d a y , g i i i a h a i
thoi tren d o a n M B
- 7 =
I
6: T r e n d o a n m a c h x o a y c h i e u k h o n g p h a n n h a n h co b o n d i e m
\]Q = a s i n a = 0,5a
R
• COS(p = — =
thitc:
V i du
Uc
IUR
100 V3
a p h i e u d u n g g i u a h a i d i e m A v a N la 60 ( V ) v a d i e n a p h i ^ u d y n g giCra h a i
dan
=U[Uc
U R = a c o s a = 0,5a^/3
UR
d i e m M v a N c h i co d i e n t r o t h u a n , giCra 2 d i e m N v a B c h i co t u d i e n . D i e n
72/5.
A O U R C U R L v u o n g t a i 0 =:i> a = 3 0 "
Chu
4i
=>Zc =
t r o t h u a n R va
UKL = V3 URC v a
UB
o
V ==l O100,0( (VV))
U
V i d u 4: M a c h d i e n x o a y c h i e u n o i t i e p A B t h e o d u n g t h u t u g o m c u o n c a m
L, d i e n
'"-^
D u a v a o g i a n d o vec t o t i n h d u o c :
M+i^L-^cf
thuan
*
•D
UK = U = 100N/3(V)
U L = a c o s a = 0,8a
cos tp = •
4i
= U,- = ^
C
T i r d o s u y ra m a c h c o n g h u o n g :
Uf, = 0,75a c o s a = 0,6a
U,,
u,
B
-^H
IJ
cos a = 0,8
D . 20 Q.
dan:
T a r n g i a c c a n co m o t g o c 60° la t a r n
U R = ULU(_. => A v u o n g t a i 0
t a n a = 0,75:
(V) va c u o n g
k h a n g c i i a t u d i e n la
= L/C. T i n h h e so c o n g sua't c i i a d o a n m a c h A B .
D . 0,867.
B. 0,864.
C. 0,5.
Huong
cam
• •
nen ve vec ta tongl
Chi
UR, UL, UC roi dp dung
; cos cp = HJL .
,
U
nen
he
Dien
tro
thuan
cua
\
Ail
c u o n d a y la
A. 4 0 Q .
B. l O Q .
C. 5 0 Q .
D. 20Q.
\
\
Un
\
77
B S trgkiSn
thiic
V$t IILTOH
ttenkSnh
VTV2.
l./)>
Huong
ih
van
Cty
Blen
dan
i du 8: Tren
AOUKUMM : UK = 40>/3.sin30" = 20V3 ( V )
v ; .(
:y;
) Ji
uf
j>iit,
'
' • I I I ' ; , v , : r ; ^isrr/'';4ri:^;h'-U''j,i:;fO^f.;/
tin LIR., = (ii + DW
' '
d u n g thiV tu A, N , M va B. Giun hai diem A va N chi c6 dien t r o thuan R,
giiia hai d i e m N va M chi co cuon day (c6 dien tra t h u a n r = R), giua 2 d i e m
M va B chi c6 tii dien. Dat vao hai dau doan mach m o t dien ap U - 50 H z thi
dien ap hieu d u n g tren doan A M bang tren doan N B va b3ng 30^5
(V).
Dien ap tiVc thoi tren doan A M v u o n g pha v o i dien ap tren doa.i N B . Gia trj
U bang
B. 90 V.
.
' ::
C. 60 ^/2 V.
Huang dan
AOU^Ufjij : sin a =
30^5
A/~vi I I I
^K+r
2U
AOU,..U,,:cosa = ^ . - ^
U,^,^ =30V5.cosa = 60
U,,e=30V5.cosu = 60
[fill B(iX}:i':gm:':
A
R
t-'.'
=> tan a =
- •;
D . I 20 V.
• * -
k h o n g phan nhanh c6 bon d i e m theo
sin a =
sin a
1
=—
cosa 2
i giua hai diem M va N chi c6 cuon day,
c^.
cosa = .
••
; Si
^*
Cuon day dien tro thuan r = 0,5R. D i e n
ap hieu d u n g tren doan A N la U 73
1
2
;U,.
,
va
tren doan M B ia U . Dien ap tuc thoi
tren doan A N va tren doan M B lech
pha nhau 90". D i e n ap tuc thoi UA.\m
pha hon d o n g d i e n la
A. 60".
B. 45".
if
{
{
• •
D . 15".
C. 30".
^
Huang
dan:
•u/^'«"- >
AOU^UMI, : s i n a = U
< " ' ' f . ; ; <
3U.
tan a =
A O U , , , U , , . . . . . - ^ ^ _ - ^ ^
cosa
• a = 30" => Chon C.
s
Kinh nghieni: Plnmng phdp vix hr buoe khd hieu qua v&i bai loan c6 R 6' gii'ra dong
thd'i lien quan den dien dp bat eheo. Phuvng phdp ndi/ thwang lien quan den
—
^
L.r
C
VV'J'.'V
?;1
r..!\i.
I'vV
';::^\
30 VS,-
-mm
o
4) V e gian do vec to bang each van dung
quy tac tarn giac - phuong phap
vec to trugt (vec to noi duoi)
\30V5:
\
\
Ve
-
!
i
gian
phuong
do
vec
to
theo
phap
vec
to
trugt
g o m cac buoc n h u sau:
u,.
u-
ede
doan mach sau:
=> U = J U r , , , + Ufc = 6 0 V 2 ( V ) = > C h o n C .
^
V /
.
UAM
o
Vlft
chieu
; giua hai d i e m N va B chi c6 tu dien.
V i du 7: T i e n doan mach xoay chieu khong phan nhanh c6 bon d i e m theo
, ,
Khang
d i e m A va M chi c6 dien tro thuan R, , ^
U
r = — i - = 10(Q)=>ChonB.
A. 30 V.
mach xoay
nrvDVVH
d u n g thu tir A , M , N va B. Giua hai
- ' ' i ' A O U , . ^ , U , ^ N : U|^,, =60.sin60" = 3 0 V 3 ( V ) = J . U , =10>/3(V)
• " C/tu I/; Nn/ da) /;/^? R =
doan
TNtlH
.
1. >,.•!.
1
.
R
A.
M
N
C
(in,
N
11
,
i)
+ Chon true ngang la true d o n g
dien, d i e m dau mach lam goc
UL
(do la d i e m A ) .
* '1 ': \;
1 \
Cliil J/; Mrti xkh
78
quan trong trong bai loan tren la xac dinh goc
a.
79
BS tr^
kiSa
thUc
V$t If LTD I I tt0n
kenh
VTV2,
t^p
2 - Chu
cty
Van
+ Ve Ian lu-gt cac vec to dien ap tu dau mach den cuoi mach
A M , M N , NB
"noi duoi nhau" theo nguyen tac: L - di len, R - di ngang, C - di xuo'ng.
A A M B can
^ I= ^
dien dien ap U A \ vec ta MB bieu dien dien ap UNH.
Mot so'dictn cmi Iwii y:
* Neu cuon day khong thuan cam (tren doan A M c6 ca L va r (Xem hinh a
duoi day)) thi 0^^,, = 0, + 0^ + U,^ + 0^ ta ve L truoc nhu sau: L - di len, r di ngang, R - di ngang va C - di xuong (Xem hinh a) hoac ve r truoc nhu
sau: r - di ngang, L - di len, R - di ngang va C - di xuong (Xem hinh b). ; ^
Ui
M
M
= 4 ( A ) => C h o n C .
,
,
,
vi^t
Vi du 2: (GIAN DO R-rL) Doan mach dien xoay
" ^ ^ ' ' ^ ', ^
.p
chieu AB gom dien tro thuan R mac no'i tiep
M
vai cuon day. Dien ap hieu dung 6 hai dau
,,
.-:^B
dien tro, cuon day va hai dau doan mach Ian '* '
luot la 70 V, 150 V va 200 V. He so cong sua't
-''iso/
ciiacuondayla
'
/
UL
B.0,9.
D.0,6.
= -0,6
cosMcd = 0,6
^"^-A
M
=> Chon D.
/
•
200^ = 70^ +150^ + 2.70.150.cos(p,-d
'ri-.,., ^
^
..^ '
Ta dugc: AB^ = A M " + MB^ + ZAM.MB.coscp^^
gian nhu phuong phap da neu.
"
• •
Cach 2: Binh phuong v6 huong hai ve: AB = A M + MB
Hinhb
Hinh a
'
«jw>';'.Fi
2.70.150
Neu mach dien c6 nhieu phan t u thi ta cQng ve dugc gian do mot each don
'•'). vv "*
coscp^j = 0,6
•<
f
. r •, ,
Vi du 3: (GIAN DO R-rL) Doan mach di^n xoay chieu gom dien tro thuan R
M
N
Ci
E"F
17,^ = MB = 120( V )
cos A M B =
(GiQa A va M c6 ca UL va Uj)
D
M ^
A . - " '
'1^
V> - Huang dan
Cach 1: A p dung dinh ly ham so cos cho tam giac AMB:
* Qioii tmc ngang la true dCng difen.
* Qion di^m iin mach A lam g6c.
* Ve lin luot tir A laiig B tlieo nguyen tac
ndidudinliau:
,o f
L-Diten.
,
R-Dinsans.
.
C - Di xudng.
A
tai
A 0,5.
C.0,6.
