BÀI TẬP DẠNG 1
1.1/đúng !"#$%&'()*+,-./0
/#%1234564-78/9%1234
/#%1234:;64-78/9%1234:
1.2/đúng !"91$%&'()*+,-./0
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1.3/ đúng<=34.-=)>?@A(1BC% -.)>?@
1
DE %
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IE(A J15IA JKIA J1;IE(A JK
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1.5/đúngN/O/P2QR-S?HK(4FGE(B L)/,64TUKEEVW
1
AE(π ≈
1
AE % =
X7>/>.YZ-.64TU/.
C(BC[51(BC[1BC[;CBC[
1.6/ đúngN-=34.-S?HK(\ )1E]^)*/./0-=/
1 &
-.4W
,34-S34+-=/.
K !KE$9$%&'!'5K !KE$91$%&'!'
K !KE$9$%C'!';K !KE$9B$%C'!'
1.7/ đúng<=34.>_AEB (F64-78:?@-=)C1(D% )*
/0-=/
1(B &
-.4W-3-78:?@-=/.`
1
B !K '!'
&
π
= π +
5
1E ! '!'
&
π
= π +
B !K '!'
C
π
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;
1
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&
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1.8/ đúng<=34.H64a.1(F/.
! % C'π
-=-=)-C(1D% )*
/0-=/>:-=/.`
1 !K '!'
1
π
= π + 5
!K '!'= π + π
1 ! '!'
1
π
= π − ; !K '!'
1
π
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1.9/ đúngN-=34.-S4FGIA V01(B (-=64-78/ B 1!'= − -S-=)
- AE 1! % '= − π -=/.`
AE !1 '!'
K
π
= π + 5
&
AE !1 '!'
K
π
= π + B 1 !1 '!'
K
π
= π + ;
&
B 1 ! '!'
K
π
= π −
1.11/đúngI34PF/?@b?Hc\d?@!
ñ
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1.13/ đúngN-=34.(?e@F-=/
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1
- BE!% '=
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"AE% JAE5"AE% JB
AE ! % 'J C!'ω = π
;"AE$% JB
BÀI TẬP DẠNG 2
2.1/đúngN/O/P2QR-S?HK(4FGE(B L)/,64TUKEEVW
1
AE(π ≈
1
AE % =
X7>/>.YZ-.64TU/.
C(BC[51(BC[1BC[;CBC[
2.2/đúng/O/P34.2-S?HVW-.-=)-=Fd-=
?@ed/P/.
1
1
= ±
J
-
1
ω
= ±
5
1
1
= ±
J
-
1
ω
= ±
1
= ±
J
-
1
ω
= ±
;
1
= ±
J
-
1
ω
= ±
2.3/đúng/O/P34.2-S?HVW-.-=)-=Fd-=
?@&/\ed/P/.
1
= ±
J
&
-
1
ω
= ±
5
1
= ±
J
-
1
ω
= ±
&
1
= ±
J
&
-
1
ω
= ±
;
&
1
= ±
-
1
ω
= ±
2.4/đúngN/O/PU@Y-=UF)/,AF-./PF)/,FfFR
AEE[%(34.I6434./P?eHg1Ee&1d-=/.
A(Bh5E(&Ch&h;E(ADh
2.5/ đúngN/PF)/,iFfF(34.>H
E
l
(RF2QRI2-=
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AEE=
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1
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34./.&1
1
AE % =
jR/P/.
AEE[%5AEEE[%AE[%;
B
AE [ %
2.6/N/O/P34.2QRVPF)/,FfF-.RFKE[%(-=U
F)/,1EEIFk-=g-78:?@S4)SBY?4fl-=VW
1
AE % =
X7>-.>4/>.Y/.
I 1[JI A(1[= =
5
I K[JI 1[= =
I 1[JI E[= =
;
I K[JI E[= =
2.7/ đúng/O/P!FKE[%'34.2QR-S\ )/.AE% )m
n-78:?@(34S/H-.F-E/PFf?eVW
2
g 10m / s= V>.YZ-.-=F-=
-=)-DE% -.//.`
1(K[51[A(C[;A(D[
2.8/ đúngN-=2-./P/.+K
1
AE % =
(
1
AEπ ≈
5e/>.Y>(>4/\/,/.
AE[-.C[34.>H/P1E34.>-.>4/P64/.
