Nội dung ôn tập học kì 1 Toán 11 năm 2020 - 2021 trường THPT Trần Phú - Hà Nội - TOANMATH.com

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vA

DAo

r4o

QUANG

TRI

an

rnr

cnirvn

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@A thi c6 2 trang)

rt

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srNH

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Lop

9

Kh6a

ngiy

20 thimg 3 n5m 2$1,8
naoN

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Thdi gian ldm

bdi:

150 philt, kh6ng kA thdi gian giao

di

Ciu

1. (2,0 diAm)

Khi n6i vC thAn kinh

vi

giic quan i' ngucri, c6c ph6t bi6u sa,r dny

li

d,ing hai, sai? Giai thich.

r.

Phan x4 kh6ng cii6u kiQn c6 tinh ch6lcii truy€n va _{4a11glLjIlxl,1ifoCt}.][h(r.}

.^.r

--B*..^----J.



^-Z.Dsavdo

c6u truc, hQ thAn ki-nh

d"#

ctriittranh hQ

thin

t<Hn van dQng vn hQ th6n

kinh siirh du6ng.

3. Ngucri cQn thi mu6n nhin rO nhtng vpt o xa ph6i deo kinh m6t l6i.

4. Khi b4n d6 chdn tr6i thi phAn vo b6n cAu bdn ndo tr6i se khoi ph6t ho4t tlQng cIo"

Ciu2.

(3,0 di€m)

1. Khi n6i vC lodi ong vd lodi hoa, c6c ph6t bi6u sau ddy ld dring hay sai?

Giii

thich.
a) Tflp hqp nhfrng con ong thq l6y mflt hoa o mQt

vuln

hoa ld mQt quAn thO.

b) Trong m6i quan h6 gifra mQt lodi hoa vh lodi ong

hft

m4t hoa d6 thi lodi ong c5 ltyi
cdn lodi hoa bihai.

2. Gih sr? lu6'i

thfc

5n ctia mQt quin x6 sinh vpt gdm c6c lodi sinh vAt

ki

hi6u

laA,

B,

C, D;-E, F, G vd

Il.

Cho bi€t loai A vd loi\i C 1a sinh .,'flt sdn suit, c6c

loii

con iqri ld sinh r,4t
ti6u thU. Trong

iudi

th,3c .In nlry, n€u bo lodi C ra

kii6i

qriiin xd

thi

chi loai D vd

loii

Ir rn6t

di. So AO tuOi thric dn ndo sau dAy dring

voi

chc thdng tin d6 cho? GiAi thich.

,/

Sl*

tt

Cffu 3. (2,0 di€m)

T4i sao khi lai hai ddng thuAn, uu thti lai bi6u hiQn cao ntr6t O F1, sau d6 gi6m dAn qua

cac tht! hgt

Cflu 4. (2,0 di€m)

Gen

B

c6 900 nucl€dtit lopi timin (T) va c6

ti

lQ

_.A+T3

_{:i: :}

_f.

c"r,

B

bi

dQt bi6n dang
thay th6 mQt cflp G-X bAng mQt c4p A-T tr& thAnh gen b.

finl

tOng sO 1i6n t<tit triOrO cta gen

b bdng hai c6ch.

Cffu 5. (2,0 diAm)

O mQt lodi c6n

trtng,

gen

A

quy dinh thdn xdm trQi hodn todn so

vdi

gen a quy dinh

th6n tlen; gen B. quy ttinh c6nh ddi trQi hodn

toin

so

v6i

gen b quy dfnh cdnh cpt. Cdc gen
quy dinh mdu sic th6n vd hinh dpng c6nh nim tr€n mQt c4p nhi6m iAc thC thudne vA lien ktit
hoan.toan.

Lai

phdn tfch co ttriS.ai hcyp

tg

vO hai

c{p

gin.n6i

tr6n thu duqc E6.

fheo

l1i

thuyiSt,

ti

lQ kiiiu hinh 0 F6 nhu thti ndo? Vit5t scr OO tai. Bitit ring, _{kh6ng x6y}_ra_d0rbi6n.

It'q*--*l---*'fi

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III.

^

v

fAir-+"ll**

if

\m}i,

eAI*o

k:>.-@6ffi*

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y) _C6ra_6.('2,0 dt\m)

K iti n6i -,,e dOt bit5n nhiErn sis th6, c6c phdtbi6u sau d6y ld dting hay sai? Gi6i thfch.
1. Dot bi6n nhiSrn s6c th6 ohi xay ra

b

cdc nhi6m s6c thO thudng md kh6ng

xiy

ra o
c6c nhiSrn sic th6 gi6i tinh.

2. HQi chrlng Eao chi _e?pe nam md kh6ng c6 0

nt.

3. Co chO ph6t sinh th6 da bQi ch8n ld

tlt

cd c6c c[p nhiSm sic th0 tg nhan ddi nhung
cc mgt s0 cap nhi6rn shc thiS khdng ph6n ly.

4.

Lolt

tac nh6n tiQt bitin eid dugc sri dpng d6 tac, ra gi6ng dfiu

tiin

da bQi c5 16 to vd

div

hon dan_e ltrdng bOi binh thuone ld EMS (6t1,1 _{rndtan sunphdnat).}

Ciu

7.

13,tt

diintl

Cho bi6t rnSi gen quy dlnh mQt tinh trang, gen trQi lA trQi hodn todn, kh6ng ph6t sinh

dQt biiSn. X6t cdc phdp lai sau:

(1) AaBb x

aabb.

_{Z;

aanb x

AaBB.

(3) aaBb x aaBb.

;(4)

AaBb x

AaBB.

_{'(5) AaBb x}

aaBb.

(6) AAbb x aaBb.

Theo

li

thu1,[1, troug c6c ph6p lai tr6n, phep lai nao cho doi con co sO loai ki6u gen

nhiOu hon s6 loai ki6u hinh? Gi6i thich.

"

C6u 8. (2,0 dilm)

Then l,.thuy6t, khi 2 te bao sinh tinh cua mot co thO co kieu gen Hatsb giArn

pirit

l;inir

.

thudng c6 thO tpo ra bao nhi6u lo4i giao tri? Vi6t

ti

lQ c6c lopi

giaoi*

AO.

a-A',3 r) q t:i---t
i_arj. ..r. _iz,:):!!,_'in,i

) ?

'

_O_mQt

lodi thFc v4t tg thu phAn

bit

budc, gen

A

quy dinh hoa d6 trQi hoin

toin

so v6i

gen a qu1' ,Jinh _{hoa trdng. Cho 2}c61, lrou d6. (P) tU thU ph6n, thu duoc F1. Theo

ly

thuy6t,

ti

l0 ki6u hinh o Fr ld bao nhi6u? Bi0t 6t gen een ndrn tr6n nhiSrn ndm tr6n nhi6m sic s[c th6 thrriyns vA th6

thulng

va kh6ng kh6no *ay xAv rar:u

-.!

dOt bi6n.

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