N
M
loiang
Huattg dan
+ Noi A voi B thi vec to AB bieu dien dien ap UAH. Tuong tu, vec to A N bieu
L,r
D vvn
Timn nrv
BiSn
mac noi tiep voi cuon day. Dien ap hieu dung 6 hai dau dien tro, cupn day
va hai dau doan mach Ian luot la 35 V, 85 V va 75 N/2 V. Cuon day tieu thu
O
M
N
B
UL2
Ur
cong sua't 40 W. Tong dien tro thuan ciia toan mach la
UT
A.
*0»
50 (Q). ^
B.
35 (Q).
C. 40 (Q).
Humgdan
-••I
• - cm-
352+(7572f-85^
2.35.75V2
\inM 'of 'A'i <)!>
V i du 1: ( G I A N DO R-rL) Doan mach dien
xoay chieu gom di$n tro thuan 30 (Q) mac
R
noi tiep voi cuon day. Dien ap hieu dung 6
hai dau cuon day la 120 V. Dong di^n
1
' ) ) -J';;'
r, L
A.
C. 4 (A).
D. ^
(A).
,
2
•
..-;lB
x''
•
/
pL
I
=>r + R = i ^
= 75(Q)r^ChonD.
Uj^
M
^' dy 4: (GIAN DO L-R-C) Dat mot dien ap xoay chieu c6 gia tri hi#u dung
ap hai dau cuon day. Cuong do hi^u dung
B. 3 (A).
A - - C Z > - ^ « - ^ B
Pr=I^r = I.U, = ^ I = - ! J ^ = 1 ( A )
B
ctau doan mach va lech pha 7i/3 so voi dien
A. 3 V3 (A).
rL
M
trong mach lech pha 7r/6 so voi dien ap hai
dong dien qua mach bang
R
/2
=^UK+r = A E = ABcos(p = 7 5 ( V ) = ^ U , =45(V)
D. 75 (Q).
120,V
200(V) vao hai dau doan mach A B gom cupn cam thuan c6 dg t u cam L,
/ \"
di?n tro thuan R va tu dien c6 dien dung C mac no'i tiep theo t h u t u tren.
^i?n ap hieu dung tren L la 200 V2 (V) va tren doan chua RC la 200(V). Di?n
hieu dung giiia hai dau tu dien la
' '
81
a' tr(» hien thitc
V^t 11LTBH
trgn kSnh
VMn Bt&n
72 (V).
D. 100 V3 (V). ' '
Ve gian do vec to truot.
M
AMB = 45
tai B
nen
N
=^Uc = ^^ = 100V2(V)r^ChpnC.
: .
giac
U 'R
200V
vuong
can
Vt^t
,
N
Uc
200 V2V
A.
=>NMB = 45"=> ANMB la
tai
tam
—f45"
Vi A B I M B nen B pliai nam tren. AAMB
giac vuong can
Huang dan
= U = 200(V) => Chon B.
AAMB Id tam giac deu
Huong dan
la tam
Cty Tiy/ltl MTV D VVtl Khang
B. 60 (V).
A. 80 (V).
C 100
VTV2. t^p 2 - Chu
200V
I
A
n du 5: (GIAN DO L-R-C) Dat dien ap u = 120 V2 coslOOnt (V) vao hai dau
doan mach AB gom hai doan mach A M va MB mac noi tiep. Doan A M gom
cuon cam thuan L mac noi tiep voi dien tro thuan R, doan MB chi c6 tu dien
C. Biet di?n ap giira hai dau doan mach A M va dien ap giiia hai dau doan
mach MB lech pha nhau 2n/3. Di|n ap h i f u dung tren A M bang mot nira
tren MB. Dien ap hieu dung giira hai dau doan mach A M bang
A. 40
V3 V.
B. 220/
73 V.
C. 120 V.. ,
D. 40 V.
Huang dan
1i "
120^ = AM^ + 4.AM^ - 2.AM.2.AM.0,5
tiep voi tu dien. Do lech pha giira cuang dp dong di?n trong mach va dien
ap hai dau mach la 7i/3. Dien ap hi?u dung giira hai dau tu bang Vs Ian
dien ap hai dau cuon day. D Q ]|ch pha ciia di?n ap giira hai dau cupn day
so voi cuong do dong dien trong mach la
A. 71/3.
B. 7t/2.
AM = 40^3 (V)
] Ap dung djnh l i ham so sin cho AAMB:
^
R
L
C. 7i/4.
D . 7i/6.
Ur
sin(60°+9,d)
sin 30°
Chon A.
sin(60"+Vcd^
^
I .
Huang dan:
Ap dung djnh ly ham so cos cho AAMB:
AB^ = AM^ + MB^ - 2.AM.MB.COS60''
i du 7: (GIAN DO Lr-C) Mot doan mach xoay chieu gom cuon day mac noi
M
L,r M
• ^0° +
= 120° =^
= 60°
Chon A.
.B
I
•1^
J
f
B
t:fr:i
Vi du 6: (GIAN D 6 Lr-C) Mach dien gom cuon day mac noi tiep voi tu dien C
Dat vao hai dau doan mach dien ap xoay chieu 200 V - 50 Hz thi di?n ap ha'
dau cuon day va hai dau tu d i f n c6 cung gia tri hi?u dung nhung lech pb^
nhau 120". Dien ap hi?u dung tren tu la
A. lOOV.
B.200V.
, C.300V.
6:
D . 400 V.
du 8: (GIAN DO Lr-C) Dat dien ap 100 V - 25 Hz vao hai dau doan mach
mac noi tiep gom cuon day c6 dif n tro thuan r, c6 do t y cam L va tu dien c6
dien dung C = 0,l/7i (mF). Biet di^n ap hai dau cuon day som pha han dong
i trp kUfn thUc V$t It LTDH tr&n k&nh VTV2. t^p 2 - Chu V^n Biin
dien trong mach la K/6, dong thoi dien ap hieii d u n g hai dau cuon day gap
doi tren tu dien. Cong sua't tieu thu cua toan mach la
A.lOOVaW.
B.50/V3W.
C.200W.
D.120W.
, ^ - Huong dan
Z e = 4 r = 50Tt.^10 = 200(Q)
AAMB vuong nen ME = U,,, sin 30" = — =
U(^- = UK tan30"
100P=
R m)S
A
CV a n t ' !
S
E = B Mach cgng hudng
ChonB. '
,
Vi du 10: (DH - 2012) (GIAN D O C-L-R) Dat dien ap u = Uocosojt (Uo va co
khong doi) vao hai dau doan mgch AB theo thu tu gom mot tu di^n, mot
cuon cam thuan va mot dien tro thuan mSc noi tiep. Goi M la diem noi giua
tu dien va cuon cam. Bie't dien ap hieu dung giua hai dau A M bang dien ap
hieu d u n g giua hai dau MB va cuong do dong dien trong doan mach lech
pha 7r/12 so voi dien ap giua hai dau doan mach. He so cong sua't cua doan
mach MB la
A. 0,5 Vs.
B.0,26.
C.0,50.
D.0,5V2./ '
AAMB can tai M nen 15" +
VMl!
Huong dan
= 75"
9MI3
= 60" => COS ipi^i, = 0,5 => Chon C.
7
15"
.
A
i^i
B
M
15
P;.3 /
JO
/i d^ 9: (GIAN D O C-L-R) Dat di$n ap
u = Udcoscot (Uo va co khong doi) vao
hai dau doan mach AB theo thii tu
gom mot tu dien, mot cuon cam
thuan va mot dien tro thuan mac
noi tiep. Goi M la diem noi giua tu
dien va cuon cam. Bie't dien ap hieu
d u n g giiJa hai dau MB gap N/3 Ian .4
dien ap hieu d u n g giiia hai dau AM
va cuong d o dong dien trong doan
mach lech pha n/6 so vol dien ap
giiia hai dau doan mach. H e so cong
sua't cua doan mach MB la
A. 0,5 7 3 .
C. 0,50.
B. 0 , 5 > / 2 . - V 5 ^
D. 1.
Huong dan
AAMB can tai A nen AMB = 30"
=^ ^p^g = 60" ^ cos VMB = 0,5 => Chgn C.
M
Vi du 11: (DH - 2012) (GIAN D O R-L-C) Dat dien ap u = UocoslOOnt (V) vao hai
dau doan mach AB gom hai doan mijch AM va MB mac noi tiep. Doan
mach A M gom dien tro thuan 100 Vs Q m^c noi tiep voi cuon cam thuan co
dp tu cam L. Doan mach MB chi co tu dien co dien d u n g 10-4/(2TC) (F). Bie't
dien ap gii>a hai dau doan mach AM lech pha 7i/3 so voi dier. ap giua hai
dau doan mach AB. Gia tri cua L bSng
A. 2/71 (H).
.