Ao-.1A51K-.1& 1C-.1K;1B-.1&
2.9/ đúngN/O/P!FJE(&F'VW
1 1
AE %
π =
Ig-78:?@mFk64TUFi-78:?@
&(FT4W364TU-=)
- AC % = π
S-3-78:?@<=-S?HBjRF?@`
&E[%51M[%KE[%;KD[%
2.10/ đúng/O/P2QR34.(n-78:?@/P+&L/P34.>4/P
?7k15H/O/.
A51&;B
2.12/ đúng/O/P34.2`V>.Y>Z-.-=?@1[-.)>
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1
1 %
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2.13/ đúng
1
AE % =
p-78:?@/P2QR+AE(*-=Ug/0/P34.
>e/0-=64-78:?@/\R/.
E(A ! 'π
5
E(AB ! 'π
E(1 ! 'π
;
E(& ! 'π
2.14/ đúng/O/PRFAEE[%2QR34.(n-78:?@/P+Kj+
>/PF/.oV>.YZ-.-=F/P34.O?@
E5A[1[;K[
2.15/ đúng/O/P2QR(/PF)/,FfF]P?n-78:?@,Fk4)
S2QR&YT]P?>_BE1E
1 1
AE % = π =
Ic )
/S/>.Y>-./>.Y>4/PF/.`
M5BK;&
2.16/ đúng/O/PQR)m/.-78:?@-=Uj-=-3-78./PFf
?7?eYTFf-=)\4(-=34.-S\ )
AE! % 'ω =
VW
1
AE % =
34S
4)()*/./0T-=-=/.`
AE !AE '!'
1
π
= +
5
AE !AE '!'
1
π
= −
AE !AE'!'=
;j3e4q/_4
2.17/ đúngN/O/P34.2QR-S\ )K(B]^I6434.
/P?ergKEeBC34S/H(/0E/P34.B1-.-=-78:?@
-=/.`
AC !o '!'
C
π
= π +
5
D !o '!'
&
π
= π −
D !o '!'
&
π
= π +
;
D !o '!'
C
π
= π −
2.18/ đúngN/O/P2QRp-78:?@/P+o/O(dn/
&/.E(E&1h5e&CE
1
AE % =
-.
1
AE
π ≈
5H/O/.`
K5&B;o
2.19/ đúngN/O/P34.2<=)>-=/.oC% 5eF
K 1=
ed?@d4FG/O/.`
E(1 5E(&1 E(KB ;E(B1
2.20/ đúng/O/PF)/,AEE(/P34.>H1EL2QR(-=:?@/P
34.11(BL88/O2QRVW
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2.21/đúngN/O/P2QR`-=UF)/,AFLk-=4)S /P+
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2.22/ đúngN/O/PF)/,E(1F2QR34.34.>H/P/.
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l
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BÀI TẬP DẠNG 3
3.1/ N/OY-=iF)/,1-. ,:W2T(34. l ,F8834
.I*
t∆
/O>_KELd34./OHM(ot*
t∆
H/O34
.l’>_,&oVW
2
g 9,8m / s= 34.?\4l/O/.
AKK(15AB1(AACE(E;ACM(o
3.3/ đúng[*YY64T/OgIj/HNUId.Ff34c/?e)>H
NUId?@A%CHIj64T/OYY/O34.Ffr4F64T/OdW
TW/\u
T
6
/\5d
6
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3.4/ đúng[*YY64T/OgU/HBF5e?F8vCKEEFNw.WH
YYW=`
CB(M 5CM(B MC(B ;BM(C
3.5/đúng[*/OgU/HAEF5e?F8CKEEFj4F
/OFfWrTT34.e.u
3%∆ =l l
5
0,3%∆ =l l
0,03%∆ =l l
;
0,64%∆ =l l
3.6/đúng34./OdAx4F
dAx5dE(BxTE(Bx;dE(Ax
3.7/ đúngN/O.l2)7)*Lk/OFiQR
0
α YTlI*:W2,-SQR
α
-=)/.
0
v 2g (cos cos )= α − αl 5
0
v 2g (cos cos )= α − αl
0
v 2g (cos cos )= α − αl
;
0
v 2g (cos cos )= α − αl
3.8/ đúngN/O.l2)7)*Lk/OFiQR
0
α
YTlF)/,/OI*:W2,-SQR
α
/>d:W/.
