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Một số đề và bài giải Toán OLYMPIAD bậc Tiểu học

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Giới thiệu cùng các em một vài bài toán trích từ các đề thi Olympiad bậc tiểu học
kèm theo bài giải bằng tiếng Anh để các em tham khảo.
TÔN NỮ BÍCH VÂN
 Suppose today is Tuesday. What day of the week will it be 100 days from
now?
 I have four 30¢ stamps and three 50¢ stamps. Using one or more of these
stamps, how many different amounts of postage can I make?
 Find the sum of the counting numbers from 1 to 25 inclusive. In other
words, if S = 1 + 2 + 3 + ... + 24 + 25, find the value of S.
 In a stationery store, pencils have one price and pens have another price. 2
pencils and 3 pens cost 90¢. But 3 pencils and 2 pens cost 85¢. How much
does 1 pencil cost?
 A work crew of 3 people requires 3 weeks and 2 days to do a certain job.
How long would it take a work crew of 4 people to do the same job if each
person of both crews works at the same rate as each of the others?
Note: Each week contains 6 work days
SOLUTIONS
 Every 7 days from "today" will be Tuesday. Since 98 is a multiple of 7, the 98th day
from today will be Tuesday. Then the 100th day from today will be Thursday.
 Method 1
List the amounts in an organised manner.
Amounts Number
Amounts from 30¢ stamps: 30, 60, 90, 120 4
Amounts from 50¢ stamps: 50, 100, 150 3
Amounts from combining
30¢ stamps and 50¢ stamps: 30+50, 30+100, 30+150 3
60+50, 60+100, 60+150 3
90+50, 90+100, 90+150 3
120+50, 120+100, 120+150 3
Total 19


Method 2
The number of choices we have in using the 30¢ stamps is 5; we can use either 0, 1,
2, 3 or 4 of the 30¢ stamps. Similarly, we have 4 choices with respect to the 50¢ stamps;
we can use either 0, 1, 2 or 3 of the 50¢ stamps. Each of the 5 choices for stamps. This
gives a total of 20¢ combinations. However, this total includes the combination of zero
30¢ stamps and zero 50¢ stamps. Since one or more of the stamps must be used, we
exclude the combination of none of each. Therefore, 19 different amounts of postage can
be made.
 Method 1:
Arrange the numbers like this: 1 + 25 = 25
2 + 23 = 25
3 + 22 = 25



12 + 13 = 25
25 = 25
Method 2:
Given (1) S = 1 + 2 + 3 + ... + 23 + 24 + 25
Reverse order of right side of (1) (2) S = 25 + 24 + 23 + ... + 3 + 2 + 1
Add (1) and (2) (3) 2S = 26 + 26 + 26 + ... + 26 + 26 + 26
Simplify the right side of (3) (4) 2S = 26 x 25
Divide both sides of (4) by 2 (5) S = 13 x 25 or 325
The required sum is 325
 Method 1:
By combining both purchases, we find that 5 pencils and 5 pens cost 175¢. Then 1
pencil and 1 pen cost 35¢, or 2 pencils and 2 pens cost 70¢. Since 3 pencils and 2 pens
cost 85¢, 1 pencil costs 15¢.
Method 2:
Algebra: Let x represent the cost of one pencil and y the cost of one pen.

Give (1) 2x + 3y = 90
Give (2) 3x + 2y = 85
Multiply both sides of (2) by 3 (3) 9x + 6y = 255
Multiply both sides of (1) by 2 (4) 4x + 6y = 180
Subtract (4) from (3) (5) 5x = 75
Divide both sides of (5) by 5 (6) x = 15
Answer: A pencil costs 15¢
 Each person of the work crew of 3 people worked 20 days. Thus the number of
individual work days needed to do the job was 60. Then each member of the work
crew of 4 people must work 15 days in order to provide a total of 60 individual work
days.
13 x 25 = 325

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