^
^
__ c•
M
B. 1/TC (H).
d:Miion5ofc iiril) ififi
^,C.V2/71(H). V
•6-¥.&a.D
.V U)l ,f
M
D. 3/71 (H).
• J ^,
/
/
/
1
c.\ts
Huong dan
1 = 200(0).
uC
Tarn^ 1 . giac AMB deu:
-^ = -(H)
=>Z,
=100=>L='^
0)
71
=:> Ch9n B,
'
_
j
, (viob^
Z,. =200
85
Irct lileif^liiltc V^t II LTDtl tren Keitn VTfm;~T^~i - L H U van
men-
d u 12: ( G I A N D O R-L-C) Dat di?n ap xoay chieu tan so 50 H z vao hai dau
du 14: ( G I A N D O C-rL) M o t doan mach g o m
doan mach A B g o m hai doan mach A M va M B mMc no'i tie'p. Doan A M g o m
^^^ dien mac noi tie'p v o i m o t cuon day. Dien
dien t r o t h u a n 100 N/S Q m3c n o i tie'p v o i cuon cam t h u a n c6 do t u cam L ,
ap g'"'^
doan M B chi c6 t u dien c6 di#n d u n g 0,05/K (mF). Biet d i e n ap giiia hai dau
cuong do d o n g dien va lech pha n/2 so v o i
doan mach M B va d i e n ap giij-a hai dau doan mach A B lech pha nhau 7r/3.
di?n
Gia t r i L bang
d u n g giiia hai dau doan mach bang 100 V,
A . 2/71 ( H ) .
,„j,
B. l/7t ( H ) .
Huang
C. V3 In ( H ) .
dan:
D . 31% ( H ) .
JJ'
ay lech pha n/3 so v o i
I
^^^^'^ mach. Biet dien ap hieu
100 V
|
B
Uc
U,
cd
A. 60Vva60V3 V .
B. 200V va 100 x/3 V.
C.60V3Vval00V.
D . 100 ^/3 V va 200V.
^ V i
. Chon B.
L.r
A
cuon day Ian k r g t la
Zc = — = 200(Q) ; AAEB : BE = AE.cotnn- = lOO(O)
wC
3
• Z L = Z C - B E = 100(Q)=^L =
'^^^ cuon'
M
A.
Huang
Ui
30"
M
dan
CO
M
tan 30'
100
Xet A A M B :
=>ChonB.
= 200(V)
sin 30'
.B
V i d u 15: ( G I A N D O C-rL) M o t doan mach dien xoay chieu g o m m o t tu dien
Ur
CO d u n g khang 200 Q va m g t cuon day m^c noi tie'p. K h i dat vao hai dau
Ui
A.
- I
doan
Ur
hieu d u n g la 120 va som pha 7i/2 so v o i dicMi ap dat vao mach. Cong suat
mach
tren
mot
dien
ap
xoay
chieu
luon
c6
bieu
thuc
u =
120Ny5cos(1007tt + 7i/3) (V) thi tha'y dien ap giua hai dau cuon day c6 gia trj
tieu thu cua cuon day la
B
A. 7 2 W .
B . 2 4 0 W . ,?,t
C. 120VV.
Huong
i d u 13: ( G I A N D O R-L-C) Dat dien ap xoay chieu tan so 300 V - 50 H z vao
hai dau doan mach A B g o m hai doan mach A M va M B mac noi tie'p. Doan
D. 144 W .
dan
C
A A M B la can tai B:
M
L,r
A.
„ 1 ,^
•B
f
Uc = V M B ^ T A B ^ = ^20^/2 ( V )
•\
I
A M g o m d i e n t r o t h u a n mac noi tie'p v o i cuon cam thuan, doan M B chi c6
tu d i f n . Biet d i e n ap hieu d u n g giii'a hai dau doan mach M B la 140 V va
d o n g d i e n t r o n g mach tre pha h a n dien ap hai dau doan mach A B la cp sao
V
I = - ^ = 0,672 (A)
B. 200 V .
C. 500 V . •
Huang
A E = 300cos(p = 240(V)
D . 400 V .
A A M B la can tai B :
=
60V2 ( V )
B
120V
\
M
t : Wall.,
N
^ ' du 16: ( G I A N D O R-C-L) Tren doan mach xoay chieu k h o n g p h a n nhanh c6
• E M = EB + B M = 320
bon d i e m theo d u n g t h u t u A, M , N va B. GiiJa hai d i e m A va M chi c6 dien
A M = 7AE^ + E M ^
1H)
.
=
=>Pr =!'r = i.U, =72(W)
«
Chon A .
=:>ChonD.
^
!,
dan
BE = 300sintp = 300Vl-cos (p =180
= ^240^ +320- = 400 ( V )
120V
1
cho coscp = 0,8. D i e n ap hieu d u n g giija hai dau doan mach A M la
A . 300 V .
f
thuan, giua hai d i e m M va N chi c6 tu dien, giua hai d i e m N va B chi c6
^Uon cam thuan. Dat vao A B m o t dien ap xoay chieu 120 V - 50 H z thi dien
tuc thoi tren doan A N va tren doan A B lech pha nhau 60", dien ap tiic
87
io trf> hicn
thuc
Vat li LTBtl
tren
henh
VTV2,
lii/i
( liu
J
Vein
Bien
t h o i tren d o a n A B va tren doan N B lech pha nhau 60". D i e n ap hieu dung
H i n h thoi c6 goc 60
giCra hai dau tu d i e n la
A . 120 (V).
B. 6 0 ( V ) .
C. 6OV2 ( V ) .
D . 100 (V).
' '
A A N B deu
1
U AN
' •
' Humtgdan
,},!•
nen:
NB = A B = 1 2 0 ( V )
< n i : yiiijo
tUi.rn
iiSioh
r Y '
nov
'
A^60«
= 60(V)
M
2
u,.
= 60N/3(V)
COS a
V i du 18: ( G I A N D O R-C-rL) Tren doan mach xoay chieu k h o n g phan nhanh
CO bon d i e m theo d u n g thiV t u A , M , N va B. Giua hai d i e m A va M chi c6
M
Up
f
dien t r o thuan, giua hai d i e m M va N chi c6 tu dien, giua hai d i e m N va B
C
chi CO cuon cam. Dat vao hai dau doan mach m o t dien ap xoay chieu 240V 50 H z t h i UMii va UAM lech pha nhau 7x/3, UAIS va UMH lech pha n h a u 7t/6. D i e n
,Vt)(
=> C h o n B . J
N
CM
• a = 30"
Binh luan: Cdch gidi2 phdi ve nhieii dieang net phicc tapl ' .'WMH •'*>
• ''
NB
=>Ur = M N =
Cdch 2: D u n g p h u o n g phap vec to buoc:
y: Doi vai mach c6 4 phan tu tra len ma khong lien quart den dien ap bat chco
heme R a giila thi nen diing phivang phdp vec ta tnegt.
ap hieu d u n g tren R la
A . 80 (V).
B. 60 (V).
C.80>/3 (V).
D. 6 O V 3
B
A A N B can tai M :
dien t r o thuan R, giira hai d i e m M va N chi c6 tu dien, giua hai d i e m N va B
fyz A B M = 60" - 3 0 " = 3 0 " )
chi CO cuon cam. D a t vao hai dau doan mach m o t dien ap 90 V3 V - 50Hz thi
Theo d i n h ly h a m so'sin:
d i e n ap hieu d u n g tren R va tren doan M B deu la 90 ( V ) . D i e n ap tuc thoi
UR
AB
hai d a u doan mach A N va M B lech pha nhau nil. D i e n ap hieu d u n g tren
sin 30"
sin 120"
'^'^^^
D . 6OV3 ( V ) .
C.IOOV2 ( V ) .
Huang
dan
'30""^
R
Ur
A
R
•-cz:
M
N
L,r
f
•
^
N
=> C h o n C.
c u o n g do hieu d u n g qua mach la 0,5 A . Doan A M g o m d i e n t r o thuan R
• £1 -
u
UMB
••••••
*
/:
90/
:
mac noi tiep v o i t u dien C, doan M B g o m cuon cam. Biet d i e n ap g i u a hai
dau doan mach M B va dien ap giija hai dau doan mach A B lech pha nhau
7i/2. D i e n ap hieu d u n g tren R bang m o t nua dien ap h i e u d u n g tren doan
90>-'''
A M . C o n g suat tieu t h y cua mach la
I
A. 60(W).
B.90(W).
C.90V3(W).
D.60V3(W).
III
Huang
A A M N :sin(p =
Ur
''''' "'^'^
AN
AM
AN
• coscp = yjl - sin^ (p =
M
s
^'''
P = U I coscp = 120V3.0,5.— = 9 0 ( W )
UAN = - ^
cos a
58
„ cIA ±
hai dau doan mach A B g o m hai doan mach A M va M B mSc n o i tiep thi
m't.
A A M B can goc a day 30" => a = 30"
B
V i du 19: ( G I A N D O R-C-rL) Dat dien ap xoay chieu u =120 V6 coscot (V) vao
u,,t
Zdch 1: D i i n g p h u o n g phap vec to trugt:
120V
A .
„
=> U R = 8 O V 3 ( V )
B.60(V).
%
UT
CO bon d i e m theo d u n g thir t y A , M , N va B. Gifra hai d i e m A va M chi c6
A.80(V).
.d
Huong dan
/ i du 17: ( G I A N D O R-C-rL) Tren doan mach xoay chieu k h o n g phan nhanh
doan A N la
.-n
(V).