0
T mg(3cos 2cos )= α − α
5
0
T mg(2cos 3cos )= α − α
0
T mg(3cos 2cos )= α − α
;
0
T mg(3cos 2cos )= α − α
3.9/ đúngN/O.
l
1E2)7Lk/OFiQR?@E(A
-38?HT(Y4W3/O-=)?@AK% 2-4f-S:W-38-78:?@/O
34.(34Sg-78:?@ T()*/./0/O64-78:?@/\R
2
g 9,8 m / s= )-S/./O/.
s 2 sin(7t )cm= − π
5
s 2 2 sin(5t )cm= − π
s 2 2 sin(7t )cm= − π
;
s 2 2 sin 7t(cm)=
U3.10/ đúngN/On)*
2
g 10 m / s= (10KE:W>_,AEE
VW
2
10π ≈
Ig-78:?@Fk4&YyWl-S-=)
5
π
% 2-4f:W2)
*/./064-78:?@234/O/.
4
s 5 sin( t ) (cm)
5
π
= −π
5
5
s 5 sin t (cm)
4
π
=
5
s 4sin( t ) (cm)
4
π
= − π
;
5
s 5 sin( t ) (cm)
4
π
= − π
3.12/đúngN/O34. l -.F)/,64TU/.5e@64TU_86-./O,2
qZQ[e4*_*Z/.z(4F/O/.
1
l
g
π
5
1
1
1
l
qE
g
m
π
+
÷
1
l
qE
g
m
π
+
;
1
l
qE
g
m
π
−
3.13/đúngNffFn.H*@-=)- 4FW\34,64+*{I\ff
2/O.l4Fi/O/.
1
l
g
π
5
1
1
1
1
-
9
1{
π
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l
1
1
1
-
9
1{
π
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l
;
1
1
1
1
-
9
{
π
÷
l
3.14/ đúng/O34.l ,2-.\W4W-S)|E4F
T 2
g a
= π
−
l
4WW/.
j/H\345j/H=\34j4)Q34;j4)=\34
3.15/đúngN/O34. l -.F)/,64TU/.5e@64TU_86|E-./O,
34._*34
E
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* RQR(34S/H4F/OH/.
1
1
1 π
+
÷
l
qE
g
m
5
1
1
1 π
−
÷
l
qE
g
m
1 π
+
l
qE
g
m
;
1 π
−
l
qE
g
m
BÀI TẬP DẠNG 4
Bài 1:]34P/\/,/.`
A
A
!
1E
&
t
π
π
+
'-.
1
1
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1E
C
t
π
π
+
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C
π
5`;A1
&
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−
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&
π
D`;1A
C
π
Bài 3`Ir,
A
!
&
t
π
ω
+
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1
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t
π
ω
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t
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1
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t
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J;`E
Bài 4:}7r,.\~ 4:W`
A
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1
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t
π
π
+
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1
& 1 c
π
`
`1(K !
1 E(&Mt
π
−
'J5`1(K
1 t
π
J` !
1 E(&Mt
π
−
'J;`
1 t
π
Bài 5`N-=Y*34.~(/\/,/.
A
& !AE#π%&'!'J
1
K !AE9
π%C'!'!?@:W'
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BE% 5BE% B% ;B%
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'1% !B
ππ
+=
tx
J5
'1% !1B
ππ
+=
tx
J
'1% !B
ππ
+=
tx
J;
'K% !B
ππ
−=
tx
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r,/.. 4:W`
& AEE
1
x a t
π
π
= +
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J5
& AEE
1
x a t
π
π
= +
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J
& AEE
&
x a t
π
π
= −
÷
J;
& AEE
&
x a t
π
π
= −
÷
Bài 8`N-=>_Y*34P~2 4`
A
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t
π α
+
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1
K & ! 't
π
5Hr,/S
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9
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+=
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J5
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ππ
+=
tx
J
'1% !B
ππ
+=
tx
J;
'K% !B
ππ
−=
tx
Bài 11`34.~(~\ )(~?H
1
-.?\4/\/,/.
1
&
π
-.
C
π
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B
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J15
&
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J
1 1
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K
π
;
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Bài 12N-=Y*-.34.`
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A
π=
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A
π=
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Bài 13:N-=34.~~\ )`
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B !ω#
&
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&
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&
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Bài14:]34.~/.
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9
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