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De ktra toan 12chuong 2

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<span class='text_page_counter'>(1)</span>kiÓm tra. Hä tªn:................................... Líp:........................................ M«n : To¸n GT 12 Thêi gian : 45 phót. ĐỀ 1 0,75. 81 Câu 1:(2đ) Thực hiện tính A =.  1      125 . . 1 3.  1     32 . . 3 5. 8. 2 3. Câu 2:(8đ) Giải phương trình : a) b). 9 x+1 +3 x+2 − 18=0. log 2 (x - 3) + 3.log 8 (x - 1) = 3 log3  x  1 log 1  5 x  1  3. c). 3 x. x d) log 2 (4.3  6) = log 2 (9 - 6) + 1. ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………....

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<span class='text_page_counter'>(3)</span> kiÓm tra. Hä tªn:................................... Líp:........................................ M«n : To¸n GT 12 Thêi gian : 45 phót. ĐỀ 2 0,75. 81 Câu 1:(2đ) Thực hiện tính A =.  1     125 . . 1 3.  1     32 . . 3 5. 8. 2 3. Câu 2:(8đ) Giải phương trình : a). 4 x −10 .2 x −1 − 24=0. 1  log 1  x   log 2 x  1 2 2  b) x x c) log 2 (4.3  6) = log 2 (9 - 6) + 1. log3  x  1 log 1  5 x  1  3 3 d) ………………………………………………………………………………………………............ ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………........... ……………………………………………………………………………………………………... ………………………………………………………………………………………………........... ………………………………………………………………………………………………............

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