= 6OV3(V)
• Chon B.
dan
Bo
t r p k i e n thiic
V^t l i LTOH
tren henli
VTV2.
t a p 2 - Chu VHn B i e n
W\u 20: ( G I A N D O Lr-R-C) Tren doan mach xoay chieu tchong phan n h a n h
yf dV 22: ( G I A N D O Lr-R-C) Tren doan mach xoay chieu k h o n g phan nhanh
CO bon d i e m theo d u n g t h u tir A , M , N va B. G i u a hai d i e m A va M chi c6
CO bon d i e m theo d u n g thu' t y A , M , N va B. Giua hai d i e m A va M chi c6
cuon day, giua hai d i e m M va N chi co dien t r o thuan R = 60 Q, gifra 2 d i e m
cuon day, giua hai d i e m M va N chi c6 dien t r o thuan R, giua 2 d i e m N va B
N va B chi c6 tu dien. D i e n ap hieu d u n g giua hai d i e m A va N la 120 (V) va
CO tu dien. D i e n ap hieu d u n g tren A B , A N va M N thoa m a n he t h i i c
d i e n ap h i ^ u d u n g hai d i e m M va B la 80A/3 ( V ) . D i e n ap tiVc t h o i tren doan
0,^15 = U A N = U M \ N/3 = 120N/3 ( V ) . D o n g hieu d u n g t r o n g mach la 2 N/2 ( A ) .
A N va tren doan M B lech pha nhau 90", dien ap tiic t h a i tren M B va tren N B
Dien ap tiic t h o i tren A N va tren doan A B lech pha nhau m o t goc d u n g
lech pha nhau 30". D i e n trcV thuan cua cuon day la
bang goc lech pha giua d i e n ap tiVc thoi tren A M va d o n g dien. T i n h cam
A. 40Q.
B. 6 0 Q .
C. 30 Q .
Hu6iig
' »
D . 20 Q .
khang cua cuon day.
A.60N/3Q.
dan
N
U«
A M N B i M N = UK =MB.sin30" = 4 0 V 3 ( V )
B.1576Q.
C. 3 0 V 3 Q .
Huong
D. 30-./2Q.
dan
A A N B can tai A ma M A I = N A B
>
A
^mms'^
UL
120'
A A E N ^ E N = AN.COS30" =60N/3(V)
=>
/
Uc
• •
N
g
L,T
SOVJV
«y
120
N
= E N - M N = 20^/3
30"
=^- = ^ = -=>r
R
UR
=> A A M N can tai M vd a = 30"
= - = 30in)=> ChonC.
B 4
Vi du 21: ( G I A N D O Lr-R-C) Dat dien ap xoay chieu u = 120>y6 coscot (V) vao
U L = ^ 2 0 ^ / 3 s i ^ a = 60^/3
=^ZL
=^
/
= 15V6(Q)
hai dau doan mach A B g o m hai doan mach A M va M B mac no'i tiep. D o a n
A M la cuon day c6 dien t r o thuan r va c6 do tir cam L, doan M B g o m dien
=> Chon B .
t r a thuan R mac noi tiep v a i tu dien C. D i e n ap hieu d u n g tren doan M B
gap d o i d i e n ap hieu d u n g tren R va c u o n g do hieu d u n g cua d o n g d i e n
t r o n g mach la 0,5 A . D i e n ap tren doan M B lech pha so v a i dien ap hai dau
doan mach la n/2. C o n g sua't tieu thu toan mach la
A. 150W.
m^iruhi
B.20W.
.M-).of8A f , i r : f . . '".i/ri:-
A M F B : sincp =
C.90W.
Huvngdan
D . 100 W .
-
Vi du 23: ( G I A N D O C-R-rL) M o t mach dien xoay chieu n o i tiep g o m tu dien
CO d i e n d u n g C, dien t r a thuan R va cuon day c6 d o tir cam L c6 dien tro
thuan r. Diang v o n k e c o dien tro rat Ian Ian l u g t do hai dau dien tro, hai
U,,
= 0,5 =:i> cp = •
dau cuon day va hai dau doan mach t h i so chi Ian l u g t la 50 V, 30V2 V va
u Mti
P = UI COS (p = 120 V3.0,5 cos - = 90 ( W )
6
• Chon C.
80 V . Bie't d i e n ap tuc t h a i tren cuon day som pha h o n d o n g d i e n la 7i/4.
Dien ap hieu d u n g tren tu la
B. 30V2V.
A . 30 V.
C. 60 V.
D.20V.
Hu6itg dan
A
M
R
^AMB
=^ Tii gidc AMNB
= MN + NE = 80V = AB
=*-ChonA.
1 •d
>
Id hmh ch a nhat
= > U c = A M = EB = 3 0 ( V )
Kinh nghicm: Khi cho bie't do lech pha bang nhau thi tren gidn dovec ta c6 the c6
tamgidccdn!
/
; i • ,5-.:
• 1 , 1 ' ,i
Id tarn gidc uuong can tai E
=>NE = EB = 30V^ME
>
*
,
: •
'
91
ISO TTp Rfen
thiTc
vpt
n L m n
tn
->
I
B
A
c
R
M
L,
N
r
.B
Cty
A A E B :
A B -
=
TISnn
MTV o w n Khang
3200 = (25 + x ) ' + [ 6 0 - V 6 2 5 - X -
A E ^ + EB^
Vlft
N
= 15
P
30V
P=IUcoscp = I.AE=>I = — =
=>ChonB.
M
40
U
-
= ] ( A ) ^ r = Y-
= 15(Q)
^^^^
.
30V
V i d u 24: ( G I A N D O C-R-rL) M o t mach dien xoay chieu noi tiep A B g o m : doan
A N chiVa tu dien C noi tiep v o i dien tro thuan R va doan N B chi c6 cuon
day CO d o t u cam L ccS dien tro thuan r. Dien ap hieu d u n g tren cac doan
A N , N B va A B Ian l u p t la 8 0 V, 1 7 0 V va 1 5 0 V. C u o n g d o hieu d u n g qua
Co thedimg may Huh Casio 570cs
mach la 1 A . H e so cong sua't cua doan A N la 0 , 8 . T o n g dien t r o thuan cua
degiai phieong trinh va bam uhir saii:
toan mach la
i
A. 1 3 8 Q .
B. 3 0 N / 2 Q .
Huattg
i
Bam
C. 60 Q.
D . 9 0 Q.
ANPm
Gidi phiidng tr i nh:
dan
B
Nkap xong bajn \SHIFT\CALC\
•i •
R
N
r
=
Ur
(^dc CO canh tiCdiig ling vuong goc)
M
A F = ABsincpAN = 9 0 ( V )
U K + U ,
AF
I
I
=
Z
\
A
U
R+r
N
cuon day c6 cam khang 100 n c6 dien t r o r = 0,5R, giiJa 2 d i e m N va B chi c6
tu dien c6 d u n g k h a n g 200 Q. Dien ap hieu d u n g tren d o a n A N la 200 (V).
D i e n ap tuc t h o i tren doan M N va A B lech pha n h a u n/2. N e u bieu thuc
tro t h u a n r va tu dien C t h i cong sua't tieu t h u cua mach la 40 W . Bie't dien
d o n g dien t r o n g mach la i = IV2 cos(1007tt + (pi) A t h i gia t r j cua I va cpi Ian
l u p t la
A. 1
A
va K / 3 .
B.
Cdch 1: Pliu'ongplidpdqiso':
«"iW,,
--^m, ,?5^Vi 4 - V i W \ 7\M., X-^. 'AM',
Z,
ni'c D.3on.
92
: N E =
X / M N '
- M E '
=
sjeiS-x^
E B = 60 -
A
^b25-y}
,
.jfv n o d r >
s,
va K/3.
U
C.
+ Z
A
va 7r/4.
^y'
Z, - Z r
D . 1 A va 7i/4.
| ,y
v
= -l=>r =
IOON/S)^
100
(O)
( i HA
200
AN
V2
Humgddn
R+r
Huong Mn
A M N E
V2
.
ap h i ^ u d u n g tren dien tro, tren cupn cam va tren ty d i ? n Ian l u p t la 25V,
C.20Q.
V vao hai
G i i i a hai d i e m A va M chi c6 dien tro thuan R, giu-a hai d i e m M va N chi c6
Ur
( <i>AH
dau doan mach noi tiep g o m di$n tro R, cuon cam c6 d p t u cam L , c6 dien
B. IS n .
^ ,v
dau doan mach A B . Doan A B c6 bon die'm theo d u n g t h u t u A , M , N va B .
V i d u 25: ( G I A N D O R-rL-C) Dat dien ap xoay chieu u = SOcoscot (V) vao hai
A. s o n .
_
^
V i d u 26: ( G I A N D O R - r L - C ) Dat dicfn ap u = U ^ / 2 cos(100Tct + n/6)
\80V
90(Q)=>ChonD.
25V va 60 V. Gia t r j r bSng
{AI^IPHA^
ta se t i m d u o c he so cons sua't va cong sua't:
UT
i7oy/
=> A B F = A N M =
=:>R + r =
/
f->
A N H A B ^
Bmn
Doi v o i loai bai toan nay mat xich quan t r p n g la t i m U r . Sau k h i t i m d u p e Ur
.B
A A N B la tarn gidc ywong tai A v\:
NB^
+(60--j625-
xf
Bam liNPHiQ
=0'6
M
CALC
3200 = (25 +
Tarn gidc uuong A A M N : COS9AN = 0 , 8
COS 9 A N
f
= 1(A)
+100^
93
Bo" t r p h f S n
fan cp =
thurc
V^t I I L T D H
tren kenh
VTV2.
t^p 2 - Chu
R + r^ " " ^ " ^ " ^ " " f
V^n
BIcn
C/y
^""^ P'''^ h o n d o n g dien la 7t/6
iiay d o n g dien sam piia hon dien ap la Tt/6.
=> i = l72cos 1007rt + - + - l = 72 COS
6 6
T/VHHMTV
DVVHKhang
Vift
V i d u 27: Tren doan mach xoay chieu k h o n g phan nhanh c6 bo'n d i e m theo
f-diing t h u t u A , M , N va B. Giua hai d i e m A va M chi c6 dien t r o R, giua hai
i; d i e m M va N chi c6 cuon cam ma dien t r a thuan r = 0,5R va d o t u cam L =
1007tt +
-
' 1/n H , g i i i a 2 d i e m N va B chi c6 t u dien c6 dien d u n g C = SO/TT ^ F . D i e n ap
( A ) = > C h o n A.
hieu d u n g tren doan A N la 200 V. D i ^ n ap tren doan M N lech pha v a i dien
ap tren A B la Tr/2. Bieu thuc dien ap tren A B la UAH = Uocos(1007it + TT/12) V.
7:V
Bieu t h u c dien ap tren N B la
MN
A. UNB = 2 0 0 V 2 c o s ( 1 0 0 T T t + 5Ti/12)V.
B. UNB = 200N/2 cos(1007Tt - 7i/4)V.
C. UNB = 200cos(1007Tt + Ti/4)V.
o
I
D . UNB = 200 V2 cos(100rt + 7n/12)V.
Huong
G
- I
dan
Z, = u L = 100(Q);Z^-= — = 200(Q) = 2Z, : A M la duang trung tuyen
cuC
cua
A A N B . Suy ra, M la t r o n g tarn cua A A N B . M a t khac M cung la true tam nen
id
•,v;i(;r
N B = 200V
> U
AD
A A N B la t a m giac d e u .
U|vjB =
200\/2
COS
tri hdn U ^ g la —
a = — => U ^ i B
(V)
lOOTltH-
12
Chon B .
3)
T o n g h o p cac vec to d i ^ n ap theo quy tac h i n h b i n h :
iiS',:' Sir
Xet AOEF ( U A N = 2 0 0 V, H la t r u n g d i e m EF, O G = G H ) d i e m G v u a la
tarn vira la true tarn nen tarn giac nay la tarn giac deu. - :
.
Uc = 2 0 0 V = > I = H c
>i = V I COS
1007Ct +
- + -
6
dch 3: Phuvng phdp gidn do vcc ta tnivt:
M vira la t r o n g tarn v u a la
true
tarn
cua
tarn
^
^
M
A A M B nen tarn giac nay la
tarn giac d e u .
T u do suy ra:
r
L
nzHD-^—O^Wfff^
.
giac
6)
N'l
B
N
N
nguai ta dd "sang tdc" ra cac "hai todn la",
; • . , ilpkil^M ^ i -
,,
U C = U A N =200(V)
_
/ u!
•M
va I s o m p h a h a n D^^g la7t/6.
D o do: i = V2cos
6
67
'i d u 28: D o a n mach xoay chieu A B g o m hai doan A M no'i tiep v a i M B . Doan
„
M
Kinh nghicm: Ne'u tavi guic ANB deu thi Zc. = Zt. vd R = 2r. Dim vcio y twang nay
A M g o m dien t r a t h u a n R noi tiep v a i cuon cam c6 dien t r a r va doan M B
chi CO tvi dien. D i e n ap tren doan A M va A B c6 cung gia t r i hieu d u n g
n h u n g lech pha nhau 60". D i f n ap tren cupn .cam v u o n g pha v o i d i ^ n ap
tren A B . T i so r/R la
(A):
A . as.
- ''^
B.2.
'
C.l.'ryr.,.,^^lf,^
D.
0,87.
B
9S
Cty
Hudng dan
c
r,L
R
D
II.
60
A
B
M
-0,
(J
I
60 \
. G
0.
60
? 60 \
u.
0.
D
\
60
V
Vift
B
^
TL
M
M
3
A
it,<: Tarn giac A M B la tarn giac deu vi c6 A M = A B va goc MAB = 6 0 " . Do do, G
J vCra la true tam vua la trong tarn => UR = U r => R = 2r => Chon A .
TNilHMTVDVVnKhang
0,
B
B
Clu'i y: Voi mot bai todn cu the c6 the dimg hoqc phicang phdp dqi so hoqc phitang
/»««: Voi bai todn nay thl pitirong phdp vec ta trugt hay han phuang phdp vec
ta bugc. Nliung trong vi du tie'p theo thl ngugc Iqi.
phdp gidn dovcc ta biioc lioqc phiivng phdp gidn dovec ta trwgi. Trong ba cdch gidi
Vi du 30: Mach dien xoay chieu noi tie'p c6 bon diem theo dung thu t u A, M , N
do vffi mot dang cu the tin se c6 mot cdch gidi nhnnh vd ngdn ggn nhd't.
va B. Giua hai diem A va M chi c6 tu dien, giua hai diem M va N chi c6
V i du 29: Dat dien ap xoay chieu 60 V - 50 Hz vao hai dau doan mach AB gom
hai doan mach A D va DB mac noi tie'p. Doan A D gom dien tro thuan noi
tie'p cuon cam thuan, doan DB chi c6 tu dien. Dien ap hieu dung tren A D va
tren DB deu la 60 V. Hoi dong dien trong mach som hay tre pha hon dien
dien tro R, giua 2 diem N va B chi c6 cuon cam thuan. Dien ap hieu dung
tren doan A N va tren MB la 120 V2 V va 200 V. Dien ap tuc thai tren doan
A N va MB lech pha nhau 98,13". Tinh dien ap hieu dung tren R.
A. 120 V.
B. lOOV.
ap hai dau doan mach AB?
Huong dan
A. tre pha hon 60".
C. som pha hon 30".
^rt^-
B. som pha hon 60".
' ' '"^^<;',
jl
L
D. tre pha hon 30".
...
" • '•
Huang dan
= U?^ +
U?<+(UL-UC;
60^
602
i •'•
•
D. 160 V.
1 .
Cdchl: Phuang phdp vec ta trugt.
v ,
m
"^v ^w'
N E - = A E " + AN^ -2AN.AEcos98,13" => NE w 280
AN
NE
.
situT"" sin98 13" ^ ^'"'^ ^ ^ ' ^
Cdch 1: Phwang phdp dai so
U' =
C.250V.
" MB.sina
120(V) => Chon A.
- 2UL U C
+
602
UL
60
=30
U R = 30>/3
on
60^
tan ^ =
-—^ => ip = - — => Chon C.
S
6
R
Cdch 2;
n..i
''fil'''''
Phuang phdp vcc to bugc. T u A O U U A D deu =^ 9 = - .^
Chon C.
h'iv- Jijiq
Cdch 3;
Phuang phdp vec ta trugt. T u A A D B deu =^ 9 = — =^ Chon C.
'
6
MS)
.0
^dch 2: Phuang phdp vec ta bugc.
EF^ = OE^ + O F ' - 20E.OFcos98,13"
OF
EF sr. 280
EF
=
rr =^ siua
Sm
96
w'.
JJ
, mil
0,6 =^ U R = O E . s i n a = 120(V)
Bwiij
cjf, (•».,.; J { ! ) • / ( « ; .•V.,T. f . r t r
Chon A
'
BS
trp
kl^n
thiic
V^t
II LTDIf
trin
kinh
VTV2.
t^p
2 - Cbu
VSn
Btin
D. 1/ N/3 A va tre pha K/6 S O voi dien ap giiia hai dau doan mach.
Huong dan
nf
Khi mac noi tiep, ve gian do
vec to truot, tu tam giac vuong
can A M B :
MBA = MAB
Up
V i du 31: Co hai hop kin X va Y chi chua cac phan tu ghep noi tiep va trong
chung chi c6 the chua cac dien tro thuan, cuon cam va tu dien. Khi dat dien
ap xoay chieu 220 V - 50 Hz vao hai dau X, thi dong dien c6 gia trj hieu
!; dung 2 A va som pha so voi dien ap la n/2. Neu thay X boi Y thi dong dien
; CO gia trj hieu dung van bMng 2 A nhung ciing pha voi dien ap. Khi dat dien
, ap do vao doan mach gom X va Y mac noi tiep thi dong dien c6 gia trj hieu
J dung la
^
A. V2 (A) va tre pha 7T/4 SO voi dien ap.
B. yfl (A) va som pha 7T/4 SO voi dien ap.
Jt/4
\220V
C. 0,5 y/l (A) va som pha n/3 so voi dien ap.
D. 0,5 %/2 (A) va tre pha TT/3 so voi dien.
Huang dan
M-
U
220
Zv — Zv — — — = 110(Q)
I
2
Khi mac noi tiep, ve gian do vecta trugt, t u tam giac vuong can A M B :
0
M A B = 45'
Zn
110
Tir gian do suy ra dong dien som pha han dien ap la n/4 => Chon B.
Vi dv 32: Lan luot dat dien ap xoay chieu 220 V - 50 Hz vao cac dung cu P va
Q thi dong dien trong mach deu c6 gia tri hieu dung bang 1 A nhung do'
voi P thi dong som pha hon so voi dien ap do la n/3 con doi voi Q thi dong
cijng pha voi dien ap do. Biet trong cac dung cy P va Q chi chua cac diC'i^
tra thuan, cuon cam va tu dien. Khi mac dien ap tren vao mach chua P va Q
mac noi tiep thi dong di^n trong mach c6 gia trj hieu dung la
; A . 0,125 V2 A va tre pha n/4 so voi dien ap giua hai dau doan mach.
sin
MBA
Z,,
V
220V
Up
,0
^
30'
220,,,,
u
=*Up-—(V)
73
sin AMB
tr
220
220V3
.1.
\
M
1 1
V3
:A)
3
B
Tu gian do suy ra dong dien som pha hon dien ap la 71/6 => Chon C.
n du 33: Lan hrgt dat diCfn ap xoay chieu 220 V - 50 Hz vao cac dung cu P va
Q thi dong dien trong mach deu c6 gia trj hieu dung bang 5,5 A nhung doi
voi P thi dong tre pha hon so voi dien ap do la n/6 con doi voi Q thi dong
som pha hon so voi dien ap do la n/2. Biet trong cac dung cu P va Q chi
chua cac dien tro thuan, cuon cam va tu dien. Khi m^c dien ap tren vao
mach chua P va Q mSc noi tiep thi dong dien trong mach c6 gia tri hieu
dung la
A. 11 V2 A va tie pha n/3 so voi dien ap giua
hai dau doan mach.
'
'
'
'
'1/
B. 1] 72 A va som pha n/6 so voi dien ap
giua hai dau doan mach.
C. 5,5 A va som pha n/6 so voi dien ap giua
hai dau doan mach.
D. 5,5 A va tre pha n/3 so voi dien ap giua hai
dau doan mach.
'
Humgdan
2,. = z„ = H , | £ . „ , „ ,
I
5,D
Khi mac noi tiep, ve gian do vec to trugt, tu tam giac vuong can AMB:
Up = Uo = U = 220(V)=>I =
220 = 5,5(A)
40
Tu gian do suy ra dong dien som pha hon dien ap la n/6
=::>ChonC.
I'J' \
B. 0,125 N/2 A va som pha n/A so voi dien ap giiia hai dau doan mach.
C. 1/N/3 A va som pha n/6 so voi dien ap giua hai dau doan mach.
99
Cty
Bo ttv
hien
tliiic
Vat li LTDII
tren henh
5) Dung gian do vec to de viet bieu thiic dong dien hoac dien ap
* Neu cho biet t u a n g minh cac dai lugng tlii nen d u n g pliuong pliap dai so
hoac p h u o n g phap so phiic de vie't bieu thuc.
* Neu con c6 mot vai dai luong chua biet thi de vie't bieu thuc mot each hieu
qua nhat la d u n g gian do vec to.
Vi du 1: Mot doan mach gom dien tro thuan R noi tiep voi tu dien c6 dien
d u n g l/(37t) (mF). Dat vao hai dau doan mach mot dien ap xoay chieu:
u = 120cosl007rt (V). Dien ap hieu dung giua hai dau dien tra bang 60 V.
Tinh R va vie't bieu thiic dong dien qua mach?
A. R = 30 Q va i = 2 V2 cos(l OOTit + 7i/4) (A).
B. R = 30 Q va i = N/2 COS(1 OOTit - 7t/4) (A). ^
C. R = ^0^/3 Q va i = 4cos(1007it - 7t/6) (A).
D. R = 30 p ya i = 4cos(lQ07Tt + K/6) (A).
Zc
'
R = Zc =
30(n);U2..u2
30Q
_^Z-R + i ( 0 - Z c ) '
1= —
Huong dan
60^2
60^ + vl
120 • = 272Z1
30 - i.30
=^ Uc = 6 0 = U R
!*,,V',0?:
i = V2(cos 100TTt + - (A): Chon A.
4 chieu u = 60 >/2 cosl007:t (V) vao hai dau doan mach
Vi du 2: Dat dien ap xoay
AB gom hai doan mach AD va DB mac noi tiep. Doan AD gojn dien tro
thuan R m a c noi tiep voi cuon cam thuan L = 0,2/7i (H), doan DB chi c6 tu
dien C. Dien ap hieu dung tren doan AD la 60 (V) va tren doan DB la 60 (V).
Bieu thuc dong dien qua mach la
A. i = V2cos(1007tt + 7i/4)(A).
R
L C
B. i = 4.cos(1007rt + 7r/3)(A).
''''' r - t > ' > ' u . A
B
C. i = 4.cos(100T:t - n/6) (A).
D. i =1,5 N/2 cos(1007tt + 7t/6) (A).
Huong dan
Cdch 1: KS't hap phwang phdp dai sova phmmg phap sophu'c
UL = 30
'
60^=0?^+(UL-60f
UK = 30V3
60^ = UK + UL + 60^ - 120UL ^ U c = 6 0
'a
60^
I = ^ = 1,5(A)
60^ - UK + UL
1 nn
TISHHMrtVDWH
Khang
Vi^,
VTV2. t^p 2 - Chu V^n Blen
R = i:?^ = 20V3
Z.=Hc=40
=>Z=R+
i (ZL-Zc) = 2073+,
u _
- =
\,5^Z-nZ 20V3 + / ( 2 0 - 4 0 )
6
100;r/ + - ( / i ) = > C h o n D .
6
J
Cach 2: Phimng phap gian do vec ta huge
' i»
Zi, = LJL = 20(n)
,
i.!
(20-40)
It
60
V,
60
•
;:
AOUU^D la tarn giac deu hen: a = 7t/6 va Ui, = UAD/2 = 30 (V).
Dong dien som p h a hon dien ap la Tt/6 va c6 gia tri hieu dung:
I = i : ^ = l,5(A)
i = l,5V2cos
100Ttt + - +
-
(A)=>ChonD.
6 6
Cdch 3: Pkiecrng phdp gian do vec to'tnt'fft
I
'-J.
AADC la tam giac d e u nen: a = n/6 va UL = UAD/2 = 30 (V).
Dong dien s a m pha h a n dien ap la n/6 va c6 gia trj hieu dung:
I = - ^ = 1,5(A)
cl
i = l,5V2cos 100TVt + - + •Chon D.
6 6
Vi du 3: Mach dien g o m cuoii day mac noi tiep vai tu dien C. Dat vao hai dau
doan mach dien ap xoay chieu u = 200cos(1007tt + 71/12) (V) thi dien ap giira
hai dau cuon day va hai dau tu dien c6 cijng gia tri hieu d u n g n h u n g lech
pha nhau 120°. Bieu thuc dien ap giiia hai dau cuon day la
A. ucd = 100 V2 cos(1007tt + n/3) (V). B. ucd = 200cos(1007tt + n/6) (V).
C. Ucd = 200cos(1007it + 71/3) (V).
D. ucd = 200cos(1007rt + 57i/12) (V).
Tir gian do ta suy ra,
AAMB la tam giac
deu, vi vay, Ucd c6
cung bien d o n h u u
nhung sam pha han
U la 7r/3 => Chon D.
Huang dan
[ft
L,r
M
M
miG
-B
jj
'cd.
60"
• I
A
, U
100V2V
Uc
B
101
S'f/y
A/an
thurc
V^t
l i LTDI1
tren
hcnh
VTVJ.
l.ijt
2 -
Chu
Vdn
B i e n
i d^ 4: Dat d i e n ap xoay chieu u = 100 N/6 cos(100Kt + n/4) (V) vac) iiai dau
doan mach g o m m o t cuon day va m o t tu dien mac noi tiep. D u n g v o n i
dien t r o rat Ion Ian l u g t d o dien ap giira hai dau cuon cam v i i hai ban tu
Huang
R
r
•-HI—c =^—rmsx<—•
dan
Xtr gian d o ta de tha'y, A A M B la tam
giac v u o n g can tai M nen:
W2
i:
U,^(_ trG pha h
d i e n t h i tha'y c h u n g co gia t r j Ian i u o t la 1 0 0 V va 200 V. Bieu thuc dien ap
/a)
gii>a hai dau cuon day la:
A . U a l = 100 N/2 C 0 S ( 1 OOTtt + 71/2) (V). "
- = 60>/2cos
F) <
'
c
B. Uccl=200cOS(1007tt + 7t/4)(V).
(V)=>ChonD.
Chii y: Dim vao dm hicii vuoiii^ plin va dung pineang phdp loai trie c6 thcplidt hien
C. ucd = 200 N/2 C O S ( 1 OOTtt + 3n/4) (V).
nhanh phuvng du dung lud kliong can phdi su dung hct du kien ciia hai todti.
D . ucd = 100>/2 cos(1007ct + 371/4) (V).
J,
4j
y
M "f »\
Huaitgdan
V i d u 6: Doan mach A B g o m A M chua dien t r o t h u a n R mac no'i tiep v o i m o t
tu dien, M B chua cuon day co d i ^ n t r o thuan r = R. D a t vao hai d a u A B dien
ap xoay chieu u = 100 ^I2 coslOOnt (V) t h i dien ap giua hai d i e m A M va g i i i a
hai d i e m M B l§ch pha so v o i c u o n g d o d o n g di§n Ian l u g t la 7T/6 va
n/3.
Bieu thuc dien ap giua hai d i e m A M la
lOOV
A
A . U A M = 50 V2 cos(lOOTtt - Tt/3) V.
B. U A M = 50 V2 cos(lOOTtt - Tt/6) V .
C. U A M = 100cos(100Ttt - TT/3) V.
D. U A M = 100cos(100Ttt - Tt/6) V.
Huang
Uc
u
Vi
200V
100V3V
U/,^M
^^'^
ph''' ho'" ^ la
dan
con
sam pha h o n / la 7t/3 nen U ^ j ^ 1
U^B
hay A A M B v u o n g tai M . T u d o suy ra
B
U^^i tre pha h o n U^^u m o t goc a sao
cho A M = ABcosa. Ta nhan tha'y chi
p h u o n g an A thoa m a n d i e u kien nay
=>ChonA.
Tit gian d o ta de tha'y, A A M B la t a m giac v u o n g tai A ( v i MB^ = AB^ + A M ^ )
Uj.j sdm phahanU
Id—
^A,rif;d E9ig''qSrfi^iffc';j,iJf^^^^
TV H
u<.d =100V2cos 1 0 0 T t t + - + - ( V ) = > C h o n D .
4
2J
,
roi mac n o i tiep v o i cuon day. Dat vao hai dau mach m o t d i ^ n ap xoay
chieu u = 120cosl007tt(V). D i ^ n ap hieu d u n g 6 hai dau doan mach RC la
60V va hai d a u c u o n day la 60 V . Bieu thuc dien ap hai dau d o a n mach
RC la
A . U R c = 60cos(100nt + H/4) V.
B. U R C = 60 V2 cos(100Tit + n/4) V.
C.
D.
60cOS(1007Tt - 7T/4) V .
U R C =
nen vegian do vec ta trugtl
„
K
,,-,4,.
..
-
'
••'
V i d u 7: Tren doan mach xoay chieu k h o n g phan nhanh co b o i i d i e m theo
d i i n g t h u t u A , M , N va B. Gii>a hai d i e m A va M chi co c u o n cam thuan,
giCra hai d i e m M va N chi co dien tro thuan, giua 2 d i e m N va B chi co tu
dyi 5: M a c h d i $ n xoay chieu g o m d i e n t r o t h u a n R mac noi tiep v o i t u dien
URC =
CM y: Khi cho lien qua den dien dp Ian luvt deviei bieu thiec dien dp bat cheo ta
60 -Jl cos(lOOTtt - Tl/4) V .
dien. D i e n ap hieu d u n g tren doan A N la 300 V va lech pha v o l d i f n ap tren
N B la 5TT/6. Bieu thuc d i e n ap tren N B la
U N B =
50V6 cos(1007it - 27i/3) V.
i D i ^ n ap tuc t h a i tren M B la
;;A. UMB = 1 0 0 N / 3 c o s ( 1 0 0 7 i t - 5 T t / 1 2 ) V.
'
"^'^-^-VK^
^B.uMB = 100>/2cos(100Txt-Tt/2) V.
,
;'C. UMB = 5 0 V 3 c o s ( 1 0 0 T t t - 5 7 T / 1 2 ) V .
' D . uMB = 100V6cos(100Ttt-Tt/3) V .
•}!?.'•
'•
#
:
>;-v:
; ,
103
Huang dan
V i du 2: Cho doan mach xoay chieu A B gom dien tro R va m o t cuon day mac
noi tiep. Dien ap dat vac hai dau doan mach c6 tan so' f va c6 gia t r i hieu
N
M
d u n g U k h o n g d o i . D i e n ap giiia hai dau doan mach lech pha \i
/5J1/6
la 7T/4. De he so cong suat toan mcich bc^ng 1 thi n g u o i ta phai mac n o i tiep
v a i mach m o t tu d i e n va k h i d o cong suat tieu thu tren mach la 200 W . H o i
khi chua mac t h e m tu t h i cong suat tieu thu tren mach bang bao nhieu?
A . lOOW.
SOVJV
B. 1 5 0 W .
C. 7 5 W .
D . 170,7 W .
Huong dan
' li
.
'j
< U u i (I
Si)
ill
u
fi
m
M
Iff
^ *
art'
rj
, i , i >,'!i
2
v
T u cong thuc: P = — cos 9 = I',,^^^,
i
R
B
P = 200cos^ ^ .... lOO(W)
i *
M N = 300cos60" =150
A M N B vuong tai N •
Chon A.
MN
lOOitt
2ii;
NB
Tt
+ 3
3
p
i;
= V3 =i> a = —
3
;v)=>ChonD.,
"hat" phai dii ng' gidn dS vie ta dc tinh cos- (p.
U K . , , SCJT?!
,
,
hdn UK,,, /d —
3
V i du 3: ( D H - 2 0 n ) M o t doan mach A B g o m hai doan mach A M va M B mac
noi tifep. Doan mach A M g o m dien tro thuan R i mac no'i tiep v o i tu dien c6
dien d u n g C, d o a n mach M B g o m dien tro thuan R2 mac noi tiep v o i cuon
cam t h u a n c6 d o t u cam L . Dat dien ap xoay chieu c6 tan so'va gia trj hieu
d u n g k h o n g d o i vao hai dau doan mach A B . K h i do doan mach A B tieu t h u
BAi TOAN LIEN QUAN DEN THAY DOI CAU TRUC MACH, HQP KIN,
GIATRI TUTCTHCri
/•i/>r|, f.rlrf 'Wt
^humtg phdp gidi
. K h i R va u = Uocos(a)t + cp) giir nguyen, cac phan tit khac thay doi.
MA
o
cong sua't bang 120 W va c6 he so'cong suat bang 1. N e u no'i tat hai dau tu
dien t h i d i e n ap g i i i a hai dau doan mach A M va M B c6 c i m g gia trj hieu
d u n g n h u n g lech pha nhau n/3, cong suat tieu thu tren doan mach A B trong
t r u o n g h o p nay bang
A. 7 5 W .
B. 160W.
C u o n g d o hieu d u n g t i n h bang cong thuc: I = — = —.— = — cos p i
K h i hen quan den cong suat tieu t h u toan mach, t u cong thuc P = l^R, thay
U
U R
Mack
CR2L cong hi/dng; P =
MachR^R^L-.V
d i n h t h i c u a n g d o hieu d u n g , cong suat va he so cong suat ciia mach Ian
=
~. -V ^, , , U
I 7 coso,
I , 0,8
, ,
T u cong thuc: I = —cos^p =>-^2-=
12. ^ _ 1 ^ _ i _ ^ = 4 ( A )
R
I i costpi
3 0,6
Tir cong thuc: P = — cos' ip =
04
cos ipi
Mir
Ri + R ,
\ , : l v ' .»
-cos' 9 = Pcos' 9 = 120cos' 9
L
Noi tat c
Huang dan
11
90
0,8)
0,6
P2 = 160(W)
D. 180 W .
M
la 0,8. T i n h c u o n g do hieu d u n g va cong suat m a c h tieu t h u .
^2
R, + R.
C
l u o t la 3 A , 90 W va 0,6. K h i thay L C bang L ' C t h i he so cong suat ciia mach
COS1P2
C.90W.
Huattg dan
U
I = - = - . - = - C 0 S 9 , ta nhan dugc: P = — c o s ^ = P^^,,^huing cos' 9
R
H du 1: D o a n mach k h o n g p h a n nhanh RLC dat d u o i d i e n ap xoay chieu on
U
2
cos 9
' Kinh n;^liiciii: Mat xich ci'tn dipi;^ toan nm/ lii cos-cp, vi vqy, ngiedi ta nay ra 1/ tinrn'^
M B = V M N ' + N B ^ = lOoVs ( V )
tana =
cos
hu.ing
A.
L
A—C
Rl
M
JR2
Diang p h u o n g phap vec to truot, tam giac can A M B t i n h duoc cp = 30° nen:
P' = 120cos'30" = 9 0 ( W ) = > C h o n C .
,
,
105
Cty
d u 4: C h o doan mach xoay chieu A B g o m d i e n t r o R va m o t cuon day mac
noi tie'p. Dien ap dat vao hai dau doan mach c6 tan so'50 H z va c6 gia t r i
hieu d u n g U k h o n g d o i . D i e n ap g i i i a hai dau ciia R va giCra hai dau cua
cuon day c6 c u n g gia t r i hieu d u n g n h u n g lech pha nhau goc n/3. De h§ so
mach tu dien (noi tat hai ban cue cua no) t l i i cong suat tieu t h u tren toan
iTiach bang
^.P/2.
-;;
B.0,2P.
j
IVlach RLC: U,
U,- - 2 U ,
B. 7 5 W .
C86,6W.
Huong
dan
M a c h R L : P' = r R = - —
D u n g p h u o n g phap vec to t r u g t , tarn giac can
B
A M B t i n h d u o c cp = 30".
P = PCH COS
9
L«c cfau; 9 = 30"
'
UL
, J
Sau CO conghadng : Pc, = lOO(W)
60"
P = Pen cos^ ^ = lOOcos^^o" = 75(W) => Chon B.
Chu y:
Ur ^
UR
•I
/ i d u 5: ( D H - 2012) D a t d i e n ap u = 150>/2 coslOOTtt (V) vao hai d a u doan
U
zf
R.5
phan tu mo In noi tat thi phan tie do xcm nhie khong khong c6 trong
mach.
V i d y 7: M o t mach d i $ n g o m cac phan t u dien t r o thuan R, cuon thuan cam L
va tu dien C mac noi tie'p. Dat vao mach dien m o t d i e n ap xoay chieu on
d j n h . D i e n ap hieu d u n g tren m o i phan t u deu bang nhau va bang 200 V.
Neu lam ngan mach tu dien (noi tat hai ban cue ciia no) t h i d i ^ n ap hieu
d u n g tren dien tro t h u a n R se bang
tu d i e n . C o n g sua't tieu t h u d i e n cua doan mach bang 250 W . N o i hai ban tu
A.IOOV2 V.
B. 200 V.
d i e n bang m o t day d a n c6 dien t r a k h o n g d a n g ke. K h i d o , d i e n ap h i ^ u
C. 2 O O V 2 V .
Huong
d u n g giij-a hai d a u dien t r o bang dien ap hieu d u n g giCra hai d a u c u g n day
A.
60 N/3 Q .
B. 30 N/3
a.
Huaiig
c. isVsn.
Mach RLC:
D.45N/3n.
L i i c d a u cong suat mach tieu t h u : P =
(R + r) =
U^CR + r)-
(R + r ) V ( Z L - Z c f
(1).
Sau d o t u n o i tat, ve gian d o vec to t r u g t va tir gian d o ta n h a n t h a y A A M B
can tai M : Z ^ B = R = 6 0 ( Q )
B
r = ZMBCOs60'' = 3 0 ( n )
250 = 90^+(30N/3-ZC)
A.
R = Z,=Ze
U = ^ U f ^ + ( U , - U e ) ^ = 200(V)
= 100N/2 ( V ) => Chon A.
noi tie'p. Doan mach A M co dien tro thuan 40 Q mac no'i tie'p v o i t u dien,
doan mach M B chi co cuon day c6 dien tro thuan 20 Q, c6 cam k h a n g Zi..
Dong d i ^ n qua mach va dien ap giua hai dau d o a n m a c h A B l u o n lech pha
nhau 60" ngay ca k h i doan mach M B bj noi tat. T i n h Z L .
B.80V3C}.
Huang
UT
Thay r va Z L vao (1):
150^.90
= 200V
V i d u 8: M o t doan mach xoay chieu A B g o m hai doan mach A M va M B mac
A.60V3Q.
Z L = Z M B sineo" =30N/3(n)
= U, =
D . lOOV.
dan
Mach RL: u ' = \JI + Uf =^ 200' = 2\j\
dan
•I
Zc = 3 0 7 3 ( 0 ) =i. Chon B.
V i d y 6: M p t m a c h d i ? n g o m cac p h a n t u d i ^ n t r a t h u a n R, c u p n t h u a n cam L
Truoc k h i noi tat: tan 9 =
Sau k h i noi tSt: tan 9 =
C. 100 N/3 Q.
h i e u d y n g tren R. C o n g suat tieu t h u t r o n g t o a n mach la P. N e u l a m ngSn
-
D.60Q.
dan
Z,
-Zr
— ^ = tan60"
R+ r
M
= tan (-60")
Noi tat MB
T u do giai ra: Z, = 100N/3 ( 0 ) => Chon C.
A—C
va t u d i ^ n C mac n o i tie'p. Dat vao mach d i f n m g t d i ^ n ap xnay chieu on
d j n h . D i ^ n ap h i ^ u d u n g tren L va C bang n h a u va b a n g h a i I a n d i ? n ap
^
R
-4)
P
= -=»ChonB.
mach mac noi tie'p g o m dien t r o thuan 60 Q, cuon day (c6 d i e n t r o thuan) va
va bSng 50 N/3 V. D u n g khang cua tu dien c6 gia t r i bang
dan
Z, = Z,- = 2R =^ P ^ I^R = —
" ^
R- + (z, - z , . ;
mac them tu thi cong suat tieu t h u tren mach bang bao nhieu?
A. SOW.
D . P.
C.2P.
Huong
cong suat hang 1 t h i n g u o i ta phai mac noi tie'p v o l mach m o t t u c6 d i e n
d u n g 100 |aF va k h i d o cong suat tieu thu tren mach la 100 W . H o i k h i chua
TNtinMTVDVVHKhahgl^
Do/ vai „iach RLC, khi R va u = UQ cos(u;t +
'^ongdien tnivc va sau khi noi tat C Ian Imt la
R
M
) giit nguyen, neii bieu thuc cua
,
di}\':>i''SX^:^.
107
lia trf) Men Ihilfc Vdt li L mil
trenhenh
VTV2. t^p 2-Cha
Ofj- T/Vi/it MTV n V VH Hhang
VSn Bien
yi d u 9: (CD-2009) Dat dien ap xoay chieu c6 gia t r i hieu d u n g 60 V vao hai
i2 + ^ i l
i | = I\/2 cos(uJt + i p j , )
_
M:
Vift
9l
Z c = 2Z,
=
-(V
i j = 1V2 cos(u!t: + 9 1 2 )
dau doan mach R, L, C mSc noi tie'p thi c u o n g do d o n g dien qua doan mach
la
tano-, =
i i = I(>cos(100-n:t + 7r/4) ( A ) . N e u ngat bo tu dien C (noi tSt) t h i c u o n g do
d o n g dien qua doan mach la h = Iiicos(]007rt - K/12) ( A ) . D i e n ap giua hai
1)
Dm vai mach RLC, khi R va u = U(, c o s ( u t + 9^,) ^n';? nguyen, neu bicu thwc cua
dong dien tritvc va sau khi ndi tat L Ian hrgt la
i j = I\/2 cos(u;t +
dau doan mach la
A . Li = 60 V2 cos(1007it - 71/12) (V).
B. u = 60 Jl cos(1007:t - 71/6) ( V ) .
C. u = 60 >/2cos(1007rt +71/12) (V).
D . u = 60 xy2 cos(1007it + :x/6) ( V ) .
Huong dan
9u =
Z,
-2Zr
U | , COs(ajt
9l
9i2 - ^ i l
[92=-"
Trieac vd sau mat C m d /2 = /,
tan 92 =
\-Tnidc : tan 9 , =
u - = U o C o s ( ^ t + 43^,)
R^ + ( Z , - Z c )^ = R^ + zf ^ZQ=
2Z^
R
'
Z, ^ Z r
R
,
'
R
=> 9 l = —(\> i j = I() COS
U t + 9 y + (\
1)
TrUdcvdsaumat
Cmdl^=
I2
R^ + ( Z L - Z C ) ^ = R^ + Z ^
Z C = 2ZL
+Sau : tan 92 =
>:
+7>-ui:)'c;tan9j = -z — z
_j_TV,//J^ .
,^. _ __L R C ^
^ 92 = « =^ i2 = I() cos
ujt +
9y - a
z
*i2
RL ^ (•an(-a)
+ S a u ; tan92 = - ~ = tancv => 92 = " =^ '2 =
9] = - a
LOt
= IQ COS
«1
+ S^u ~
,
9il
^i2.^^^ChonC.
I
»„•>
f
12
V i d u 10: Dat dien ap xoay chieu on d j n h vao hai dau doan mach C mac noi
tiep g o m dien t r d thuan R = 100 Q, cuon cam thuan c6 cam k h a n g Z L va tu
«2
dien CO d u n g khang Zc t h i cuong cto d o n g d i e n qua doan mach la ii =
Iiicos(1007i:t + K/4) ( A ) . Neu ngat bo cuon cam (no'i tat) t h i c u o n g do d o n g
a =
1 I!.'.
9il - 9 i 2
, ^^ (6:
dien qua doan mach la i2 = I()cos(1007rt + 3n/4) ( A ) . D u n g k h a n g cua tu bang
A. 100Q.
B.200Q.
2)
T'rw'dc ud sau mat L ma
^ I2
.,,1 rjn
T)2 +
R
M = Uocos(ojt + 9 , , )
Hf, r i ' ^ i '
( 2 L - Z ( - ) = R + Z ^ =^ Z L = 2 Z c
z —z
+Sau : tan 92 =
R
=
-Zc
R
o rhesrs -nmrl,>
z
^ = —
R = tan a => 9^ = a
= IQ cos
+Tradc:
tan V
9 1l =
,,J5;«i .if..
Z,
—
-Zc
R
R
:
':.4Ay;rvrt + u r i j o n e o ) S V s ; i
m d I j = I2 => R^ + ( Z ^ -Z^f
Trade vd sau mat
: tan
D.50Q,
Huong dan
u = Uo cos(ut + s:)u)
+Triidc
C. 150Q.
=
+ZQ
= tan(\ 9 i = rt => i 1 = IQ cos
=>Z^=
IZQ
uJt + 9,, - a
':
= tan ( - a )
92 = ""^i
'2 = ^0
wt +
+ a
-Pi 2
-z
-VSau : tan 92 = — — = tan ( - a ) =^ 92 —
^2 = ^0 '^os wt + 9 u + (-V
•Pi2
_ 9il +912
2
4
—^ = tana = 1
R
Chon A .
^1 d u 11: M o t doan mach xoay chieu g o m cuon day c6 dien t r a thuan R, do
tir cam L noi tie'p v o i m o t tu dien c6 dien d u n g C dat d u o i hieu dien the
Xoay chieu c6 gia trj hieu d y n g on djnh. C u o n g do d o n g dien qua mgch la
108
109